Calculate the pH of the three solutions described below. (25 pts)
a) 6.0 x 10-3 M HClO4
b) .0009 M Sr(OH)2
c) The solution made by mixing 25.00 mL of 0.121 M HCl + 30.00 mL of 0.100 M KOH

Answers

Answer 1

a) HClO₄ is a strong acid, and in water, it will dissociate completely into H+ and ClO₄⁻. The concentration of H⁺ in this solution is therefore equal to the concentration of HClO₄:

[H⁺] = 6.0 x 10⁻³ M

Using the definition of pH, we have:

pH = -log[H⁺]

pH = -log(6.0 x 10⁻³)

pH = 2.22

b) Sr(OH)₂ will dissociate completely into Sr²⁺ and 2OH⁻. The concentration of OH⁻ in this solution is therefore twice the concentration of Sr(OH)₂:

[OH-] = 2 x 0.0009 M

[OH-] = 0.0018 M

Using the definition of pH, we have:

pOH = -log[OH-]

pOH = -log(0.0018)

pOH = 2.74

Since pH + pOH = 14, we have:

pH = 14 - pOH

pH = 14 - 2.74

pH = 11.26

c) Solution made by mixing 25.00 mL of 0.121 M HCl and 30.00 mL of 0.100 M KOH

HCl + KOH → H2O + KCl

The moles of HCl in 25.00 mL of 0.121 M HCl are:

moles HCl = concentration x volume

moles HCl = 0.121 mol/L x 0.025 L

moles HCl = 0.003025 mol

The concentration of HCl in the final solution is:

[HCl] = moles HCl / total volume of solution

[HCl] = 0.003025 mol / (25.00 mL + 30.00 mL)

[HCl] = 0.003025 mol / 0.055 L

[HCl] = 0.055 M

Similarly, the moles of KOH in 30.00 mL of 0.100 M KOH is:

moles KOH = concentration x volume

moles KOH = 0.100 mol/L x 0.030 L

moles KOH = 0.003 mol

The concentration of OH⁻ in the final solution is:

[OH⁻] = moles OH⁻ / total volume of solution

[OH⁻] = 0.006 mol / 0.055 L

[OH⁻] = 0.109 M

Using the definition of pH, we have:

pH = 14 - pOH

pH = 14 - (-log[OH⁻])

pH = 14 - (-log(0.109))

pH = 12.06

Thus, the pH of (a) is 2.22, (b) is 11.26, and (c) is 12.06.

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Related Questions

Which of the following is true

Answers

The only true option here is option (b) Decreasing the activation energy increases the reaction rate.

What is Activation Energy

Activation Energy is the energy required to initiate a chemical reaction. When the activation energy is lowered, it becomes easier for reactant molecules to overcome the energy barrier and react, leading to an increase in the reaction rate. Therefore, decreasing the activation energy increases the reaction rate.

If you recall the statement "The activation energy of an exothermic reaction is negative". This statement is not always true. The activation energy can be positive, negative, or zero, depending on the specific reaction.

There is another statement from the question which says, "There is no relationship between activation energy and reaction rate". This statement is entirely false.

Note that the activation energy plays a crucial role in determining the reaction rate.

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Earth is the only planet in the Solar System with known, sustained life. Which of these things most likely enabled life on Earth to develop? (Choose 3) Select 3 correct answer(s) Question 4 options: Presence of liquid water Size of the Milky Way Galaxy Proximity of the Sun Composition of the atmosphere Oxygen-rich atmosphere

Answers

The three things that most likely enabled life on Earth to develop are the presence of liquid water, the composition of the atmosphere, and an oxygen-rich atmosphere, which are the first, fourth, and fifth options.

The development of life on Earth is believed to have occurred due to a combination of factors, including the presence of liquid water, the composition of the atmosphere, and the evolution of an oxygen-rich atmosphere. Water is essential for life as we know it. It provides a medium for biochemical reactions and is necessary for the functioning of many cellular processes. Earth's surface temperature and atmospheric pressure are such that water exists in its liquid state, which is ideal for life to thrive.

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at 300K, a sample of gas occupies 1.5 dm3.
Assuming the pressure remains constant, the volume of this gas at 600K would be?

