Answer:
{-1, 3, 7, 11, 15}
Step-by-step explanation:
we just substitute the set of even numbers in the function f(x) given to get our corresponding set of odds numbers
for 0
2(0)-1=0-1=-1
for 2
2(2)-1=4-1=3
for 4
2(4)-1=8-1=7
for 6
2(6)-1=12-1=11
for 8
2(8)-1=16-1=15
Please answer the question in the image below ASAP
Answer:
B
Step-by-step explanation:
Here, we have a grain silo having 2 shapes fused together to make it.
A cylinder and then a hemisphere ( half sphere)
Now, we want to calculate the volume of grain that could completely fill the silo.
Mathematically, to do that, we will need to add the volume of the cylinder to the volume of the hemisphere.
Mathematically,
Volume of cylinder is;
pi * r^2 * h
From the question, r = 6 ft and h = 168 with pi = 22/7
Substituting these values, we have
Volume of cylinder= pi * 6^2 * 168 = 6,048 pi
The volume of the sphere will be;
4/3* pi * r^3= 4/3 * pi * 6^3 = 288 pi
So the total volume of the silo will be;
288 pi + 6,048 pi = 6336 pi
So to have the final result, let’s multiply by value of pi
6336 * 22/7 = 19,193 ft^3
The closest answer here probably due to previous approximations is 19,008 ft^3
HELPPPPPPPPPPPPPPPpppp
Answer:
Option (A)
Step-by-step explanation:
Two bases of the the given cylinder are circular in shape in the given picture.
When we take a cross-section of the cylinder parallel to the bases or perpendicular to the height, we get a circle exactly same as the bases (As shown on the rectangular slide).
Cross-section will have the same radius as the bases of the cylinder.
Therefore, Option (A) will be the answer.
compare two spheres. first has a diameter of 8 yards. The second sphere has a diameter of 1064 yards. Determine the ratio of the volume of the larger sphere to the volume of the smaller sphere
Answer:
The ratio of the volume of the larger sphere to the volume of the smaller sphere is
2352637 : 1Step-by-step explanation:
Volume of a sphere is
[tex] \frac{4}{3} \pi {r}^{3} [/tex]
Where r is the radius
radius = diameter / 2
For First sphere
diameter = 8yards
radius = 8 / 2 = 4 yards
Volume of first sphere is
[tex] \frac{4}{3} \pi( {4})^{3} \\ \\ = \frac{256}{3} \pi \: {yd}^{3} [/tex]
For second sphere
diameter = 1064 yards
radius = 1064 / 2 = 532 yards
Volume of second sphere is
[tex] \frac{4}{3} \pi( {532})^{3} \\ \\ = \frac{602275072}{3} \pi \: {yd}^{3} [/tex]
Since the volume of the second sphere is the largest
Ratio of the second sphere to the first one is
[tex] \frac{602275072}{3} \pi \div \frac{256}{3} \pi \\ \\ = \frac{602275072}{3} \pi \times \frac{3}{256} \pi \\ \\ = \frac{602275072}{256} \\ \\ = \frac{ 2352637}{1} \\ \\ = 2352637: 1[/tex]
Hope this helps you
Pls help I need help with 12
Answer:
B. 14
Step-by-step explanation:
22/x = 11/(21-x)
462 - 22x = 11x
462 = 33x
x = 14
Answer: The value of x is 14, answer choice B
Let y be the other line segment connected to x
Using proportions:
[tex]\dfrac{11}{22}=\dfrac{y}{x}[/tex]
Cross multiply and simplify
[tex]22y=11x[/tex]
[tex]y=\dfrac{1}{2}x[/tex]
We know that x and y add to 21, so we can create the following equation:
[tex]x+y=21[/tex]
Substitute y=(1/2)x
[tex]x+\dfrac{1}{2}x=21[/tex]
Simplify by adding like terms
[tex]\dfrac{3}{2}x=21[/tex]
Divide both sides by 3/2
[tex]x=14[/tex]
Let me know if you need any clarifications, thanks!
A cube has a side length of 5 cm. Determine the surface area of the largest pyramid that will fit inside the cube. Round if necessary.
