0.017 moles PbNO₃
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableMolesStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 4.5 g PbNO₃
[Solve] moles PbNO₃
Step 2: Identify Conversions
[PT] Molar Mass of Pb - 207.2 g/mol
[PT] Molar Mass of N - 14.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of PbNO₃ - 207.2 + 14.01 + 3(16.00) = 269.21 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 4.5 \ g \ PbNO_3(\frac{1 \ mol \ PbNO_3}{269.21 \ g \ PbNO_3})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 0.016716 \ moles \ PbNO_3[/tex]Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
0.016716 moles PbNO₃ ≈ 0.017 moles PbNO₃
Calculate the molar mass of Ba(C2H3O2)2
Answer:
1. Barium Acetate.
2. Formula: Ba(C2H3O2)2.
3. Molar Mass: 255.415.
Explanation:
Consider these compounds:
a. CuCO3
b. ZnS
c. Ni(CN)2
d. Ag2CrO4
Complete the following statements by entering the letter corresponding to the correct compound. Without doing any calculations it is possible to determine that silver carbonate is more soluble than _________ , and silver carbonate is less soluble than ____________. It is not possible to determine whether silver carbonate is more or less soluble than _______________ by simply comparing Ksp values.
Explanation:
If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.
- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B
3.604m + 104.29m + 3.1m + 17.41m. The sum expressed in the correct number of significant figures is
Answer:
128.4 m
Explanation:
3.604m + 104.29m + 3.1m + 17.41m
Add all the values
= 128.404 m
The significant figure rule for addition is for the sum to have the same number of decimal places as the value with the least number of decimal places. In the addition sentence 3.604m + 104.29m + 3.1m + 17.41m, the value with the least number of decimal places is 3.1, which has 1 decimal place. Therefore, we round our sum so that it also has 1 decimal place.
128.404 m
= 128.4 m
I hope this helps!
N2+H2---2 NH3?
ASSIGN OXIDATION STATES AND
FIND OXIDIZING AND REDUCING
AGENTS?
Please with steps if possible
Answer:
Oxidizing Agent - Nitrogen
Reducing Agent - Hydrogen
Explanation:
The equation of the reaction is given as;
N2 + H2 --> 2 NH3
Oxidation Rules:
- The oxidation number of an element in it's free state is Zero. This means oxidation state of N2 and H2 are Zero.
- The oxidation number of a neutral compound is the sum of the oxidation state of the individual elements and is equal to zero.
- Oxidation Number of Hydrogen in a compound/Molecule is 1 except in hydrides where it is -1
This means that oxidation number of H in NH3 = 1
Oxidation state of N in NH3;
x + 3(1) = 0
x = -3
The reducing agent loses electrons. Loss of electrons is represented by increase in oxidation Number. The oxidation number of H increases from 0 to + 1
The Oxidizing agent gains electrons. Gain of electrons is represented by decrease in oxidation Number. The oxidation number of N decreases from 0 to -3
EXPERIMENT 1: Identify the oxidation and reduction half-reactions that occur in
Cell 5: Mn(s) | Mn(NO3)2 (aq) || Zn(NO3)2(aq) | Zn(s)
Remember to use proper formatting and notation.
Answer:
Cathode: Mn → Mn²⁺ + 2e⁻ (Oxidation)
Anode: Zn²⁺ + 2e⁻ → Zn (Reduction)
Mn | Mn²⁺ || Zn²⁺ | Zn
Explanation:
To identify the half reaction we need to see the oxidation states.
Mn(s) → Ground state → Oxidation state = 0
Mn(NO₃)₂ → Mn²⁺ → The oxidation state has increased.
This is the oxidation reaction. It has released two electrons:
Mn → Mn²⁺ + 2e⁻
Zn(NO₃)₂ → Zn²⁺
Zn → Ground state → The oxidation state was decreased.