Answers

If the pressure remains constant, the volume of the gas is directly proportional to the absolute temperature. The absolute temperature is the temperature in Kelvin (K) and is equal to the Celsius temperature (°C) plus 273.15.

So, to find the volume of the gas at 600K, we can use the formula:

(Volume at 600K) = (Volume at 300K) x (Temperature at 600K / Temperature at 300K)

(Temperature at 600K) = (600°C + 273.15) = 873.15K

(Temperature at 300K) = (300°C + 273.15) = 573.15K

So, the volume of the gas at 600K would be:

(Volume at 600K) = (1.5 dm³) x (873.15K / 573.15K) = 2.28 dm³

Therefore, the volume of the gas at 600K would be 2.28 dm³.

6. Calculate the pH of a buffer prepared by mixing 0.10 mol-L-' acetic acid (CH;COOH, HAc) and
0.10 mol L NaOH solution with the volume ratio of 3:1. (Answer pH = 4.45

Answers

When acetic acid (HAc) reacts with sodium hydroxide (NaOH), it forms sodium acetate (NaAc) and water (H2O):

CH3COOH + NaOH → CH3COONa + H2O

The resulting solution will contain both the weak acid (HAc) and its conjugate base (Ac-). The pH of the buffer can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([Ac-]/[HAc])

where pKa is the dissociation constant of HAc, [Ac-] is the concentration of the acetate ion, and [HAc] is the concentration of acetic acid.

The pKa of acetic acid is 4.76.

To calculate the concentrations of HAc and Ac-, we can use the volume ratio of 3:1 to find the total volume of the solution:

Total volume = 0.10 L HAc + 0.03 L NaOH = 0.13 L

The concentration of HAc is:

[HAc] = 0.10 mol / 0.13 L = 0.769 mol/L

The concentration of Ac- is:

[Ac-] = 0.03 mol / 0.13 L = 0.231 mol/L

Now we can substitute these values into the Henderson-Hasselbalch equation:

pH = 4.76 + log([0.231]/[0.769]) = 4.45

Therefore, the pH of the buffer is 4.45.
The pKa of acetic acid is 4.76. Therefore, the pH of the buffer can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where [A-]/[HA] is the ratio of the concentration of the conjugate base to the concentration of the weak acid. In this case, acetic acid is the weak acid and its conjugate base is acetate (CH3COO-).

The volume ratio of the acetic acid and NaOH solutions is 3:1. Therefore, we can assume that we have 0.075 L of acetic acid solution and 0.025 L of NaOH solution.

The concentration of acetic acid is 0.10 mol-L¹. Therefore, the number of moles of acetic acid is:

moles of HAc = concentration × volume = 0.10 mol-L¹ × 0.075 L = 0.0075 mol

Since the volume of the NaOH solution is 0.025 L and its concentration is 0.10 mol-L¹, the number of moles of NaOH is:

moles of NaOH = concentration × volume = 0.10 mol-L¹ × 0.025 L = 0.0025 mol

The NaOH reacts with the HAc to form water and acetate:

NaOH + HAc → NaAc + H2O

Since the number of moles of NaOH is less than the number of moles of HAc, all of the NaOH will react with the HAc. Therefore, the number of moles of acetate formed is:

moles of acetate = moles of NaOH = 0.0025 mol

The number of moles of HAc remaining after the reaction is:

moles of HAc remaining = moles of HAc - moles of acetate = 0.0075 mol - 0.0025 mol = 0.0050 mol

The total volume of the buffer is 0.075 L + 0.025 L = 0.1 L. Therefore, the concentration of acetate is:

concentration of acetate = moles of acetate / volume of buffer = 0.0025 mol / 0.1 L = 0.025 mol-L¹

The concentration of HAc is:

concentration of HAc = moles of HAc remaining / volume of

so what would these items be ranked, from highest PH to lowest PH \\

milk
soda
baking soda
water vinegar
ammonia
glass cleaner

Answers

Answer:

From highest pH to lowest pH, the ranking of the items would be:

1. Ammonia (pH ~ 11-12)

2. Baking soda (pH ~ 8.3)

3. Glass cleaner (pH ~ 7-10)

4. Water vinegar (pH ~ 2.5-3.5)

5. Milk (pH ~ 6.5-6.7)

6. Soda (pH ~ 2.4)

Explanation:

what is the answer to this question and how do i figure it out?

