1 Pine- apple equal to 9 Apples.
What is Ratio proportion?The divisional comparison of two quantities yields a ratio, and the equality of two ratios yields a proportion.
A ratio is commonly written as "x: y," though it can also be read as "x is to y" or "x/y."
In terms of comparison, a proportional equation says that two ratios are equal.
When x: y: z: w is used to represent a ratio, it is understood to mean that x is to y as z is to w.
In this case, w and Y are not equal to 0, therefore x/y Equals z/w.
6 Apples = 4 Pomegranates
6 Pomegranates = 1 Pine- apple
1 Pine- apple = 9 Apples.
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How do I simplify my answer of 42i^2+32i+6 when the original problem was (2-6i)(3-7i)
Given problem is
[tex](2-6i)(3-7i)[/tex]Now,
[tex]\begin{gathered} (2-6i)(3-7i)=42i^2-14i-18i+6 \\ =42i^2-32i+6 \end{gathered}[/tex]We know that
[tex]i^2=-1[/tex]Using this face,
[tex]\begin{gathered} 42i^2-32i+6=-42-32i+6 \\ =-32i-36 \end{gathered}[/tex]Hence, the simplified form is
[tex]-32i-36[/tex]what is the conjugate of the denominator of the expression 9i/-2+7i
The answer is D.
The figure below is made up of a triangle and a circle. The ratio of the area of the triangle to the area of the circle is 5:6. If 1/5 of the area of the triangle is shaded, what is the ratio of the shaded area to the area of the figure?
ANSWER
[tex]\begin{equation*} 1:10 \end{equation*}[/tex]EXPLANATION
The ratio of the area of the triangle to the area of the circle is:
[tex]5:6[/tex]Let the area of the triangle be T.
1/5 of the area of the triangle is shaded i.e. 1/5 T
The total area of the figure is the sum of the area of the triangle that is not shaded and the area of the circle.
The area of the triangle that is not shaded is:
[tex]\begin{gathered} T-\frac{1}{5}T \\ \frac{4}{5}T \end{gathered}[/tex]Let the area of the circle be C. The ratio of the area of the triangle to that of the circle is 5/6. This implies that:
[tex]\begin{gathered} \frac{T}{C}=\frac{5}{6} \\ \Rightarrow C=\frac{6T}{5} \end{gathered}[/tex]And so, the area of the figure is in terms of T is:
[tex]\begin{gathered} \frac{4}{5}T+\frac{6}{5}T \\ 2T \end{gathered}[/tex]Therefore, the ratio of the shaded area to the area of the figure is:
[tex]\begin{gathered} \frac{1}{5}T:2T \\ \Rightarrow\frac{1}{5}:2 \\ \Rightarrow1:10 \end{gathered}[/tex]That is the answer.
The sign points at the smaller number. True or False. Example 2 < 100 True False
When working with inequalities you have to remember that:
The symbol "<" indicates that the number on the left is smaller than the number on the right, then, for example:
[tex]85<90[/tex]This indicates that 85 is less than 90.
The symbol ">" indicates that the number of the left is greater than the number on the right, for example:
[tex]70>54[/tex]This indicates that 70 is greater than 54.
Now for the given statement:
[tex]2<100[/tex]"The sign points at the smaller number"
The expression indicates that 2 is less than 100, so the statement is true.
The functions f(x) and g(x) are shown on the graph.f(x)=x^2What is g(x)?A. g(x)=(x+3)^2B. g(x)=(x-3)^2C. g(x)=(1/3x)^2D. g(x)=3x^2
Given:
[tex]f(x)=x^2[/tex]Let's find g(x).
From the given graph, we can see the graph of g(x) is compressed horizontally from f(x).
Thus, to find g(x) aply the transformation rules for function.
We have:
Horizontal compression of b units ==> f(bx)
Given the point on g(x):
(x, y) ==> (2, 12)
Let's solve for the value of the compressed factor.
We have:
[tex]\begin{gathered} 12=b(2)^2 \\ \\ 12=b4 \\ \\ \text{Divide both sides by 4:} \\ \frac{12}{4}=\frac{b4}{4} \\ \\ 3=b \\ \\ b=3 \end{gathered}[/tex]This means the graph of f(x) was compressed horizontally by a factor of 3 to get g(x).
