Answer:
In a third class lever, the effort is located between the load and the fulcrum. ... If the fulcrum is closer to the effort, then the load will move a greater distance. A pair of tweezers, swinging a baseball bat or using your arm to lift something are examples of third class levers.
Explanation:
The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave?
SOLVE IT COMPLETELY
The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?
Answer:-Given:-Velocity (V) = 40 m/s
Wavelength [tex] (\lambda) [/tex] = 80 cm = 0.8 m
To Find:-The frequency (F) of the wave.
Solution:-We know,
[tex] \bf V \: = \: F \: × \: \lambda [/tex]
40 = F × 0.8
F = [tex] \frac{40}{0.8} [/tex]
F = 50
The frequency of the wave is 50 Hz. [Answer]Using a Boltzmann distribution, find the fraction of atoms in the excited state versus the ground state (i.e. the relative population) in a plasma source and a flame source. Assume that the lowest energy of a sodium atom lies at 3.371x10-19 J above the ground state, the degeneracy of the excited state is 2, whereas that of the ground state is 1, and the temperature of the flame is 3000 K and 10,000 K for plasma.
Answer:
0.174 plasma
[tex]$5.85 \times 10^{-4}$[/tex] flame
Explanation:
Given :
Energy :
[tex]$\Delta E=3.371 \times 10^{-19} $[/tex] J per atom
[tex]$g^*=2$[/tex] (degenraci of excited state)
g = 1 (degenraci of excited state)
Boltzmann Distribution
[tex]$\frac{N^*}{N}=\frac{g^*}{g}e^{-\frac{\Delta E}{kT}}$[/tex]
where,
[tex]$N^*$[/tex] = atoms in excited state
N = atoms in lower energy level
k = [tex]$1.38 \times 10^{-23}$[/tex] J/K
Therefore,
Relative population in plasma
T = 10,000 K
[tex]$\frac{N^*}{N}=\frac{g^*}{g}e^{-\frac{\Delta E}{kT}}$[/tex]
[tex]$\frac{N^*}{N}=\frac{2}{1}e^{-\frac{-3.37\times 10^{-19}}{1.38 \times 10^{-23} \times 10000}}$[/tex]
[tex]$\frac{N^*}{N}=2 \times e^{-2.44275}$[/tex]
[tex]$\frac{N^*}{N}=2 \times 0.8692$[/tex]
[tex]$\frac{N^*}{N}=0.1738$[/tex]
Relative population in flame
T = 3000
[tex]$\frac{N^*}{N}=\frac{g^*}{g}e^{-\frac{\Delta E}{kT}}$[/tex]
[tex]$\frac{N^*}{N}=\frac{2}{1}e^{-\frac{-3.371\times 10^{-19}}{1.38 \times 10^{-23} \times 3000}}$[/tex]
[tex]$\frac{N^*}{N}=2 \times e^{-8.1425}$[/tex]
[tex]$\frac{N^*}{N}=2 \times 2.9090 \times 10^{-4}$[/tex]
[tex]$\frac{N^*}{N}=5.85 \times 10^{-4}$[/tex]
When a wave of light strikes a diffraction screen (or grating) it will cause the wave to pass through each slit, causing the emerging light to radiate outward as if from a new source. These newly formed waves create alternating patterns of constructive and destructive interference, which can be observed when projected onto a screen. Select the variables listed below that determine the angle at which these patterns occur (you might need to select more than one answer):
Answer:
The answer is "the angle depends on wavelength and distance of slits".
Explanation:
[tex]d \sin \theta = m\lambda[/tex] as well as angular, of mth order darkened border is indicated only by angular position, the [tex]\theta[/tex] mth order bright border generated by a light wavelength [tex]\lambda[/tex] , and use the grating of the segregation slit.
[tex]d \sin \theta = ( m + \frac{1}{2}) \lambda[/tex]
Therefore, [tex]\theta[/tex] depends on d and [tex]\lambda[/tex] for a specific order.
If a 75 W lightbulb is 15% efficient, how many joules of light energy does the bulb produce every minute?