Answers

The m/z that can be seen in propan - 1 ol but not propan - 2 ol is m/z = 15

What is the mass spectrum?

The distribution of ions produced by a sample in a mass spectrometer is depicted graphically as the mass spectrum.  A sample is ionized in a mass spectrometer, where the resultant ions are sorted according to their m/z ratio.

Each peak in the mass spectrum corresponds to a certain m/z ratio and represents one of the several ions that the sample produced. Thus the propan - 1 ol has the m/z = 15

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The rate of deforestation to create new buildings and farmland has increased over the last 100 years. What effect could this have on the atmosphere in the future?

Answers

The increase in deforestation can have a significant impact on the atmosphere in the future, mainly by reducing the number of trees that absorb carbon dioxide during photosynthesis.

Trees take in carbon dioxide and release oxygen as a byproduct, reducing the amount of carbon dioxide in the atmosphere. However, when trees are cut down, the carbon they have stored is released back into the atmosphere, contributing to increased levels of greenhouse gases.

The increase in greenhouse gases can lead to global warming and climate change, which can have a range of negative effects on the environment and human health, such as rising sea levels, increased frequency and severity of natural disasters, and more intense heat waves. Additionally, deforestation can lead to soil erosion, loss of biodiversity, and disruption of local ecosystems.

It is important to find ways to reduce deforestation and promote sustainable land use practices to mitigate the potential impacts on the atmosphere and the environment as a whole.

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What is hydrogen fuel cell technology

Answers

Answer:

By combining hydrogen and air in the presence of a catalyst, a fuel cell generates electricity to drive an electric motor, with water vapor as the only by-product. So, compared to a battery, a fuel cell is an energy converter rather than a storage device.

Explanation:

What is the numerical value of Kc
for the following reaction if the equilibrium mixture contains 0.032 M
N2O4 and 0.24 M NO2?

N2O4(g)⇌2NO2(g)

Answers

The expression for the equilibrium constant (Kc) for the given reaction is:

Kc = [NO2]^2 / [N2O4]

Where [NO2] and [N2O4] are the molar concentrations of NO2 and N2O4, respectively, at equilibrium.

Substituting the given equilibrium concentrations into the expression for Kc, we get:

Kc = (0.24 M)^2 / (0.032 M) = 1.8 M

Therefore, the numerical value of Kc for the given reaction, when the equilibrium mixture contains 0.032 M N2O4 and 0.24 M NO2, is 1.8 M.

Please name this compound.

Answers

Answer:

3 methyl hexene

Explanation:

Name the property shown.

9. 2 x= x 2

td

11. 7(z+ y) = 7z+ 7y

10. 231= 23

12. a + (2b + 3c) = (a + 2b) + 3c

Why are zinc sulfate and copper sulfate solutions used for the battery? Why not just plain water?

Answers

Answer:

Combinations of certain metals, such as copper and zinc, will produce electrical activity when placed in special solutions called electrolytes. The two metals form the electrodes. The electrolyte creates a chemical action that causes the zinc to form positive ions and the copper to form negative ions.

Water can't be used due to copper sulfate being highly soluble in water.

The student who represents Earth sees different stars from different positions in the circle. How does this model suggest evidence that Earth circles the sun once a year?

Answers

Earth orbits the sun in a predictable pattern. The pattern of Earth's seasons depend on how much sunlight reaches different areas of Earth as the planet moves around around the sun. It is the earth sun model which shows that the earth circles the sun once a year. So revolution is responsible for it.

Earth has a nearly circular orbit around the sun, Earth also rotates around its north-south axis, an imaginary line passing through earth from pole to pole. Every place on the planet gets 12 hours of light and 12 hours of dark each day.

The temperature conditions on the planet change depending on the distance from the sun. There are colder temperatures at the poles and warmer temperature at the equator.

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If 4.53g Ar are added to 1.12 atm He in a 2.00 L cylinder at 27.0 Celsius degree

What is the total of gaseous mixture?

Answers

The total gaseous mixture is 4.48 g.

The total gaseous mixture can be calculated using the ideal gas law: PV = nRT.

