Answer:
7.8
Explanation:
Here, an effort of 50 N is applied at the car key and overcomes the resistance(or load) of 390 N at the lid.
mechanical advantage
=load/effort
=390 N/50 N
=7.8
Wat would happen if a feather and a ball were released from the same height at the same time? Gravity Experiments for Kids – Science Experiments for Kids
Answer:
They would land at the same time
Explanation:
They would land at the same exact time.
As weird, impossible and unbelievable as it appears. When in a vacuum, every weight, body and material when released from the same height would land on the ground at the same time. This also means that like in the question, a feather and a ball would land at the same time. And just for illustrations as well, a feather and a car would land at the same time as well.
In a series circuit, there is a 2-ohm resistor with a current of 5A. If there is another resistor with a resistance of 5 ohms, what is the current inside that resistor?
Answer:
if 2ohms gives 5A
then 5ohms will give 12.5A
since its directly proportional
V=IR
Sunlight is a form of electromagnetic energy.
Please select the best answer from the choices provided
T
F
Answer: True
Explanation: Hope this helps :)
Neptune and Uranus are called the "ice giants" due to the presence of ice on their surface. Which is a reasonable explanation for why there aren't any ice giants in the group of terrestrial planets? A. They have rocky surfaces. B. They do not have rings. C. They are too close to the sun.
Answer:
C. They are too close to the sun.
Explanation:
Due to their relative location the gas giant such as neptune and Uranus are mostly cold and icy planets as they are located deep into the solar system and have large distance firm the sun.As compared to those of the earth and other rocky planets. Due to their distance they consist of primitive atmosphere and have slow rotation and movement.what is this simple machines name
Answer:
bottle opener and door knob
Explanation:
Answer:
bottle opener
door handle
Una bola se lanza verticlamente de la parte superior de un edificio con una velocidad inicial 25 m/s la bola impacta al suelo en la base del edificio 7 segundos despues de ser lanzada ¿que altura subio la bola
Answer:
S = 415.1 meters
Explanation:
Dados los siguientes datos;
Velocidad inicial = 25 m/s
Tiempo, t = 7 segundos
Para encontrar la altura (desplazamiento) de la pelota, usaríamos la segunda ecuación de movimiento;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Dónde;
S representa el desplazamiento o altura medida en metros.
u representa la velocidad inicial medida en metros por segundo.
t representa el tiempo medido en segundos.
a representa la aceleración medida en metros por segundo cuadrado.
Sustituyendo en la ecuación, tenemos;
[tex] S = 25*7 + \frac {1}{2}*(9.8)*7^{2}[/tex]
[tex] S = 175 + 4.9*49 [/tex]
[tex] S = 175 + 240.1 [/tex]
S = 415.1 meters
An ant walks 15 m east, then 40 m north, and finally 20 m west. What is the total displacement from the starting point
Answer: 40.311 m
Explanation:
Given
Ant walks 15 m east
then 40 m North and finally 20 m west
from the figure, ant is 40 m North and 5 m west
Using Pythagoras, we can write
[tex]\Rightarrow d=\sqrt{40^2+5^2}\\\Rightarrow d=\sqrt{1625}=40.311\ m[/tex]
It's almost always difficult to select healthy foods at a fast-food restaurant. O True O False
Answer:
yesExplanation:
because its most likely to have chucks than heathy foodDefine heat according to molecular theory .
I think ....... the answer will be ......
like a theory
Plzzz help!! A stationary speed gun emits a
microwave beam at 2.10x1010 Hz. It
reflects off a car and returns 1030 Hz
higher. What is the speed of the car?
(Unit = m/s)
Answer:
The speed of the car is 14.7m/second or 15 m/second approximately.
