Calculate the pH and pOH of 500.0 mL of a phosphate solution that is 0.285 M HPO42– and 0.285 M PO43–. (Ka for HPO42- = 4.2x10-13 at 25°C)

Answers

Answer 1

Answer: when concentrations of acid and base are same, pH = pKa

PH = 12.38 pOH = 1.62

Explanation: pKa= -log(Ka)= 12.38. PH + pOH = 14.00

Answer 2

The pH of the solution is 12.38 and the pOH of the solution is  1.62.

Using the Henderson Hasselbalch equation;

pH = pKa + log [A-]/[HA]

Where;

pKa = - log Ka = -log[ 4.2x10-13] = 12.38

[A-] = [PO43–] = 0.285 M

[HA] = [HPO42-] = 0.285 M

Substituting values;

pH =  12.38 + [ 0.285 M]/[ 0.285 M]

pH = 12.38

But;

pH + pOH = 14

pOH = 14 - 12.38

pOH = 1.62

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Related Questions

A ___________ ion is made of 2 or more atoms of different elements
O nuclear
O polyatomic
O magnetic
O mono-atomic

Answers

Answer: polyatomic

Explanation:hope you find helpful

A polyatomic is made of 2 or more atoms of different elements.

How do separate the pure ethanol from the mixture of coloured aqueous solution with ethanol​

Answers

Answer:

Fractional distillation is a method for separating a liquid from a mixture of two or more liquids. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points. When the mixture is heated, one liquid evaporates before the other.

What is the IUPAC name for the compound shown?

Answers

2-methyl-1,4-dibutal. That could be wrong but it looks right to me. Sorry if it isn’t righ

What is total distance traveled?
What is the displacement (change in positions) ​

Answers

Answer:

Exercise 1

a)  140 m

b)  100 m

c)  180 m

d) 140 m

Exercise 2

a) 20 yards

b) 30 yards

c) 20 yards

d) 55 yards

Exercise 3

a)  11 Kilometers

b) 7 Kilometers

Explanation:

Exercise 1

Distance from B to C = 140 m

Distance from  to D = 100 m

Total distance = 100+40+40 = 180 m

Total displacement i.e. distance between A and D is 140 m

Exercise 2

a) Distance from B to C = 35 -15 = 20 yards

b) Distance from C to D  = 5 + 35  = 30 yards

c) Distance from B to D = 5 + 15 = 20 yards

d) Displacement = 5 + 50 = 55 yards

Exercise 3

a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers

b) Displacement = 5-2 + 4 = 7 Kilometers

2.56 x 10^13 molecules of HgO equates to how many moles of HgO?

Answers

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

[tex]n = \frac{2.56 \times {10}^{13} }{6.02 \times {10}^{23} } \\ \\ \\ = 4.25 \times {10}^{ - 11} \: \: \: moles[/tex]

Hope this helps you

You want to produce a casting of sterling silver that is silver plus 13 atomic% copper. Pure silver is too soft for many applications and adding 13 atomic% copper strengthens the silver without significantly changing the color. To produce the sterling silver casting, you are going to melt commercially available pure silver and copper in a furnace, and then you will pour the liquid metal mixture into a mold. The following questions relate to this alloy. (a) In selecting a furnace, what must be the minimum value of the high-temperature capability of your selected furnace

Answers

Answer:

1085° C

Explanation:

From the phase diagram of Ag-Cu shown below:

The minimum value of the high-temp required to be selected for the furnace is: 1085° C

This is on the grounds that the furnace should be chosen to such an extent that it should melt any sort of possible material including pure Cu that melts and liquefies at the temperature of 1085° C.

or the formula C6H14 , calculate the index of hydrogen deficiency (IHD) and select all the types of unsaturation that might be present in the molecule based on the IHD. The IHD is Which types of unsaturation might be present

Answers

Answer:

See explanation

Explanation:

The term IHD means index of hydrogen deficiency. It tells us the number of missing hydrogen atoms from a given chemical formula. This number of missing hydrogen atoms corresponds to the number and type of multiple bonds in a given compound.