First, we need to convert the temperature to Kelvin: 27.0°C + 273.15 = 300.15 K.

Next, we can use the ideal gas law to calculate the number of moles of each gas:

For He: n = (1.12 atm) (2.00 L) / (0.08206 L·atm/mol·K) (300.15 K) = 0.0906 mol

For Ar: n = (4.53 g) / (39.95 g/mol) = 0.113 mol

The total number of moles of gas in the mixture is then:

n(total) = n(He) + n(Ar) = 0.0906 mol + 0.113 mol = 0.204 mol

Finally, we can calculate the total mass of the mixture:

m(total) = n(total) × M(avg)

where M(avg) is the average molar mass of the mixture, which can be calculated as:

M(avg) = (M(He) + M(Ar)) / 2 = (4.003 g/mol + 39.95 g/mol) / 2 = 21.98 g/mol

Thus,

m(total) = 0.204 mol × 21.98 g/mol = 4.48 g

Therefore, The total weight of the gaseous mixture is 4.48 g.

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How many liters of a 3.4 m isopropanol solution can be made with 78 g of isopropanol

Answers

Answer:

You can make 2.29 L of 3.4 M isopropanol solution with 78 g of isopropanol.

Explanation:

Determine the density of a sample of ozone gas, O3 at 755 Torr and 18C.

Answers

The concept ideal gas equation is used here to determine the density of the ozone gas. The gas equation obtained by the combination of Boyle's law, Charles's law and Avogadro's law is known as the ideal gas equation.

Density is the measurement of how tightly a material is packed together. It is known as the mass per unit volume.

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 1 × 0.0821 × 291 / 0.9966 = 23.97 L

755 Torr = 0.9966 atm

18°C = 291 K

Density = Mass / Volume

d = 48 / 23.97

d = 2.002 g/L

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Calculate the percentage by mass of oxygen in copper (II) tetraoxosulphate (VI) (Cu = 64.0, S = 32.0, 0 = 16.0) ​

Answers

The percentage by mass of oxygen in CuSO4 is 40%.

What is the percentage by mass of an atom in a compound?

Finding the compound's molar mass is the first step in calculating the percentage of an atom by mass. The atomic masses of all the atoms in the compound are added up to determine the molar mass, which is the mass of one mole of the molecule.

We have the molar mass of the CuSO4 is given  as;

64 + 32 + 4(16) = 160 g/mol

Then we have the percentage by mass of oxygen as;

4(16)/160 * 100/1

40%

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find the ΔG°rxn for a reaction that has a K = 17.23 at 371 K. Is the reaction spontaneous. Note: R = 8.314 J/mol.K

Answers

The value of ΔG°rxn is - 6979 J/mol, and the reaction is spontaneous.

The change in Gibbs free energy (ΔG°rxn) for a reaction can be calculated using the equation;

ΔG°rxn = -RT ln(K)

where; R = gas constant = 8.314 J/mol.K

T = temperature in Kelvin (K)

K = equilibrium constant for the reaction

Given;

K = 17.23

T = 371 K

R = 8.314 J/mol.K

Plugging in the given values into the equation;

ΔG°rxn = - (8.314 J/mol.K) × (371 K) * ln(17.23)

Using a calculator, we can calculate the natural logarithm of 17.23:

ln(17.23) ≈ 2.848

Plugging this value back into the equation;

ΔG°rxn = - (8.314 J/mol.K) × (371 K) × 2.848

ΔG°rxn ≈ - 6979 J/mol

The negative value of ΔG°rxn indicates that the reaction is spontaneous, as ΔG°rxn < 0.

Therefore, the reaction will occur spontaneously in the forward direction at 371 K when the equilibrium constant (K) is 17.23.

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b) 2.38 gm of a metal on treatment with nitric acid and sub sequent ignition gave 3.022 gm of the oxide. Specific heat of the metal is 0.055, calculate the extra atomic weight.

Answers

The extra atomic weight in a metal on treatment with nitric acid is 100.361 g/mol.

How to calculate extra weight?