Explanation:
A microwave beam at [tex]2.10\times10^1^0Hz[/tex] is generated by a stationary speed gun. It bounces off a car and returns at a higher frequency of 1030 Hz. The car's observed frequency would be the product of adding the two frequencies. That is to say,
F =[tex]2.1\times10^1^0+1030[/tex] =[tex]2.100000103\times10^1^0Hz[/tex]
Using doppler effect formula
[tex]F=\frac{C}{C-V}\times f[/tex]
Where
F = observed frequency
f = source frequency
C = speed of light = [tex]3\times10^8[/tex]
V = speed of the car
Putting the values in the formula -
[tex]2.100000103\times10^1^0=\frac{3\times10^8}{3\times10^8-V}\times2.1\times 10^1^0[/tex]
[tex]\frac{2.100000103\times10^1^0}{2.1\times10^1^0}[/tex] [tex]=\frac{3\times10^8}{3\times10^8-V}[/tex]
[tex]1.000000049=\frac{3\times10^8}{3\times10^8-V}[/tex]
by cross multiplication ,
300000014.7 - 1.000000049V = [tex]3\times10^8[/tex]
Collect the like terms
1.000000049V = 14.71429
Make V the subject of formula
V = [tex]\frac{14.71429}{1.000000049}[/tex]
V = 14.7 m/s
Therefore , the speed of the car is 15m/second approximately.
Select the correct answer from each drop-down menu.
Photosynthesis is a process in which plants prepare food using carbon dioxide, chlorophyll, and water in the presence of sunlight.
During photosynthesis,(blank)
energy is transformed into(blank)
1.Chemical,electrical,kinetic, Solar ?
2.Chemical, Electrical, Kinetic, Solar
Answer:
During photosynthesis solar energy is converted into chemical energy
Explanation:
During photosynthesis solar energy is converted into chemical energy in the form of energy rich bond of ATP molecule.
ATP (Adenosine triphosphate) and ADP (Adenosine diphosphate) molecules are termed currency of energy. ADP molecule is converted into ATP molecules, whenever energy is available in certain exothermic reactions of metabolism.
ATP molecules are store- house of energy. ATP molecule is broken down into ADP molecule in presence of enzyme ATPase, releasing energy whenever energy is required.
The synthesis of ATP molecules, utilizing solar energy during photosynthesis, is termed photo-phosphorylation.
These ATP molecules produced during light reaction of photosynthesis are utilized in dark reaction of photosynthesis (Calvin cycle).
ATP molecules synthesized during photo-phosphorylation may also be used in other metabolic reactions.
Photo-phosphorylation is of 2 types, i.e. Cyclic and Non-cyclic photo-phosphorylation.
Chlorophyll molecules entrap solar energy . There are 2 types of photo-systems in chlorophyll. These are photo-system -I and photo-system-II .
The electrons of chlorophyll molecule of photo-system I get excited which pass through series of electron carriers in electron transport system arranged in the order of decreasing energy level.
During the passage of electrons from carriers of higher energy level to the carriers of lower energy level, the energy is lost which is utilized for converting ADP molecule into ATP molecule.
Photo-system I is concerned with light reaction of photosynthesis only, constituting cyclic photo-phosphorylation.
The electron transport during Photo-system II results in the synthesis of NADPH2 in presence of enzyme NADP reductase. NADPH2 is used in reduction reaction of Calvin cycle.
Both Photo-systems participate in non-cyclic photo-phosphorylation that results in the synthesis of NADPH2 in addition to the synthesis of ATP molecules.
5. What is the velocity of a 0.5 kg ball that has a momentum of 3.00 kg m/s?
Answer:
6 m/s
Explanation:
p=mv
p=3 kg.m/s
m=0.5 kg
rearrange and substitute to find v:
(3)=(0.5)v
v=3/0.5
v=6 m/s
3 ways objects can be grouped are
Answer:
Transparent = lets light pass through without significant interference
Translucent = lets light pass through with significant interference
Opaque = Doesn't let light pass, instead absorbs it
who invented Pascal??
What is a key difference between transverse and longitudinal waves?
A.) Transverse move up and down while longitudinal can do in any direction.
