Which graph represents the function of f(x) = 9x^2 – 36/3x+6?

Answer:

220 units

Step-by-step explanation:

ER = ET = 33   tangents from same poiint

DE = 59 => DS = DR = 59-33 = 26

DC = 77 => CR =CT = 77-26 = 51

Perimeter

= 2 *( ES + DR + CT )

= 2* (33 + 26 + 51)

= 220

Credit and thanks to ValerieUlbrich.  :)

Answer:

48 wings

Step-by-step explanation:

12:3 is the ratio. So multiply both of it by 4. Then it would be 48:12

Answer:

48 chicken wings

Step-by-step explanation:

If Bao can eat 12 chicken wings in 3 minutes and 12 minutes is 3 minutes times 4, then the answer would be 12 chicken wings times 4, so 12 times 4, which is 48, so the answer would be 48 chicken wings.

Answer:

108

Step-by-step explanation:

Answer: Center D I think

Step-by-step explanation:

Answer:

A.

Step-by-step explanation:

Anwer A has the following equation:

[tex]g(x)=\frac{3}{5}x^2-3[/tex]

In this equation, we can calculated the intercept replacing x by 0, as:

[tex]g(x)=\frac{3}{5}0^2-3=-3[/tex]

if this is the answer, the graph of g(x) should be through the point (0,-3) and that happens.

Additionally, the roots of the equations are calculated replacing g(x) by 0 and solving for x, so:

[tex]0=\frac{3}{5}x^2-3\\x_1=\sqrt{5}=2.236\\x_2=-\sqrt{5}=-2.236[/tex]

It means that the graph of g(x) should be through the points (2.236,0) and (-2.236,0) and that happens too.

So, the answer is A, [tex]g(x)=\frac{3}{5}x^2-3[/tex]

Answer:

According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.

Step-by-step explanation:

Let consider a second-order polynomial of the form [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex], [tex]\forall \,x \in\mathbb{R}[/tex]. The procedure is presented below:

1) [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex] (Given)

2) [tex]a\cdot x^{2} + b \cdot x = -c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)

3) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x = -4\cdot a \cdot c[/tex] (Compatibility with multiplication)

4) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x + b^{2} = b^{2}-4\cdot a \cdot c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)

5) [tex](2\cdot a \cdot x + b)^{2} = b^{2}-4\cdot a \cdot c[/tex] (Perfect square trinomial)

According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.

Answer: D

Step-by-step explanation:

EDGE 2023

Answer:

Option B

Step-by-step explanation:

As shown in the picture, g(x) is the red one which can be obtained by translating f(x) - the blue one toward +x-axis direction 4 units.

=> g(x) = f(x) + 4 = |x| + 4

Answer: Choice D

g(x) = |x-4|

=================================================

Explanation:

Replacing x with x-4 shifts the xy axis four units to the left. If we fix the blue V shape to not move while the xy axis does move, then it gives the illusion of the V shape moving 4 units to the right to end up producing the red curve.

You can use a table of values to compare the two functions or you could use a graphing tool to confirm the answer.

--------

Extra info:

Choice A will move the blue graph 4 units down

Choice B will move the blue graph 4 units up

Choice C will move the blue graph 4 units to the left

Answer:

8/9

Step-by-step explanation:

2/3 + 1 / ( 2 2/5) - 1/x = 1/3 -  1 / ( 2 2/3)

Changing to improper fractions

2 2/5 = ((5*2+2) / 5 = 12/5

2 2/3 = ( 3*2+2) /3 = 8/3

2/3 + 1 / ( 12/5) - 1/x = 1/3 -  1 / ( 8/3)

