Quadrilateral RSTU is reflected across the line x = 1. Determine the coordinates of R’, S’, T’, and U’.

Quadrilateral R S T U plotted in the first quadrant of a coordinate plane. The vertices are at R (5, 2), S (4, 4), T (5, 6), and U (6, 4).

R’: (
,
)

S’: (
,
)

T’: (
,
)

U’: (
,
)

The best day to sell both stocks is Day 2, since the total value of both stocks is highest on that day, option C is correct.

On Day 1, the total value of the 30 shares of Metropolis stock is:

30 shares x $17.95 per share = $538.50

And the total value of the 55 shares of Suburbia stock is:

55 shares x $5.63 per share = $309.65

So the total value of both stocks on Day 1 is:

$538.50 + $309.65 = $848.15

On Day 2, the total value of the shares of Metropolis stock is:

30 shares x $18.28 per share = $548.40

And the total value of the shares of Suburbia stock is:

55 shares x $5.88 per share = $323.40

The total value of both stocks on Day 2 is: $871.8

for Day 3, total value of both stocks on Day 3 is $$821.40

Therefore, we can see that the best day to sell both stocks is Day 2, since the total value of both stocks is highest on that day:

$871.80 - $848.15 = $23.65

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The shape of the data of the line plot is best described by the option

A line plot is a graphical display of data as check marks showing the frequency of a data point above a number line.

The description of the line plot can be presented as follows;

The number of dota above the points marked 10, 11, 14, 16, and 17 = One dot each

The number of dots above the point marked 13 = Two dots

The number of dots above the points marked 12, and 15 = Four dots each

The above description of the line plot indicates;

The mode of the dataset are 12 and 15, therefore;

The option that best describes the shape of the data, is therefore;

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The probability that an arrival does not have to wait before service is 0.7 (Option B).

To calculate the probability that an arrival does not have to wait before service, we need to use the Poisson and exponential distributions.

First, we can calculate the average number of arrivals per hour:

60 minutes / 10 minutes per arrival = 6 arrivals per hour

Next, we can use the exponential distribution to calculate the probability that a phone call is less than or equal to 10 minutes (the time between arrivals):

P(call length ≤ 10 minutes) = 1 - e^(-10/3) ≈ 0.957

This means that there is a 95.7% chance that a phone call will end before the next arrival.

Finally, we can use the Poisson distribution to calculate the probability that there are no arrivals in the 10-minute window between the end of a phone call and the next arrival:

P(no arrivals in 10 minutes) = e^(-6) ≈ 0.002

So the probability that an arrival does not have to wait before service is:

P(no wait) = P(call length ≤ 10 minutes) * P(no arrivals in 10 minutes)

P(no wait) = 0.957 * 0.002

P(no wait) ≈ 0.002

Therefore, the answer is A) 0.3.

We're given that arrivals at a telephone booth follow a Poisson distribution with an average time of 10 minutes between arrivals, and the length of a phone call is exponentially distributed with a mean of 3 minutes. We need to find the probability that an arrival does not have to wait before service.

Step 1: Calculate the arrival rate (λ) and service rate (μ)
The average time between arrivals is 10 minutes, so the arrival rate λ is 1/10 arrivals per minute.
The average length of a phone call is 3 minutes, so the service rate μ is 1/3 calls per minute.

Step 2: Calculate the traffic intensity (ρ)
The traffic intensity ρ is the ratio of the arrival rate to the service rate.
ρ = λ/μ = (1/10) / (1/3) = 3/10 = 0.3

Step 3: Calculate the probability that an arrival does not have to wait (P_0)
For an M/M/1 queue (Poisson arrivals and exponential service times with a single server), the probability that an arrival does not have to wait before service is given by P_0 = 1 - ρ.
P_0 = 1 - 0.3 = 0.7

So, the probability that an arrival does not have to wait before service is 0.7 (Option B).

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The common difference is 6, and the sum of the first 20 terms for the arithmetic sequence 1120.

U2 = 5

U3 = 11

Finding the common difference (d)

U3 - U2

= 11 - 5

= 6

Finding the first term (U1):

U1 = U2 - (2 - 1) × d

= 5 - (2 - 1) × 6

= 5 - 6

= -1

Finding the sum of the first 20 terms:

Sn = n/2 × (2U1 + (n - 1)d)

Sn = 20/2 × (2 × -1 + (20 - 1) × 6)

= 10 × (-2 + 19 × 6)

= 10 × (-2 + 114)

= 10 × 112

= 1120

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If a square pyramid is sliced in a way that the plane cuts in a direction perpendicular to the base but doesn't pass through the vertex, the resulting cross-section will be a trapezoid.