B.) Transverse can e described as troughs and crest while, longitudinal waves can be described as compression and rarefactions.
C.) There is no difference, it depends on the scientific uses and calculations involved.
D.) Transverse waves can only represent sound while longitudinal are represented by ocean waves, light and other waves
Answer:
B.) Transverse can e described as troughs and crest while, longitudinal waves can be described as compression and rarefactions.
13.If a jet plane with a velocity of 20 m/s at t = 0 accelerates at a rate of 40 m/s²
for 3 seconds, what is its veloaty at time = 3 seconds?
Answer:
140m/s
Explanation:
V=V0+at. V=20+40*3=140m/s
A block of size 100cmX50cm applies a force of 100N on the ground. Calculate the pressure
exerted by the block on the ground.
(2 Points)
Answer:
200 N/m²
Explanation:
Pressure = Force / Area
Force =100N
Area = 100cm x 50 cm= 5000cm² =0.5m²
Hence Pressure = 100N / 0.5m²
Pressure = 200N/m²
You ride your bike 5 miles east to school, then 2 miles east to Wawa, return to school, then ride 2 miles west to the library to work on your homework. What is your displacement?
Answer:
3 miles
Explanation:
5 + 2 - 2 - 2 = 3 miles
Define 1 pascal pressure
Answer:
Hey mate....
Explanation:
This is ur answer.....
A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared. For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa.
Hope it helps you,
mark me brainliest plz.....
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pascal is the SI unit of pressure symbolized by Pa
1 Pa=1N/m^2
1Pa=1kg/ms^2
What is an abyssal fan
Answer:
Abyssal fans, also known as deep-sea fans, underwater deltas, and submarine fans, are underwater geological structures associated with large-scale sediment deposition and formed by turbidity currents
Explanation:
They are underwater deltas and submarine fans, they are associated with large scale sediment, and formed by turbidity currents.
1. A student lifts a box of books that weighs 200 N. The box is lifted 2.5 m. How much work
does the student do on the box?
Answer:
The student does a work of 500 Newton meter on the box.
Explanation:
An organism with the alleles Aa is called __________, while one with AA or aa is called __________.
A. heterozygous, hom/ zygous
B. heterozygous, homo/zygous
Answer:
Hetefrozygous, homofzygous
A disturbance that generates a wave may be a simple pulse or shock
True or false
Answer:
That would be true.
-- a bell starts ringing (wave) when you tap it (simple pulse)
-- a pond starts rippling (wave) when a stone drops in (simple shock)
-- a guitar strings starts waving when you pluck it
which lever is human arm
Answer:
The human arm is a class 3 lever
Explanation:
Answer:
A bent arm is a Class 3 lever. The pivot is at the elbow and the forearm acts as the lever arm. The biceps muscle provides the effort (force) and bends the forearm against the weight of the forearm and any weight that the hand might be holding.
Explanation:
A net force of 125 N is applied to a certain object. As a result, the object accelerates with an acceleration of 24 m/s2. The mass of the object is
Answer:
5.2 kg
Explanation:
mass Is force divided by the acceleration125÷4 5.2083333333How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?
Answer:
313.92w
Explanation:
Formula for power:
P=W/∆t = Fv
Givens:
m=20kg
∆y=4.0m
∆t=2.5s
a=9.81m/s²
In order to find power, we first need to solve for work.
W=Fd (force*displacement), f=mg
W=mg∆y
W=(20kg)(9.81m/s²)(4.0m)
W=784.8J
P=W/∆t
P=784.8J/2.5s
P=313.92 watts
Use the term chemical bond in a complete sentence
Pilings are driven into the ground at a building site by dropping a 2250 kg object onto them. What change in gravitational potential energy does the object undergo if it is released from rest 16.0 m above the ground and ends up 1.30 m above the ground ? Change in gravitational potential energy:
Answer: 324.135 kJ
Explanation:
Given
Mass of dropping is [tex]m=2250\ kg[/tex]
The initial height of dropping is [tex]h_1=16\ m[/tex]
The final height of dropping [tex]h_2=1.3\ m[/tex]
Gravitational potential energy is the function of height i.e.
