Calculate the average of these values: 38, 48, 58, 68?​

Answers

Answer 1

Answer:

53 is the average value.

Step-by-step explanation:

To find the average, or mean of multiple values you first add them all up:

38+48+58+68=212

Then you count how many different numbers there are, (there are 4 numbers here, if there are 2 of the same numbers you still count them both, just so you understand).

Then you need to divide the total you got, 212, by the total amount of numbers, 4, to get the average amount, 53.

I hope that my answer has helped you, have a great day, ask any questions you have below.


Related Questions

PLS HELP REWARDING A LOT!!

Answers

Answer:

157°

Step-by-step explanation:

Sum of interior angles of polygon

(n-2)*180 ---- n = total number of sides

7 angles, 7 sides

5*180 = 900

final angle will be

900-162-115-125-138-105-98

=157

Answer:

157

Step-by-step explanation:

it is obvious that it's a heptagon

so (n-2) x180

n=7

(7-2) x 180 =900

900-162-115-125-138-105-98

900-743=157

final unknown=157°

What is the value of w?

Answers

Answer:

w= -2. Solve for w: (w-5) (w+2) = w^2-4. Expand out terms of the left hand side: w^2-3 w-10 = w^2-4. Subtract w^2-4 from both sides

Step-by-step explanation:

2 (3) to the power of 3 + 5

Answers

Answer:

13122

Step-by-step explanation:

Our equation is 2(3)⁸

once its solve we get 13122 as our answer

which option is right??

Answers

Side- Angle- Side
is the correct answer

hope this helps :)

Answer:

its the third choice

Step-by-step explanation:

Side angle side cuz there r 2 sides congruent in the picture shown above.

you have to estimate​

Answers

The answer is 75388.
802x94
=75388

Answer:

75,388

Step-by-step explanation:

Long Multiplication form

[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]

[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]

[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]

[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]

[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]

[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]

[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]

[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex]     [tex]=75,388[/tex]

See Image for the addition:

Y=4x+8 y=-x-7 solve by substitution

Answers

Step-by-step explanation:

Alrighty! here you go image.

Answer:x=15

Step-by-step explanation:

Evaluate the algebraic expression if w= -0.5, x = 2, y= -3, and z = 2.5.

2w^2 - 3x + y - 8z

Answers

Answer:

-28.50

Step-by-step explanation:

Given the algebraic expression, 2w² - 3x + y - 8z, where w = -0.5, x = 2, y= -3, and z = 2.5:

Substitute the given values for the variables to evaluate the algebraic expression.

2w² - 3x + y - 8z

= 2(-0.5)² - 3(2) + (-3) - 8(2.5)

= 2(0.25) - 6 - 3 - 20

= 0.50 - 6 - 3 - 20

= -28.50

Therefore, 2w² - 3x + y - 8z = -28.50.

Answer:

-28.5

Step-by-step explanation:

Substitute the values for their given variables and evaluate.

[tex]2w^2-3x+y-8z\\\\2(-0.5)^2-3(2)+(-3)-8(2.5)\\\\2(0.25)-6-3-20\\\\0.5-6-3-20\\\\-28.5[/tex]

find the integral.......

Answers

Answer:

1/5(2ln|x|+3*5^1/3)+c

Step-by-step explanation:


The cost of 2 bunches of
roses and 5 bunches of
carnations is £45.
The cost of 3 bunches of
roses and 4 bunches of
carnations is £50.
Find the cost of one bunch of each

Answers

Answer:

vtdOveractivity of the pituitary gland is called hyperpituitarism. Several disorders related to an overactive pituitary gland can occur.

...

Symptoms may include:

Nervousness.Rapid or irregular heartbeat.Weight loss.Fatigue.Muscular weakness.

Help !!!!!!!!!!!!!!!!!!!!

Answers

Answer:

Step-by-step explanation:

One must rearrange the function to decreasing value of exponents

f(x) = -7x⁴ + 8x³ - 3x² - 9x + 11

to see that it is a 4th degree polynomial with leading coefficient of -7

which of the following are perfect cubes 1)3375 2)8000 3)6859​

Answers

Answer:

all are perfect cubes

Step-by-step explanation:

you can just cube root the numbers and bom if it aint decimal its a perfect cube

Which expression is the factored form of−4.5n+3?


