calculate the rate per litre of which a car uses petrol if it uses 20 litre of petrol to travel 180 km​

Answer:

Coordinates of G = [tex](2,0)[/tex]

Step-by-step explanation:

Given: Three vertices of parallelogram DEFG are D(-4,-2), E(-3,1) and F(3, 3).

To find: coordinates of G

Solution:

Midpoints of a side joining points [tex](a,b),\,(c,d)[/tex] are given by [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

Diagonals of a parallelogram bisect each other.

So,

Midpoint of DF = Midpoint of EG

Midpoint of DF = [tex](\frac{-4+3}{2},\frac{-2+3}{2})=(\frac{-1}{2},\frac{1}{2})[/tex]

Midpoint of EG = [tex](\frac{-3+x}{2},\frac{1+y}{2})[/tex]

Let coordinates of G be [tex](x,y)[/tex]

Therefore,

[tex](\frac{-1}{2},\frac{1}{2}) =(\frac{-3+x}{2},\frac{1+y}{2})\\\\\frac{-1}{2}=\frac{-3+x}{2},\,\frac{1}{2}=\frac{1+y}{2}\\\\-1=-3+x,\,1=1+y\\\\x=-1+3,\,y=1-1\\x=2,\,y=0[/tex]

So,

Coordinates of G = [tex](2,0)[/tex]

Answer:

it's not fair, because it's only a 1 in 6 chance of rolling gold.

it would be fair if 3 of the 6 sides were gold

Answer:

it aint fair it only 1/6 listen to the other guy

Step-by-step explanation:

i needed points sorry

Answer:

An arc is a segment of a circle around the circumference. An arc measure is an angle the arc makes at the center of a circle, whereas the arc length is the span along the arc. This angle measure can be in radians or degrees, and we can easily convert between each with the formula  

π

r

a

d

i

a

n

s

=

180

°

.

Step-by-step explanation:

Answer:

∆ABC ≅ ∆EFD by the SSS Congruence Theorem.

Step-by-step explanation:

The digram shows that 3 sides of ∆ABC are congruent to the 3 sides of ∆ EFD.

Based on the Side-Side-Side Congruence Theorem (SSS), we can conclude that both triangles are congruent to each other.

Therefore:

∆ABC ≅ ∆EFD by the SSS Congruence Theorem.

Answer:

Basically this is because division can be thought of as how many times does the divisor have to be multiplied in order to produce the dividend.

So you would need to multiply 1 8 times in order to produce the dividend,

Similarly, 10 goes into 80 8 times. The zeros are simply cancelled out in the division.

Answer:

41

Step-by-step explanation:

Answer:

3015

Step-by-step explanation:

Answer:B

Step-by-step explanation:  ok its B because i need some $$$

Answer:

D and E

Step-by-step explanation:

The question asks which one would always form an image that is congruent to the pre-image.

Note that Translation, Reflection, and Rotation do not change the size or shape of the pre-image while Dilation will change the size of your pre-image.

Therefore, the most likely answer would be options D and E that do not include dilation in their series of transformations so the image will not change its size making it congruent to the pre-image.

Answer:

1/2 ft or 6 inches

Step-by-step explanation:

1/6 of 3 yards = 1/2 ft or 6 inches

Answer:

b) The number of vinyl album sales in the country in the year 2020 will be 18.3 million.

Step-by-step explanation:

Given - The number of vinyl album sales (in millions) in a country x years after 2010 can be modeled by y = 0.12 x² + 0.3 x +3.3  for 2010 through 2016.

To find - Use this model to predict the number of vinyl album sales in the country in the year 2020 where  x = 10

a) The number of vinyl album sales in the country in the year 2020 will be 20.5 million.

b) The number of vinyl album sales in the country in the year 2020 will be 18.3 million.

c) The number of vinyl album sales in the country in the year 2020 will be 7.74 million.

d) The number of vinyl album sales in the country in the year 2020 will be 21.12 million.

Proof -

Given that,

The equation be - y = 0.12 x² + 0.3 x +3.3

Now,

Put x = 10 in above equation we get

y = 0.12×10² + 0.3×10 +3.3

  = 0.12×100 + 3 + 3.3

  = 12 + 6.3 = 18.3

⇒y = 18.3

∴ we get

The number of vinyl album sales in the country in the year 2020 will be 18.3 million.

So,

The correct option be - b) The number of vinyl album sales in the country in the year 2020 will be 18.3 million.