The first step is to calculate the mass of oxygen in the oxide formed:

Mass of oxygen = Mass of oxide - Mass of metal

Mass of oxygen = 3.022 g - 2.38 g

Mass of oxygen = 0.642 g

Use the specific heat of the metal to determine its identity:

specific heat = 6.4 / atomic weight

Solving for atomic weight:

atomic weight = 6.4 / specific heat

atomic weight = 6.4 / 0.055

atomic weight = 116.36 g/mol

The atomic weight to calculate the extra atomic weight:

extra atomic weight = atomic weight - atomic weight of oxygen

extra atomic weight = 116.36 g/mol - 15.999 g/mol

extra atomic weight = 100.361 g/mol

Therefore, the extra atomic weight is 100.361 g/mol.

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a 40 ml solution containing .30 M Ti+3 was titrated with 0.75 M Sn+2. what potential at the equivalence point if the resulting solution is
measured against a reference electrode

Answers

In this redox reaction, Ti+3 is oxidized to Ti+4, and Sn+2 is reduced to Sn+4:

Ti+3 + Sn+2 → Ti+4 + Sn+4

The balanced equation shows that one mole of Ti+3 reacts with one mole of Sn+2. We can use this to calculate the number of moles of Sn+2 required to react completely with the Ti+3 in the solution:

n(Sn+2) = (0.30 mol/L) x (0.040 L) = 0.012 mol

The volume of Sn+2 required to react with the Ti+3 can be calculated using the molarity and the number of moles:

V(Sn+2) = n(Sn+2) / [Sn+2] = 0.012 mol / 0.75 mol/L = 0.016 L = 16 mL

At the equivalence point, all of the Ti+3 has reacted with the Sn+2, so the resulting solution contains only Ti+4 and Sn+4. The potential at the equivalence point can be calculated using the Nernst equation:

E = E° - (RT/nF) x ln(Q)

where E° is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred in the reaction, F is the Faraday constant, and Q is the reaction quotient.

The standard cell potential can be calculated using the reduction potentials for the half-reactions:

Ti+4 + 2 e- → Ti+3 E° = -0.15 V
Sn+4 + 2 e- → Sn+2 E° = 0.15 V

The overall cell potential is the sum of the reduction potentials:

E°cell = E°reduction (cathode) - E°reduction (anode) = 0.15 V + 0.15 V = 0.30 V

At the equivalence point, the reaction quotient Q is equal to the equilibrium constant K:

K = [Ti+4] / [Sn+4]

The concentrations of Ti+4 and Sn+4 can be calculated from the number of moles and the total volume of the solution:

n(Ti+4) = n(Sn+2) = 0.012 mol
V(total) = 0.040 L + 0.016 L = 0.056

Tin hydroxide, Sn(OH)4, is an extremely insoluble substance. In an acidic buffer with a pH of 1.0, the solubility of Sn(OH)4 is 1.0 x 10^-7M. Calculate the Ksp for Sn(OH)4.

Answers

the Ksp for Sn(OH)₄ is 2.56 × 10⁻⁵

The solubility product constant is the equilibrium constant for the dissolution of a solid substance into an aqueous solution. It is denoted by the symbol Ksp.

The solubility product is a kind of equilibrium constant and its value depends on temperature. Ksp usually increases with an increase in temperature due to increased solubility.

Given,

Solubility of Sn(OH)₄ = 1 × 10⁻⁷

Sn(OH)₄ = Sn⁴⁺ + 4OH⁻

Ksp = s × (4s)⁴

= 256 s⁵

Ksp = 256 × 1 × 10⁻⁷

= 2.56 × 10⁻⁵

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Classify each element. Note that another term for main group is representative, another term for semimetal is metalloid, and the
inner transition metals are also called the lanthanide and actinide series.
Main-group metal
(representative metal)
Ru
Ta
Main-group nonmetal
(representative nonmetal)
As
Rn
Main-group
semimetal
(metalloid)
Answer Bank
In
Transition metal
Eu
Se
Inner transition metal.
(lanthanide/actinide)

Answers

Main-group metal (representative metal): Ru, Ta. Main-group nonmetal (representative nonmetal): As, Rn. Main-group semimetal (metalloid): In. Transition metal: Eu.  Inner transition metal (lanthanide/actinide): Se is not an inner transition metal. Therefore, the correct answer for Se should be replaced with an inner transition metal (lanthanide or actinide) .Possible replacements for Se: La (lanthanide), Am (actinide).