−1.5(3n+2)

−3(1.5n+1)

−3(1.5n−1)

−1.5(−3n+2)

Answers

Answer:

— 3 (1.5n — 1)

Step-by-step explanation:

[tex] - 4.5n + 3 = - \frac{9}{2} n + 3 = 3( - \frac{3}{2} n + 1) = - 3( \frac{3}{2}n - 1) \\ = - 3(1.5n - 1)[/tex]

what is a degree 3 polynomial with integer coefficients with zeros 3, -4, 5

Answers

4 would it or maybe 12

6^3 multiplied by (1/2)^3 ​

Answers

Step-by-step explanation:

6³×(½)³

=> 216÷8 = 27.

hope this helps you.

(2³ x 2⁵) ÷ 2⁸
Solution​

Answers

Answer:

it is 1

Step-by-step explanation:

Let's use PEMDAS (do the parenthesis first).

2 to the 3 = 2x2x2 = 8

2 to the 5 = 2x2x2x2x2 = 32

8 x 32 = 256 (all the solutions are factors of 2048).

2 to the 8 = 2x2x2x2x2x2x2x2 = 256 again

256 / 256 = 1

i need help on this math problem

Answers

Answer:

Step-by-step explanation:

Slope: 3/1 (positive: line go uphill)

y-intercept: -5

Place your pencil on the vertical line (y) on -5. Go up 3 units and 1 to the right, repeat and trace the line (actually you only need two points to trace a line)

50 points + brainliest answer questions 7 and 8 with work and all

Answers

Answer:

7) m∠BHE = 146°

8) m∠BAC = 25°

Step-by-step explanation:

Question 7:

Given that, [tex]\displaystyle\mathsf{\overline{CD}\:||\:\overline{EF}}[/tex], and that [tex]\displaystyle\mathsf{\overline{AB}}[/tex] is a transveral.

We are also provided with the following measures of the angles: m∠DGH = 2x, and m∠FHB = 5x - 51.

∠DGH and ∠FHB are also corresponding angles, as they have corresponding positions on the same side of the transversal, [tex]\displaystyle\mathsf{\overline{AB}}[/tex]. These two angles also have the same measure.  

Solve for x:

In order to find the measure of ∠BHE, we could set up an equality statement on ∠DGH and ∠FHB to solve for the value of x.

m∠DGH = m∠FHB

2x = 5x - 51

Add 51 and subtract 2x from both sides of the equation:

2x -2x + 51  = 5x - 2x - 51 + 51

51 = 3x

Divide both sides by 3:

[tex]\displaystyle\mathsf{\frac{51}{3}\:=\:\frac{3x}{3}}[/tex]

x = 17

 m∠DGH = 2x = 2(17) = 34°,

 m∠FHB = 5x - 51 = 5(17) - 51 = 34°.

Since ∠FHB and ∠BHE are supplements (whose sum add up to 180°), we could determine the measure of ∠BHE as follows:

m∠BHE + m∠FHB  = 180°

m∠BHE + 34° = 180°

m∠BHE + 34°- 34° = 180°- 34°

m∠BHE = 146°.

Therefore, the measure of ∠BHE is 146°.

Question 8:

Given that ΔABC with [tex]\displaystyle\mathsf{\overline{AC}}[/tex] extended to D, and that m∠ABC = 63° and m∠BCD = 92°:

The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the two nonadjacent interior angles. In other words: ∠BCD = ∠BAC + ∠ABC.  

Before we could apply the Exterior Angle Theorem, we must first find m∠BAC. Since ∠BCD and ∠BCA are supplements:

m∠BCD + m∠BCA = 180°

92° + m∠BCA = 180°

92° - 92°+ m∠BCA = 180° - 92°

m∠BCA = 88°

Solve for m∠BAC:

Now that we have the measure for ∠BCA, we can find m∠BAC by applying the Triangle Sum Theorem where it states that the sum of the interior angles of a triangle is equal to 180°.

m∠BCD + m∠ABC + m∠BAC = 180°

92° + 63° + m∠BAC  = 180°

125° + m∠BAC  = 180°

155° - 155° + m∠BAC  = 180° - 155°

m∠BAC  = 25°

Therefore, the measure of ∠BAC is 25°.