This trapezoid will have one pair of parallel sides and one pair of non-parallel sides.

To understand why the resulting cross-section is a trapezoid, imagine a square pyramid standing on its base. Now, imagine slicing the pyramid horizontally, parallel to the base. The resulting cross-section would be a square.

However, if we change the direction of the slice to be perpendicular to the base, but not passing through the vertex, the resulting cross-section will not be a square. Instead, it will be a trapezoid, with one set of parallel sides corresponding to the base of the pyramid, and the other set of sides corresponding to the slice that was made.

This type of cross-section is commonly seen in architectural and engineering designs, where different shapes need to be created by slicing or intersecting 3D shapes. Understanding the resulting cross-section of different slicing techniques is essential to ensure the proper fit and function of the final product.

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Answer:

a. The interior angles of Parallelogram B (Pipe B) are 30°, 150°, 150°, and 30°. Angle x measures 60° because the 120° angle and angle x are supplementary angles.

c. Correct answers, in order: 360, 360, 150, supplementary, 30, complementary, 60

To find the value of z for a 95% confidence level, we can use a z-score table or a calculator. The z-score corresponding to a 95% confidence level is 1.96.

To determine the sample size, we can use the formula:

n = (z^2 * s^2) / E^2

where:
n = sample size
z = z-score (1.96 for 95% confidence level)
s = estimated standard deviation (3 cards)
E = margin of error (1 card)

Plugging in the values, we get:

n = (1.96^2 * 3^2) / 1^2
n = 34.56

We need to round up to the nearest whole number, so the sample size should be 35 people. This means that if we randomly select 35 employees and calculate their average number of credit cards, we can be 95% confident that the true average number of credit cards per employee is within 1 card of our sample mean.
To determine the required sample size for your survey with a 95% confidence level and a margin of error of 1 point, you'll need to use the sample size formula and find the appropriate z-value.

The sample size formula is: n = (z^2 * σ^2) / E^2

Where:
- n is the sample size
- z is the z-value corresponding to the desired confidence level (95% in this case)
- σ is the estimated standard deviation of the population (3 credit cards per employee)
- E is the margin of error (1 point)

For a 95% confidence level, the z-value is approximately 1.96. You can find this value using a z-table or an online calculator.

Now, plug the values into the formula:

n = (1.96^2 * 3^2) / 1^2
n = (3.8416 * 9) / 1
n ≈ 34.5744

Since you cannot survey a fraction of a person, round up to the nearest whole number. Therefore, you should survey approximately 35 people to achieve a 95% confidence level with a margin of error of 1 point for the average number of credit cards per employee.

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Answer:{2,2,3,3}

Step-by-step explanation:

six by six is 36 and 2 times three would give you six

Answer:

(2,2,3,3)

Step-by-step explanation:

To calculate the reorder point, we need to consider the lead time (6 days) and the average daily usage of the product. Assuming a 30-day month, the average daily usage can be calculated as:
Product used per day = Total product used in a month / Number of days in a month
Product used per day = Inventory / 30

To determine the reorder point, we need to know the daily consumption rate of the product and the lead time (number of days it takes for the order to arrive).

1. Calculate the daily consumption rate: Since we have a 30-day month, we will divide the monthly consumption by 30.
Total consumption in a month = X gallons (Information not provided)
Daily consumption rate = X gallons / 30 days

2. Calculate the lead time demand: Since it takes 6 days for the order to arrive, we need to find out how many gallons are consumed during this time.
Lead time demand = Daily consumption rate * Lead time
Lead time demand = (X gallons / 30 days) * 6 days

3. Determine the reorder point: The reorder point is the level of inventory at which the product should be reordered to ensure that there is enough stock to cover the lead time demand.
Reorder point = Lead time demand
Reorder point = (X gallons / 30 days) * 6 days

Let's assume that the reorder point is the level of inventory at which we need to place a new order to avoid running out of stock. So, the reorder point can be calculated as:

Reorder point = Lead time demand + Safety stock

Here, the lead time demand is the product used during the lead time (6 days) and the safety stock is the buffer inventory kept to avoid stockouts. Let's assume a safety stock of 50 gallons.

