Two train cars with the same mass (30,000 kg) are traveling in the same direction when they collide.
Train Car A has a velocity of 10 m/s and Train Car B has a velocity of 5 m/s. What is their total
momentum after the collision? Make sure to show all your work and include proper units.

Answer:

Velocidad final, V = 8 m/s

Explanation:

Dados los siguientes datos;

Velocidad inicial, u = 4 m/s

Aceleración, a = 2 m/s²

Tiempo, t = 2 segundos

Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;

V = u + at

Sustituyendo en la fórmula, tenemos;

V = 4 + 2*2

V = 4 + 4

Velocidad final, V = 8 m/s

Answer:

B The resultant force on the satellite is towards the Earth.

Explanation:

In the case when the satellite orbits earth would be at constant speed in the circular orbit so hee the resultant force that on the satellite would be with regard to the earth

So as per the given situation, the option B is correct

And, the rest of the options would be wrong

And, the same would be relevant

The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.

The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.

The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.

The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.

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Answer:

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Explanation:

Given:

Blue light of wavelength λ1 = 435 nm

n2 in diamond = 2.42

Find:

Wavelength of light in  diamond λ2

Computation:

Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.

So,

n1λ1 = n2λ2

(1)(435) = (2.42)λ2

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Answer:

180

Explanation:

got it right on acellus

Answer:

C. Elements with intermediate number of valence electrons are the most chemically stable.

Answer:

 m = 4.0

Explanation:

For this exercise in geometric optics we will use the equation of the constructor

         [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and image, respectively.

In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image

         [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]

let's calculate

         [tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6

         [tex]\frac{1}{q}[/tex] = -0.125

         q = -8 cm

the magnification is

        m = - q / p

        m = 8/2

        m = 4.0

Answer:

The building are not getting farther and farther away, road signs, exits, other cars

Explanation:

Answer:

0.19 and 0.45

Explanation:

edge

The first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.

The velocity of an object is defined as the product of the distance travelled in a given direction and the time required to travel that distance. The velocity is expressed mathematically as,

v = d/t

Here, d represents the travelled distance.

And t is the typical amount of time needed to go the distance.

Given,

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

Then the first velocity of the car at 0.25 m is,

[tex]v_1 = d_1/t_1\\v_1 = 0.25 / t_1[/tex]

Thus,[tex]t_1[/tex] denotes the first distance's typical time.

The second velocity of the car with three washers at the 0. 50 m mark is

[tex]v_2 = d_2/t_2\\v_2 = 0.50 /t_2[/tex]

Here, [tex]t_2[/tex] stands for the second distance's typical time.

Thus, the first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.

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