1 over and improper fraction flips the improper fraction  1 / ( a/b) = b/a

2/3 + 5/12 - 1/x = 1/3 -3/8

Subtract 2/3 from each side

5/12 -1/x = 1/3 -2/3 -3/8

5/12 -1/x =  -1/3 -3/8

Subtract 5/12 from each side

-1/x =  -1/3 -3/8-5/12

Multiply each side by 24 to get rid of the fractions

-24/x = -24/3 -3*24/8 -5*24/12

-24/x = -8 -9 -10

-24/x = -27

Multiply each side by x

-24 = -27x

Divide by -27

-24/-27 =x

8/9 =x

Answer:

N = 33

Step-by-step explanation:

N = D + 19

.05N + .10 D = 3.05

N = 33

D = 14

Answer:

here you go :)

Step-by-step explanation:

You would take 20% of $22.50 (22.5 multiplied by .2). You would get $4.50 off of the book with the discount. So you would subtract 4.5 from 22.5 and get $18. Then you would take 10% of $18 for the sales tax. (18 multiplied by .1). You would get $1.80 towards sales tax. you would then add $1.80 to $18 and get $19.80.

Answer:

∠A=123°.

Step-by-step explanation:

From the given figure it is clear the CD and CE are two tangent lines on circle with center A.

Radius is perpendicular to the tangent at the point of tangency.

[tex]\angle ADC=90^{\circ}[/tex]

[tex]\angle AEC=90^{\circ}[/tex]

Smaller arc DE = (5x-2)°

It means central angle DAE is (5x-2)°.

[tex]\angle DAE=(5x-2)^{\circ}[/tex]

Now, ADCE is a quadrilateral and sum of all angles of a quadrilateral is 360 degrees.

[tex]\angle ADC+\angle DCE+\angle AEC+\angle DAE=360^{\circ}[/tex]

[tex]90^{\circ}+(2x+7)^{\circ}+90^{\circ}+(5x-2)^{\circ}=360^{\circ}[/tex]

[tex](7x+5)^{\circ}+180^{\circ}=360^{\circ}[/tex]

[tex](7x+5)^{\circ}=360^{\circ}-180^{\circ}[/tex]

[tex](7x+5)^{\circ}=180^{\circ}[/tex]

[tex]7x+5=180[/tex]

[tex]7x=175[/tex]

[tex]x=25[/tex]

The value of x is 25.

[tex]\angle A=5x-2=5(25)-2=125-2=123^{\circ}[/tex]

Therefore, the measure of ∠A is 123°.

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

Answer:

[tex]2\sqrt{14\\}[/tex] = q

Step-by-step explanation:

use geometric mean method

4/s = s/10

s^2 = 40

s = 2[tex]\sqrt{10}[/tex]

consider the triangle STR and using the Pythagorean theorem

[tex]s^{2} +16 = q^{2} \\[/tex]

[tex](2\sqrt{10})^{2} +16 = q^{2}[/tex]

40 + 16 = q^2

56 = q^2

[tex]2\sqrt{14\\}[/tex] = q

Answer:

B. 14

Step-by-step explanation:

22/x = 11/(21-x)

462 - 22x = 11x

462 = 33x

x = 14

Answer: The value of x is 14, answer choice B

Let y be the other line segment connected to x

Using proportions:

[tex]\dfrac{11}{22}=\dfrac{y}{x}[/tex]

Cross multiply and simplify

[tex]22y=11x[/tex]

[tex]y=\dfrac{1}{2}x[/tex]

We know that x and y add to 21, so we can create the following equation:

[tex]x+y=21[/tex]

Substitute y=(1/2)x

[tex]x+\dfrac{1}{2}x=21[/tex]

Simplify by adding like terms

[tex]\dfrac{3}{2}x=21[/tex]

Divide both sides by 3/2

[tex]x=14[/tex]

Let me know if you need any clarifications, thanks!

Answer:

The ratio of the volume of the larger sphere to the volume of the smaller sphere is

Step-by-step explanation:

Volume of a sphere is

[tex] \frac{4}{3} \pi {r}^{3} [/tex]

Where r is the radius

radius = diameter / 2

For First sphere

diameter = 8yards

radius = 8 / 2 = 4 yards

Volume of first sphere is

[tex] \frac{4}{3} \pi( {4})^{3} \\ \\ = \frac{256}{3} \pi \: {yd}^{3} [/tex]

For second sphere

diameter = 1064 yards

radius = 1064 / 2 = 532 yards

Volume of second sphere is

[tex] \frac{4}{3} \pi( {532})^{3} \\ \\ = \frac{602275072}{3} \pi \: {yd}^{3} [/tex]

Since the volume of the second sphere is the largest

Ratio of the second sphere to the first one is

[tex] \frac{602275072}{3} \pi \div \frac{256}{3} \pi \\ \\ = \frac{602275072}{3} \pi \times \frac{3}{256} \pi \\ \\ = \frac{602275072}{256} \\ \\ = \frac{ 2352637}{1} \\ \\ = 2352637: 1[/tex]

Hope this helps you

Divide the two numbers to find the ratio:

400 / 1200 = 1/3

The ratio is 1:3

Answer:

B

Step-by-step explanation:

Gear A has 400 teeth.

Gear B has 1200 teeth.

Write as a ratio of gear A to gear B.

400:1200

Simplify the ratio.

4:12

1:3

Answer:  A) 1       B) [tex]\sqrt5[/tex]

Step-by-step explanation:

[tex]A)\quad \dfrac{2\sqrt3}{\sqrt{12}}=\dfrac{2\sqrt3}{2\sqrt3}=1\\\\\\\\B)\quad \dfrac{5\sqrt7}{\sqrt{35}}=\dfrac{5\sqrt7}{\sqrt5\cdot \sqrt7}=\dfrac{5}{\sqrt5}\bigg(\dfrac{\sqrt5}{\sqrt5}\bigg)=\dfrac{5\sqrt5}{5}=\sqrt5[/tex]

Step-by-step explanation:

-3x² + 2y² + 5xy -2y + 5x² - 3y²

= -3x² + 5x² +2y² -3y² + 5xy -2y

= 2x² - y² +5xy -2y

2 terms

Answer:

[tex] d = 123 [/tex]

Step-by-step explanation:

The given figure above is an inscribed quadrilateral with all four vertices lying on the given circle, thereby forming chords each.

Therefore, the opposite angles of the above quadrilateral are supplementary.

This means:

[tex] c + 31 = 180 [/tex] , and

[tex] d + 57 = 180 [/tex]

Find the measure of d:

[tex] d + 57 = 180 [/tex]

Subtract 57 from both sides.

[tex] d + 57 - 57 = 180 - 57 [/tex]

[tex] d = 123 [/tex]

Answer:

The function has two real roots and crosses the x-axis in two places.

The solutions of the given function are

x = (-0.4495, 4.4495)

Step-by-step explanation:

The given quadratic equation is

[tex]G(x) = -x^2 + 4x + 2[/tex]

A quadratic equation has always 2 solutions (roots) but the nature of solutions might be different depending upon the equation.

Recall that the general form of a quadratic equation is given by

[tex]a^2 + bx + c[/tex]

Comparing the general form with the given quadratic equation, we get

[tex]a = -1 \\\\b = 4\\\\c = 2[/tex]

The nature of the solutions can be found using

If [tex]b^2- 4ac = 0[/tex] then we get two real and equal solutions

If [tex]b^2- 4ac > 0[/tex] then we get two real and different solutions

If [tex]b^2- 4ac < 0[/tex] then we get two imaginary solutions

For the given case,

[tex]b^2- 4ac \\\\(4)^2- 4(-1)(2) \\\\16 - (-8) \\\\16 + 8 \\\\24 \\\\[/tex]

Since 24 > 0

we got two real and different solutions which means that the function crosses the x-axis at two different places.

Therefore, the correct option is the last one.

The function has two real roots and crosses the x-axis in two places.

The solutions (roots) of the equation may be found by using the quadratic formula

[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]

[tex]x=\frac{-(4)\pm\sqrt{(4)^2-4(-1)(2)}}{2(-1)} \\\\x=\frac{-4\pm\sqrt{(16 - (-8)}}{-2} \\\\x=\frac{-4\pm\sqrt{(24}}{-2} \\\\x=\frac{-4\pm 4.899}{-2} \\\\x=\frac{-4 + 4.899}{-2} \: and \: x=\frac{-4 - 4.899}{-2}\\\\x= -0.4495 \: and \: x = 4.4495 \\\\[/tex]

Therefore, the solutions of the given function are

x = (-0.4495, 4.4495)

A graph of the given function is also attached where you can see that the function crosses the x-axis at these two points.

Answer:

[tex]2ab - 6a + 5b - 15[/tex]

Step-by-step explanation:

Given

[tex]2ab - 6a + 5b + \_[/tex]

Required

Fill in the gap to produce the product of linear expressions

[tex]2ab - 6a + 5b + \_[/tex]

Split to 2

[tex](2ab - 6a) + (5b + \_)[/tex]

Factorize the first bracket

[tex]2a(b - 3) + (5b + \_)[/tex]

Represent the _ with X

[tex]2a(b - 3) + (5b + X)[/tex]

Factorize the second bracket

[tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]

To result in a linear expression, then the following condition must be satisfied;

[tex]b - 3 = b + \frac{X}{5}[/tex]

Subtract b from both sides

[tex]b - b- 3 = b - b+ \frac{X}{5}[/tex]

[tex]- 3 = \frac{X}{5}[/tex]

Multiply both sides by 5

[tex]- 3 * 5 = \frac{X}{5} * 5[/tex]

[tex]X = -15[/tex]

Substitute -15 for X in [tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]

[tex]2a(b - 3) + 5(b + \frac{-15}{5})[/tex]

[tex]2a(b - 3) + 5(b - \frac{15}{5})[/tex]

[tex]2a(b - 3) + 5(b - 3)[/tex]

[tex](2a + 5)(b - 3)[/tex]

The two linear expressions are [tex](2a+ 5)[/tex] and [tex](b - 3)[/tex]

Their product will result in [tex]2ab - 6a + 5b - 15[/tex]

Hence, the constant is -15

Answer:

The surface area of the pyramid is 80.9 cm²

Step-by-step explanation:

The side length, s of the cube is given as 5 cm

Therefore, the largest pyramid that can fit into the cube will have a base side length, s = The side length of the cube = 5 cm

The height, h of the largest pyramid = The height of the cube = 5 cm.

The surface area of a pyramid =  Area of base, A + 1/2 × Perimeter of base, P × Slant height, S

The slant height of the pyramid = √(h² + (s/2)²) = √(5² + (5/2)²) = (5/2)×√5

The perimeter of the base = 4×5 = 20 cm

The area of the base = 5×5 = 25 cm²

The surface area of a pyramid = 25 + 1/2×20×(5/2)×√5 = 80.9 cm².

The surface area of a pyramid =  80.9 cm².

Answer:

put it in a calculator, 8,000 times whatever number u need

The graph of y=2x^2-8x+15 has no x-intercepts.

Answer:

40.08%

Step-by-step explanation:

From the given information;

the annual interest rate can be determined using the formula:

[tex]A =P \times( 1+ \dfrac{r}{n})^{nt}[/tex]

where;

A = amount

P is the installment per period = $625

r = interest rate

nt = number of installments=  14×(12) =168

i = rate of interest per year

[tex]156700 = 625 \times( 1+ \dfrac{r}{12})^{168}[/tex]

[tex]\dfrac{156700}{625} = {(1+ \dfrac{r}{12})^{168}[/tex]

[tex]250.72 = {(1+ \dfrac{r}{12})^{168}[/tex]

[tex]\sqrt[168]{250.72} = {(1+ \dfrac{r}{12})[/tex]

1.0334 = [tex]{(1+ \dfrac{r}{12})[/tex]

1.0334 -1 = r/12

0.0334 = r/12

r = 0.0334 × 12

r = 0.4008

r = 40.08%

Thus; Karla Harby received an interest rate of 40.08%

Answer:

C. Fertility= Nutrients * Moisture / Pollutant

Step-by-step explanation:

F=NM/P

F= Fertility of the soil

N= Amount of nutrients in the soil

M= Amount of moisture in the soil

P= Amount of pollutant in the soil

F=NM/P

Fertility of the soil

= Amount of nutrients in the soil * Amount of moisture in the soil / Amount of pollutant in the soil

Fertility= Nutrients * Moisture / Pollutant

Option C is the correct answer

Answer:

x = 1

Step-by-step explanation:

Given

[tex]\frac{1}{2}[/tex] : [tex]\frac{2}{3}[/tex] = [tex]\frac{3}{4}[/tex] : x

Multiply all parts by 12 to clear the fractions

6 : 8 = 9 : 12x , simplifying

3 : 4 = 3 : 4x

Thus

4x = 4 ( divide both sides by 4 )

x = 1

Answer:

Option (A)

Step-by-step explanation:

Two bases of the the given cylinder are circular in shape in the given picture.

When we take a cross-section of the cylinder parallel to the bases or perpendicular to the height, we get a circle exactly same as the bases (As shown on the rectangular slide).

Cross-section will have the same radius as the bases of the cylinder.

Therefore, Option (A) will be the answer.

Answer:

The correct answer is 50.6195

Step-by-step explanation:

The probability that only girls bought lunches is given as D. 50%

To find the probability that only girls bought lunches, we solve:

We can see that the total number of girls is 30 and the total number of both boys and girls is 60

So, to solve, it becomes:

30/60= 50%

Probability is a mathematical concept used to measure the likelihood of an event occurring, ranging from 0 (impossible) to 1 (certain), and is calculated using ratios, frequencies, or subjective judgments.

Read more about probability here:

https://brainly.com/question/23417919

#SPJ2

Answer:

1. 44 + 3x

2. 2y - 8

3. x - 6

15. [tex]5\frac{7}{8}[/tex]

16. [tex]6\frac{1}{3}[/tex]

17. [tex]3\frac{7}{9}[/tex]

Step-by-step explanation:

1. 7² + 2² - 5 - 4 + 3x

   49 + 4 - 5 - 4 + 3x

       53 - 5 - 4 + 3x

           48 - 4 + 3x

              44 + 3x

2. - y - 5 + y + 2(2y-y) - 3

     -y - 5 + y + 4y - 2y -3

      -y - 5 + 5y - 2y - 3

          4y - 2y - 5 - 3

                2y - 8

3. 5x -3 - x - 3(x + 1²)

    5x - 3 - x - 3x - 3

      4x - 3x - 3 -3

           x - 3 -3

             x - 6

15.  [tex]7\frac{1}{4} - 1\frac{3}{8}[/tex]

   = [tex]7 \frac{2}{8} - 1\frac{3}{8}[/tex]

   = [tex]\frac{58}{8} - \frac{11}{8}[/tex]

   = [tex]\frac{47}{8}[/tex] → [tex]5\frac{7}{8}[/tex]

16.  [tex]9 - 2\frac{2}{3}[/tex]

   = [tex]\frac{54}{6} - 2\frac{4}{6}[/tex]

   = [tex]\frac{54}{6} - \frac{16}{6}[/tex]

   = [tex]\frac{38}{6}[/tex] → [tex]6\frac{2}{6}[/tex] → [tex]6\frac{1}{3}[/tex]

17.  [tex]10\frac{1}{3} - 6\frac{5}{9}[/tex]

   =  [tex]10 \frac{3}{9} - 6\frac{5}{9}[/tex]

   =    [tex]\frac{93}{9} - \frac{59}{9}[/tex]

   =     [tex]\frac{34}{9}[/tex] → [tex]3\frac{7}{9}[/tex]

Hope this helps.