Calculate the volume of 0.875 mol/dm3 NaOH solution needed to make up a 100.0 ml of a diluted solution with a concentration of 0.235 mol/dm3 NaOH.

According to given statement NaCI compounds are more likely to dissolve in water.

Polar solvents, which do have "positive" and "negative" charges at different points throughout their structures, can dissolve other polar compounds. Acetone, methanol, dimethylformamide (DMF), dimethylsulfoxide (DMSO), isopropanol, and ethanol are some other polar solvents. A few of these solvents is water.

Due to the uneven distribution of its electron density, water is a polar molecule. This demonstrates that water is indeed a polar molecule because hydrogen and oxygen have different electronegativities. The fact that water can dissolve more chemicals compared to any other liquid makes it known as the "universal solvent."

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Hello

To solve this question, we should understand that an element is is the base form in which a particule exit. However, it can either be in a molecule, atom or in a compound. Elements are pure substance which form up the molecule, atom or compounds. An element can said to be an identity of a substance. Elements are generally classified using the periodic table into metals, non-metals, metalliods.

In this question, the most possibe defination is that an element is a pure substance

A homogenous mixture is a mixture that is said to have one phase of substance throughout. I.e the comprising substance are all in a single phase.

A solution is the mixture of a solute that is completely dissolved in a solvent.

A heterogeneous mixture is a solution that the substance are not in a single phase.

The answer to this question is option B

The balanced equation of the reaction is:

CoCl2 + F2 → CoF2 + Cl2

Now, we will follow the next steps to solve the question.

1. We find the moles present in 124.13 g of cobalt(II)fluoride (CoF2) using the molar molar mass of CoF2. The molar mass of CoF2 is: 96.93g/mol

2. By stoichiometry we find the moles of fluorine (F2) needed. Since the ratio CoF2 to F2 is 1, the moles will be the same as those produced from cobalt(II)fluoride.

3. We find the grams of fluorine by multiplying the moles by the molar mass of fluorine. The molar mass of fluorine is 38.00 g/mol

Let's proceed with the calculations:

1. Moles of CoF2

2. Moles of F2

3. Grams of F2

Answer: To produce 124.13 grams of cobalt(II)fluoride are required 48.66grams of fluorine

The percent by volume is 27.27%

Answer:

Bones, teeth, shells, and other hard body parts can be fairly easily preserved as fossils. However, they might become broken, worn, or even dissolved before they are buried by sediment. The soft bodies of organisms, on the other hand, are relatively hard to preserve.

Answer:

Explanation:

Here, we want to get the number of moles

Mathematically:

The number of moles in the question would be:

The pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.

Ideal gas equation is defined as the state equation for a fictitious perfect gas. Although it has significant drawbacks, it is a decent approximation of the behavior of many gases under various conditions.

Ideal gas equation is expressed as

PV = nRT

By using Ideal gas equation

P x 0.016773 = 1 x 81.49 x 483

P = 1.861 MPa

By using generalized compressibility chart

For r134a

Temperature = 374.2 K

Pressure = 4.06 MPa

vR = V / R x Tc / Pc

    = 0.016773 / 81.49 x ( 374.2 / 4.06 x 10⁶ )

    = 2.2332

Tr = T/Tc = 383 / 374.2 = 1.024

Therefore from the chart Z = 0.85

So, P = Z mRT / V

      P = 0.85 x 1 x 81.49 x 383 / 0.016773

         = 1.582 MPa

By using refrigerant tables

T = 110 C and v = 0.0167763

So, P = 1.6 MPa

Thus, the pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.

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Answer:

The number of groups attached to a center atom with trigonal planar geometry is 3 groups.

Answer

B. When ΔH is negative and ΔS is positive

Explanation

The spontaneity of a reaction can be determined by the sign of the Gibbs free energy change. For a spontaneous reaction, the change in Gibbs free energy should be negative, that is:

The spontaneity of a process can depend on the temperature. Since the temperature value here corresponds to the absolute temperature, this implies that T > 0 for any T. Therefore, to have a negative difference for any temperature value, the change in enthalpy (ΔH), should be negative and the change in entropy (ΔS) should be positive so that we always subtract a positive number from a negative number. This corresponds to a negative value in ΔG.

Hence, the

Physical properties are the ones that describe the behavior of the substances when exposed to different physical changes.