Answer:
11.25J
Explanation:
15=(output/75)x100
output =(75x15)/100=11.25J
An electron of kinetic energy 1.59 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 35.4 cm. Find (a) the electron's speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion.
Answer:
a) [tex] v = 2.36 \cdot 10^{7} m/s [/tex]
b) [tex] B = 3.80 \cdot 10^{-4} T [/tex]
c) [tex] f = 1.06 \cdot 10^{7} Hz [/tex]
d) [tex] T = 9.43 \cdot 10^{-8} s [/tex]
Explanation:
a) We can find the electron's speed by knowing the kinetic energy:
[tex] K = \frac{1}{2}mv^{2} [/tex]
Where:
K: is the kinetic energy = 1.59 keV
m: is the electron's mass = 9.11x10⁻³¹ kg
v: is the speed =?
[tex] v = \sqrt{\frac{2K}{m}} = \sqrt{\frac{2*1.59 \cdot 10^{3} eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}}{9.11 \cdot 10^{-31} kg}} = 2.36 \cdot 10^{7} m/s [/tex]
b) The electron's speed can be found by using Lorentz's equation:
[tex] F = q(v\times B) = qvBsin(\theta) [/tex] (1)
Where:
F: is the magnetic force
q: is the electron's charge = 1.6x10⁻¹⁹ C
θ: is the angle between the speed of the electron and the magnetic field = 90°
The magnetic force is also equal to:
[tex] F = ma_{c} = m\frac{v^{2}}{r} [/tex] (2)
By equating equation (2) with (1) and by solving for B, we have:
[tex] B = \frac{mv}{rq} = \frac{9.11 \cdot 10^{-31} kg*2.36 \cdot 10^{7} m/s}{0.354 m*1.6 \cdot 10^{-19} C} = 3.80 \cdot 10^{-4} T [/tex]
c) The circling frequency is:
[tex] f = \frac{1}{T} = \frac{\omega}{2\pi} = \frac{v}{2\pi r} [/tex]
Where:
T: is the period = 2π/ω
ω: is the angular speed = v/r
[tex] f = \frac{v}{2\pi r} = \frac{2.36 \cdot 10^{7} m/s}{2\pi*0.354 m} = 1.06 \cdot 10^{7} Hz [/tex]
d) The period of the motion is:
[tex] T = \frac{1}{f} = \frac{1}{1.06 \cdot 10^{7} Hz} = 9.43 \cdot 10^{-8} s [/tex]
I hope it helps you!
51.Shoveling snow can be extremely taxing because the arms have such a low efficiency in this activity. Suppose a person shoveling a footpath metabolizes food at the rate of 800 W. (a) What is her useful power output? (b) How long will it take her to lift 3000 kg of snow 1.20 m? (This could be the amount of heavy snow on 20 m of footpath.) (c) How much waste heat transfer in kilojoules will she generate in the process?
Complete question is;
Shoveling snow can be extremely taxing since the arms have such a low efficiency in this activity. Suppose a person shoveling a sidewalk metabolizes food at the rate of 800 W. (The efficiency of a person shoveling is 3%.)
(a) What is her useful power output? (b) How long will it take her to lift 3000 kg of snow 1.20 m? (This could be the amount of heavy snow on 20 m of footpath.) (c) How much waste heat transfer in kilojoules will she generate in the process?
Answer:
A) P_out = 24 W
B) t = 1470 s
C) Q = 1140.72 KJ
Explanation:
We are given;
Input Power; P_in = 800 W
Efficiency; η = 3% = 0.03
A) Formula for efficiency is;
η = P_out/P_in
Making P_out the subject, we have;
P_out = η•P_in
P_out = 0.03 × 800
P_out = 24 W
B) We know that;
Power = work done/time taken
Thus;
P_out = mgh/t
We are given;
m = 3000 kg
h = 1.20 m
Thus, time is;
t = (3000 × 9.8 × 1.2)/24
t = 1470 s
C) amount of heat wasted is calculated from;
Q = (P_in - P_out)t
Q = (800 - 24) × 1470
Q = 1,140,720 J
Q = 1140.72 KJ
Wind power is considered a renewable energy source.