Answer:
The surface area of the pyramid is 80.9 cm²
Step-by-step explanation:
The side length, s of the cube is given as 5 cm
Therefore, the largest pyramid that can fit into the cube will have a base side length, s = The side length of the cube = 5 cm
The height, h of the largest pyramid = The height of the cube = 5 cm.
The surface area of a pyramid = Area of base, A + 1/2 × Perimeter of base, P × Slant height, S
The slant height of the pyramid = √(h² + (s/2)²) = √(5² + (5/2)²) = (5/2)×√5
The perimeter of the base = 4×5 = 20 cm
The area of the base = 5×5 = 25 cm²
The surface area of a pyramid = 25 + 1/2×20×(5/2)×√5 = 80.9 cm².
The surface area of a pyramid = 80.9 cm².
Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to height of the tetrahedron.
Answer:
[tex]\frac{4}{3}[/tex]
Step-by-step explanation:
The area of a regular octahedron is given by:
area = [tex]2\sqrt{3}\ *edge^2[/tex]. Let a is the length of the edge (diagonal).
area = [tex]2\sqrt{3}\ *a^2[/tex]
Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.
a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:
[tex]h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a[/tex]
The area of a tetrahedron is given by:
area = [tex]\sqrt{3}\ *edge^2[/tex] = [tex]\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2[/tex]
The ratio of area of regular octahedron to area tetrahedron regular is given as:
Ratio = [tex]\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}[/tex]
Please help me to solve this . Thank you so much .
And if possible , could you explain the answer too ?
Base on the diagram , state
a) The point which is 2 cm from R and 4 cm from P
b) The point which is more than 2 cm from R and 4 cm from T
c) The location of a moving point X in the diagram such that it is less than 4 cm from P and more than 2cm from R
d) The location of a moving point Y in the diagram such that YR < 2 cm and YP < 4 cm
e)The location of a moving point Z in the diagram such that ZT > 4 cm , ZP > 4 cm and ZR > 2 cm
Answer:
a) N
b) L
c) area I
d) area II
e) area VI
Step-by-step explanation:
a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.
b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.
c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.
d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.
e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.
Find the area of the shape shown below
Answer: 28
Step-by-step explanation:
I can't really think of a way to explain this well without visuals and idk how to add images on my answer. But, what I normally do is draw out the shape on paper divide the shape into different sections. Solve the area of the separate sections. It simplifies the more complex figure and turns them into basic shapes. After solving each shape, add all of them together and that leaves you with the area. Hopefully you understand what I mean. I hope this sort of helped:)
first correct answer gets best marks
Answer:
the answer would be x is less than 6.
Step-by-step explanation:
the reason why it would not be x is less than or equal to 6 is that the circle is not filled in.
Answer:
B
Step-by-step explanation:
x≤6
We can see from the graph that it starts from 6 and goes to 5, 4, 3, 2.
Hope this helps ;) ❤❤❤
What fraction is equal to six-sevenths times eight-fifths?
Answer:
1 13/35 (mixed number) or 48/35 (simplified)
Step-by-step explanation:
6/7 times 8/5
= (6 times 8) / (7 times 5)
= 48/35 or 1 13/35
hope this helped :)
Answer:
48/35
Step-by-step explanation:
6/7*8/5=48/35
When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to create a perfect square trinomial?
Answer:
According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.
Step-by-step explanation:
Let consider a second-order polynomial of the form [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex], [tex]\forall \,x \in\mathbb{R}[/tex]. The procedure is presented below:
1) [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex] (Given)
2) [tex]a\cdot x^{2} + b \cdot x = -c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)
3) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x = -4\cdot a \cdot c[/tex] (Compatibility with multiplication)
4) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x + b^{2} = b^{2}-4\cdot a \cdot c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)
5) [tex](2\cdot a \cdot x + b)^{2} = b^{2}-4\cdot a \cdot c[/tex] (Perfect square trinomial)
According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.
Answer: D
Step-by-step explanation:
EDGE 2023
the diagram above shows a rectangle inscribed in a circle AB=10 and AC =12 caculate the total surface area of the shaded part
Answer:
[tex]71.63 \: \: \mathrm{cm^2 }[/tex]
Step-by-step explanation:
Once we know the diameter of the circle, we can figure out the problem.