Main group elements can be further classified as metals, nonmetals, or metalloids (also known as semimetals) based on their physical and chemical properties. Metals are typically shiny, good conductors of heat and electricity, and malleable. Nonmetals are typically brittle, poor conductors of heat and electricity, and have low melting and boiling points. Metalloids have properties of both metals and nonmetals and are semiconductors.

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What mass of oxalic acid is required to prepare 0.01 N solution in 5 liters?

Answers

Answer:

The mass of oxalic acid required to prepare 0.01 N solution in 5 L is 0.78 g.

Explanation:

The rate constant for the first-order reaction below is 0.0739 s-1
If the reaction is begun with an initial concentration of A equal to 0.95 M. what is the concentration of A after 38.02 s?
______M

Answers

The concentration of A after 38.02 s is 0.057 M.

What is the concentration of A after 38.02 s?

The concentration of A after 38.02 s is calculated by using rate equation as follows;

[A] = [A]₀e^(-kt)

where;

k is the rate constantA is the concentration of reactant AA₀ is the initial concentration of A at t=0t is the time elapsed since the reaction started

The concentration of A after 38.02 s is calculated as;

[A] = [A]₀e^(-kt)

   = 0.95 M e^(-0.0739 s⁻¹  x 38.02 s)

   = 0.057 M

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Change element and compound names into chemical formulas for lithium hydroxide + hydrogen acetate-lithium acetate+water

Answers

The balanced reaction equation is;

LiOH + HC2H3O2 → LiC2H3O2 + H2O

What is reaction equation?

If we talk about a reaction equation, what we mean is the way that there can be a combination of the reactants and the products. We always show this by the use of an equation in which the reactants are on the left and the products are on the right side.

Now we have the word equation;

lithium hydroxide + hydrogen acetate-lithium acetate+water

The balanced reaction equation is shown above in the for the reaction that is thus stated.

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3. If I have 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 K, what is the pressure inside the container?​

Answers

Answer:

The pressure would be 1.65 atmospheres.

Which phrase best defines eutrophication

Answers

Answer:

A treatment that reduces pollution - a lack of oxygen in a body of water

- an overgrowth of microorganisms

Explanation:

The process by which an aquatic body of water gets enriched with too many nutrients, mainly nitrogen and phosphorus, is known as eutrophication.

These nutrients encourage the excessive development of whom?

These nutrients encourage the excessive development of algae and other aquatic plants, which overpopulates the water with organic materials.

As a result, the water's oxygen content drops, which has a detrimental effect on the equilibrium of aquatic ecosystems.

Damage to aquatic animals, oxygen depletion, hazardous algal blooms, and water quality degradation can all result from eutrophication.

Although eutrophication is a long-term natural process, human activity may drastically speed it up. The main causes of eutrophication are excessive nutrient runoff from agriculture, poor waste management, and urban growth without adequate stormwater management.

Therefore, reducing the effects of eutrophication and maintaining the health of aquatic ecosystems depend on regulating nutrient inputs and implementing sustainable practises.

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List at least five terms from the introduction that you can use as key words in your search. edmentum science

Answers

Finding and examining search phrases that people enter through search engines for the purpose to utilise that information is the process of conducting keyword research.

The phrases and words that people employ when using search engines in order to locate what they're searching for are known as keywords. For instance, you may type "mens leather coat" into a search engine to get a new jacket. The phrase is still regarded as a keyword even though it has numerous words.

Keywords are concepts and themes that describe the subject matter of your article. They are the phrases and words that users type into search engines to find information, commonly referred to as "search queries" within SEO. If you scale down the size of all the content on your page, including the images, videos, prose, and so on.

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Answer:

idek

Explanation:

Write short note on the
-physical and chemical methods
of monitoring the rate of
chemical reaction

Answers

Answer:

Physical and chemical methods can be used to monitor the rate of a chemical reaction. Physical methods measure changes in properties like temperature, pressure, or volume. Chemical methods track reactant consumption or product formation using techniques like titration or spectrophotometry. The choice of method depends on the reaction being studied, and scientists use these methods to gain insight into reaction kinetics and optimize conditions for better efficiency and selectivity.