O True
O False
Answer:
True
Explanation:
Answer:
your answer is true hope this helps
Does an infrared wave or an x-ray travel faster in the vacuum of space?
Answer:
All electromagnetic radiation, of which radio waves and X-rays are examples, travels at the speed c in a vacuum. The only difference between the two is that the frequency of X-rays is very much higher than radio waves
Hydrogen gas is maintained at 3 bars and 1 bar on opposite sides of a plastic membrane which is .3 mm thick. The temperature is 25C, and the diffusion coefficient of hydrogen in the plastic at 25C is 9x10-8 m2/s. The solubility of hydrogen in the plastic membrane is 1.5x10-3 kmol/m3. What is the mass diffusive flux (in kg/m2.s) of hydrogen on the membrane
Answer:
[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]
Explanation:
From the question we are told that:
Thickness of plastic membrane [tex]L_t=0.3mm[/tex]
The temperature of hydrogen [tex]T_h=25 \textdegree C[/tex]
Diffusion coefficient of hydrogen in the plastic [tex]25 \textdegree C \mu=9*10-8m2/s[/tex]
The solubility of hydrogen in the plastic membrane [tex]\+x=1.5*10{-3} kmol/m3[/tex]
Generally the equation for molar conc is mathematically given by
[tex]CA_1=x*bar[/tex]
3bars
[tex]CA_1=1.5*10^{-3}*3[/tex]
[tex]CA_1=4.5*10^{-3}kmol/m^3[/tex]
1bar
[tex]CA_1=1.5*10^{-3}*1[/tex]
[tex]CA_1=1.5*10^{-3}kmol/m^3[/tex]
Generally the equation for molar diffusion flux of Hydrogen N_a is mathematically given by
[tex]N_a=\frac{D{AB}}{\L}(CA_1-CA_2)[/tex]
[tex]N_a=\frac{9*10^{-8}}{0.3*10^-^3} (4.5*10^{-3}-1.5*10^{-3})kmoi/m^-3[/tex]
[tex]N_a=9.*10^{-7}kmol/sm^2*2kh/kmole[/tex]
[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]
Research DNA phenotyping and make a list of pros and cons. What are its possible advantages? What might go wrong? Would it change investigations for the better, or create unfair bias? Think about how this technology would impact forensics, law enforcement, and the public in general. List at least three arguments for and three arguments against it. (1 sentence/phrase each)
Answer:
Pros of DNA phenotyping:
-Phenotypical characteristics can be predicted such as eye color, hair color, skin pigmentation, and many more.
-predict ancestry of an organism
-Use to find criminals
Cons of DNA phenotyping:
-Some phenotypical traits could not be predicted
- Invading privacy
This technology will surely help forensics, law enforcement as it helps track down unknown perpetrators of crime.
3 arguments for it:
- accurate in narrow down researches
- finding biological ancestry
3 arguments against it
It violates the privacy policy of an individual
Racial discrimination is done of public
Equality policies are not followed by it.