Thus, to write the function for g(x), we have:
[tex]g(x)=3x^2[/tex]ANSWER:
[tex]D\text{.}g(x)=3x^2[/tex]What is the value of 9 − (−4)?
Answer:13
Step-by-step explanation:
Step-by-step explanation:
remember, when 2 signs and/operations come together, for addition/subtraction and multiplication/division it always applies :
+ + = +
- + = -
+ - = -
- - = +
and therefore,
9 - (-4) = 9 + 4 = 13
a minus meeting a minus always results in a plus.
A tank is in the shape of a cylinder of radius 15 cm and height 50 cm.Work out the volume of the tank.
Answer: [tex]11250\pi \\[/tex] cm^3
Step-by-step explanation:
This could be solved with integral calculus or simple arithmetic.
If you need to show the work in calculus, let me know, otherwise, here's the easiest way to reach the answer:
Volume of a solid is equal to the area of its 2D projection multiplied by its height, assuming that it's uniform throughout its entire height. Fortunately, a cylinder is uniform throughout its height.
What is a cylinder's 2D projection? A circle!
Area of a circle = [tex]\pi r^{2}[/tex]
r = 15
Area = 225pi cm^2
Now, we multiply the area of the 2D projection by the height of the cylinder.
225pi * 50 = 11250pi cm^3
Point (7, 2) is translated up 2 units and left 5 units. Where is the new point located?(12, 4)(9, -3)(2,0)(2, 4)
The new point is located at (2,4)
Here, we want to get the result of a translation
2 units up simply mean, we are adding 2 to the y-axis value
5 units left mean we are subtracting 5 from the x-axis value
We can represent the translation as;
[tex]\begin{gathered} (x,y)\rightarrow\text{ (x-5 , y+2)} \\ =\text{ (7-5,2+2) = (2,4)} \end{gathered}[/tex]Select all the true statements about this graph A. The graph is nonlinearB. The function increases at the same rateC. The rate decreases after x = 2.D. The graph is a functionE. The graph is increasing in two intervals.SELECT ALL ANSWER CHOICES THATS RIGHT
In the graph the points are connected by the straight lines, so graph is linear graph. In nonlinear graph the points are connected by the curve. So option A is incorrect.
The slope of the line changes after x=2. The inclination of line with positive x axis is different before and after x=2. So the function not increases at same rate. Then option B is incorrect.
The rate is given by the slope of line. The inclination of line with positive x axis increase after x=2, so rate increases not decreases. Then option C is incorrect.
The graph of a straight line is function or not a function can be inspected by vertical line test.
If we draw a vertical line, then the vertical line intersect the line only once, so the graph is function. Option D is correct.
The value of y increases with increase in value of x but increase in value of y with x is different for two lines. So graph is increasing in two intervals. Option E is also correct.
Thus option D and E is only true for given graph.
For each quadratic expression below, drag an equivalent expression to its match
1. Given the expression:
[tex]\mleft(x+2\mright)\mleft(x-4\mright)[/tex]You can use the FOIL method to multiply the binomials. Remember that the FOIL method is:
[tex](a+b)\mleft(c+d\mright)=ac+ad+bc+bd[/tex]Then, you get:
[tex]\begin{gathered} =(x)(x)-(x)(4)+(2)(x)-(2)(4) \\ =x^2-4x+2x^{}-8 \end{gathered}[/tex]Adding the like terms, you get:
[tex]=x^2-2x-8[/tex]2. Given:
[tex]x^2-6x+5[/tex]You have to complete the square:
- Identify the coefficient of the x-term". In this case, this is -6.
