What are the x-intercepts (roots/ zeros)?

Answer:

-11,-1, square root of 5-13

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

0.80c

Step-by-step explanation:

'c' represents the original price.  20% off leaves 80% of c, which is the sales price:  0.80c

Answer:

276 degrees

Step-by-step explanation:

Angle <CBD

90 - 48 = 42 degrees

Corrisponding center angle = 84 degrees

m arc CAD

360 - 84 = 276 degrees

Answer: the one to the bottom right. The one under the red one.

Step-by-step explanation:

Hope this helps

the second one.

Step-by-step explanation:

sjisidjdododpdpddod

Answer:

[tex] \angle HIG \: and \: \angle KLI[/tex]

Step-by-step explanation:

[tex] \angle HIG \: and \: \angle KLI[/tex] are corresponding angles.

Answer:

75 vitamins = 18 dollars

Step-by-step explanation:

25 vitamins are equal 6 dollars

Answer:

$311.25

Step-by-step explanation:

Hope its right!   50/$12 divided by 6 = 2/$8.3 divided by 2 = 1/$4.15

1/$4.15 x 75 = 75/$311.25  I hope this is right if not im so sorry!

======================================================

Explanation:

The jump from CD = 2 to C'D' = 4 is "times 2". That must mean we go from BC = 3 to B'C' = 2*(BC) = 2*3 = 6. Therefore, x = 6.

-------

We could use a proportion to get the value of x as an alternative method:

(B'C')/(BC) = (C'D')/(CD)

x/3 = 4/2

2x = 3*4 ... cross multiply

2x = 12

x = 12/2 .... dividing both sides by 2

x = 6

Answer:

He can fit 11 ft^3

Step-by-step explanation:

Here, we want to get the volume it clothes that could fit into the two boxes

What we have to do here is to add the amount of space each of the box has to offer

Mathematically, we have this as;

7 ft^3 + 4 ft^3 = 11 ft^3

Answer:

tara and range

Step-by-step explanation:

Answer:

x=1+√13 or x=1−√13

Step-by-step explanation:

Step 1: Subtract 39 from both sides.

5x2−10x−21−39=39−39

5x2−10x−60=0

For this equation: a=5, b=-10, c=-60

5x2+−10x+−60=0

Step 2: Use quadratic formula with a=5, b=-10, c=-60.

x=

−b±√b2−4ac

2a

x=

−(−10)±√(−10)2−4(5)(−60)

2(5)

x=

10±√1300

10

x=1+√13 or x=1−√13

Answer:

Step-by-step explanation:

Rewrite this quadratic in standard form by subtracting 39 from both sides.  We get:

5x^2 - 10x - 60 = 0

Reduce this by dividing all four terms by 5:

x^2 - 2x - 12 = 0

Use the quadratic equation to find the roots.  The coefficients of the x terms are 1, -2, -12. Thus the discriminant is b^2 - 4ac, or:

(-2)^2 - 4(1)(-12)  = -44   of which 4 is a perfect square factor and 11 is not.

Because the discriminant is negative, the given equation has two unequal, complex roots, which are:

      -(-10) ± i√4√11

x = -----------------------

                10

or x = 1 ± (1/5)√11

Answer:

3+2 = 22 +30=  59 1/2

(x + c)2 = d or (x – c)2 = d. = (c * d)(x) = 4x^3 + 18x^2 - 10x

X=1+2

Step-by-step explanation:

sorry if wrong was every confused

Answer

25(x2−4)

Rewrite 4

as 22.25(x2−22)

Answer:

Area is: 17.25 because you multiply length * width

Answer:

[tex]7.5 \times 2.3 = \frac{69}{4} [/tex]

is it?

Answer:

I think the answer is d.)120

Answer:

Step-by-step explanation:

The idea here is to find the value for x and y, then add them together. See the pic I attached below. We will solve for side x first.

Side s is across from the reference angle of 48 degrees; side measuring 50 m is adjacent to the reference angle 48 degrees. Therefore, we will use the tangent ratio to solve for x:

[tex]tan48=\frac{x}{50}[/tex] and

50tan(48) = x so

x = 55.53m

Now we will do the same and solve for y. This time the reference angle is 28 degrees. Side y is opposite the reference angle and the side measuring 50 is adjacent to the reference angle, so we will use the tangent ratio again:

[tex]tan28=\frac{y}{50}[/tex] and

50tan(28) = y so

y = 26.59. Therefore,

x + y = 55.53 + 26.59 and

the height of the taller building is

82.1 m

Answer:

Hello! Sorry about your luck before although im 99% sure my answer is correct.

