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Which expression is equivalent to 3x+10-x+12

Answers

Answer 1

Answer:

Step-by-step explanation:

3x-x+= 2x

10+ 12= 22

Answer - 2x+22


Related Questions

Which graph represents the solution 2x - 5y <3

Answers

Answer:

There is no picture... But here is a representation of the inequality on a graph

The graph 2x - 5y < 3 cut the x-axis at the point (3,0) and the y-axis at the point (0,-0.6).

What is inequality?

When two expressions are connected by a sign like "not equal to," "greater than," or "less than," it is said to be inequitable. The inequality shows the greater than and less than relation between variables and the numbers.

Given inequality is 2x - 5y <3. A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

When the inequality 2x - 5y < 3 is plotted on the graph it covers the region which is less than the line 2x - 5y < 3. The graph cut the x-axis at the point (3,0) and the y-axis at the point (0,-0.6).

The graph of the given inequality is attached with the answer below.

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Multiply. Write the answer in simplest form. 1/5 . 2/9

Answers

2/45 in simplest form

PLEASE HELP I WILL GIVE BRAINLEST!!

Answers

Answer:

8 1/8

Step-by-step explanation:

I used a calculator....

(hope this helps :P)

Add and
subtract fraction. X+5=23

Answers

X+5=23
23-5=x
18=x
Bdjxhdhdbhdudbsns

(11 - 3) x [ 15 + (10 - 5)] write 3 steps using pemdas

Answers

Answer:

160

Step-by-step explanation:

Which of the following is not true about the boundary line in the graph of a linear inequality in two​ variables?
A. The points on the boundary line are always solutions to the linear inequality.
B. The boundary line separates the ordered pair solutions to the inequality from the ordered pairs that are not solutions to the inequality.
C. A solid line is used when the inequality is​ non-strict ​( ≤ or ≥ ​).
D. A dashed line is used when the inequality is strict ​( < or > ​)

Answers

D. A dashed line is used when the inequality is strict ​( < or > ​)

A linear inequality in two variables is obtained by taking a linear equation in two variables, and replacing the equality sign with any one of the four inequality signs: <,>,=<,>=.

The graphed region of points satisfying the inequality is always half of the plane bounded by the corresponding line.

When the inequality is [tex]\leq[/tex] or [tex]\geq[/tex], the line is included. Otherwise, the line is excluded.

So, A dashed line is used when the inequality is strict ​( < or > ​) is not true about the boundary line in the graph of a linear inequality in two​ variables

Therefore, the correct option is D.

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Subtract 3x^2+8x3x 2 +8x from -9x^2+3x-8−9x 2 +3x−8.

Answers

Answer:

x =(-8+√-32)/6=(-4+2i√ 2 )/3= -1.3333+0.9428i

Step-by-step explanation:

Classify each statement about the function f(3) = 323 +6 as true or false.

Answers

Answer:

true.

false

true.

false.

Step-by-step explanation:

1. The domain (x-value) of a function is (-∞, +∞) unless there is some reason for it not to be. No matter what we make x, we do not wind up with something forbidden in the real-number coordinate plane, like a zero denominator or a square root of a negative number, so the domain for x is all real numbers. True.

2. The statement says the range (the y-value) of the function must always be more than zero. There is no particular reason to belive that. If x = -10, then x³ + 6 = -1000 + 6 = -994, which is less that zero. False.

3. We get the y-intercept by making x equal zero. In tha case y = 0³ + 6 = 6. The y-intercept always has an x-coordinate of zero, so the point is (x, y) = (0, 6). True.

4. If a function has symmetry about the origin point, then replacing y with -y and x with -x will get you an equation equivalent to the original. let's try it.

-y = 3(-x)³ + 6    now lets see what happens it we let x = 2

For the original equation:   y = 3(2)³ + 6 = 3(8) + 6 = 24 + 6 = 30

Now we try the test equation:  -y = 3(-2)³ + 6 = 3(-8) + 6 = -24 + 6 = -18

                                               So   -y = -18

                                                So    y = 18

The first equation and the test equation are not equivalent, as they do not yield the same results for the same value of x.

Thus, the origin is not a point of symmetry. False.

I am attaching a picture of this function's graph so you can see the actual point of symmetry is (0, 6), which is also the y-intercept. I made it on Desmos dot com, which is free for everyone.

The Domain  = (-∞, ∞) and Range = (-∞, ∞), y-intercept occurs at (0, 6) and the origin is not a point of symmetry.

Domain, range, and y-intercept

Given the function [tex]f(x)=3x^3 + 6[/tex]

Domain and range are the value of input and output that the function exists.

For the given function, the domain and range exist on all real numbers.

Domain  = (-∞, ∞) and Range = (-∞, ∞)

The y-intercept occur at (x) = 0

g(0)= 3(0)^3 + 6

g(0) = 6

Hence the Domain  = (-∞, ∞) and Range = (-∞, ∞), y-intercept occurs at (0, 6) and the origin is not a point of symmetry. False.

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Katy invests £200 000 in a savings account for 4 years. The account pays compound interest
at a rate of 1.5 % per annum.
Calculate the total amount of interest Katy will get at the end of 4 years

Answers

Answer:

212272.71

Step-by-step explanation:

we have the following equation (for interesting that compound yearly)

PV(1+i)^n

200000(1+.015)^4

212272.71

The total amount of interest Katy will get at the end of 4 years is £12,272.71

Compound interestCompound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on principal plus interestCompound interest refers to the phenomenon whereby the interest associated with a bank account, loan, or investment increases exponentiallyrather than linearlyover time.Compound interest (or compounding interest) is the interest on a loan or deposit calculated based on both the initial principal and the accumulated interest from previous periods

How to solve this problem?

The steps are as follow:

Given:

p = £200 000

r = 1.5%

n = 4 years

Formula to find Amount (A) after 4 years will as follow:

A = p(1+r/100)ⁿ

A = 200000(1+1.5/100)⁴

A = 212,272.71 £

The compound interest is given by:

C.I. = A - p

C.I. = 212,272.71 - 200,000

C.I. = £12,272.71

So the  total amount of interest Katy will get at the end of 4 years is £12,272.71

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Starting at a fixed time, each car entering an intersection is observed to see whether it turns left (L), right (R), or goes straight ahead (A). The experiment terminates as soon as a car is observed to turn left. Let X = the number of cars observed. What are possible X values? List five different outcomes and their associated y values.

Answers

Answer:

Outcomes are { L, RL, AL, RAL, ARL }

Associated X values are { 1, 2, 2, 3, 3 }

Step-by-step explanation:

As given,

left  = (L),

right = (R)

goes straight ahead  = (A)

Now,

The Sample space become = { L, RL, AL, RAL, ARL }

In L -

Number of cars = 1

In RL-

Number of cars = 2

In AL-

Number of cars = 2

In RAL-

Number of cars = 3

In ARL-

Number of cars = 3

40 points please help!! I will mark brainliest! Random answers will be reported

Answers

Answer:

B. Yes, SAS

Step-by-step explanation:

Given

PS ≅ RQPR ≅ RP∠SPR ≅ ∠QRP

The two sides and the included angle - SAS

Correct option is

B. Yes, SAS

SOMEONE HELP I NEED TO PASS

Answers

number 3 is y - 9 = 3/7 • (x + 6)

A tank is filled with 1000 liters of pure water. Brine containing 0.08 kg of salt per liter enters the tank at 6 liters per minute. Another brine solution containing 0.09 kg of salt per liter enters the tank at 5 liters per minute. The contents of the tank are kept thoroughly mixed and the drains from the tank at 11 liters per minute.
A. Determine the differential equation which describes this system. Let SG) denote the number of kg of salt in the tank after t minutes. Then ds/dt=_____.
B. Solve the differential equation for S(t).