- Divide -6 by 2 and square the result:
[tex](\frac{-6}{2})^2=(-3)^2=9[/tex]- Now add 9 to the polynomial and also subtract 9 from the polynomial:
[tex]=x^2-6x+(9)+5-(9)[/tex]- Finally, simplifying and completing the square, you get:
[tex]=(x-3)^2-4[/tex]3. Given the expression:
[tex]\mleft(x+3\mright)^2-7[/tex]You can simplify it as follows:
- Apply:
[tex](a+b)^2=a^2+2ab+b^2[/tex]In this case:
[tex]\begin{gathered} a=x \\ b=3 \end{gathered}[/tex]Then:
[tex]\begin{gathered} =\lbrack(x)^2+(2)(x)(3)+(3)^2\rbrack-7 \\ =\lbrack x^2+6x+9\rbrack-7 \end{gathered}[/tex]- Adding the like terms, you get:
[tex]=x^2+6x+2[/tex]4. Given:
[tex]x^2-8x+15[/tex]You need to complete the square by following the procedure used in expression 2.
In this case, the coefficient of the x-term is:
[tex]b=-8[/tex]Then:
[tex](\frac{-8}{2})^2=(-4)^2=16[/tex]By Completing the square, you get:
[tex]\begin{gathered} =x^2-8x+(16)+15-(16) \\ =(x-4)^2-1 \end{gathered}[/tex]Therefore, the answer is:
I am asked to graph f(x) = (- 1/x-2) -1
Answer
[tex]f(x)=-\frac{1}{x-2}-1[/tex]1 a) is the above sequence arithmetic? Justify your answer. b) Write the explicit formula for the above sequence. c) Find the 18th term.
First, we count the number of boxes.
We have: 4,8,12,16
(a)Now:
• 8-4=4
,• 12-8=4
,• 16-12=4
Since the difference is the same, the sequence is an arithmetic sequence.
(b)In the sequence
First term, a =4
Common difference, d=4
The nth term of an arithmetic sequence is:
[tex]\begin{gathered} U_n=a+(n-1)d \\ =4+4(n-1) \\ =4+4n-4 \\ =4n \end{gathered}[/tex]The explicit formula for the above sequence, f(n)= 4n.
(c)18th term
f(18)= 4 x 18
=72
The 18th term is 72.
In a poll, students were asked to choose which of six colors was their favorite. The circle graph shows how the students answered. If 11,000 students participated in the poll, how many chose green?Orange 13%Pink 7%Blue 10%Red 24%Purple 10%Green 36%
Total of 11,000 students
Green 36%
how many chose green?
Chose green = 11000 * 36/100 = 3960
36% of 11,000 is 3960
Answer:
3,960 students chose green
what is the probability that a student will be in both chemistry and math but not Spanish round to three decimal places
Answer :
3/13
Explanation :
The probablity of an event = favourable outcome / total outcomes
Now in our case,
favorable outcome = 60
Total number of outcomes = 5 + 70 + 5 + 85 + 60 + 15 + 3 + 17 = 260
Therefore,
probablity = 60 / 260
= 3 /13
Which statement is the converse of the conditional statement:
If point B bisects line segment AC into two congruent segments, then point B is the midpoint.
• If point B is the midpoint, then point B bisects line segment AC into two congruent segments.
O If point 8 is not the midpoint, then point B does not bisect line segment AC into two congruent segments.
Point B bisects line segment AC into two congruent segments if, and only if, point B is the midpoint.
O if point B
does not bisect line segment AC into two congruent segments, then point B is not the midpoint.
Point B is the midpoint if it divides line segment AC into two congruent segmentsIf point B is not the midpoint, then point B does not divide the line segment AC into two congruent segments, which is the statement opposite to the one that has been made.
Which statement is the converse of the conditional statement ?