The diameter of the circle = The diagonal of the rectangle inscribed in the circle
To find the diagonal of the rectangle, we can use a formula.
[tex]d=\sqrt{w^2 + l^2}[/tex]
The width is 10 cm and the length is 12 cm.
[tex]d=\sqrt{10^2 + 12^2}[/tex]
[tex]d \approx 15.62[/tex]
The diagonal of the rectangle inscribed in the circle is 15.62 cm.
The diameter of the circle is 15.62 cm.
Find the area of the whole circle.
[tex]A=\pi r^2[/tex]
The [tex]r[/tex] is the radius of the circle, to find radius from diameter we can divide the value by 2.
[tex]r = \frac{d}{2}[/tex]
[tex]r=\frac{15.62}{2}[/tex]
[tex]r=7.81[/tex]
Let’s find the area now.
[tex]A=\pi (7.81)^2[/tex]
[tex]A \approx 191.625[/tex]
Find the area of rectangle.
[tex]A=lw[/tex]
Length × Width.
[tex]A = 12 \times 10[/tex]
[tex]A=120[/tex]
Subtract the area of the whole circle with the area of rectangle to find area of shaded part.
[tex]191.625-120[/tex]
[tex]71.625 \approx 71.63[/tex]
Solve the following 2 + 8 ÷ 2 x 3
Answer:
14Step-by-step explanation:
Solution,
Use the BODMAS Rule:
B = Bracket
O = Of
D = Division
M= Multiplication
A = Addition
S = Subtraction
Now,
Let's solve,
[tex]2 + 8 \div 2 \times 3[/tex]
First we have to divide 8 by 2
[tex] = 2 + 4 \times 3[/tex]
Calculate the product
[tex] = 2 + 12[/tex]
Calculate the sum
[tex] = 14[/tex]
Hope this helps...
Good luck on your assignment..
Answer:
14
Step-by-step explanation:
2 + 8 ÷ 2 x 3 =
There is an addition, a division, and a multiplication. According to the correct order of operations, we do first the multiplications and divisions in the order they appear from left to right.
= 2 + 4 x 3
= 2 + 12
Now we do the addition.
= 14
The graph of g(x) resembles the graph of f(x)=x^2, but it has been changed. Which of these is the equation of g(x)?
Answer:
A.
Step-by-step explanation:
Anwer A has the following equation:
[tex]g(x)=\frac{3}{5}x^2-3[/tex]
In this equation, we can calculated the intercept replacing x by 0, as:
[tex]g(x)=\frac{3}{5}0^2-3=-3[/tex]
if this is the answer, the graph of g(x) should be through the point (0,-3) and that happens.
Additionally, the roots of the equations are calculated replacing g(x) by 0 and solving for x, so:
[tex]0=\frac{3}{5}x^2-3\\x_1=\sqrt{5}=2.236\\x_2=-\sqrt{5}=-2.236[/tex]
It means that the graph of g(x) should be through the points (2.236,0) and (-2.236,0) and that happens too.
So, the answer is A, [tex]g(x)=\frac{3}{5}x^2-3[/tex]
Identifying relationships from diagrams
Answer: <CED is the right angle, which measures 90 degrees. Since the measure of a straight angle is 180 degrees. <CEA must also be 90 degrees by the Definition of Right Angle. A bisector cuts the angle measure in half. m<AEB is 45 degrees.
The following box plot shows the number of years during which 40 schools have participated in an interschool swimming meet: A box and whisker plot is drawn using a number line from 0 to 10 with primary markings and labels at 0, 5, 10. In between two primary markings are 4 secondary markings. The box extends from 1 to 6 on the number line. There is a vertical line at 3.5. The whiskers end at 0 and 8. Above the plot is written Duration of Participation. Below the plot is written Years. At least how many schools have participated for more than 1 year and less than 6 years?
Answer:
Step-by-step explanation:
The box encloses data between the two quartiles, namely at least half of the data. If there are 40 schools, then half of them would be in the box, between 1 and 6.
see attached plot.
