Mathematics College



What was Bear B's average speed in
m/min? No units required for answer.

What Was Bear B's Average Speed Inm/min? No Units Required For Answer.

Answers

Answer 1

Given:

Graph of positions of Bear A and Bear B.

To find:

The average speed of Bear B in m/min.

Solution:

From the graph it is clear that initial point of graph of Bear B is (0,100) and the end point is (60,2800).

The average speed of Bear B is

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\dfrac{2800-100}{60-0}[/tex]

[tex]m=\dfrac{2700}{60}[/tex]

[tex]m=45[/tex]

Therefore, the average speed of Bear B is 45 m/min.

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Answer:

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Step-by-step explanation:

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Answers

Answer:

Slope = y2 - y1/x2 - x1

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Step-by-step explanation:

hope that will help you

The slope of the line will be 2/3.

The formula for the slope will be:

= (y2 - y1) / (x2 - x1)

where,

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Answers

Answer:

[tex]125.35[/tex]

Step-by-step explanation:

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Answers

L = 31
M = 90
N = 59

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Answers

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Step-by-step explanation:

   

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

plug the points into the slope formula

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

[tex]2^{3} = 8[/tex]  Plug 8 in: 12 - [2 + 6 ÷ (10 - 8)]10 - 8 = 2Plug 2 in: 12 - [2 + 6 ÷ (2)]6 ÷ 2 = 3Plug 3 in: 12 - [2 + 3]2 + 3 = 5Plug 5 in: 12 - 512 - 5 = 7

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

Answer:

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