A point that separates a segment into two congruent segments is the segment's midpoint.The segment is bisected by a point (or segment, ray, or line) that separates it into two congruent segments.Trisecting is the process of dividing a segment into three congruent segments using two points (segments, rays, or lines). A perpendicular bisector is a segment, ray, line, or plane that is perpendicular to another segment at its halfway. The x-coordinate of the midpoint M of the line segment AB is, as we can see from the formula, equal to the arithmetic mean of the x-coordinates of the segment's two endpoints.The midpoint's y-coordinate is also equal to the mean of the endpoints' y-coordinates. Even a unique postulate just for midpoints exists.Midpoint of a Segment Hypothesis.Any line segment will only have one midpoint, neither more nor less. Any line segment with equal measure is referred to as a congruent line segment.Congruent line segments, for instance, refer to the sides of an equilateral triangle since they all have the same length. Line segments that are congruent have the same length.There is a point in a line segment that will divide it into two congruent line segments.The middle is where you are now. A segment bisector runs through the middle of a line segment and divides it into two congruent portions.A segment bisector that intersects the segment at a right angle is called a perpendicular bisector.AB B C A C D E By applying algebraic techniques to solve the midpoint formula for one endpoint, the endpoint formula can be discovered.After performing the necessary algebra, (xa,ya)=((2xmxb),(2ymyb)) (x a, y a) = ((2 x m x b), (2 y m y b)) is the formula for the Endpoint A A of line AB A B.To learn more about mid point refer
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GWhich inequalities have no solution? Check all of the boxes that apply.XX-3x -3x–4 + x>-2 + xX-2
For every number x, x = x, not x < x. So, the inequality x < x has no solution.
Since -3x = -3x for every real number, the inequality
[tex]-3x\leq-3x[/tex]holds for every real number, that is, every number is a solution.
Consider the inequality
[tex]-4+x>-2+x[/tex]Subtract x on both sides gives -4 > -2, which is not possible.
Hence the inequality - 4 + x > - 2 + x has no solution.
Consider the inequality
[tex]x-2Subtract x on both sides gives -2 < 3, which is true.Every real number is a solution of the inequality. Hence the inequality has solution.
Thus the inequalities with no solution are: x < x and -4+x>-2+x
Find the first four terms of the sequence given by the following
1) In this question, we need to resort to that Explicit formula, with the first term so that we can find the terms:
[tex]\begin{gathered} a_n=54+8(n-1) \\ a_1=54+8(1-1) \\ a_1=54 \\ \\ a_2=54+8(2-1) \\ a_2=54+8 \\ a_2=62 \\ \\ a_3=54+8(3-1) \\ a_3=54+8(2) \\ a_3=54+16 \\ a_3=70 \\ \\ a_4=54+8(4-1) \\ a_4=54+8(3) \\ a_4=78 \\ \end{gathered}[/tex]2) As we can see, this is an Arithmetic sequence. And the answer is:
[tex]54,62,70,78[/tex]How do I add the probabilities? And what is the solution after doing that?
In order to calculate the probability of P(Z<3), let's add all cases where Z<3:
[tex]P(Z<3)=P(Z=0)+P(Z=1)+P(Z=2)[/tex]The minimum value of Z is given when X = 0 and Y = 1, so Z = 1.
The maximum value of Z is given when X = 1 and Y = 2, so Z = 3.
Therefore P(Z = 0) is zero.
Z = 1 can only happen when X = 0 and Y = 1.
Z = 2 can happen when X = 1 and Y = 1 or when X = 0 and Y = 2.
So we can rewrite the expression as follows:
[tex]\begin{gathered} P(Z<3)=0+P(X=0)P(Y=1)+[P(X=1)P(Y=1)+P(X=0)P(Y=2)\rbrack\\ \\ =0+0.5\cdot0.4+0.5\cdot0.4+0.5\cdot0.6\\ \\ =0+0.2+0.2+0.3\\ \\ =0.7 \end{gathered}[/tex]Therefore the correct option is A.
A gumball machine contains 5 blue gumballs and 4 red gumballs. Two gumballs are purchased, one after the other, without replacement.
Find the probability that the second gumball is red.
===================================================
Work Shown:
5 blue + 4 red = 9 total
A = P(1st is red, 2nd is red)
A = P(1st is red)*P(2nd is red, given 1st is red)
A = (4/9)*(3/8)
A = 12/72
B = P(1st is blue, 2nd is red)
B = P(1st is blue)*P(2nd is red, given 1st is blue)
B = (5/9)*(4/8)
B = 20/72
C = P(2nd is red)
C = A+B
C = 12/72 + 20/72
C = 32/72
C = 4/9
since birth hakem has had a savings account that started at $3,000 and had been growing at a rate of 13% per year the amount of money in the account can be modeled by the equation y equals P =(1.13)^ Z where why is the value of the count is the number of years and pee was original deposit amount is it possible for hakem account to grow to $31812 11.42 in hakem lifetime?( try to figure out the bounds of the perameter)
Solution
For this case we have the following formula:
[tex]y=3000(1.13)^x^{}[/tex]And we want to find the value for t in order to have y = 3181211.42 , solving for y we got:
[tex]3181211.42=3000(1.13)^x[/tex]and solving for x we got:
[tex]\ln (\frac{3181211.42}{3000})=x\cdot\ln (1.13)[/tex][tex]x=56.99\approx57[/tex]for this case we need 57 years to reach the amount so then assuming that a person lives about 80 years , then is possible
yes
although the actual amount varies by the season and time of the day the average volume of water that flows over the false each second is 2.9 x 10 to the 5th power gallons how much water flows over the falls in an hour write the result in scientific notation hint 1 hour equals 3600 second
We were told that volume of water that flows over the fall each second is 2.9 x 10^5 gallons.
Recall, 1 hour = 3600 seconds
If 1 second = 2.9 x 10^5 gallons, then
3600 seconds = 3600 x 2.9 x 10^5
= 1.044 x 10^9 gallons
Thus, 1.044 x 10^9 gallons of water will flow over the falls in an hour.
Simplify. -(-6w + x - 3y)
Answer: 6w - x + 3y
Step-by-step explanation:
An air plane can cruise at 640mph. How far can it fly in 3/2 Ths of an hour?
Answer: 960 miles
3/2 of an hour would be 1 hour and 30 min or an hour and a half
640mph (mph = miles per hour)
1/2 of an hour is 30 minutes so its 640 miles in half so 320
now all you gotta do is add it
so 640 + 320 = 960
INT. ALGEBRA: Write an equation that passes through (-10,-30) and is perpendicular to 12y-4x=8
Thank you for your help, and please do show work! I will be looking to give the Brainliest answer to someone!
The equation of the perpendicular line is y = -3x - 60
How to determine the line equation?The equation is given as
12y - 4x = 8
Make y the subject
12y= 4x + 8
y = 1/3x + 2/3
The point is also given as
Point = (-10, -30)
The equation of a line can be represented as
y = mx + c
Where
Slope = m
By comparing the equations, we have the following
m = 1/3
This means that the slope of 12y - 4x = 8 is 1/3
So, we have
m = 1/3
The slopes of perpendicular lines are opposite reciprocals
This means that the slope of the other line is -3
The equation of the perpendicular lines is then calculated as
y = m(x - x₁) +y₁
Where
m = -3
(x₁, y₁) = (-10, -30)
So, we have
y = -3(x + 10) - 30
Evaluate
y = -3x - 30 - 30
y = -3x - 60
Hence, the perpendicular line has an equation of y = -3x - 60
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using the given quadratic function f(x)=x^2+2x-15, find the following information"Coordinates of x- intercept(zero) as ordered pairs"
the given expression is
f(x) = x^2 + 2x - 15
we will find x intercept by putting f(x) = 0
x^2 + 2x - 15 = 0
x^2 + 5x - 3x - 15 = 0
x(x +5) -3(x + 5) = 0
(x +5) (x -3) = 0
x = -5 & x = 3
so the ordered pairs are
(-5, 0) and (3, 0)
A number cube labelled 1 to 6 is rolled 276 times. Predict how many times a 5 will show.
All the outcomes of the cube are equally probable, therefore, it is expected to have all the outcomes after 6 rolls. To find the amount of times we're supposed to get one of the outcomes, we multiply the amount of rolls by the probability of this outcome.
The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. We have one number five out of six possible numbers, therefore, the probability of getting a 5 is:
[tex]P(5)=\frac{1}{6}[/tex]Therefore, in 276 rolls we're going to get the following amount of 5's:
[tex]276\times P(5)=\frac{276}{6}=46[/tex]5 will show 46 times.
Two lines intersect in the diagram shown below. 127° to What is the value of x? Hide All 37 53 127 D 217 O
x=127º
1) Since those angles x, and 127º share a common vertex we can state that these are Vertical Angles
2) Therefore they are congruent to each other. And we can state:
x = 127º as well.