Answers

Answer:

The answer is below

Step-by-step explanation:

Let s(t) represent the amount of salt in the tank at time t. Therefore:

ds / dt = (rate of salt flowing into the tank) - (rate of salt going out of the tank)

[tex]\frac{ds}{dt}=[(0.08\ kg/L*6\ L/min)+(0.09\ kg/L*5\ L/min)]-(\frac{s\ kg}{1000\ L}*11\ L/min ) \\\\\frac{ds}{dt}=(0.48\ kg/min+0.45\ kg/min)-(\frac{11s}{1000}\ kg/min )\\\\\frac{ds}{dt}=0.93\ kg/min-\frac{11s}{1000}\ kg/min \\\\\frac{ds}{dt}=\frac{930-11s}{1000}\ kg/min \\\\\frac{ds}{930-11s}=\frac{1}{1000}dt\\\\Integrating:\\\\\int\limits { \frac{ds}{930-11s}} \, ds=\int\limits {\frac{1}{1000}} \, dt\\\\-\frac{1}{11}ln(930-11s)=\frac{t}{1000}+C\\\\multiply\ through\ by\ -11:[/tex]

[tex]ln(930-11s)= - \frac{11t}{1000}+A\\\\Take \ exponential:\\\\930-11s=e^{ - \frac{11t}{1000}+A}\\\\930-11s=C_1e^{ - \frac{11t}{1000}}\\\\11s=930-C_1e^{ - \frac{11t}{1000}}\\\\s=\frac{930-C_1e^{ - \frac{11t}{1000}}}{11} \\\\To \ find\ C_1,s(0)=0.Hence:\\\\0=\frac{930-C_1e^{ - \frac{11(0)}{1000}}}{11} \\\\0=930-C_1\\\\C_1=930\\\\s(t)=\frac{930-930e^{ - \frac{11t}{1000}}}{11} \\\\s(t)=930(\frac{1-e^{ - \frac{11t}{1000}}}{11})[/tex]

A) So, the required value is [tex]1.01-\frac{11S}{1000}[/tex].

B) The required value is [tex]\frac{1010}{11} (1-e^{-11/1000t} )[/tex]

Differential Equation:

A differential equation is an equation that contains one or more terms and the derivatives of one variable (i.e., dependent variable) with respect to the other variable (i.e., independent variable).

                                                    [tex]\frac{dy}{dx} =f(x)[/tex]

(A) Let [tex]S(t)[/tex] denotes the number of kg of the salt in the tank at the time [tex]t[/tex] minutes.

Then,

[tex]\frac{ds}{dt}=[/tex](rate of salt in to tank)-(rate of salt of tank)

[tex]\frac{ds}{dt}=\left ( 0.08\times 0.09\times 5 \right )-\left ( \frac{s\left (t\right )}{1000}\times 11 \right ) \\ \therefore \frac{ds}{dt}=1.01-\frac{11S}{1000}[/tex]

(B)

[tex]\frac{ds}{dt}=\frac{101}{100}-\frac{11S}{1000} \\ \Rightarrow \frac{ds}{dt}=\frac{1010-11S}{1000} \\ \Rightarrow \frac{ds}{1010-11S}=\frac{dt}{1000}[/tex]

Integrating we get,

[tex]-\frac{1}{11}I_n|1010-11S|=\frac{t}{1000}+In \ C_1 \\ \Rightarrow 1010-11S=C_1e^{-11/1000t} \\ S(t)=\frac{1010-C_1e^{-11/1000t}}{11}[/tex]

Initially, [tex]S(0)=0\\\Rightarrow C_1=1010[/tex]

Then the required solution is,

[tex]\therefore S(t)=\frac{1010}{11} (1-e^{-11/1000t} )[/tex]

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5
B
C
Find the composition of
transformations that
map ABCD to EHGF.
Reflect over the [? ]-axis,
then translate
(x+[ ], y+[ ]).
Note: Enter x ory for axis.
4
3
2
D
H
4
813
2
1
0
4
6
7

Answers

Answer:

Step-by-step explanation:

Reflect over the Y axis, then translate (x+[-2], y+[-3])

The composition of transformations that map ABCD to EHGF will be [(x + 6), (y + 1)].