Answer: area is 180

Step-by-step explanation:

Ok so first starting off im going to calculate the area for each shape serperately and add them up since thats easier so as demonstrated in the picture the rectangle is 25 because i multiply by base × height and the base and height is 5 and 5 pointed in the picture so thats 25 although i didnt calculate the rest because the base and height is the same for each so we can just do 25 × 6 to get all the rectangles so 25 × 6 = 150 now we got the easy part out of the way now we should do the triangles I pointed to the base and height for that on the left the base being 5 and the height being 3 5 × 3 = 15 BUT WAIT this isn't are area for the triangles because when finding area for triangles we have to divide by 2 so... 15 ÷ 2 = 7.5 since there are 4 of those triangles I dont have to solve for the rest because i can just do 7.5 × 4 so...

7.5 × 4 = 30 now we just combine those areas together! so... 150 + 30 = 180 so 180 is our area HOPE THAT HELPS!

Answer: 50.4

Step-by-step explanation:

The area of a triangle is base multiplied by height, then divided by two.

8* 6.3= 50.4

since theres two triangles you don't divide it

Answer:

3 is the answer

Step-by-step explanation:

Mark brainliest

Given:

Two vectors are:

[tex]u=\left <0,6\right>[/tex]

[tex]v=\left <2,17\right>[/tex]

To find:

The projection of u onto v.

Solution:

Magnitude of a vector [tex]v=\left <a,b\right>[/tex] is:

[tex]|v|=\sqrt{a^2+b^2}[/tex]

Dot product of two vector [tex]v_1=\left <a_1,b_1\right>[/tex] and [tex]v_2=\left <a_2,b_2\right>[/tex] is:

[tex]v_1\cdot v_2=a_1a_2+b_1b_2[/tex]

Formula for projection of u onto v is:

[tex]Proj_vu=\dfrac{u\cdot v}{|v|^2}v[/tex]

[tex]Proj_vu=\dfrac{\left <0,6\right>\cdot \left <2,17\right>}{(\sqrt{2^2+17^2)^2}}\left <2,17\right>[/tex]

[tex]Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left <2,17\right>[/tex]

[tex]Proj_vu=\dfrac{0+102}{293}\left <2,17\right>[/tex]

On further simplification, we get

[tex]Proj_vu=\dfrac{102}{293}\left <2,17\right>[/tex]

[tex]Proj_vu=\left <\dfrac{102}{293}\cdot 2,\dfrac{102}{293}\cdot 17\right>[/tex]

[tex]Proj_vu=\left <\dfrac{204}{293},\dfrac{1734}{293}\right>[/tex]

Therefore, the projection of u onto v is [tex]Proj_vu=\left <\dfrac{204}{293},\dfrac{1734}{293}\right>[/tex].

Answer: 2

Hope this Helps!

The common difference of the given arithmetic sequence is 2.

The given arithmetic sequence is -17, -15, -13, .....

We need to find the common difference in the given arithmetic sequence.

A common difference is a difference between consecutive numbers in an arithmetic sequence. To find it, simply subtract the first term from the second term, or the second from the third, or so on...

Now, common difference=-15-(-17)=-15+17=2

-13-(-15)=-13+15=2

Therefore, the common difference of the given arithmetic sequence is 2.

To learn more about an arithmetic sequence visit:

https://brainly.com/question/12952623.

#SPJ2

Answer:

Two Real Solutions

Step-by-step explanation:

Use quadratic equation discriminant5t^2+3t-7=0

[tex]\sqrt{b^2-4ac} \\\sqrt{9-4*5*-7}\\\sqrt{149}\\discriminant>0 two real solutons[/tex]:

Since the discriminant is greater then 0, it two real solutions.

Answer:

B

Step-by-step explanation:

Answer:

4 is the gradient

Step-by-step explanation:

choose any two coordinate then apply the gradient equation

10-2= 8

3-1= 2

8/2= 4

4 is the gradient

Answer:

Below

Step-by-step explanation:

The answer I got was (-5/2, -9/2) but in your case the answer is:

(-2.5, -4.5)

Answer:

hello your question is incomplete attached below is the missing part

answer : Path C

Step-by-step explanation:

when a positively charged particle is launched past the fixed negatively charged particle in the attached diagram the most likely  Path that will be formed is "C".  and this is

Given that the launched charge is positive hence the field lines will point radially away from the point charge ( fixed negative charge )

Answer:

12.57

Step-by-step explanation:

V=πr^2 h/3

=π×2^2×3/3

Answer:

[tex]12.57\ ft^3[/tex]

Step-by-step explanation:

[tex]We\ are\ given,\\Radius\ of\ the\ base\ of\ the\ cone(r)=2\ feet\\Perpendicular\ height\ of\ the\ cone(h)=3\ feet\\Hence,\\We\ know\ that,\\Volume\ of\ a\ cone\ of\ perpendicular\ height\ h,\ and\ a\ base\ radius\ of\ r\ is:\\V=\frac{1}{3} \pi r^2h\\Here,\\Substituting\ r=2\ and\ h=3,\ we\ get:\\Volume\ of\ the\ given\ cone=\frac{1}{3}*\pi*(2)^2*3=\frac{\pi*4*3}{3}=\pi*4 \approx 12.57\ ft^3[/tex]