Lead time demand = Product used per day * Lead time
Lead time demand = (Inventory / 30) * 6
Lead time demand = Inventory / 5

Reorder point = (Inventory / 5) + 50

We need to solve for the inventory level at which we should reorder. Let's assume the answer is X.

X / 5 + 50 = X
X - X/5 = 50
4X/5 = 50
X = (5/4) * 50
X = 62.5

So, the reorder point is 62.5 gallon. Therefore, the correct answer is "none of the above".

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The perimeter of the equlateral triangle is 42 units

The dimensions of the triangle are given as

x + 8, y + 4 and 4x - y​

The side lengths of an equilateral triangle are equal

So, we have

x + 8 = y + 4

4x - y​  = y + 4

When evaluated, we have

x = 6 and y = 10

So, we have

Perimeter = 3 * (y + 4)

This gives

Perimeter = 3 * (10 + 4)

Evaluate

Perimeter = 42

Hence, the perimeter is 42 units

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The length of the arc BC is given as follows:

Arc BC = 10π units.

The circumference of a circle of radius r is given by the equation presented as follows:

C = 2πr.

The radius in this problem is of 10 units, hence the length of the whole circumference is of:

C = 20π units.

The entire circumference is of 360º, hence arc BC is half the circumference, and it's length is given as follows:

Arc BC = 10π units.

The problem asks for the length of arc BC.

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Answer: 43 - x =25

Step-by-step explanation:

43 - x = 25

so 43 - 25 = x

x = 18

The equation of the parabola in standard form is f(x) = -(x - 3)² + 25

the vertex of the parabola is given as (3, 25), we know that the equation of the parabola can be written in vertex form as:

f(x) = a(x - 3)² + 25

where a is a constant that determines the shape of the parabola.

The point (6, 16) lies on the parabola

so we can substitute x = 6 and y = 16 into the equation above to find 'a'.

16 = a(6 - 3)² + 25

-9 = 9a

Dividing both sides by 9, we get:

a = -1

Now we know that the equation of the parabola is:

f(x) = -(x - 3)² + 25

Hence, the equation of the parabola in standard form is f(x) = -(x - 3)² + 25

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Answer:

coefficient

Step-by-step explanation:

the 4 is the coefficient

Answer:

I'm not sure if this what your looking for as an answer, but I hope it helped!

The function h(x) is given as the power series:

=h(x) = x³ + (x⁴/3) + (x⁵/5) + (x⁶/7) + (x⁷/9) + ...

Part A: To determine the interval of convergence, we use the ratio test:

lim(n→∞) |(x^(n+4))/(2(n+2)+1) * (2n+1)/(x^n+3)| = lim(n→∞) |x|^2/2 = |x|^2/2

The ratio test tells us that the series converges if |x|²/2 < 1 and diverges if |x|²/2 > 1. Therefore, the interval of convergence is -√2 < x < √2.

Part B: To find h′(−1), we differentiate the power series term by term:

h′(x) = 3x² + 4x³/3 + 5x⁴/5 + 6x⁵/7 + 7x⁶/9 + ...

h′(−1) = 3(−1)² + 4(−1)³/3 + 5(−1)⁴/5 + 6(−1)⁵/7 + 7(−1)⁶/9 + ...

= 3 − 4/3 + 1/5 − 6/7 + 1/9 − ...

= ∑(n=0 to ∞) (−1)^n * (2n+3)/(2n+1)

We can use the alternating series test to show that the series converges. The terms decrease in absolute value, and the limit of the terms approaches zero. Therefore, h′(−1) converges.

The relationship between the radius of convergence and interval of convergence of h(x) and h′(x) is that the radius of convergence of h′(x) is the same as that of h(x), but the interval of convergence may be different due to the behavior at the endpoints.

Part C: To determine if h(x²) has any points of inflection, we differentiate twice:

h(x²) = (x²)³ + ((x²)⁴/3) + ((x²)⁵/5) + ((x²)⁶/7) + ((x²)⁷/9) + ...

h′(x) = 3x⁴ + 4x⁵/3 + 5x⁶/5 + 6x⁷/7 + 7x⁸/9 + ...

h″(x) = 12x³ + 20x⁴/3 + 30x⁵/5 + 42x⁶/7 + 56x⁷/9 + ...

We can see that h″(x) is always positive, so h(x²) does not have any points of inflection.

Answer: Number Question #1 - To find the volume generated by rotating the region bounded by y=e^(−x^2), y=0, x=0, and x=1 about the y-axis using the method of cylindrical shells, we can integrate the volume of each cylindrical shell. The radius of each shell will be x, and the height will be e^(−x^2).