A proton moving at v1 = 7.0 Mm/s collides elastically head-on with a second proton moving in the opposite direction at v2 = 8.3 Mm/s. (a) Find the velocity of the first proton after the collision. (b) Find the velocity of the second proton after the collision
Answer:
(a) The final velocity of the first proton after the collision = 8.3 m/s in the opposite to its initial direction
(b) The final velocity of the second proton after the collision = 7 m/s in the opposite to its initial direction
Explanation:
The given parameter of the protons are;
The velocity of the first proton, v₁ = 7.0 Mm/s
The velocity of the second proton, v₂ = -8.3 Mm/s
The type of collision = Elastic collision
In an elastic collision, the kinetic and momentum energies are conserved, therefore, we have, for the initial and final momentums;
(m₁·v₁ + m₂·v₂)₁ = (m₁·v₁ + m₂·v₂)₂
1/2·(m₁·v₁² + m₂·v₂²)₁ = 1/2·(m₁·v₁² + m₂·v₂²)₂
Where, m₁ = m₂ or the protons, we get;
(v₁ + v₂)₁ = (v₁ + v₂)₂
(v₁² + v₂²)₁ = (v₁² + v₂²)₂
Therefore;
7.0 - 8.3 = v₁ + v₂
-1.3 = v₁ + v₂...(1)
7.0² + (-8.3)² = v₁² + v₂²
117.49 = v₁² + v₂²...(2)
From equation (1), we have;
v₁ = -1.3 - v₂
Plugging the value v₁ = -1.3 - v₂ in equation (2) gives;
117.49 = v₁² + v₂² = (-1.3 - v₂)² + v₂² = 2·v₂² + 12·v₂ + 1.69
∴ 2·v₂² + 2.6·v₂ + 1.69 - 117.49 = 0
2·v₂² + 2.6·v₂ - 115.8 = 0
Using the quadratic formula, we have;
v₂ = (-2.6 ± √(2.6² - 4×2×(-115.8)))/(2 × 2)
∴ v₂ ≈ -8.3 m/s or 7 m/s
When v₂ ≈ -8.3, v₁ = -1.3 - v₂ ≈ -1.3 - (-8.3) = 7
When v₂ ≈ 7, v₁ = -1.3 - v₂ ≈ -1.3 - (7) = -8.3
Therefore, the final velocity of the first proton after the collision = 8.3 m/s in the opposite to its initial direction
(b) The final velocity of the second proton after the collision = 7 m/s in the opposite to its initial direction.
Aluminum has a shear strength of 210 megapascals. When you bend aluminum foil around an edge (i.e., the edge of the box) and pull, you are effectively applying a shear force along the bent edge of the foil. If a roll of household aluminum foil is 30.0 centimeters wide and its thickness is approximately 15.0 micrometers, how much shear force is needed to pull off a sheet
Answer:
The answer is "[tex]945\ N[/tex]"
Explanation:
Aluminum has 210 megapascals of tensile resistance. They choose a shear force only at bent foil edge to bend aluminum foil over an edge (that is the edge of its box) to pull them. When a roll of aluminium domestic foil is 30 cm in width and about 15.0 micrometers.
[tex]\to 0.000015 \times 0.300 = 0.0000045\\\\\to 210000000 = \frac{F}{0.0000045}\\\\\to F=210000000 \times 0.0000045\\\\\to F = 945\ N[/tex]
Three capacitors, C1 = 2 μF, C2 = 4 μF, C3 = 4 μF, are connected in series Determine the capacitance of a single capacitor that will have the same effect as the combination.
Answer:
1 μF
Explanation:
To obtain the answer to the question, all we need to do is to calculate the equivalent capacitance of the capacitors. This can be obtained as illustrated below.
From the question given above, the following data were obtained:
Capacitor 1 (C₁) = 2 μF
Capacitor 2 (C₂) = 4 μF
Capacitor 3 (C₃) = 4 μF
Equivalent capacitance (Cₑq) =?
Cₑq = 1/C₁ + 1/C₂ + 1/C₃
Cₑq = 1/2 + 1/4 + 1/4
Cₑq = (2 + 1 + 1)/4
Cₑq = 4/4
Cₑq = 1 μF
Thus, the answer to the question is 1 μF
a car initially at rest move with the constant accerates along straght line read after it's spread increase and finally related uniformly. the time interval for the three parts of the jounry are in the ratio 1:3:1 find average velocity ?
Answer:
32km per hour
Explanation:
Explanation:
In first case v = a t
==> a t = 40 km p h
Now distance covered S1 + S2 + S3
S1 = 1/2 a t^2 and S3 = 1/2 a t^2
But S2 = 3t * 40 = 120 t km
Hence total distance = at^2 + 120 t
Time taken (total) = t + 3t + t = 5 t
Hence average speed = at^2 + 120 t / 5 t
Cancelling t we have at + 120 / 5 = 40 + 120 / 5 = 160/5 = 32 km per hour
Which statement identifies a true relationship between the various wave components?
If amplitude increases, frequency increases.
If frequency increases, wavelength decreases.
If wavelength decreases, amplitude decreases.
Answer:
it's the second one;
if the frequency increases, wavelength decreases
Explanation:
we know, v=f×lamda(wave length)
so for constant velocity Frequency f is inversely proportional to lamda
i.e.
fα 1/lamda
so as the f increases lamda decreases and vise versa
A true relationship between the various wave components is if frequency increases, wavelength decreases.