Step-by-step explanation:

4a² - 8ab + 4b²

= (2a)² - 2 * 2a * 2b + (2b) ²

= (2a - 2b) ²

Hope it helps :)

Answer:

3 pancakes

Step-by-step explanation:

Answer:

3 pancakes

Step-by-step explanation:

Multiply 3/4 by 4/1 and you get 12/4 (multiple the top numbers and the bottom numbers). Simplify that down, 12 divided by 4 is 3. So, 3 whole pancakes

Answer:

continuity correction factor

Step-by-step explanation:

A value of 0.5 that is added to and/or subtracted from a value of x when the continuous normal distribution is used to approximate the discrete binomial distribution is called continuity correction factor.

Reason -

A continuity correction factor is used when you use a continuous probability distribution to approximate a discrete probability distribution.

The answer is 3) Pythagorean.

A trigonometric identity derived from the Pythagorean theorem is called a Pythagorean identity.

Mathematically, the Pythagorean theorem states that

Hypotenuse^2 = Adjacent^2 + Opposite^2

Divide through by Hypotenuse^2

This gives

1 = cos^2(x) + sin^2(x)

Rewrite as:

cos^2(x) + sin^2(x) = 1

As a general rule, the above represents the basic Pythagorean identity.

Hence, the word that completes the blank is Pythagorean.

Read more about Pythagorean identity at:

https://brainly.com/question/1969941

#SPJ2

Answer:

chale. necesita. 20 caracteres

This question is incomplete, the complete question is;

Suppose that a researcher using data on class size (CS) and average test scores from 100 third grade classes, estimates the following OLS regression. Test-Score = 520.4 - 5.82 × CS, n = 100, R² = 0.08, SER = 11.5

a. A class has 22 students. What is the regression's prediction for this classroom's average test score?

b. Last year, a class had 19 students, and this year it has 23 students. What is the regression's prediction for the change in the classroom average test score?

c. The sample average class size across the 100 classrooms is 21.4. What is the sample average of the test scores across the 100 classrooms?

d. What is the sample standard deviation of test scores across the 100 classrooms?

Answer:

a)

the regression's prediction for this classroom's average test score is 392.36

b)

the regression's prediction for the change in the classroom average test score is -23.28

c)

the sample average of the test scores across the 100 classrooms is 395.852

d)

the sample standard deviation of test scores across the 100 classrooms is 11.92887

Step-by-step explanation:

Given the data in the question;

Test-Score = 520.4 - 5.82 × CS, n = 100, R² = 0.08, SER = 11.5 -----1

the general formula for the average test score is as follows;

Test score = ^β₀ + ( ^β₁ × CS ) -------- 2

the general for change in test score ;

ΔTest Score = β[tex]_{ class-size[/tex] × ΔClass size  -------- 3

General formula for the sum of squared residuals SSR

SSR = ( n - 2 ) SER² ----- 4

General formula for total sum of squares TSS

TSS = SRR / 1 - R² -------- 5

General formula for sample standard deviation;

Sy = √(TSS / (n-1) )  ------ 6

now, from the given formula;

^β₀ = 520.4

aslo, β[tex]_{ class-size[/tex] = ^β₁ =  - 5.82

so

a) A class has 22 students. What is the regression's prediction for this classroom's average test score?

given that class size CS is 22, to get  the regression's prediction for this classroom's average test score, we make use of formula 2 above;

Test score = ^β₀ + ( ^β₁ × CS )

so we substitute

Test score = 520.4 + ( -5.82  × 22 )

Test score = 520.4 + ( - 128.04 )

Test score = 520.4 - 128.04

Test score = 392.36

Therefore,  the regression's prediction for this classroom's average test score is 392.36

b) Last year, a class had 19 students, and this year it has 23 students. What is the regression's prediction for the change in the classroom average test score.

we make use of formula 3 above

ΔTest Score = β[tex]_{ class-size[/tex] × ΔClass size

we substitute

ΔTest Score = -5.82 × ( 23 - 19 )

ΔTest Score = -5.82 × 4

ΔTest Score = -23.28

Therefore,  the regression's prediction for the change in the classroom average test score is -23.28

c) The sample average class size across the 100 classrooms is 21.4. What is the sample average of the test scores across the 100 classrooms?

we make use of formula 2 above;

Test score = ^β₀ + ( ^β₁ × CS )

we substitute

Test score = 520.4 + ( -5.82 × 21.4 )

Test score = 520.4 + ( -124.548 )