Answer:
really hard to tell what the box plot is like without an attachment so im gonna help u find it out anyway
Step-by-step explanation:
basically when u look at a box plot and the range the line in the middle is the median and then the max the lowest range the lower quartile and then the higher quartile you can find ur anser, simply find the median first, find where the lower quartile is and then the lowest number in the group thats in betweeen 1 and 6
Bao can eat 12 chicken wings in 3 minutes.She eats the chicken wings at a constant rate how many chicken wings can bao eat in 12 minutes
Answer:
48 wings
Step-by-step explanation:
12:3 is the ratio. So multiply both of it by 4. Then it would be 48:12
Answer:
48 chicken wings
Step-by-step explanation:
If Bao can eat 12 chicken wings in 3 minutes and 12 minutes is 3 minutes times 4, then the answer would be 12 chicken wings times 4, so 12 times 4, which is 48, so the answer would be 48 chicken wings.
Solve by the quadratic formula: x^2= 6x-4
Answer:
3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].
Step-by-step explanation:
x^2 = 6x - 4
x^2 - 6x + 4 = 0
Now, we can use the quadratic formula to solve.
[tex]\frac{-b\pm\sqrt{b^2 - 4ac} }{2a}[/tex], where a = 1, b = -6, and c = 4.
[tex]\frac{-(-6)\pm\sqrt{(-6)^2 - 4 * 1 * 4} }{2 * 1}[/tex]
= [tex]\frac{6\pm\sqrt{36 - 4 * 4} }{2}[/tex]
= [tex]\frac{6\pm\sqrt{36 - 16} }{2}[/tex]
= [tex]\frac{6\pm\sqrt{20} }{2}[/tex]
= [tex]\frac{6\pm2\sqrt{5} }{2}[/tex]
= 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex]
x = 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].
Hope this helps!
help me Please!!!!!!!
Answer:
[tex]2\sqrt{14\\}[/tex] = q
Step-by-step explanation:
use geometric mean method
4/s = s/10
s^2 = 40
s = 2[tex]\sqrt{10}[/tex]
consider the triangle STR and using the Pythagorean theorem
[tex]s^{2} +16 = q^{2} \\[/tex]
[tex](2\sqrt{10})^{2} +16 = q^{2}[/tex]
40 + 16 = q^2
56 = q^2
[tex]2\sqrt{14\\}[/tex] = q
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.
Answer:
The function has two real roots and crosses the x-axis in two places.
The solutions of the given function are
x = (-0.4495, 4.4495)
Step-by-step explanation:
The given quadratic equation is
[tex]G(x) = -x^2 + 4x + 2[/tex]
A quadratic equation has always 2 solutions (roots) but the nature of solutions might be different depending upon the equation.
Recall that the general form of a quadratic equation is given by
[tex]a^2 + bx + c[/tex]
Comparing the general form with the given quadratic equation, we get
[tex]a = -1 \\\\b = 4\\\\c = 2[/tex]
The nature of the solutions can be found using
If [tex]b^2- 4ac = 0[/tex] then we get two real and equal solutions
If [tex]b^2- 4ac > 0[/tex] then we get two real and different solutions
If [tex]b^2- 4ac < 0[/tex] then we get two imaginary solutions
For the given case,
[tex]b^2- 4ac \\\\(4)^2- 4(-1)(2) \\\\16 - (-8) \\\\16 + 8 \\\\24 \\\\[/tex]
Since 24 > 0
we got two real and different solutions which means that the function crosses the x-axis at two different places.
Therefore, the correct option is the last one.
The function has two real roots and crosses the x-axis in two places.
The solutions (roots) of the equation may be found by using the quadratic formula
[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]
[tex]x=\frac{-(4)\pm\sqrt{(4)^2-4(-1)(2)}}{2(-1)} \\\\x=\frac{-4\pm\sqrt{(16 - (-8)}}{-2} \\\\x=\frac{-4\pm\sqrt{(24}}{-2} \\\\x=\frac{-4\pm 4.899}{-2} \\\\x=\frac{-4 + 4.899}{-2} \: and \: x=\frac{-4 - 4.899}{-2}\\\\x= -0.4495 \: and \: x = 4.4495 \\\\[/tex]
Therefore, the solutions of the given function are
x = (-0.4495, 4.4495)
A graph of the given function is also attached where you can see that the function crosses the x-axis at these two points.
30 POINTS!!!
Suppose f(x) = x2 and
g(x) = (1/3)^2. Which statement best compares the graph of g(x) with the graph of f(x)?