This is the reduction reaction. It has gained two electrons:
Zn²⁺ + 2e⁻ → Zn
Cathode: Mn → Mn²⁺ + 2e⁻
Anode: Zn²⁺ + 2e⁻ → Zn
Mn | Mn²⁺ || Zn²⁺ | Zn
How many microliters are in 41.0 mL
Answer:
41000 is the answer
The amount of microliters in 41.0 mL is 41,000 microliters
How to find the volume in microlitersTo convert milliliters (mL) to microliters (µL), you need to multiply the value in milliliters by 1000 because there are 1000 microliters in 1 milliliter.
So, to convert 41.0 mL to microliters:
41.0 mL * 1000 = 41,000 µL
Therefore, there are 41,000 microliters in 41.0 mL.
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Question: A first order reaction : B===>C has a half life of 20mins. What percentage shall have reacted after 47minutes
Answer:19.6%
Explanation:
From K=0.693/t
0.693/20 =0.03465min^-1
But rate law is K =2.303/t log a/(a-x)
Substitute the value of k
0.03465=2.303/47 log a / (a-x)
Log a/ (a-x) = 0.7071
a/ (a-x) = 5.094
(a-x)/ a = 1/5.094 = 0.196
Percentage of reactants remaining after 47 minutes= 0.196× 100% = 19.6%
Which of the following wavelengths penetrate earth's atmosphere?
O Microwaves
O Gamma rays
O Radio waves
O X-rays
Answer:
Radio waves are able to penetate the earth's atmosphere due to their low frequency and long wavelength.
Let me know if this helps!
what is the oxidation state of nitrogen in a nh4f molecule
Answer:
+3
Explanation:
NH₄F
=> N + 4H + F = 0
=> N + 4(+1) + 1(-7) = 0
=> N = 7 - 4 = +3
A 0.5242-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.9740 g of CO2 and 0.1994 g of H2O. What is the empirical formula of the compound?
Answer:
C₃H₃O₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 0.5242 g
Mass of CO₂ = 0.9740 g
Mass of H₂O = 0.1994 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For carbon, C:
Mass of CO₂ = 0.9740 g
Molar mass of CO₂ = 12 + (16×2)
= 12 + 32 = 44 g/mol
Mass of C = 12/44 × 0.9740
Mass of C = 0.2656 g
For hydrogen, H:
Mass of H₂O = 0.1994 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16 = 18 g/mol
Mass of H = 2/18 × 0.1994
Mass of H = 0.0222 g
For oxygen, O:
Mass of compound = 0.5242 g
Mass of C = 0.2656 g
Mass of H = 0.0222 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C + Mass of H)
Mass of O = 0.5242 – (0.2656 + 0.0222)
Mass of O = 0.5242 – 0.2878
Mass of O = 0.2364 g
Finally, we shall determine the empirical formula. This can be obtained as follow:
Mass of C = 0.2656 g
Mass of H = 0.0222 g
Mass of O = 0.2364 g
Divide by their molar mass
C = 0.2656 /12 = 0.0221
H = 0.0222 /1 = 0.0222
O = 0.2364 /16 = 0.0148
Divide by the smallest
C = 0.0221 / 0.0148 = 1.5
H = 0.0222 / 0.0148 = 1.5
O = 0.0148 / 0.0148 = 1
Multiply through by 2 to express in whole number.
C = 1.5 × 2 = 3
H = 1.5 × 2 = 3
O = 1 × 2 = 2
Empirical formula => C₃H₃O₂
Kayla is creating a model to show her understanding of the water cycle. She wants to show that water is constantly cycling between the atmosphere and Earth’s surface.
What would be the BEST type of model for Kayla to create.
A 3-D model of H2O created with gumdrops and toothpicks.
A. A diagram of molecules gaining energy as they being to evaporate and enter the atmosphere.
B. A poster with pictures of lakes, oceans, rivers and ponds.
C. A circular diagram with arrows showing the movement of water between Earth’s surface and atmosphere.
Answer:C
Explanation:
It would be the most visually understandable.It would be easyer to understand what you are modeling.
QUICK PLZZZ why do people run away from the hot weather into the cool ocean on a sunny day? Explain your answer using one of the properties of water?
Which of the following is TRUE if Esys = 260 J?
Answer:
Both the system and the surroundings are losing 260 J. The system is gaining 260 J, while the surroundings are losing 260 J. Both the system and the surroundings are gaining 260 J. The system is losing 260 J, while the surroundings are gaining 260 J. None of the above is true.
