[tex] \\ { \rm{If \: }{\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}}, { \rm{shown \: that \: AB = A \: and \: BA = B}}[/tex]
[tex] \: [/tex]
Don't Spam
Explain well ​

Answers

Answer 1

Answer:

Given:

[tex] \\ {\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}[/tex]

Matrix A is of order 3 × 3 and Matrix B is of order 3 × 3

To Show:

Matrix AB = A , BA = B

Formula Used:

[tex]\\ { \rm{ \left[ \begin{array}{c c c} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33}\end{array} \right] \times \left[ \begin{array}{c c c} b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23} \\ b_{31} & b_{32} & b_{33} \end{array} \right] = \: \left[ \begin{array}{c c c} \: \: a_{11}b_{11} + a_{12}b_{21} + a_{13}b_{31} & a_{11}b_{12} + a_{12}b_{22} + a_{13}b_{32} & a_{11}b_{13} + a_{12}b_{23} + a_{13}b_{33} \\ \: \: a_{21}b_{11} + a_{22}b_{21} + a_{23}b_{31} & a_{21}b_{12} + a_{22}b_{22} + a_{23}b_{32}&a_{21}b_{13} + a_{22}b_{23} + a_{23}b_{33} \\ \: \: a_{31}b_{11} + a_{32}b_{21} + a_{33}b_{31}&a_{31}b_{12} + a_{32}b_{22} + a_{33}b_{32} & a_{31}b_{13} + a_{32}b_{23} + a_{33}b_{33}\end{array} \right]}}[/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix AB exits and is of order a×d , if and only if b = c.

[tex] \: \: [/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix BA exits and is of order c×b , if and only if d = a.

[tex] \: \: [/tex]

____________________________________________________________________

For Matrix AB, a = 3, b = c = 3, d = 3 , thus Matrix AB is of order 3×3

[tex]\\ { \rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = \left[\begin{array}{c c c} \: \: \: \: 2(2)-3(-1)-5(1) & \: \: \: \: 2(-2)-3(3)-5(-2) & \: \: \: \: 2(-4)-3(4)-5(-3) \\ -1(2)+4(-1)+5(1) & -1(-2)+4(3)+5(-2) & -1(-4)+4(4)+5(-3)\\ \: \: \: \: 1(2)-3(-1)-4(1) & \: \: \: \: 1(-2)-3(3)-4(-2) & \: \: \: \: 1(-4)-3(4)-4(-3) \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 4 + 3 - 5 & \: \: \: -4 -9 + 10 & \: \: -8 - 12 + 15 \\ -2 - 4 + 5 & \: \: \: \: \: \: + 2 + 12 - 10 & \: \: \: \: \: 4 + 16 - 15 \\ \: \: \: \: \: 2 + 3 - 4 & \: \: -2 - 9 + 8 & -4 - 12 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] = Matrix \: A}}[/tex]

Matrix AB = Matrix A____________________________________________________________________

For Matrix BA, a = 3, b = c = 3, d = 3 , thus Matrix BA is of order 3 × 3

[tex]\\ {\rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: \: 1 & -3 & -4 \end{array} \right]}}= \left[ \begin{array}{c c c} \: \: \: \: \: 2(2) -2(-1) -4(1) & \: \: \: \: 2(-3) -2(4) -4(-3) & \: \: \: \: 2(-5) -2(5) -4(-4) \\ \: -1(2) + 3(-1) + 4(1) & -1(-3) + 3(4) +4(-3) & -1(-5) + 3(5) + 4(-4) \\ \: \: \: \: \: 1(2) -2(-1) -3(1) & \: \: \: \: 1(-3) -2(4) -3(-3) & \: \: \: \: 1(-5) -2(5) -3(-4) \end{array} \right][/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 4 + 2 - 4 & \: \: \: -6 -8 + 12 & \: \: -10 - 10 + 16 \\ -2 - 3 + 4 & \: \: \: \: \: \: +3 + 12 - 12 & \: \: \: \: \: + 5 + 15 - 16 \\ \: \: \: \: \: 2 + 2 - 3 & \: -3 -8 +9 & \: \: \: \: \: -5 -10 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right]}}[/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = Matrix \: B}}[/tex]

Matrix BA = Matrix B____________________________________________________________________

Related Questions

A bag contains 9 green marbles, 6 purple marbles, 4 red marbles, 10 blue marbles, and 7 orange marbles. One marble is randomly selected from the bag.