H₂SO4what compound is this

Answers

Answer:

H₂SO₄ is sulfuric acid

Explanation:

H₂SO₄ is a chemical formula for sulfuric acid. It is a highly corrosive and dense liquid that is commonly used in many industrial processes, such as the production of fertilizers, dyes, detergents, and pharmaceuticals. Sulfuric acid is also used in car batteries and as a laboratory reagent.

What is the rate of the reaction in L/min

Answers

The rate of the reaction is obtained from the calculation as 0.022 L/min.

What is the rate of reaction?

We know that the rate of reaction has to do with the change in the volume or the concentration of one of the reactant which the volume of the oxygen have been chosen for the particular question that we are dealing with here.

Thus;

Rate of reaction = Change in the volume of oxygen/Time

= v2 - v1/t

= 0.35 L - 0.02 L/15 min

=0.022 L/min

Thus, we can see that the rate of the reaction can be obtained as 0.022 L/min.

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The basilica vein terminates by emptying into the 23) What type of medium is frequently used in post-Internet art?A) TapestryB) InstallationC) AcrylicD) Digital software Where should you park an emergency vehicle at a collision scene with no hazards? The mass of a bowling ball is 9ibs and the volume is 135 in. How many lbs per cubic inch is its density? Round to the nearest hundreth Differentiate a regular savings account from a CD, a money market fund, and a money market deposit account. Kaveh and Jessa baked a blueberry pie. They each ate 2/8 of the pie. How much of the pie is left? Learning turns into 'validated learning' when assumptions and goals can be assessed through results. What is a key way for a Product Owner to apply validated learning? Who is the primary partner in the Domains/Activities/Partners model?ParentsTeachersStudentsAdministrators A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 8.5 to 15.5 on the number line. A line in the box is at 12. The lines outside the box end at 3 and 27. The graph is titled Super Fast Food.A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 9.5 to 24 on the number line. A line in the box is at 15.5. The lines outside the box end at 2 and 30. The graph is titled Burger Quick.Which drive-thru typically has more wait time, and why? Burger Quick, because it has a larger median Burger Quick, because it has a larger mean Super Fast Food, because it has a larger median Super Fast Food, because it has a larger mean The ability of water to rise inside a tube of narrow diameter against the pull of gravity is called Since we know how long after death each species arrives at a body, what can we use ADH to estimate? two ideal gasses have the same mass density and the same absolute pressure. one of the gasses is helium, and its temperature is 175 K. The other gas is neon (Ne). What is the temperature of the neon? Let {N(t) : t 0} be a conditional Poisson process with rate Lthat is distributed as Exp(). If T1 is the arrival time of therst event of the process, show that the pdf of T1 is givenby 11. Check the boxes for the translation(s) for each equation.-(x - 2) + 43xx + 3ReflectionShift LeftShift RightShift UpShift DownVertical ShrinkVertical Stretchx+22321x1-5 Pat Middleton owns a non-depreciable capital asset that originally cost $20,000 and is now worth $80,000. Pat transfers the asset to a corporation, receiving as payment debt of $60,000 and preferred shares with a value of $20,000. Pat and the corporation will elect under Section 85 to avoid paying tax on the transfer.Determine the appropriate transfer price under Section 85. Determine the cost of the asset for the corporation, and the ACB and PUC for the preferred shares received as consideration. what is x if f (x) = 4x + 13 = 9 with panic disorder criteria B, at least ___ of the panic attacks has been followed by ___ month or more of 1 or both of what 2 things? (PS) Traditional project management approaches do allow changes through a formal change control process. What is the main issue with this? At the beginning of the year, Mirmax set its predetermined overhead rate for movies produced during the year by using the following estimates: overhead costs, $1,680,000, and direct labor costs, $480,000. At year- end, the company's actual overhead costs for the year are $1,670,000 and actual direct labor costs for the year are $480,000 1. Determine the predetermined overhead rate using estimated direct labor costs. 2. Enter the actual overhead costs incurred and the amount of overhead cost applied to movies during the year using the predetermined overhead rate. Determine whether overhead is over- or underapplied (and the amount) for the year. 3. Prepare the entry to close any over- or underapplied overhead to Cost of Goods Sold. Complete this question by entering your answers in the tabs below. Help me (Question 3) (Q3)Answer:Explanation: