[tex] \huge \mathcal{Question}[/tex]


Help ! FBD (free body diagram) required

Select all correct choices ~

Thanks for Answering ! have a great day ~

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Hi there!

Since we are dealing with such large distances, we can approximate.

Recall that the equation for speed is:

displacement / time = velocity

OR:

d/t = v

Begin by converting one hour to seconds:

1 hr  = 3600 sec

Now, we can solve for velocity:

(-2.0 × 10⁷) / 3600 = -5555.6 m/s ⇒ D: -5.55 × 10³ m/s

Answer:

4.8 N*s

Explanation:

P = F*t

P = Impulse/ momentum

F = force (Newtons)

t = time (seconds)

P = 9.5N*0.5s

P = 4.75 N*s

Hi there!

[tex]\large\boxed{I = 4.8 N}[/tex]

Impulse = Force (N) × Time (s)

We can also express this as:

I = Δp = Ft

Plug in the given values:

I = 9.5(.50) = 4.75 ≈ 4.8 Ns

The question is fishing for "balanced force".

But the description in the question is terrible.

Answer: 100 pascals times 0.2 m^2= 20 N force is applied.

Explanation:

Answer:

Explanation:

BMI= weight/(height × height)          ; weight in kilogram and height in metter

     = 58kg / (1.61m  × 1.61m )

     = (58/ 2.5921) kg/[tex]m^{2}[/tex]

     = 22.375  kg/[tex]m^{2}[/tex]

     ≈ 22.4 kg/[tex]m^{2}[/tex]

Answer:

5.54 [kg].

Explanation:

1) if m₁=6; g=9.81; a=0.75 and m₂ - reqired mass, then

2) it is possible to write: m₁*a=m₁*g-m₂*g, and

3) [tex]m_2=\frac{m_1(g-a)}{g}; \ => \ m_2=\frac{6*(9.81-0.75)}{9.81}=5.54[kg].[/tex]

The definition of the center of mass allows to find the result for the position of the mass center of more than the H₂O molecule is;

         [tex]x_{cm} = 0 \ and \ y_{cm} = 6.9 10^{-3 } nm[/tex]  

the concept of center of mass of a system is the point where external forces are applied, it is given by the expression

             [tex]\frac{x}{y} =\frac{1}{M_{total}} \sum m_i r_i[/tex]  

Where M is the total mass of the systemr_i and m_i sums the position and masses of the element i of the system

In the attachment we have a diagram of the system where the axis and coordinates of the molecules are shown, in this case it is indicated that the origin is in the oxygen atom, so its distance is zero.

           [tex]r_{cm} = \frac{1}{2 m + M} \ (2 m r )[/tex] )

They indicate the mass of the hydrogen atom m = 1.008 amu, the bond length r = 0.103 nm and there is an angle 106º between the two hydrogens, therefore the angle from the vertical is:

           θ = 106/2 = 53º

Let's find the position of the center of mass for each axis.

x-axis

           [tex]x_{cm} = \frac{1}{2m+ M} \ ( m x_1 - m x_2)[/tex]  

y-axis

          [tex]y_{cm} = \frac{1}{2m + M} \ ( m y_1 + m_2)[/tex]

Let's use trigonometry to find the components of the bond length.

         cos θ = [tex]\frac{y}{L}[/tex]  

         sin θ = [tex]\frac{x}{L}[/tex]  

         y = L cos θ

         x = L sin θ  

We substitute.

          [tex]x_{cm} = \frac{1}{2m+M} \ (mL (sin 53 + sin (-53)) \\y_{cm} = \frac{1}{2m + M} \ ( mL cos 53 + mL sin 53)[/tex]

we use.  

          sin θ = - sin -θ

          cos θ = cos -θ

Let's calculate.

        [tex]x_{cm} = 0 \\y_{cm} = \frac{1}{2 \ 1.008 + 15.9999} \ ( 2 \ 1.008 \ 0.103 cos 53)[/tex]

We see that the center of mass is on the x axis and at a distance from the y-axis of 6.9 10-3 nm

In conclusion using the definition of the center of mass we can find the result for the position of the center of mass of the H₂O molecule is;

          [tex]x_{cm}=0[/tex]  and [tex]y_{cm}[/tex]cm = 6.9 10⁻³ nm

Learn more here: brainly.com/question/8662931

Answer:

The nuclei of source have greater stability than those of source B.

Answer:

11.1

Explanation:

2 hours 15 mins = 2 1/4 hours

2 1/4 hours = 25 miles

1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles

Answer:

D is the answer

Explanation:

D is the most highest one so

the answer is D

Answer:

10 kg rock at 15 degrees celcius

Convert km to meters:

1km = 1000 m

1.5 km x 1000 = 1500 m

1500m / 4.8 m/s = 312.5 seconds

312.5 seconds / 60 seconds per minute =5.2 minutes = 5 minutes 12.5 seconds

Answer:

ETotal=38505J

Explanation:

Known values:

m=150kg

h=20m

v=11m/s

KE=mv^2/2

PE=mgh

ETotal=PE+KE

KE=(150(11^2))/2

KE=9075

PE=150(9.81)(20)

PE=29430

ETotal=9075+29430

ETotal=38505J

Answer:

101.937 kg

Explanation:

The force needed to get the box moving must just cancel the static friction force:

F = µsmg  =  0.35•m•9.81 = 350 --->   m = 350 / (0.35•9.81) = 101.937 kg

Again, with units shown, and using 1 N = 1 kg•m/s2:

0.35•m•9.81(m/s2) = 350 N

solving for m:

m = 350 N / (0.35•9.81 m/s2)  =  (350 kg•m/s2) / (3.434 m/s2 ) = 101.937 kg

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(Hope this helps can I pls have brainlist (crown)☺️