Test score = 520.4 - 124.548

Test score = 395.852

Therefore, the sample average of the test scores across the 100 classrooms is 395.852

d) What is the sample standard deviation of test scores across the 100 classrooms.

first we make use of formula 4 above; to calculate the sum of squared residuals SSR

SSR = ( n - 2 ) SER²

we substitute

SSR = ( 100 - 2 ) (11.5)²

SSR = 98 × 132.25

SSR = 12,960.5

Also, for total sum of squares TSS, we use formula 5

TSS = SRR / 1 - R²

we that R² = 0.08; from the given formula

so we substitute

TSS = 12,960.5 / 1 - 0.08

TSS = 12,960.5 / 0.92

TSS = 14087.5

so, the sample standard deviation will be;

from formula 6 above

Sy = √(TSS / (n-1) )

we substitute

Sy = √(14087.5 / (100-1) )

Sy = √(14087.5 / 99)

Sy = √142.297979

Sy = 11.92887

Therefore, the sample standard deviation of test scores across the 100 classrooms is 11.92887

Answer:

D

Step-by-step explanation:

Ed2021

Answer:

✓2=1.41421

✓5=2.23607

✓8=2.82842

✓11=3.31662

✓14=3.74166

Step-by-step explanation:

Therefore the numbers are increasing by three so they cant be perfect square

9514 1404 393

Answer:

  squares are of the form 3n or 3n+1; the sequence is of the form 3n-1, so none of the sequence will be a square

Step-by-step explanation:

The given arithmetic sequence has first term 2 and common difference 3, so its explicit formula is ...

  an = 2 +3(n -1) = 3n -1 . . . . for counting numbers n

__

All integers are of one of these forms: 3n-1, 3n, 3n+1, for some integer n. The squares of these are ...

  (3n -1)² = 9n² -6n +1 = 3(3n² -2) +1 = 3k+1 for some k

  (3n)² = 3(3n²) = 3k for some k

  (3n +1)² = 9n² +6n +1 = 3(3n² +2) +1 = 3k+1 for some k

Note that none of these squares is of the form 3n -1.

Hence, the square of an integer cannot be in the given sequence.

Answer:

what

Step-by-step explanation:

where is the question its not showing

Answer:

4

Step-by-step explanation:

the total height is 12 and the first half of the shape has a height of 8 so the other part is 4.

Answer:

so the answer is 5

Step-by-step explanation:

the equation will be for this is

7x + 20 = 55

7x = 55-22

7x = 35

x = 35÷7

x=5

Answer:

x ≥ -6

Domain is just all of the possible x values in a list

Answer: Y = -x/2 + 12.5

Step-by-step explanation:

You wrote the equation strange so i don't really know if the end of the equation is a 25 or not

Answer:

$2954.91 end of year eight

Step-by-step explanation:

2000 x 1.05^8 = 2000 x 1.04775 = $2954.91

Proof:

2000 x 1.05 = 2100 end of year one

2100 x 1.05 = 2205 end of year two

2205 x 1.05 = 2315.25 end of year three

2315.25 x 1.05 = 2431.01 end of year four

2431.01 x 1.05 = 2552.56 end of year five

2552.56 x 1.05 = 2680.19 end of year six

2680.19 x 1.05 = 2814.20 end of year seven

2814.20 x 1.05 = $2954.91 end of year eight

Answer:

0.2159 = 21.59% probability this student’s score will be at least 1500.

Step-by-step explanation:

To solve this question, we need to understand the normal distribution and conditional probability.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Recognized student(scored more than 1350)

Event B: Score of at least 1500.

SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200

This means that [tex]\mu = 1100, \sigma = 200[/tex]

Probability of being recognized.

1 subtracted by the pvalue of Z when X = 1350. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1350 - 1100}{200}[/tex]

[tex]Z = 1.25[/tex]

[tex]Z = 1.25[/tex] has a pvalue of 0.8944.

1 - 0.8944 = 0.1056

So [tex]P(A) = 0.1056[/tex]

Probabibility of being recognized and scoring at least 1500.

Intersection between more than 1350 and more than 1500 is more than 1500. So this probability is 1 subtracted by the pvalue of Z when X = 1500.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1500 - 1100}{200}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a pvalue of 0.9772

1 - 0.9772 = 0.0228

So, [tex]P(A \cap B) = 0.0228[/tex]

What is the probability this student’s score will be at least 1500?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0228}{0.1056} = 0.2159[/tex]

0.2159 = 21.59% probability this student’s score will be at least 1500.