What is geometric transformation?

Change is referred to as transformation. As a result, a geometric transformation entails making modifications to any geometric shape.

Vertices of the quadrilateral ABCD having coordinate A,B,C,D are  (-5, 2),(-3, 4), (-2, 4),(-1, 2) respectively.

The image quadrilateral A'B'C'D' is formed by reflecting the supplied quadrilateral ABCD across the x-axis.

The rule for a point's reflection across the x-axis is:

(x, y) → (x , -y)

The picture point A' coordinates will be,

A(-5, 2) → A'(-5, -2)

Point E is produced by translating point A', as shown in the diagram. The rule for translating a point by h units right and k units up is as follows:

A'(x+h, y+k) → E(x', y')

By comparing coordinates of A' and E,

-5 + h = 1

h = 6

-2 + k = -1

k = 1

That is to say, the translation rule will be:

[(x + 6), (y + 1)]

Hence, the composition of transformations that map ABCD to EHGF will be [(x + 6), (y + 1)].

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Plz, Help me! I will give a point if you help answer! with 5 star rating, Thanks, and Brainliest!

Answers

Answer:

-4/10+(-7/10)= -1 1/10(the bottom left one)

Step-by-step explanation:

starts from 0 and subtract 4/10.  From there you subtract 7/10 more.

Which equation is not a polynomial.

A.-sqrt(2)
B.-3x^2+xy-2y^2
C.x^/y +3xy -2y^2/x
D.sqrt(2a^2)-4xy-2x^2y^2
E.5x^-2 +x^-1 y-2

Answers

A. -sqrt(2)

Explanation:
there are no degrees, etc

Click here to read aloud.
A rocking horse has a weight limit of 60 pounds.

What percentage of the weight limit is 33 pounds?
What percentage of the weight limit is 114 pounds?
What weight is 95% of the limit?
please answer asap with explanation qwq

Answers

Answer:

1. 55%

2. 190%

Step-by-step explanation:

1a. set up an expression.

33/60 = x/100

33 out of 60 is the 33 pounds out of the 60 weight limit. The x is what you're solving for, and the 100 is the given percent, because the percent is always going to be out of 100%.

1b. do cross multiplication; so do 33*100, which equals 3300

1c. divide; 3300 divided by 60, which equals 55.

For the second problem, do the same thing. your expression should be 114/60 = x/100

Find the rate of change in a table

Answers

Answer:

excuss me where the picture

Step-by-step explanation:

There’s no picture? There’s no table how to u find the rare of change without the table

is 25/4 a rational number

Answers

Answer:

No.

Because,24/4=5.25

Answer:

Yes

Step-by-step explanation:

All rational numbers have endings. Since 25/4=6.25 it is rational

what is 550 x 34 ?????

Answers

Answer:

18,700

Step-by-step explanation:

Answer:

18,700

Step-by-step explanation:

i hope this helps


Order of operations. Need to find the unknown number. Help?

8 + 2 x 5 = m
9 - 7 + 2 = k
7 x 8 - 6 = g
16 + 4 divide 2 = s
12 - 6 divide 2 = y
36 divide 6 + 13 = f

Answers

Answer:

m = 18

k = 4

g = 50

s = 18

y = 9

f = 19

Step-by-step explanation:

M = 18
K = 4
G = 42
S = 18
Y = 9
F = 19

HELP NOWWWWW PLEASEEEEE
How many 1/3's are in 1 and 2/3?

Answers

Answer:

5 thirds

Step-by-step explanation:

Make 1 2/3 into a improper fraction. Now you have 5/3. 5/3-(1/3*5)=0

Therefore, 5x1/3=5/3=1 2/3

Answer:

This guy is wrong. 1 2/3 is equal to 5/3. But that is not the answer(like that dummy above said)

The Question is asking "How many 1/3's are in 1 2/3" (5/3)

The answer is 5, not 5/3's.