What is the frequency?The frequency is the reciprocal of the time period of the wave.
The wavelength is the distance between the two adjacent crest of the wave.
If the wavelength decreases, the number of cycles will increase in a certain time.
Hence, a true relationship between the wave components is if frequency increases, wavelength decreases.
Learn more about Frequency.
https://brainly.com/question/5102661
#SPJ2
Which two mixtures are homogeneous?
Answer:
sand and air
Explanation:
air is a mix of carbon dioxide and oxygen and sand is a mix of rocks and stuff
A capacitor is constructed of two large, identical, parallel metal plates separated by a small distance d
a. True
b. False
Find the frequency and wavelength of the wave below, assuming it has a speed of 30 m/s
A plate of uniform areal density is bounded by the four curves: where and are in meters. Point has coordinates and . What is the moment of inertia of the plate about point
The question is incomplete. The complete question is :
A plate of uniform areal density [tex]$\rho = 2 \ kg/m^2$[/tex] is bounded by the four curves:
[tex]$y = -x^2+4x-5m$[/tex]
[tex]$y = x^2+4x+6m$[/tex]
[tex]$x=1 \ m$[/tex]
[tex]$x=2 \ m$[/tex]
where x and y are in meters. Point [tex]$P$[/tex] has coordinates [tex]$P_x=1 \ m$[/tex] and [tex]$P_y=-2 \ m$[/tex]. What is the moment of inertia [tex]$I_P$[/tex] of the plate about the point [tex]$P$[/tex] ?
Solution :
Given :
[tex]$y = -x^2+4x-5$[/tex]
[tex]$y = x^2+4x+6$[/tex]
[tex]$x=1 $[/tex]
[tex]$x=2 $[/tex]
and [tex]$\rho = 2 \ kg/m^2$[/tex] , [tex]$P_x=1 \ $[/tex] , [tex]$P_y=-2 \ $[/tex].
So,
[tex]$dI = dmr^2$[/tex]
[tex]$dI = \rho \ dA \ r^2$[/tex] , [tex]$r=\sqrt{(x-1)^2+(y+2)^2}$[/tex]
[tex]$dI = (\rho)((x-1)^2+(y+2)^2)dx \ dy$[/tex]
[tex]$I= 2 \int_1^2 \int_{-x^2+4x-5}^{x^2+4x+6}((x-1)^2+(y+2)^2) dy \ dx$[/tex]
[tex]$I= 2 \int_1^2 \int_{-x^2+4x-5}^{x^2+4x+6}(x-1)^2+(y+2)^2 \ dy \ dx$[/tex]
[tex]$I=2 \int_1^2 \left( \left[ (x-1)^2y+\frac{(y+2)^3}{3}\right]_{-x^2+4x-5}^{x^2+4x+6}\right) \ dx$[/tex]
[tex]$I=2 \int_1^2 (x-1)^2 (2x^2+11)+\frac{1}{3}\left((x^2+4x+6+2)^3-(-x^2+4x-5+2)^3 \ dx$[/tex]
[tex]$I=\frac{32027}{21} \times 2$[/tex]
[tex]$= 3050.19 \ kg \ m^2$[/tex]
So the moment of inertia is [tex]$3050.19 \ kg \ m^2$[/tex].
How does Newton's first law affect human motions answer
19
What is the mass of a ball that is traveling 30 m/s and has 4.5 J of kinetic energy?
ave a GPF of 35512
Answer: The mass of ball is 10 grams.
Explanation:
Given : Kinetic energy = 4.5 J
Velocity = 30 m/s
The formula for Kinetic energy is as follows.
[tex]K.E = \frac{1}{2}mv^{2}[/tex]
where,
K.E = Kinetic energy
m = mass
v = velocity
Substitute the values into above formula as follows.
[tex]K.E = \frac{1}{2}mv^{2}\\4.5 J = \frac{1}{2} \times m \times (30 m/s)^{2}\\m = \frac{4.5 J \times 2}{900 m^2/s^2} (1 Js^{2} = kg m^{2})\\= 0.01 kg (1 kg = 1000 g)\\= 10 g[/tex]
Thus, we can conclude that the mass of ball is 10 grams.
[tex]can \: you \: answer \: that[/tex]
Answer:
1. k
2. t
3. k
4. k
5. k
6. k
7. k
8. k
9. k
10. k
I'm not sure but hope it helps:)
Do anyone know this ?
Answer:
Distance is 100m, displacement is 0m
Explanation:
Distance is how much you travelled in total (100m)
Displacement is when you compare your final and initial positions.
It is usually Final position - Initial position.
Since you start and finish at the same point, it would be 0 - 0 = 0m
So the displacement is 0m.
En una balanza de fábrica se determina la masa de un cuerpo y se obtiene
1 M kg 280
con
un error aparente
1 1 0,5 a
M kg
. En un laboratorio, se hace lo mismo con otro cuerpo y
se determina
2 M g 23,545
con un error
2 2 0,001 a
M g .
¿Dónde se cometió mayor erro
SOMEONE HELP PLEASE I ASKED THIS TWICE LAST NIGHT I MEAN DAM!! You drop a water balloon from a second-story window. Which formula would you use to calculate the velocity of the water balloon just before it hits the ground, assuming it is in free fall?
A. v=g/t B. v=get C. g=vt D. t=vg
Answer:
I think it would be V=g/t
A 2.5 V battery is connected to a small light
bulb with a resistance of 4.8 Ω .
What is the current in the bulb?
Answer in units of A.
Answer: I=0.52 A
Explanation:
Given
Voltage is [tex]2.5\ V[/tex]
Resistance [tex]R=4.8\ \Omega[/tex]
Current is given by
[tex]I=\dfrac{V}{R}[/tex]
[tex]\Rightarrow I=\dfrac{2.5}{4.8}=0.52\ A[/tex]
Tawny notices that Jim has been forgetting to check two forms of
identification for new patients. How could she best communicate this
effectively to Jim in a way that avoids conflict?
A. "I forget this a lot, too, so I'm not blaming you or anything, but you
need to check two forms of identification."
B. "Did you forget your training? We always have to check two forms
of identification for each patient."
C. "We have to check two forms of identification, so stop forgetting
to do it."
D. "I think the proper procedure is to check two forms of
identification for each patient."
Answer: D. "I think the proper procedure is to check two forms of
identification for each patient."
Explanation: took the quiz
An electric motor operates a pump that irri-
gates a farmer's crop by pumping 10 000 L of
water a vertical distance of 8.0 m into a field
each hour. The motor has an operating resis-
tance of 22.0 2 and is connected across a
110-V source.
a. What current does it draw?
b. How efficient is the motor?
Answer:
a. 5A
b. 39.60%
Explanation:
The computation is shown below:
a. The current does it draw is
= v ÷ R
= 110v ÷ 22
= 5A
b. Now the efficiency of the motor is
n = mgh ÷ vlt
= (10,000 × 9.8 × 8) ÷ (5 × 3600 × 110)
= 784000 J ÷ 1,980,000
= 39.60%
hence, the above formulas are applied & the same is relevant
What is the wavelength associated with an electron with a velocity of 4.8x10*5 m/s?
(mass of the electron is 9.1 X 10-*31kg)
Answer:
Explanation:
Given the following data;
Mass = 9.1 X 10^{-31} kg
Velocity = 4.8x10⁵ m/s
Planck’s constant ( h ) = 6.6262 * 10^{-34}
To find the wavelength;
Applying de broglie's equation;
Wavelength = h/mv
Wavelength = ) = 6.6262 * 10^{-34}/(9.1 X 10^{-31} * 4.8x10⁵)
Wavelength = 1.52 * 10^{-71} meters
PLS HELP, WILL GIVE BRAINLIEST!!!
A piece of clay with a mass of 350 g is dropped to the floor from a height of 1.5 m (A). Calculate the KE and PE of the clay at
a. (A = 1.5 m).
b. (B = 70 cm), and
c. (C = 0 m, just before hitting the ground). d. Make an energy graph at each point
Answer:
b bro it's b bro