What can wind energy be transformed or converted into?
Answer:
Electrical energy
Explanation:
The wind Mill is an example of a device that converts wind energy into electrical energy
Convert to moles 12.06 x 10^22 molecules
Answer:
0.2 mole
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 12.06×10²²
Number of mole =?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
12.06×10²² molecules = 12.06×10²² / 6.02×10²³
12.06×10²² molecules = 0.2 mole
Thus, 12.06×10²² molecules is equivalent to 0.2 mole
what is the equation between aqueous sodium carbonate and dilute hydrochloric acid
Answer:
When solutions of sodium carbonate and hydrochloric acid are mixed, the equation for the hypothetical double displacement reaction is: Na2CO3 + 2 HCl → 2 NaCl + H2CO3 Bubbles of a colorless gas are evolved when these solutions are mixed.
2NaN3 produces 2Na+3N2 How many moles of each product are produced when 6 moles of NaN3 react?
Answer:
[tex]6molNa\\\\9molN_2[/tex]
Explanation:
Hello there!
In this case, given the chemical reaction:
[tex]2NaN_3\rightarrow 2Na+3N2[/tex]
It is possible to evidence the 2:2 mole ratio of the reactant to Na and the 2:3 mole ratio of the reactant to the N2; therefore, the following setups allows us to compute the moles of products:
[tex]6molNaN_3*\frac{2molNa}{2molNaN_3}=6molNa\\\\6molNaN_3*\frac{3molN_2}{2molNaN_3}=9molN_2[/tex]
Best regards!
A certain electromagnetic wave a wavelength of 415 nm. What is the frequency of the wave in hz?
Answer:
The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz
Explanation:
The wavelength of the electromagnetic wave, λ = 415 nm
The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s
Given that an electromagnetic wave is a periodic wave, we have;
The speed of the electromagnetic wave, c = f×λ
Where;
f = The frequency of the electromagnetic wave
Therefore, we have;
f = c/λ
From which we have;
f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz
The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz
WS 3.5 more Lewis structures
La
Nd
Pm
Sm
Tb
Но
Er
Tm
Yb
Lu
Ac
Np Pu Am Cm Bk
CH
Es
Fm Md No
100 g of acetic acid (CH, COOH) is dissolved in a 500.0 ml solution. What is the molarity? Report your answer with the
correct number of significant figures
Answer:
3.34 M
Explanation:
Step 1: Given data
Mass of acetic acid: 100 gVolume of solution (V): 500.0 mL (0.5000 L)Step 2: Calculate the moles of acetic acid
The molar mass of acetic acid is 60.05 g/mol.
100 g × 1 mol/60.05 g = 1.67 mol
Step 3: Calculate the molarity of acetic acid
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
M = 1.67 mol/0.5000 L = 3.34 M
Consider the reaction of nitrogen dioxide with molecular hydrogen: 2 NO2(g) + 7 H2(g) + 4H2O(l) + 2 NH3(g) Calculate AH°rxn for this reaction given by manipulation of reactions (i) and (ii): 2 NH3(g) → N2(g) + 3 H2(g) AH°rxn = +92.0 kJ (i) N2(g) +4 H2O(l) ---> 2 NO2(g) + 4 H2(g) AHºrxn = +3.40E2 kJ (ii)
The reaction enthalpy is the heat energy absorbed or evolved from a reaction. The enthalpy of reaction for the given reaction is -432 KJ.
What is enthalpy?Enthalpy is the heat energy evolved or absorbed by a reaction system. The reaction enthalpy can be negative or positive. A positive enthalpy means the heat is absorbed and a negative enthalpy means that the heat is evolved by the system.
The given two reactions 1 and 2 have to be reversed to get the net reaction as follows. Thus the positive enthalpy of these reactions becomes negative when reversed.
[tex]2NO_{2} + 4 H_{2} \rightarrow N_{2} +4H_{2}O\\ -92 KJ\\ \\N_{2} + 3 H_{2} \rightarrow 2NH_{3} - -340 J[/tex]
Now, add these two reactions so that we get the reaction of nitrogen dioxide and hydrogen to give water and ammonia and the enthalpies of the above reactions are also added.
