Brand A coffee sells for $7/pound, while Brand B sells for $5.40/pound. How much of each brand of coffee is needed to make 5 pounds that will cost
$6.75/pound?

A. 0.8 pounds Brand A, 4.2 pounds Brand B
B. 2.7 pounds Brand A. 2.3 pounds Brand B
C. 4.2 pounds Brand A. 0.8 pounds Brand B
D. 2.3 pounds Brand A. 2.7 pounds Brand B

Answers

Answer 1

Answer:

C. 4.2 pounds Brand A. 0.8 pounds Brand B

Step-by-step explanation:

How much of each brand of coffee is needed to make 5 pounds that will cost

$6.75/pound?

Let the number of pounds for Brand A = x

Let the number of pounds for Brand B = y

Brand A coffee sells for $7/pound, while Brand B sells for $5.40/pound.

$7 × x + $5.40 × y = $6.75 × 5

7x + 5.40y = 33.75.......Equation 1

x + y = 5 .......Equation 2

x = 5 - y

7(5 - y)+ 5.40y = 33.75

35 - 7y + 5.40y = 33.75

35 - 33.75 = 7y - 5.40y

= 1.25 = 1.6y

y = 1.25/1.6

y = 0.78125 pounds.

Approximately to the nearest whole number, Brand B = 0.8 pounds.

x = 5 - y

x = 5 - 0.8 pounds

x = 4.2 pounds

Brand A = 4.2 pounds


Related Questions

(Simplify the equation) 3n+5+2n=5+n+6n-n​

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Answer:

n=0

Step-by-step explanation:

3n+5+2n=5+n+6n-n​

move like terms together

3n+2n+5=5+n+6n-n

simplify down

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Answer:

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x² – 9/3x²+8x-3 divided by x-3/x+2


Answers

Answer:

-(x(2x squared-8x+3))/(x-1)(x+3)

Step-by-step explanation:

This can't be simplified very far, but the answer is above. Hope it helps!

The simplified equation of x² – 9/3x²+8x-3 divided by x-3/x+2 is (x-3)(4x+1)/(3x-1)(x+2).

What is Simplification?

Simplification is the process of replacing a mathematical expression by an equivalent one, that is simpler. Therefore,

WE need to simplify the given;

[tex]\dfrac{x^{2}-9 }{3x^{2} +8x-3}+\dfrac{x-3}{x+2}[/tex]

3x² + 8x - 3 = (3x - 1)(x + 3)

x² - 9 = (x - 3)(x + 3)

Then;

[tex]\dfrac{(x-3)(x+3)}{(3x-1)(x+3)} +\dfrac{x-3}{x+2} =\dfrac{(x+2)(x-3)(x+3)+(x-3)(x+3)(3x-1)}{(3x-1)(x+3)(x+2)}[/tex]

Therefore,

[tex]\frac{(x+2)(x-3)(x+3)+(x-3)(x+3)(3x-1)}{(3x-1)(x+3)(x+2)}=\frac{((x+3)(x-3)((x+2)+(3x-1)))}{(3x-1)(x+3)(x+2)}[/tex]

[tex]\dfrac{((x+3)(x-3)((x+2)+(3x-1)))}{(3x-1)(x+3)(x+2)}=\dfrac{(x-3)((x+2)+(3x-1))}{(3x-1)(x+2))}[/tex]

[tex]\dfrac{(x-3)((x+2)+(3x-1))}{(3x-1)(x+2))} = \dfrac{(x-3)(x+2+3x-1)}{(3x-1)(x+2)}[/tex]

[tex]\dfrac{(x-3)(x+2+3x-1)}{(3x-1)(x+2)}=\dfrac{(x-3)(4x+1)}{(3x-1)(x+2)}[/tex]

Hence, The simplified equation of x² – 9/3x²+8x-3 divided by x-3/x+2 is (x-3)(4x+1)/(3x-1)(x+2).

Learn more about simplification;

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Graph each function and determine the y-intercept, then use the graph to determine the approximate value of the given expression.
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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Answers

Step-by-step explanation:

there is 3 feet in a yard

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true

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It has been observed that a large percentage of professional hockey players have birthdays in the first part of the year. It has been suggested that this is due to the cut-off dates for participation in the youth leagues - those born in the earlier months are older than their peers and this advantage is amplified over the years via more opportunities to train and be coached. Of the 511 professional hockey players in a season, 159 of them were born in January, February, or March.

Requried:
a. Assume that 25% of birthdays from the general population occur in January, February, or March (these actually contain 24.7% of the days of the year). In random samples of 508 people, what is the mean number of those with a birthday in January, February, or March?
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d. If the men in the professional hockey league were randomly selected from the general population, would 158players out of 508 be an unusual number of men born in the first 3 months of the year?

e. Which of the following is an acceptable sentence to explain this situation?

1. If the men in the professional hockey league were selected randomly from the general population, this would be an unusual collection of birth dates.
2. There is good reason to believe that a significantly larger than expected proportion of professional hockey league players are born in the first three months of the year.
3.This could be a result of the random variation of birth dates within a sample. However, it would be pretty unlikely to happen by chance.
4. All of these are valid statements.

Answers

Answer:

a

[tex]\mu  =  127[/tex]

b

[tex]\sigma  =  9.76[/tex]  

c

[tex]z-score  =  3.18 [/tex]

d

Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158  is  greater than  3( Note :the probability of  z-score = 3 is  97%)

e

The correct option is  option 3

Step-by-step explanation:

From the question we are told that

   The population proportion is  p =  0.25

   The sample size is  n =  508

   

Generally the mean is  mathematically represented as  

     [tex]\mu  =  np[/tex]

=>   [tex]\mu  =  508 * 0.25[/tex]

=>   [tex]\mu  =  127[/tex]

Generally the standard deviation is mathematically represented as

     [tex]\sigma  =  \sqrt{ np (1-p)}[/tex]

=>   [tex]\sigma  =  \sqrt{ 508 * 0.25 (1-0.25)}[/tex]    

=>    [tex]\sigma  =  9.76[/tex]  

Generally the z-score of  158 is mathematically represented as

    [tex]z-score  =  \frac{158 - 127}{9.76}[/tex]

=>  [tex]z-score  =  \frac{158 - 127}{9.76}[/tex]

=>  [tex]z-score  =  3.18 [/tex]

Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158  is  greater than  3( Note :the probability of  z-score = 3 is  97%)

What this means is that the almost the whole  professional hockey league player are born in the first month which is unusual

HELP!!!
Find the equation of a line parallel to 2x + 2y=6 that contains the point (3,-5), Write the equation in slope-intercept

Answers

Answer:

[tex]y = -x -2[/tex]

Step-by-step explanation:

Slope-Intercept form of the line

Any given line with slope m and y-intercept b can be written as:

y=mx+b

We need to find the equation of a line parallel to

2x + 2y = 6

Dividing by 2:

x + y = 3

Solving for y:

y = -x + 3

Comparing with the slope-intercept form of the line:

m = -1

Parallel lines have the same slope, thus the required line must have a slope m = -1.

Since we have a point through which the line passes, we use the point-slope form:

y - k = m ( x - h )

Where (h,k) is the point.

The required equation of the line is:

y - (-5) = -1 (x - 3)

Operating:

y + 5 = -x + 3

Solving for y:

[tex]\boxed{y = -x -2}[/tex]

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