Image attached
Please help!!!
Answer:
A. The graph of g(x) is vertically compressed by a factor of 3.
Step-by-step explanation:
When there is a fraction, that means that there is a veritcal dilation.
Hope this helps! Good luck!
The total value of a collection of nickels and dimes is $3.05. If the number of nickels is 19 greater than the number of dimes, how many nickels are in the collection?
Answer:
N = 33
Step-by-step explanation:
N = D + 19
.05N + .10 D = 3.05
N = 33
D = 14
asap help !!
How much additional interest is earned if $8000 is invested for 7 years at 6.5% when
interest is compounded annually, as compared with simple interest paid at the same
rate?
Answer:
put it in a calculator, 8,000 times whatever number u need
Katya has $20.00 to spend at her college bookstore, where all students receive a 20% discount . katya wants to purchase a copy of a book that normally sells for $22.50 plus 10% sales tax. how much dose the book sell for dose katya have enough money bc bc?
Answer:
here you go :)
Step-by-step explanation:
You would take 20% of $22.50 (22.5 multiplied by .2). You would get $4.50 off of the book with the discount. So you would subtract 4.5 from 22.5 and get $18. Then you would take 10% of $18 for the sales tax. (18 multiplied by .1). You would get $1.80 towards sales tax. you would then add $1.80 to $18 and get $19.80.
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2ab-6a+5b+___ Please include an explanation too!
Answer:
[tex]2ab - 6a + 5b - 15[/tex]
Step-by-step explanation:
Given
[tex]2ab - 6a + 5b + \_[/tex]
Required
Fill in the gap to produce the product of linear expressions
[tex]2ab - 6a + 5b + \_[/tex]
Split to 2
[tex](2ab - 6a) + (5b + \_)[/tex]
Factorize the first bracket
[tex]2a(b - 3) + (5b + \_)[/tex]
Represent the _ with X
[tex]2a(b - 3) + (5b + X)[/tex]
Factorize the second bracket
[tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]
To result in a linear expression, then the following condition must be satisfied;
[tex]b - 3 = b + \frac{X}{5}[/tex]
Subtract b from both sides
[tex]b - b- 3 = b - b+ \frac{X}{5}[/tex]
[tex]- 3 = \frac{X}{5}[/tex]
Multiply both sides by 5
[tex]- 3 * 5 = \frac{X}{5} * 5[/tex]
[tex]X = -15[/tex]
Substitute -15 for X in [tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]
[tex]2a(b - 3) + 5(b + \frac{-15}{5})[/tex]
[tex]2a(b - 3) + 5(b - \frac{15}{5})[/tex]
[tex]2a(b - 3) + 5(b - 3)[/tex]
[tex](2a + 5)(b - 3)[/tex]
The two linear expressions are [tex](2a+ 5)[/tex] and [tex](b - 3)[/tex]
Their product will result in [tex]2ab - 6a + 5b - 15[/tex]
Hence, the constant is -15
Which graph represents the solution set for the system x+y greater than or equal to 5 and -3x+2y less than or equal than to -2
Step-by-step explanation:
in each equation once substitute the value of x as 0 and again y as zero by this way you will get two values of X and y .
then again find the slope for each equation by the formula
slope= -coefficient of x / coefficient of y
for example,
X+y is greater or equals to 5
or, X+y= 5
or, X=5-y
or, when y is equals to zero
X= 5
and when X is equals to zero
y= 5
then plot the above point in the graph with respect to its slope and the shaded part is the solution
Someone please help! Thank you
Answer:
110
Step-by-step explanation:
the sum of straight angle is 180
the sum of angle of triangle=180
angle E=180-120=60
triangle BDE: <B=180-60-90=30
<B in triangle ACB=180-(130+30)=20)
in traingle ACB: <A = 180-(90+20)=70
angle x=180-70=110 degrees
In this figure, and are parallel. is perpendicular to line segment . If the length of is a units, then the length of is units.
Answer:
is perpendicular to line segment
GH
. If the length of is a units, then the length of is
a
units.
Step-by-step explanation:
had to do it myself.
Answer:
Blank 1-
GH
Blank 2-
a
AB is perpendicular to line segment GH. If the length of EF is a units, then the length of GH is a units.