[tex]\Rightarrow \text{G.E.}=mgh[/tex]
Change in Gravitational Energy is
[tex]\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ[/tex]
ILL MARK BRAINLIEST
PLEASE HELP
2.Write the formula associating energy with power
3.Write the formula associating potential energy with height.
(PLEASE HELP ASAP )
Explanation:
2. Power is defined as the rate of doing work. Mathematically, it can be given by :
[tex]P=\dfrac{W}{t}[/tex]
Where
W is work done or energy
t is the time taken
3. The formula of potential energy can be given by :
[tex]P=mgh[/tex]
Where
m is the mass of the object
g is the acceleration due to gravity
h is height
Hence, this is the required solution.
A 12 N [E] force is applied to a toy train with a mass of 2.7 kg. The toy train is attached by a light string to a wagon with a mass of 1.8 kg which is attached to a second wagon with a mass of 1.0 kg. If the train is pulled on a surface with a coefficient of kinetic friction of 0.05, determine the tension in the string between the first and the second wagon. (6T, 3C) Include free body diagrams for the three masses involved in the acceleration. (3 Comm.)
See the attached diagram for reference and free body diagrams. The acceleration a of each body will be the same since each connecting string is in tension.
By Newton's second law, we have
• net force on the train:
- - horizontal
[tex]\sum F = F - F_{k,T} - T_1 = m_Ta[/tex]
(where F = 12 N)
- - vertical
[tex]\sum F = N_T - m_Tg = 0[/tex]
• net force on wagon 1:
- - horizontal
[tex]\sum F = T_1 - T_2 - F_{k,1} = m_1a[/tex]
- - vertical
[tex]\sum F = N_1 - m_1g = 0[/tex]
• net force on wagon 2:
- - horizontal
[tex]\sum F = T_2 - F_{k,2} = m_2a[/tex]
- - vertical
[tex]\sum F = N_2 - m_2g = 0[/tex]
We want to determine T₂, the tension in the string connecting the two wagons.
For each body, the corresponding normal force has magnitude
N = mg
where m is the respective mass, and the kinetic friction has magnitude
Friction = 0.05 N = 0.05mg
So if µ = 0.05, then the frictional force on each body is
[tex]F_{k,T} = 0.05 (2.7\,\mathrm{ kg}) g = 1.323\,\mathrm N[/tex]
[tex]F_{k,1} = 0.05 (1.8\,\mathrm{ kg}) g = 0.882\,\mathrm N[/tex]
[tex]F_{k,2} = 0.05 (1.0\,\mathrm{ kg}) g = 0.49\,\mathrm N[/tex]
which leaves us with the system of equations,
[1] … 12 N - 1.323 N - T₁ = (2.7 kg) a
[2] … T₁ - T₂ - 0.882 N = (1.8 kg) a
[3] … T₂ - 0.49 N = (1.0 kg) a
Adding [1] and [2] eliminates T₁ :
(12 N - 1.323 N - T₁) + (T₁ - T₂ - 0.882 N) = (2.7 kg) a + (1.8 kg) a
[4] … 9.795 N - T₂ = (4.5 kg) a
Divide through both sides of [3] by 1.0 kg to solve for a :
a = (T₂ - 0.49 N) / (1.0 kg)
Substitute this into [4] and solve for T₂ :
9.795 N - T₂ = (4.5 kg) (T₂ - 0.49 N) / (1.0 kg)
(9.795 N - T₂) (1.0 kg) = (4.5 kg) (T₂ - 0.49 N)
9.795 N - T₂ = 4.5 T₂ - 2.205 N
12 N = 5.5 T₂
T₂ = (12 N) / 5.5 ≈ 2.1818 N ≈ 2.2 N