Thus, the volume is given by:

V = ∫[0,1] 2πxe^(−x^2) dx

Using u-substitution with u=−x^2 and du/dx=−2x, we can rewrite this integral as:

V = ∫[0,−1] −πe^udu

Evaluating the integral, we get:

V = π/2(e^0 − e^(−1)) ≈ 0.436

Therefore, the volume generated by rotating the region about the y-axis is approximately 0.436 cubic units.

Number Question #2 - To find the volume of the solid obtained by rotating the region bounded by y=sqrt(x−1), y=0, x=5 about the line y=5, we can again use the method of cylindrical shells. In this case, the radius of each shell will be 5−y, and the height will be x−1.

Thus, the volume is given by:

V = ∫[0,4] 2π(5−y)(x−1)dy dx

Integrating with respect to y first, we get:

V = ∫[1,5] π(x−1)(5−y)^2 dx

Expanding and simplifying, we get:

V = 2π/3 [(5x−x^2−13)∣[1,5]]

Evaluating the integral, we get:

V = (32π/3)

Therefore, the volume of the solid obtained by rotating the region about y=5 is (32π/3) cubic units.

Number Question #3 - To find the volume of the solid obtained by rotating the region enclosed by the graphs of y=x^2, y=8−x^2, and to the right of x=1.5 about the y-axis using the method of cylindrical shells, we can integrate the volume of each cylindrical shell. The radius of each shell will be x, and the height will be (8−x^2)−x^2=8−2x^2.

Thus, the volume is given by:

V = ∫[1.5,2] 2πx(8−2x^2)dx

Integrating, we get:

V = (32π/3) − (9π/2)

Therefore, the volume of the solid obtained by rotating the region about the y-axis is (32π/3) − (9π/2) cubic units.

The curvature is zero at the origin, but f(x) is not twice continuously differentiable function at x = 0, because f''(x) does not exist at x = 0. Therefore, the statement is not necessarily true.

An inflection point is a point on a curve where the sign of the curvature changes. At an inflection point, the curvature may be zero, but it may also be undefined.  Moreover, even if the curvature is defined and equal to zero at an inflection point, it does not necessarily imply that the function is twice continuously differentiable at that point.

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Answer: x = 2√381

Step-by-step explanation:

Call A the dotted line.

Using the Pythagorean theorem, we find that [tex]A^{2} + 16^{2}[/tex] [tex]= 22^{2}[/tex]

Simplifying gives:

[tex]A = \sqrt{16^2 + 22^2}\\A = \sqrt{740}\\A = 2\sqrt{185}[/tex]

Now we move to the other triangle we can call the sides: a, the dotted side, b the height, and x, the hypotenuse.

[tex]a = 2\sqrt{185}[/tex]

and

[tex]b = 44-16 = 28[/tex]

So,

[tex](2\sqrt{185})^{2} + 28^2 = x^2\\x = \sqrt{(2\sqrt{185})^2 +28^2 }\\x = \sqrt{740+784}\\x= \sqrt{1524}\\x= 2\sqrt{381}[/tex]

Answer:

Step-by-step explanation:

m = 32g

According to the information, Samuel can stain the deck in 4 hours, and Julio can do it three times faster, in 4/3 hours or 1 hour and 20 minutes.

Let's assume that Samuel can stain the deck in x hours. Then, Julio can do the same job in x/3 hours (since he is three times faster).

Working together, they can stain the deck in 3 hours. Using the concept of work, we can set up the following equation:

1/x + 1/(x/3) = 1/3

Simplifying this equation by finding a common denominator, we get:

3/(3x) + x/(3x) = 1/3

Combining like terms, we get:

4x/(3x) = 1/3

Cross-multiplying, we get:

12x = 3x

Solving for x, we get:

x = 4

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The number -3/11 on the number line is added as an attachment

From the question, we have the following parameters that can be used in our computation:

Number = -3/11

To represent -3/11 on a number line, we use the following steps

Using the above as a guide

The number line is added as an attachment

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The final matrix product has dimensions 10x1.

To multiply a chain of matrices with given dimensions, we need to follow the associative property of matrix multiplication and multiply the matrices in a certain order.

Given the dimensions 10x3, 3x5, 5x10, 10x12, and 12x1, we need to multiply them in the order of (10x3) x (3x5) x (5x10) x (10x12) x (12x1).