The formula for IHD is; IHD = C + 1 + N/2 – H/2 – X/2

C = Number of carbon atoms

N = Number of nitrogen atoms

H = Number of hydrogen atoms

X = Number of halogen atoms

Since;

N=0, X=0

Then;

IHD = C + 1 – H/2

Hence;

IHD = 6 + 1 - 14/2

IHD = 7 -7

IHD = 0

An IHD of 0 implies that there is no hydrogen deficiency or multiple bond in the molecule. It is purely a saturated compound.

Calculate the percent mass of hydrogen in ethane (C2H6).

Answers

Answer:

80.% carbon and 20.% hydrogen

Explanation:

Ethane has molecular formula C2H6. So What is the composition of carbon and hydrogen in ethane. its alot to explain but yea thats wht i got

Look at the diagram of a fuel cell below.

Which part of the fuel cell does A represent?
A. air
B. anode
C. cathode
D. electrolyte

Answers

Answer:

It is a electrolyte.

Explanation:

I took the test.

It represents an electrolyte.

What happens if electrolytes are low in the body?

A level under three can cause muscle weakness, spasms, cramps, paralysis, and respiratory problems. If it continues, kidney problems may occur.

What do electrolytes do for your body?

Electrolytes are substances that have a natural positive or negative electrical charge when dissolved in water. They help your body regulate chemical reactions, maintain the balance between fluids inside and outside your cells, and more.

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If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?

Answers

Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles[/tex]  

[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]  

According to stoichiometry :

2 moles of [tex]K[/tex] produce = 2 moles of [tex]KOH[/tex]

Thus 0.57 moles of [tex]K[/tex] will produce=[tex]\frac{2}{2}\times 0.57=0.57moles[/tex]  of [tex]KOH[/tex]

Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g[/tex]

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

2. A plant growing in response to the sunlight.
Gravitropism

Phototropism

Thigmotropism

Hydrotropism

Answers

Answer:

Phototropism.

Explanation:

Phototropism is the phenomenon of plants growing in response to light. This is a response to the plants to align or steer towards the source of sunlight, thereby becoming the 'path' to their growth.

The term "photo" means light and "tropism" means "growth" or movement towards". So, we can safely say that phototropism is the scientific and natural phenomenon of plants growing towards or in response to the sunlight.

Thus, the correct answer is phototropism.

Aeronautical engineers have to consider the weight, trust, life, and drag of an airplane to determine whether or not…

Answers

Answer:

the plane will crash, or if it is usable or not.

What is the main difference between rain and hail?

Answers

Answer:

Rain is a liquid and hail is a solid.

When 4.088 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.82 grams of CO2 and 2.829 grams of H2O were produced.

In a separate experiment, the molecular weight of the compound was found to be 78.11 amu. Determine the empirical formula and the molecular formula of the hydrocarbon.

Answers

Answer:

Empirical formula: CH

Molecular formula: C₆H₆

Explanation:

Based on the combustion of a hydrocarbon, the moles of CO₂ = Moles of Carbon in the hydrocarbon and the moles of H₂O = 1/2 moles of hydrogen in the hydrocarbon.

The empirical formula is the simplest whole number of atoms present in a molecule. With the moles of C and H we can find empirical formula:

Moles C -Molar mass CO₂ = 44.01g/mol-:

13.82g * (1mol / 44.01g) = 0.314 moles C

Moles H -Molar mass H₂O = 18.01g/mol-:

2.829g H₂O * (1mol / 18.01g) = 0.157 moles H₂O * (2mol H / 1mol H₂O) = 0.314 moles of H

The ratio of moles H: moles C:

0.314 moles / 0.314 moles = 1

That means empirical formula is:

CH

With the molecular weight and empirical formula we can find the molecular formula:

Molar mass CH = 12.01g/mol+1.01g/mol = 13.02g/mol

As the molecular weight of the molecule is 78.11amu = 78.11g/mol, there are:

78.11g/mol / 13.02g/mol = 6 times the empirical formula in the molecular formula

That means molecular formula is:

C₆H₆

If 45 grams of solid aluminum and 301 grams of ammonium perchlorate are reacted. How much excess reactant is left over? Show your work using equation editor.