2 - 2x 4x + 12
------- = ---------
4 3

Answers

[tex]\tt\frac { 2 - 2 x } { 4 } = \frac { 4 x + 12 } { 3 }[/tex]

[tex]\tt3\left(2-2x\right)=4\left(4x+12\right) [/tex]

[tex]\tt6-6x=16x+48 [/tex]

[tex]\tt6-6x-16x=48 [/tex]

[tex]\tt6-22x=48 [/tex]

[tex]\tt-22x=42 [/tex]

[tex]\tt\:x=\frac{42}{-22} [/tex]

[tex]\boxed{\tt\:x = -\frac{21}{11} = -1\frac{10}{11} \approx -1.90}[/tex]

Method used :-

◇ ✖ Cross multiplication ❌

________

Hope it helps ⚜

Step-by-step explanation:

Given equation is [{(2-2x)/4} = {(4x+12)/3]

On applying cross multiplication then

Since, (a/b) = (c/d)

⇛ab = bc

Where, a = (2-2x), b = (4), c = (4x+12) and d = (3).

Now,

⇛3(2-2x) = 4(4x+12)

Multiply the number outside the bracket with numbers and variables in the bracket.

⇛6 - 6x = 16x + 48

Shift the variable value on LHS and constant on RHS.

⇛-6x - 16x = 48-6

Subtract the values on LHS and RHS.

⇛-22x = 42

Shift the value (-22) from LHS to RHS.

⇛x = 42/-22

Write the obtained answer in lowest form by cancelling method.

⇛x = (42÷2)/(-22÷2)

Therefore, x = 21/-11 = -(21/11)

Answer: Hence the value of x for the given problem is -21/11.

VERIFICATION:

If x = -21/11 then the equation is

[{(2-2x)/4} = {(4x+12)/3]

Substitute the value x = -21/11 in expression, then

⇛[{2-2(-21/11)}/4 = {4(-21/11)+12}/3]

Multiply (-2) from (-21) to get 42 on LHS.

⇛[{2(42/11)}/4 = {4(-21/11)+12}/3]

Again multiply 4 from (-21) to get 81 on RHS.

⇛[{2(42/11)}/4 = {(-81/11) + 12}/3]

Take the LCM of the denominator 1 and 11 is 11 on LHS

⇛[{(2*11 + 42*1)/11}/4 = {(-81*1 + 12*11)/11}/3]

Multiply the numerator on both LHS and RHS.

⇛[{(22+42)/11}/4 = {(-81 + 132)/11}/3]

Add the numerator numbers on both LHS and RHS

⇛[{(64/11)}/4 = [{(48/11)}/3]

Now, conver the division fraction in multiply fraction on both LHS and RHS.

⇛[{(64/11) * 4} = {(48/11) * 3}]

Now, write the numbers in Lower form by cancelling method, on both LHS and RHS.

⇛(16/11) = (16/11)

LHS = RHS

Please let me know if you have any other questions.

100 Points
Emily wants to buy turquoise stones on her trip to New Mexico to give to at least 4 of her friends. The gift shop sells small stones for $4 and large stones for $6, and Emily has no more than $30 to spend.
Write and graph a system of Linear Equations and write two possible solutions.

Answers

Answer:

Step-by-step explanation:

what is she going to buy? Small stones or big stones? if its small stones then she can buy 7 small stones. If its big stones then she can buy 5 big stones.

Compare the expressions 7+3^2-2⋅5 and (3/4+1/8)÷1/8 using , =, or . Show your work. Answer:

Answers

[tex]A=7+3^2 -2 \cdot 5 = 7 + 9 - 10 = 9-3=6\\\\\\B = \left(\dfrac 34 + \dfrac 18\right) \div \dfrac 18 = \dfrac 78 \times 8 =7\\\\\\B>A[/tex]

The expression relation is 7+3²-2⋅5 > (3/4+1/8)÷1/8.

What is Inequality?

Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

Given:

First, 7+3²-2⋅5

Solving the above expression

= 7 + 9 -2.5

= 16 - 2.5

= 13.5

Second,

(3/4+1/8)÷1/8

= (6/8 + 1/8) ÷ 1/8

= 7/8 ÷ 1/8

= 7/8 x 8/1

= 7

Hence, 7+3²-2⋅5 > (3/4+1/8)÷1/8.

Learn more about Inequality here:

https://brainly.com/question/30231190

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The height of a parallelogram is 6[tex]a^{2}[/tex][tex]b^{5}[/tex] and the base of a parallelogram is 4[tex]a^{3}[/tex][tex]b^{4}[/tex] Find the area of the parallelogram using the formula A = bh

Answers

[tex]\text{Area of parallelogram} = \text{Base}~ \times~\text{Height} = (4a^3b^4)(6a^2 b^5)=24a^5 b^9[/tex]

-7(8) What is it please help me I need help help help help

Answers

The Answer should be 10

HELP ME PLEASE!!!!!!!!!!!