Step 1: Multiply the first two matrices, (10x3) and (3x5), to get a resulting matrix of dimension (10x5).

Step 2: Multiply the resulting matrix from step 1, which is (10x5), with the next matrix, (5x10), to get a new matrix of dimension (10x10).

Step 3: Multiply the resulting matrix from step 2, which is (10x10), with the next matrix, (10x12), to get a new matrix of dimension (10x12).

Step 4: Multiply the resulting matrix from step 3, which is (10x12), with the last matrix, (12x1), to get a final matrix of dimension (10x1).

Therefore, the final answer obtained by multiplying the chain of matrices in the given order is a matrix of dimension (10x1).

The steps performed in the multiplication of the chain of matrices with dimensions 10x3, 3x5, 5x10, 10x12, and 12x1 are as follows:
(10x3) x (3x5) = (10x5)
(10x5) x (5x10) = (10x10)
(10x10) x (10x12) = (10x12)
(10x12) x (12x1) = (10x1)

To multiply a chain of matrices efficiently, you should follow the Matrix Chain Multiplication algorithm, which determines the optimal parenthesization to minimize the number of scalar multiplications. For your matrices with dimensions 10x3, 3x5, 5x10, 10x12, and 12x1, here's the best way to multiply them:

1. Start by finding the optimal parenthesization:
  - Multiply the 10x3 and 3x5 matrices first, resulting in a 10x5 matrix.
  - Then, multiply the 5x10 and 10x12 matrices, resulting in a 5x12 matrix.
  - Finally, multiply the 10x5 and 5x12 matrices, and then the resulting 10x12 matrix with the 12x1 matrix.

2. Perform the multiplications:
  - A = 10x3 * 3x5 = 10x5
  - B = 5x10 * 10x12 = 5x12
  - C = A * B = 10x5 * 5x12 = 10x12
  - D = C * 12x1 = 10x12 * 12x1 = 10x1

By following this approach, you minimize the total number of scalar multiplications, resulting in a more efficient calculation. The final matrix product has dimensions 10x1.

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Sleeping is more important than the having full stomach when it comes to doing well on an exam

Based on the contour diagram, it seems that the percentage a student earns on an exam (l) is affected by both x and y. In other words, the more hours a student sleeps (x), the higher their percentage in the exam tends to be. Similarly, the fuller a student's stomach is (y), the higher their percentage in the exam tends to be.
It's important to note that the impact of x and y on l isn't necessarily equal. For example, if a student sleeps for 10hours (x=10) and has a full stomach (y=10), their percentage in the exam appears to be close to 100%. However, if they only sleep for 5 hours (x=5) and have a full stomach (y=10), their percentage in the exam appears to be closer to 70%. This suggests that sleeping is more important than having a full stomach when it comes to doing well on an exam.
Overall, this function seems to demonstrate that the amount a student sleeps and their level of hunger can impact their performance on an exam. However, it's important to note that this is just one function and may not apply to every student or every exam.

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The larger picture costs $7.72

The wallet-sized image has the following area:

A1 = length x width = 5 cm x 7 cm = 35 cm2.

The bigger image has the following measurements because it is twice as long and wide as the wallet-sized image:

Length equals 2 x 5 cm = 10 cm

width equals 2 x 7 cm = 14 cm

The size of the larger image is given by the formula:

A2 = length x width = 10 cm x 14 cm = 140 cm^2

The price per square centimeter is something we must know. By dividing the price of the wallet-sized photo by its surface area, we can determine this:

Cost per cm^2 = $1.93 / 35 cm^2 = $0.05514 per cm^2

By dividing the area of the larger image by the price per square centimeter, we can now determine its cost:

Cost of larger picture = A2 x Cost per cm^2

= 140 cm^2 x $0.05514 per cm^2

= $7.7196

Therefore, the larger picture costs $7.72

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The expression  x²-6x+9 is equal to the expression (x-3)², option A is correct.

The given expression is x²-6x+9

x is the variable in the expression

Plus and minus are the operators

We have to factor the expression

x²-6x+9

x²-3x-3x+9

x(x-3)-3(x-3)

(x-3)(x-3)

x²-6x+9 is equal to (x-3)²

(x-3)²

Hence, the expression  x²-6x+9 is equal to the expression (x-3)², option A is correct.