Answers

Answer: Your balanced equation is 2Al + 3S --> Al_2S_3. In two separate equations, first use the 48.5g of Al to find the amount (in moles) of Al_2S_3. Then use the 62.8g of S to find the amount (in moles) of Al_2S_3. By doing these, you find which reactant (the Al or the S) produces the least amount of Al_2S_3. Since it's the S, that's the limiting reactant: you then use that 62.8g of S to find how many grams of Al will be used in the reaction. (Use the same balanced equation.) You find that 35.2g of Al will be used, then find the excess by subtracting that 35.19 from the original 48.5g. Your excess amount is 13.3g of Al!

Explanation:

hopefully this is what you were looking for <3 :)

The amount of excess reactant that left over the chemical reaction between aluminum and ammonium perchlorate is 0.9 moles.

How do we convert mass into moles?

Mass into moles (n) will be converted by using the below equation as:

n = W/M, where

W = given mass

M = molar mass

Moles of 45g of Aluminum = 45g / 27g/mol = 1.66 mol

Moles of 301g of ammonium perchlorate = 301g / 117.4g/mol = 2.56 mol

Both reactants are reacted with each other and one of the reactant is fully consumed, so the excess reactant will be calculated as:

Excess reactant = 2.56mol - 1.66mol = 0.9 moles

Hence amount of excess reactant is 0.9 moles.

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ection
9)
A compound consists of 25.9% nitrogen and 74.1% oxygen by mass. What is the empirical
formula of the compound?
A)
NOZ
B)
NO
C)
N₂Os
D)
0
1
N20
2
3
4
5
6
7
8
9
0
21
2

Answers

Answer:

69

Explanation:

the maximum amount of copper sulfate that can be dissolved in 45.0g of water at 70C is 20.0g. what is the solubility of copper sulfate at that temperature?
(in grams per 100g water)​

Answers

Answer:

That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.

Explanation:

If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O

If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O

Molecules on the surface of the ice escaping into the water happen in ————.

A. Boiling
B. Freezing
C. Condensation
D. Melting
E. Sublimation

Answers

D melting hope this was right

Give the systematic (IUPAC) name for each molecule. This molecule has the condensed formula C H 3 C O C H 3. The oxygen atom has a double bond to the center carbon. systematic (IUPAC) name: This molecule has the condensed formula C H 3 C H 2 C H 2 C O C H 3. The oxygen atom has a double bond to carbon. systematic (IUPAC) name:

Answers

Answer: The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.

Explanation:

The basic rules for naming of organic compounds are :

1. First select the longest possible carbon chain. The longest possible carbon chain should include the carbons of double or triple bonds or functional group.For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and ketones by adding the suffix -one.;

3. The numbering is done in such a way that the carbon containing the functional group gets the lowest number. While writing the name, the word root is given first , followed by the position of carbon containing the functional group followed by the suffix.

The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.

An inventor claims to have developed a new perfume that lasts a long time because it doesn't evaporate. Comment on this claim.
a. This would be impossible to make because the perfume would have to be pressurized in order to not evaporate.
b. This product is sure sweep the market making many happy customers.
c. In order to smell something, the molecules must evaporate and reach your nose. If the new perfume doesn't evaporate, it will not have an odor.
d. A perfume that does not evaporate could be toxic since the molecules never leave the skin.

Answers

Answer:

C

Explanation:

Perfume needs to evaporate in order to smell.  If this perfume didn't evaporate, it would stay as a liquid and never smell.  

It wouldn't be D, as no toxic perfumes is sold.

It's not A because perfume doesn't have to be pressurized in order to not evaporate.