Answers

Answer:

SAS theorem >This is the correct

Answer:

SSS theorem

Step-by-step explanation:

[tex] \huge\colorbox{pink}{hope \: its \: help}[/tex]

Please tell me how much can 6 go into 14 without going over 14

Answers

2 times without leaving a remainder.

one added to the square root of the sum of a number and one is equal to four. find the number​

Answers

[tex]\stackrel{\textit{one added to the }\sqrt{\qquad }}{1+\sqrt{\quad }}~~,~~ \stackrel{\sqrt{~~}\textit{ of a number and one}}{\sqrt{x+1}}\implies 1+\sqrt{x+1}\stackrel{\textit{equals}}{=}4 \\\\\\ \sqrt{x+1}=3\implies \left( \sqrt{x+1} \right)^2=3^2\implies x+1=9\implies \boxed{x=8}[/tex]

Which of the following could be a helpful first step in solving this equation for q?

p2q+2q=11
Question 5 options:

Combine p2q+2q

Divide the whole equation by 11.


Divide the first term by p2

Factor a q out of p2q+2q

Answers

Answer:

D: Factor a q out of p^2 q+ 2q

Step-by-step explanation:

I took the test. Hope it was helpful! :)

The first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.

What is the equation?

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that, the equation is,

p²q+2q=11

Take q common from the L.H.S as

q(p²+2)=11

The value of q is obtained by rearranging the equation as,

q=11/(p²+2)

The value of q obtained after solving the equation p²q+2q=11 will be q=11/(p²+2).

Thus, the first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.

Learn more about the equation here,

https://brainly.com/question/10413253

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2.
Fit a quadratic function to these three points:

(−2, 8), (0, −4), and (4, 68)

A. y = −2x2 − 2x − 4

B. y = 4x2 + 2x − 4

C. y = −4x2 − 2x − 4

D. y = −2x2 + 2x − 4

Answers

Answer:

It's C.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

just put the x and y values into the equations and see which equation stays true.

for example, point (4, 68) rules out A and C even without detailed calculation, because these 2 expressions can produce for positive x only negative y (and 68 is clearly a positive y).

so, when using this point in B :

68 = 4×4² + 2×4 - 4 = 4×16 + 8 - 4 = 64 + 8 - 4 = 68

correct.

and it is correct also for the other points.

so, B is the right answer.

7(x+7)≤56 plz help im bad at math

Answers

Answer:x[tex]\geq[/tex]1

Step-by-step explanation:

remove the brackets

7x+49≤56

collect like terms

7x≤56-49

7x[tex]\geq[/tex]7

divide both sides by 7

x[tex]\geq[/tex]1

List all the factors pairs in the table 64

Answers

(1, 64), (2, 32), (4, 16), (8, 8).

Answer:

1 x 64

2 x 32

4 x 16

8 x 8

Step-by-step explanation:

Factors of 64: 1, 2, 4, 8, 16, 32 and 64.

Pairs:

1 x 64

2 x 32

4 x 16

8 x 8

Hope this helps :)

Flying against the wind, a jet travels 3780 miles in 6 hours. Flying with the wind, the same jet travels 5950miles in 7 hours. What is the rate of the jet in still air and what is the rate of the wind? 1111 Rate of the jet in still air: ​

Answers

The rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.

The given parameters;

distance traveled against the wind, d₁ = 3780 milestime of motion, t₁ = 6 hoursdistance traveled with wind, d₂ = 5950 milestime of motion, t₂ = 7 hours

Let the rate of the jet in still air = R₁

Let the rate of the wind = R₂

The rate of the jet against the wind:

[tex]R_1 - R_2 = \frac{3780}{6} \\\\R_1 - R_2 = 630[/tex]

The rate of the jet with the wind:

[tex]R_1 + R_2 = \frac{5950}{7} \\\\R_1 + R_2 = 850\\\\[/tex]

The rate of the jet in still air is calculated as follows;

[tex]R_1 = \frac{630 + 850}{2} \\\\R_1 = 740 \ mph[/tex]

The rate of the wind is calculated as follows;

[tex]R_1 - R_2 = 630\\\\R_2 = R_1 - 630\\\\R_2 = 740 - 630 \\\\R_2 = 110 \ mph[/tex]

Thus, the rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.

Learn more about rate here:https://brainly.com/question/11664428

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