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When we compare functions we see that Jack and Jill have the smaller slopes

Jack's function: d = 0.05t

Slope (m1) = 0.05

Y-intercept (b1) = 0

Jill's function: d = 0.04t + 0.5

Slope (m2) = 0.04

Y-intercept (b2) = 0.5

Linear parent function: d = t

Slope (m0) = 1

Y-intercept (b0) = 0

When we compare functions we see that Jack and Jill have the smaller slopes

B. Given that they have smaller slopes this tells us that the pace with which they are running is smaller than that of the parent function

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a) a = 2.72 makes the statement P(x ≤ a) = 0.24 true.

b)a = 3.77 makes the statement P(x > a) = 0.41 true.

c) a = 3.37 makes the statement P(2.29 ≤ x ≤ a) = 0.36 true.

Part A:

For a uniform probability distribution with range [2,5], the probability density function is:

f(x) = 1/(5-2) = 1/3 for 2 <= x <= 5

a) To find the value of a such that P(x ≤ a) = 0.24, we need to solve the following equation:

∫[2,a] f(x) dx = 0.24

Simplifying the equation, we get:

(a-2)/(5-2) = 0.24

a-2 = 0.72

a = 2.72

Therefore, a = 2.72 makes the statement P(x ≤ a) = 0.24 true.

b) To find the value of a such that P(x > a) = 0.41, we need to solve the following equation:

∫[a,5] f(x) dx = 0.41

Simplifying the equation, we get:

(5-a)/(5-2) = 0.41

5-a = 1.23

a = 3.77

Therefore, a = 3.77 makes the statement P(x > a) = 0.41 true.

c) To find the value of a such that P(2.29 ≤ x ≤ a) = 0.36, we need to solve the following equation:

∫[2.29,a] f(x) dx = 0.36

Simplifying the equation, we get:

(a-2.29)/(5-2) = 0.36

a-2.29 = 1.08

a = 3.37

Therefore, a = 3.37 makes the statement P(2.29 ≤ x ≤ a) = 0.36 true.

Part B:

Let D be the event that a family owns a dog, and let C be the event that a family owns a cat.

Given information:

P(D) = 0.35

P(C | D) = 0.20

P(C) = 0.32

We need to find:

P(D)

P(D | C)

Using Bayes' theorem, we can write:

P(D | C) = P(C | D) * P(D) / P(C)

Substituting the given values, we get:

P(D | C) = (0.20 * 0.35) / 0.32 = 0.21875

Therefore, the conditional probability that a randomly selected family owns a dog given that it owns a cat is 0.21875.

To find P(D), we can use the following formula:

P(D) = P(D | C) * P(C) + P(D | C') * P(C')

where C' represents the complement of C, i.e., the event that a family does not own a cat.

Since the probability of owning a cat or not owning a cat covers all possibilities, we have:

P(D) = P(D | C) * P(C) + P(D | C') * (1 - P(C))

Substituting the given values, we get:

P(D) = (0.20 * 0.35) + P(D | C') * (1 - 0.32)

We do not have enough information to directly calculate P(D | C'), so we need to use the fact that the probabilities must add up to 1. Thus:

P(D | C') = 1 - P(C' | D)

Using Bayes' theorem, we can write:

P(C' | D) = P(D | C') * P(C') / P

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In the derivation of the Quadratic Formula is shown by completing the square and applying square roots. The missing step is D. x^2 + b/a + c/a = 0.

The quadratic formula derivation requires the initial equation of ax^2 + bx + c = 0, where a, b and c are constants; it is also necessary that a cannot be zero.

the step simplifies the division of a:

0 divided by anything is still zero, so you can remove the a denominator

a/a = 1, and is therefore irrelevant, so ax^2 / a = x^2

The correct option is D

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The probabilities of the possible outcomes obtained from tossing a fair coin two times are;

(a) Pr(0 heads) = 1/4

(b) Pr(1 head) = 1/2

(c) Pr(2 heads) = 1/4

The probability of an event is the ratio of the number of required outcome to the number of possible outcomes.

The equiprobable sample space of tossing a fair coin two times is; {HH, HT, TH, TT}, where;

H = Heads

T = Tails

The sample space indicates that there are 4 possible outcomes

(a) The possibility of getting 0 heads, is to get TT, therefore, the probability of getting zero heads, Pr(0 heads) = TT = 1/4

(b) The possibility of getting 1 head is to get. HT or TH, therefore;

The probability of getting 1 head, Pr(1 heads) = 2/4 = 1/2

(c) The number of possibility of getting 2 heads, is to get HH = 1

Therefore, the probability of getting 2 heads, Pr(2 heads) = 1/4

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