Step-by-step explanation:
I got it correct
Jane, Paul and Peter can finish painting the fence in 2 hours. If Jane does the job alone she can finish it in 5 hours. If Paul does the job alone he can finish it in 6 hours. How long will it take for Peter to finish the job alone?
==================================================
Explanation:
Jane does the job alone and she can finish it in 5 hours. Her rate is 1/5 of a job per hour. By "job", I mean painting the entire fence. Notice that multiplying 1/5 by the number of hours she works will yield the value 1 to indicate one full job is done.
Through similar reasoning, Paul's rate is 1/6 of a job per hour.
Let x be the time, in hours, it takes Peter to get the job done if he worked alone. His rate is 1/x of a job per hour.
Combining the three individual rates gives
1/5 + 1/6 + 1/x = (6x)/(30x) + (5x)/(30x) + (30)/(30x)
1/5 + 1/6 + 1/x = (6x+5x+30)/(30x)
1/5 + 1/6 + 1/x = (11x+30)/(30x)
The expression (11x+30)/(30x) is the total rate if the three people worked together. This is assuming neither worker slows another person down.
Set this equal to 1/2 as this is the combined rate (based on the fact everyone teaming up gets the job done in 2 hours). Then solve for x
(11x+30)/(30x) = 1/2
2(11x+30) = 30x*1 .... cross multiply
22x+60 = 30x
60 = 30x-22x
60 = 8x
8x = 60
x = 60/8
x = 7.5
It takes Peter 7.5 hours, or 7 hours 30 minutes, to get the job done if he worked alone.
--------------
Here's another equation to solve though its fairly the same idea as above
1/5 + 1/6 + 1/x = 1/2
30x*(1/5 + 1/6 + 1/x) = 30x*(1/2) ... multiply both sides by LCD
30x(1/5) + 30x(1/6) + 30x(1/x) = 30x(1/2)
6x + 5x + 30 = 15x
11x + 30 = 15x
30 = 15x-11x
30 = 4x
4x = 30
x = 30/4
x = 7.5
We get the same answer
Answer: 7 . 5 hrs
Step-by-step explanation:
It takes Jane 5 hours to finish the fence so she can get [tex]\dfrac{1}{5}[/tex] of the job done in 1 hour.
It takes Paul 6 hours to finish the fence so he can get [tex]\dfrac{1}{6}[/tex] of the job done in 1 hour.
It takes Peter x hours to finish the fence so he can get [tex]\dfrac{1}{x}[/tex] of the job done in 1 hour.
Together, it takes them 2 hours to finish the fence so they can get [tex]\dfrac{1}{2}[/tex] of the job done in 1 hour.
Jane + Paul + Peter = Together
[tex]\dfrac{1}{5}\quad +\quad \dfrac{1}{6}\quad +\quad \dfrac{1}{x}\quad =\quad \dfrac{1}{2}[/tex]
Multiply everything by 30x to eliminate the denominator:
[tex]\dfrac{1}{5}(30x) + \dfrac{1}{6}(30x) +\dfrac{1}{x}(30x) =\dfrac{1}{2}(30x)[/tex]
Simplify and solve for x:
6x + 5x + 30 = 15x
11x + 30 = 15x
30 = 4x
[tex]\dfrac{30}{4}=x[/tex]
7.5 = x
Can someone help me with these two questions I don’t know how to do it and it’s due at 11 I would really appreciate it
Answer:
6. Unit rate = 1.3 yards per second
7. Unit rate = 0.8 page per minute
Step-by-step explanation:
The unit rate is simply the comparison of 2 quantities, whereby dividing both, the denominator must be 1.
For example, in the graph given comparing distance walked over time, when x (time in s) = 3, y (distance in yd) = 4.
Unit rate represented by the slope is the yards covered per second.
Unit rate = [tex] \frac{4}{3} = 1.33 [/tex]
Unit rate ≈ 1.3 yards per second
For the second graph given, unit rate of the slope is the number of pages read per minute.
From the graph, 4 pages is read at 5 minutes.
Thus,
Unit rate = [tex] \frac{4}{5} = 0.8 [/tex]
Unit rate = 0.8 page per minute