Madison is in the business of manufacturing phones. She must pay a daily fixed cost of $400 to rent the building and equipment, and also pays a cost of $125 per phone produced for materials and labor. Make a table of values and then write an equation for C,C, in terms of p,p, representing total cost, in dollars, of producing pp phones in a given day.
I need the equation
Here is the completed table:
Number of phones manufactured Total cost of Manufactured phones
0 $400
1 $525
2 $650
3 $775
The equation that represents the total cost is C = $400 + $125p .
What is the total cost?The equation that represents the total cost is a function of the fixed cost and the variable cost. The fixed cost remains constant regardless of the level of output. The variable cost changes with the level of output.
Total cost = fixed cost + total variable cost
Total cost = fixed cost + (variable cost x total output)
C = $400 + ($125 x p)
C = $400 + $125p
Total cost when 0 phones are made = $400 + $125(0) = $400
Total cost when 1 phone are made = $400 + $125(1) = $525
Total cost when 2 phones are made = $400 + $125(2) = $650
Total cost when 3 phones are made = $400 + $125(3) = $775
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I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem is attached. These are 2 parts of the same question.
We are given the following triangle:
We need to determine the area of the triangle. To do that we need to determine sides "a" and "b". We will use the sine law to determine the side "b":
[tex]\frac{b}{sin107}=\frac{98}{sin48}[/tex]Now, we multiply both sides by "sin107":
[tex]b=sin(107)\frac{98ft}{sin(48)}[/tex]Solving the operations:
[tex]b=126.11ft[/tex]Now, before determining side "a" we will determine the angle "x" that is opposed to "a". To do that we will use the fact that the sum of the interior angles of a triangle is 180, therefore:
[tex]107+48+x=180[/tex]Adding the values:
[tex]155+x=180[/tex]Now, we subtract 155 from both sides:
[tex]\begin{gathered} x=180-155 \\ x=25 \end{gathered}[/tex]Therefore, the angle opposite to "a" is 25 degrees. Now, we apply the sine law:
[tex]\frac{a}{sin(25)}=\frac{98}{sin(48)}[/tex]Now, we multiply both sides by "sin(25)":
[tex]a=sin(25)\frac{98}{sin(48)}[/tex]Solving the operations:
[tex]a=55.73ft[/tex]Now, we determine the area using the following formula:
[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]Where:
[tex]s=\frac{a+b+c}{2}[/tex]Now, we determine the value of "s":
[tex]s=\frac{55.73ft+126.11ft+98ft}{2}[/tex]Solving the operation:
[tex]s=139.92ft[/tex]Now, we substitute the value in the formula for the area:
[tex]A=\sqrt{(139.92ft)(139.92ft-55.73ft)(139.92ft-126.11ft)(139.92ft-98ft)}[/tex]Solving the operations:
[tex]A=2611.43ft^2[/tex]Now, since the search party can cover 300 ft^2/h we can use a rule of 3 to determine the number of hours it takes them to cover 2611.43 ft^2:
[tex]\begin{gathered} 300ft^2\rightarrow1h \\ 2611.43ft^2\rightarrow x \end{gathered}[/tex]Now, we cross multiply:
[tex](300ft^2)(x)=(1h)(2611.43ft^2)[/tex]Now, we divide both sides by 300ft^2:
[tex]x=\frac{(1h)(2611.43ft^2)}{(300ft^2)}[/tex]Solving the operations:
[tex]x=8.7h[/tex]Therefore, it takes 8.7 hours to cover the area. Therefore, the search party won't be able to conclude before the sun goes down.
Use the given sets to find A∩B.A={2,4,6,8,10,12}B={7,9,11,13,14,15,16}
Recall that
[tex]A\cap B[/tex]is a set that consists of all the elements that are in both A and B.
From the given sets we get that the elements that are in both A and B are:
[tex]\text{None.}[/tex]Therefore, the intersection of the sets is the empty set.
Answer:
[tex]A\cap B=\emptyset.[/tex]