What is the probability that the marble selected is blue or purple?

Answers

The probability that the marble selected is blue or purple is the likelihhood of selecting a blue or purple marble

The probability that the marble selected is blue or purple is 0.444

How to determine the probability?

From the question, we have:

Green = 9

Purple = 6

Red = 4

Blue = 10

Orange = 7

So, the total number of marbles is:

Total = 9 + 6 + 4 + 10 + 7

Total = 36

The number of blue or purple marbles is;

Blue or purple = 10 + 6

Blue or purple = 16

So, the probability that the marble selected is blue or purple

p = 16/36

Evaluate

p = 0.444

Hence, the probability that the marble selected is blue or purple is 0.444

Read more about probability at:

https://brainly.com/question/251701

If an article is sold for rs 99000 after discount of 10% on marked price and adding 10% of Value added tax VAT find marked price​

Answers

Answer:

100000 rupees

Step-by-step explanation:

x × 0.90 × 1.10 = 99000x = 100000

99x78
123x56
98x172
38x900

Answers

Answer:

99x78=7722

123x56=6888

98x172=16856

900x38=34200

Step-by-step explanation:

Which of the following statements about area is not true?
A. Area is the total space within the outside edges of a two-dimensional object.
B. Area can be found by counting the number of unit squares that fill a space.
C. Area is the total distance around the outside of a shape.
D. Area is used to help describe the dimensions of a shape.

Answers

Answer:

C. Area is the total distance around the outside of a shape.

Step-by-step explanation:

Answer:

Area is the total distance around the outside of a shape, Would be correct.

Step-by-step explanation:

Three DVDs and four CDs cost $92. Two DVDs and three CDs cost
$65. Find the cost of each tape and CD.

Answers

Answer:

DVD: $16

CD: $11

Step-by-step explanation:

These two linear equations can represent the system of equations where x equals the cost of a DVD and y equals the cost of a CD:

3x+4y=92

2x+3y=65

When graphed, the solution is at (16,11).

Therefore, one DVD costs $16 and one CD costs $11.

ach of the
7
cats in a pet store was weighed. Here are their weights (in pounds).
5, 9, 9, 16, 12, 15, 6
Find the median and mean weights of these cats.
If necessary, round your answers to the nearest tenth.

Answers

Answer: 10.3, 9

Step-by-step explanation:

What is the mean , median

Answers

The mean is the mathematical average of a set of two or more numbers. The arithmetic mean and the geometric mean are two types of mean that can be calculated. Summing the numbers in a set and dividing by the total number gives you the arithmetic mean.
The median is the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average.

1. quadrilateral with 4 right angles

Answers

Answer:

Square

Step-by-step explanation:

. There is 40% decresed in price on a sale. It is futher decresed by 5% find the total decreased percentage​

Answers

Let x be the original price of the object.

After the 40% discount, the price of the object now becomes;

x-0.4x=0.6x

0.6x is our new price after the first discount.

Now if we want to find the price after the second discount, (5%)

That would come off to be;

0.6x-0.6(0.05)x=0.6x-0.03x=0.57x

Our last price is 0.57x

If you notice, there was a 43% discount in total, as it goes to 57% of its original price.

This is very non intuitive for some people, as they may think there will be a 45% discount.

7. Which statement proves that a quadrilateral is a rhombus? A There is no line of symmetry B. All four sides are congruent C. The diagonals bisect each other D. The diagonals are perpendicular​

Answers

Answer:

B. All four sides are congruent

Step-by-step explanation:

To prove a quadrilateral is equal, prove the four sides to be equalAs the defining feature of a rhombus is that it has 4 equal sides

What is the area of the parallelogram QRST?

Answers

[tex]\text{Area of parallelogram QRST} = QR \times TU = 20 ~in \times 18~in =360 in^2[/tex]

Triangle J K L is shown. Angle J K L is a right angle. An altitude is drawn from point K to point M on side L J to form a right angle. The length of K M is 6 and the length of M J is 3.
What is the length of line segment LJ?

9 units
12 units
15 units
18 units

Answers

Answer:

I think 9 units is the correct answer

Answer:

its 15 units

Step-by-step explanation:

momma told me it was right

what is the area of this object? ​

Answers

Answer: no idea

Step-by-step explanation:

Find the area of the parallelograms below. 21m 33m 21m​

Answers

Answer:

  a. 693²

  b. 148.2 yd²

Step-by-step explanation:

The area of a parallelogram is the product of its base length and the height measured perpendicular to that base.

__

a.

  A = bh = (21 m)(33 m) = 693 m²

__

b.

  A = bh = (19 yd)(7.8 yd) = 148.2 yd²

Mr. and Mrs. Williams hope to send their daughter to college in twelve years. How much money should they invest now at an interest rate of 8.5% per year,
compounded continuously, in order to be able to contribute $9000 to her education?

Answers

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$9000\\ P=\textit{original amount deposited}\\ r=rate\to 8.5\%\to \frac{8.5}{100}\dotfill &0.085\\ t=years\dotfill &12 \end{cases} \\\\\\ 9000=Pe^{0.085\cdot 12}\implies 9000Pe^{1.02}\implies \cfrac{9000}{e^{1.02}}=P\implies 3245.35\approx P[/tex]

15 POINTS ANSWER FAST!


A rectangle PQRS and square LMNO are drawn side by side. The length SR of the rectangle is labeled as 14 inches, and the width QR is labeled as 7 inches. The side LM of the square is labeled as 7 inches.


Anna says that the length of diagonal SQ is two times the length of diagonal OM.


Is Anna correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.

Answers

Use Pythagoras Theorem.

Diagonal of the rectangle PQRS:
7^2 + 14^2 = SQ^2
SQ = 7 root 5

Diagonal of the square LMNO:
7^7 + 7^7 = OM^2
OM = 7 root 2

When dividing SQ or multiplying OM by 2, you don’t get the exact answer so she’s wrong

What is the value of X?
Sin 55° = cos X.
Enter your answer in the box.

Answers

Answer:

x = 35°

Step-by-step explanation:

sin x = cos (90° - x)

sin 55° = cos (90° - 55°)

sin 55° = cos 35°

x = 35°

geometry. find RN. pls help!!

Answers

Apply Thales theorem

[tex]\\ \rm\rightarrowtail \dfrac{MR}{RN}=\dfrac{MQ}{QP}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{10}{RN}=\dfrac{8}{5}[/tex]

[tex]\\ \rm\rightarrowtail 8RN=50[/tex]

[tex]\\ \rm\rightarrowtail RN=50/8[/tex]

[tex]\\ \rm\rightarrowtail RN=6.25[/tex]

Answer:

RN = 6.25

Step-by-step explanation:

Triangle Proportionality Theorem: If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.

Therefore,

MQ : MP = MR : MN

⇒ 8 : (8 + 5) = 10 : (10 + RN)

⇒ 8 : 13 = 10 : (10 + RN)

⇒ [tex]\sf\dfrac{8}{13}=\dfrac{10}{10+RN}[/tex]

Cross multiply and solve:

⇒ 8(10 + RN) = 10 × 13

⇒ 80 + 8RN = 130

⇒ 8RN = 130 - 80

⇒ 8RN = 50

⇒ RN = 50 ÷ 8

⇒ RN = 6.25

Allen was making trail mix, but he only wanted to make of the recipe. If the whole recipe called for of a cup of peanuts, how many cups will he need to make of the recipe? Choose the model that matches the situation.

Answers

It can be inferred that the amount of nuts that Allen requires depends on the amount of the recipe that he wants to make.

How many cups of nuts does Allen require to make the recipe?

According to the information provided, one serving of the recipe calls for one cup of nuts. According to this, it can be inferred that to make a smaller or larger portion of the recipe, this amount must be divided or multiplied.

For example, if Allen calls for making two servings of the recipe, he would use two cups of nuts, while if he calls for making a half serving, he would use half a cup of nuts.

Note: The question is missing because there is some missing information. However I can answer it based on my general prior knowledge.

Learn more about recipes in: https://brainly.com/question/1320828

Answer:

1/6

Step-by-step explanation:

need help please again

Answers

Answer:

7 hours

Step-by-step explanation:

d=rt

d is distance

r is speed

t is time

here we need to find (t)

so d/r is t

so t is 455/65

t is 7

What is 45% of 69/3???

Answers

Answer:

10.35

Step-by-step explanation:

69/3 = 23

45% of 23 = 10.35

Solve
4x957+8465x563+834
please help i need an answer for my homework

Answers

Answer:

the answer should be 477,0457 if x means multiply but if not you are not putting the equation in a correct way

Answer:

4770457

you just need to calculate them

sketch the graph of y=2x^2-3x-4​

Answers

There is your answer

FIND THE MISSING LENGTH.

Answers

Answer:

  x = 9

  x+7 = 16

Step-by-step explanation:

The triangles in this geometry are similar, so the ratios of corresponding sides are proportional.

  long side/short side = (x+7)/12 = 12/x

  x(x +7) = 12²

  x +7x -144 = 0 . . . . . subtract 144 to put in standard form

  (x +16)(x -9) = 0 . . . . factor

  x = 9 . . . . . . only the positive solution is useful here

The missing lengths are ...

x = DC = 9x+7 = DA = 16


Write the standard equation of the circle with center (-10,-5) that passes through the point (-7.5)
The standard form of the equation of the circle is
(Type an equation. Simplify your answer.)

Answers

Answer:

  (x +10)² +(y +5)² = 9

Step-by-step explanation:

The standard form equation for a circle with center (h, k) and radius r is ...

  (x -h)² +(y -k)² = r²

The radius of your circle is the distance between the center and the given point. Those points lie on the same horizontal line, so the radius is the difference of their x-coordinates:

  r = (-7) -(-10) = 3

The equation of the circle is ...

  (x -(-10))² +(y -(-5))² = 3²

  (x +10)² +(y +5)² = 9

How to solve x + y[tex]\frac{dy}{dx}[/tex] = 0

Given that solution goes to (2,0) Neither x nor y can exceed 2

Answers

Answer:

The answer is {D}

Step-by-step explanation:

This semicircle has a radius of 8cm . What is the area of this figure?​

Answers

Answer:

100.48 cm² (Option 2)

Step-by-step explanation:

We know,

[tex]{\longrightarrow \qquad \boldsymbol{\pmb{Area_{(semicircle)} = \dfrac{1}{2}( \pi {r}^{2} ) }}}[/tex]

Where,

r is the radius of the semicircle. Here, the radius is 8 cm .

We will take the value of π as 3.14 .

Now, Substituting the values in the formula :

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{2} \times 3.14 \times ({8})^{2} }}}[/tex]

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{ \cancel2} \times 3.14 \times \cancel{64} }}}[/tex]

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 3.14 \times 32 }}}[/tex]

[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 100.48 }}}[/tex]

[tex]{\longrightarrow \qquad \boldsymbol{ \pmb{Area_{(semicircle)} \approx \it 100.48 }}}[/tex]

Therefore,

The area of the semicircle is 100.48 cm² approximately .

Answer:

100.48 cm² ( option 2 )

Step-by-step explanation:

Given:-

Radius of semicircle :- 8cm

To find:-

Area of the figure

Solution:-

Area of semi-circle :-

[tex] \frac{1}{2} \pi \: r {}^{2} [/tex]

1/2 × 3.14 × 8²

[tex]100.48 \: cm {}^{2} [/tex]

How many lines pass
through two points?
A. infinite
B. 1
C. zero
D. 2

Answers

Answer:

1

Step-by-step explanation:

Only 1 line can pass through two points.

A.infinite

Explanation: Because Infinite number of lines can pass through a single point. Similarly, an infinite number of curves can pass through 2 points, which are not straight lines. Only 1 straight line can pass through 2 points.

Answer the question 3523+4353

Answers

Answer:

7,876

Step-by-step explanation:

brainliest please

help please .and thank u :)​

Answers

Answer:

5/8

Step-by-step explanation:

because 1 minus 3/8 is 5/8

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