Sum of enthalpies of above two reactions is the enthalpy of the required reaction written as follows:
[tex]2NO_{2} + 4 H_{2} \rightarrow N_{2} +4H_{2}O\\ -92 KJ\\ \\+\\ \\\\N_{2} + 3 H_{2} \rightarrow 2NH_{3} - -340 J\\\\\rightarrow NO_{2} + 7H_{2} \rightarrow 4H_{2}O + 2NH_{3}[/tex]
Enthalpy of net reaction = -92 + -340 = -432 KJ
Therefore, enthalpy of reaction for the given reaction is -432 KJ.
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You are presented with a white solid and told that, because of careless labeling, it is not clear whether the substance is mercury(I) nitrate, calcium carbonate, or aluminum nitrate. When you transfer the solid to a beaker and add water, the solid dissolves to give a clear solution. Next, a Na2SO4(aq) solution is added and a white precipitate forms.
Required:
a. What is the identity of the unknown white solid?
b. How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 2.5 M CH3OH?
Answer:
aluminum nitrate
Explanation:
We already know that calcium carbonate is insoluble in water hence it will not even dissolve in the water.
Mercury(I) nitrate is soluble in water, when sodium sulfate (Na2SO4) is added to mercury(I) nitrate (Hg2(NO3)2), a pale yellow precipitate is formed.
Aluminum nitrate is soluble in water and reacts with Na2SO4(aq) solution according to the reaction, 2Al(NO3)3(aq)+3Na2SO4(aq) ---> Al2(SO4)3(s)+6NaNO3(aq). The precipitate, Al2(SO4)3(s) is a white crystalline hygroscopic solid.
how partition of Bengal mobilize
please help me
9.
Calculate the mass of a liquid with a density of 3.2 g/mL and a volume of 24 mL.
EASY CHEM, WILL GIVE BRAINLIEST!!
Hi there!
[tex]\large\boxed{4.04g}[/tex]
To solve, we can use dimensional analysis to convert from molecules to grams.
We must use Avogadro's number (6.02 × 10²³) in converting from molecules to moles.
After converting, multiply by the atomic mass, or grams per mole.
[tex]1.204 * 10^{24} moles *\frac{1 mol}{6.02*10^{23}moles}* \frac{2.02g}{1mol }= 4.04g[/tex]
can someone please help!!
Answer:
1:aerobic
2:anaerobic
3:aerobic
If 10 grams of NaHCO3 react with an excess of HCl, what would be the theoretical mass of NaCl produced?
Worth 15 points. I will give brainliest for best answer. Thank you.
Answer:
Explanation:Reaction NaHCO3 + HCl ⇒ NaCl + H2O + CO2
Molar mass M = (22.99+1.008+ 12.01+3·16 ) g/mol. Calculate
Amount of substance n =m/M, n(NaCl) is equal.
M(NaCl) = 58.44 g/mol and mass m= n·M
star_____ has the greatest absolute brightness
Answer:
Star A would have the greater absolute brightness. This is because absolute brightness finds out the actual brightness of a star at a standard distance from Earth. If Star A is twice as far from Earth as Star B but they still both appear to have the same amount of brightness.
Do all living things depend on nonliving things to survive? Support your answer with an example.
Answer:
Living things need nonliving things to survive. Without food, water, and air, living things die. Sunlight, shelter, and soil are also important for living things. ... Plants use water from the soil, carbon dioxide from the air, and energy from sunlight to make their own food.
Explanation:
Answer: yes they do here are is an example a tree depends on water to keep it hydrated.
Explanation:
The total oxide ion charge in a formula unit of Mn2O3 is 6-. What is the charge on each manganese ion ?
Answer:
Mn= +3 charge
Explanation:
if you take what we know, and that would be the charge of oxygen, we know that oxygen has a 2- charge and there are 3 sets of O^2- so multiply the number of oxygen times the charge and you get 6-.
Next set up an equation as listed in the picture which will be 2(x)=6
and that is the charge of the Mn ion.