If y= cx" and dy/dx =
4/root x

what are the values of c and n?

Answer:

c = 8

n = 1/2

Step-by-step explanation:

Since dy/dx is the derivative form, we can integrate the answer to get the value of y.

The values of c and n are obtained by forming the equations as 1/2 and 8 respectively.

The differentiation of a function is defined as rate of change of its value at a point. It can be written as f'(x) = (f(x + h) - f(x)) /(x + h - x).

It can be stated in terms of geometry as the slope of tangent of the function at a given point.

It is given as y = cxⁿ and dy/dx = 4/√x.

Take the derivative of y = cxⁿ with respect to x as,

dy/dx = cd(xⁿ)/dx

⇒ nc × xⁿ⁻¹

Compare the obtained derivative with 4/√x to obtain,

nc = 4   and  n - 1 = -1/2

⇒ n = 1/2 and c = 8

Hence, the values of c and n are 1/2 and 8 respectively.

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