It's not B, as it is a hasty conclusion to the claim.  Plus, if the perfume did have an odor, even while not evaporating, the sales would be low as the product is that good.  

Which option identifies all the bonds broken during this chemical reaction?
2H2 +O2 --> 2H2O
A. The bonds between the two hydrogen atoms and between the two oxygen atoms
B. The bonds between the two oxygen atoms
C. The bonds between oxygen and hydrogen atoms
D. The bonds between the two hydrogen atoms ​

Answers

Answer:

the bond b/w oxygen and hydrogen atom

Answer: A, the bonds between the two hydrogen atoms and between the two oxygen atoms.

What is the empirical formula for a compound that is 7.70 % carbon and 92.3 % chlorine?

Answers

Answer:

Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.

Explanation:

Our most recent mass extension happened about 65million years ago. Describe the effects of this event.

Answers

Answer:

To explain what caused this mass extinction, scientists have focused on events that would have altered our planet's climate in dramatic, powerful ways. The leading theory is that a huge asteroid or comet slammed into Earth 65 million years ago, blocking sunlight, changing the climate and setting off global wildfires.

Based on this information which of the following conclusions can be drawn about the growth rate of grass? hurry

Answers

A is the answer I know bc I take biology

Given this slope equation, calculate the x-intercept (the point at which y = 0).

y = 0.523x + 16.8

Answers

Answer:

The answer is (-31.58, 0) when rounded to 2 decimal places.

if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be added to reach the equivalence point

Answers

Answer:

14.91 mL

Explanation:

Assuming the weak acid is monoprotic, we can solve this problem using the equation:

C₁V₁=C₂V₂

Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.

We input the data:

25.00 mL * 0.1084 M = 0.1817 M * V₂

And solve for V₂:

V₂ = 14.91 mL

The volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.

How we calculate the volume?

Volume for the given solution will be calculated from the below equation:

M₁V₁ = M₂V₂, where

M₁ = Molarity of weak acid = 0.1084 M

V₁ = volume of weak acid = 25 mL

M₂ = molarity of NaOH = 0.1817 M

V₂ = volume of NaOH = to find?

On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL

Hence required volume is 14.91 mL.

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Is anyone good at chemistry if so can someone help me please ?

(NO LINKS)

Answers

In general, salts (formed during a neutralization reaction) are ionic compounds that are soluble in water and dissociate in solution into ions that conduct electricity. Out of the six statements given, there are three related statements that rehash the foregoing, and there are three related statements that are collectively incorrect.

Statements A, B, and D are (generally) true regarding salts formed during a neutralization reaction. When you consider that the net ionic equation of many acid-base neutralization reactions is H⁺(aq) + OH⁻(aq) → H₂O(l), the counterions of the H⁺(aq) and OH⁻(aq) are the aqueous spectator ions that comprise the salt. These ions are electrolytes, as they are charged species that can carry a current in solution; they are ionic compounds by definition since they're composed of cations and anions; and, as aqueous species, they're clearly dissolved in water.

Statements C, E, and F, as a whole, generally aren't true of such salts.

b) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
constant pressure?
C2H5OH burning in a simple alcohol lamp is -1277.3kJ/mol​

Answers

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

Identify the reactants and products in the following chemical equation: Zn +2HCl --> ZnCl2 + H2 *
20 points
A: Reactants: Zn & HCl Products: ZnCl2 & H2
B: Reactants: ZnCl2 & H2 Products: Zn & HCl
C: Reactants: Zn & H2 Products: ZnCl2 & HCl

Answers

Answer:

A.

Explanation:

zinc and hydrochloric acid reacts to form zinc chloride and hydrogen.

hope it helps. :)

What is the type of the synthesis reaction between Chromium + oxygen???

Answers

Answer:

Explanation: Reaction of oxygen with chromium(II) and chromium(III) porphyrins and synthesis of a .mu.-oxo chromium porphyrin derivative.

tion:

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