Which expression is equivalent to – 12 + (-4/5) + 31 and includes the correct justification for the equivalence?

Answers

Answer:

b

Step-by-step explanation:

Please answer ASAP!!!!!!!

Answers

Answer:

B is the correct answer

Step-by-step explanation:

just did this problem

Mr. Quick bought a new computer system. The regular price was $1850, but he got a 15% discount. How much did he pay?

Answers

He paid $1572.50 before tax

Answer:

the price Mr. Quick paid is=$1343

 

I think I can help you with this

you can easily solve this by using a rule of three

Step one

find the discount value  if

$1580⇒  100%

$x? ⇒ 15%

do the relation

the discount is $237

the price Mr. Quick paid is

the price Mr. Quick paid is=regular price - discount

the price Mr Quick paid is=$1580-$237

the price Mr Quick paid is=$1343

I hope it helps, Have a great day!!! :)

Step-by-step explanation:

Help&EXPLAIN

Don’t use for points or will be reported and I’ll take the points back

Answers

Answer:

105

Step-by-step explanation:

A straight line is 180 degrees so 180-75=105

Answer:

x= 105 degrees

Step-by-step explanation:

We know that the sum of x and 75 degrees is equal to 180 degrees.

So that means that x= 180-75 or x=105 degrees


anyone?............

Answers

[tex] \frac{132 }{2?} = 66[/tex]


You randomly draw a marble from a bag of marbles that contains 3 blue marbles, 4 green marbles, and 5 red
marbles.
What is P(draw a blue marble)?

Answers

1/4 of a chance to draw a blue marble
You have 1/4 chance to draw blue.

There are 3 blue marbles out of 12 marbles total which is 3/12. Simplify this and it equals 1/4.

I hope this explanation helps you understand this problem better.

Kevin has 1,066 trading cards. Each album holds 26 cards. How many albums does Kevin need to hold all his cards?

Answers

Answer:

41

Step-by-step explanation:

Ok so you would divide 1,066 by 26 which would equal 41. Have a great day!

If $700 is invested in an account that pays 3% compounded annually, the total amount, A(t), in the account after t years is Ant 700(1.03)^t.

Required:
a. Find the average rate of change per year of the total amount in the account for the first four years of the investment (from t= 0 to t= 4).
b. Find the average rate of change per year of the total amount in the account for the second four years of the investment (from t=4 to t=8)
c. Estimate the instantaneous rate of change for t =4.
d. The average rate of change per year of the total amount in the account for the first years of the investment â(from t= 0 to t=4â) is ___________â$
e. The average rate of change per year of the total amount in the account for the second years of the investment â(from t= 0 to t=4â) is_____________ â$
f. The instantaneous rate of change for t=4 is about â$_____________

Answers

Answer:

21.96 ; 24.72

Step-by-step explanation:

Given that :

Give the equation:

A(t) = 700(1.03)^t

A.)

Average rate of change over the first 4 years ;

(t=0 to t=4)

At t = 0

A(0) = 700(1.03)^0 = 700

A(1) = 700(1.03)^1 = 721

A(2) = 700(1.03)^2 = 742.63

A(3) = 700(1.03)^3 = 764. 9089

A(4) = 700(1.03)^4 = 787.856167

[(721 - 700) + (742.63 - 721) + (764.9089 - 742.63) + (787.856167 - 764.9089)] / 4

= 87.856167 / 4

= 21.96404175

= 21.96

Over the 2nd 4 years :

A(4) = 700(1.03)^4 = 787.856167

A(5) = 700(1.03)^5 = 811.49185201

A(6) = 700(1.03)^6 = 835.8366075703

A(7) = 700(1.03)^7 = 860.911705797409

A(8) = 700(1.03)^8 = 886.73905697133127

[(811.49185201 - 787.856167) + (835.8366075703 - 811.49185201) + (860.911705797409 - 835.8366075703) + (886.73905697133127 - 860.911705797409)] / 4

= 98.88288997133127 / 4

= 24.72

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