In this case, the one that describes a physical change is water when heated forms steams. In this case water changes its state of matter but it is still the same substance, there is not chemical change, just physical.

The correct answer is Water when heated forms steams.

Given Data:

Concentration of acid, H2SO4 = 2.59 M

For, H2SO4, n-factor = 2, i.e., the number of [tex]H^{+}[/tex] ions on dissociation

Thus, the concentration in normality, N1 = 2.59 x 2 = 5.18 N

Concentration of base, KOH = 0.827 M

For, KOH, n-factor = 1, i.e., the number of [tex]OH^{-}[/tex] ions on dissociation

Thus, the concentration in normality, N2 = 0.827 x 1 = 0.827 N

Volume of  base, V2 = 47.50 mL

Using the formula, N1 x V1 = N2 x V2, where, V1 = volume of acid

Thus, volume of acid required to neutralize, V1 = [tex]\frac{N_{2}X V_{2} }{N_{1} }[/tex] =  [tex]\frac{0.827 X 47.50}{5.18}[/tex]

                                                                               = 7.58 mL.

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Solubility of a substance changes as the pressure changes. If the pressure is high, solubility increases. When pressure is low, solubility decreases.

At 1 atm the solubility of Nitrogen in water is 23.5 mg gas/110g water.

The solution is submerged 40 m under water. Solubility increase.

The solution is carried to the top of a mountain. Solubility decrease.

The solution is placed in a chamber where the pressure is 0.50 atm. Solubility decrease.

The solution is brought into outer space. Solubility decrease.

The solution is canned at a pressure of 2.04 atm. Solubility increase.

1) Molar mass of Allicin.

1.1- Write the formula.

1.2- Look for the molar mass of each element in the formula.

C: 12.011 g/mol

H: 1.008 g/mol

O: 15.999 g/mol

S: 32.06 g/mol

1.3- Count how many atoms are there in the formula.

C: 6

H: 10

O: 1

S: 2

1.4- Set the equation.

Plug in the known values.

The molar mass (MM) of Allicin (C6H10OS2) is 162.265 g/mol.

2) Moles of Allicin in the sample.

Allicin sample: 4.20 mg

The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.

2.1- Convert mg to g.

1g = 1000 mg

2.2- Convert grams to moles.

The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.

Allicin sample: 0.00420 g

There are 0.00002588 moles of Allicin (C6H10OS2) in 4.20 mg of substance.

The result can also be expressed as 2.588*10^(-5) mol.

3) Molecules of Allicin in the sample.

The Avogadro's number is 6.022*10^(23).

1 mol C6H10OS2 = 6.022*10^(23) molecules C6H10OS2

Allicin sample: 0.00002588 mol.

There are 1.558*10^(19) molecules in the sample.

4) C atoms in the sample of Allicin.

The ratio of carbon in one molecule of Allicin is 6 C atoms: 1 molecule of Allicin.

Allicin sample: 1.558*10^(19) molecules C6H10OS2.

There are 9.35*10^(19) C atoms in the sample.

To calculate the molar mass of a compound, we need to find at the periodic table the atomic mass of each element that belongs to the compound and then we multiply for the quantity of atoms of it.

So, for:

5. K2Cr2O7:

K = 39 g/mol

Cr = 52 g/mol

O = 16 g/mol

(2x39) + (2x52) + (7x16) = 78 + 104 + 112 = 294 g/mol

Molar mass of K2Cr2O7 = 294 g/mol

6. C12H22O11

C = 12 g/mol

H = 1 g/mol

O = 16 g/mol

(12x12) + (22x1) + (11x16) = 144 + 22 + 176 = 342 g/mol

Molar mass of C12H22O11 = 342 g/mol

Explanation:

C₂H₄ + 3 O₂ ——> 2 CO₂ + H₂O

According to the coefficients of the equation 1 mol of C₂H₄ will react with 3 moles of O₂. Then, the molar ratio between C₂H₄ and O₂ is 1 to 3. We can use that relationship to find the number of moles of oxygen that are needed to react with 5.75 moles of C₂H₄.

1 mol of C₂H₄ = 3 moles of O₂

moles of O₂ = 5.75 moles of C₂H₄ * 3 moles of O₂/(1 mol of C₂H₄)

moles of O₂ = 17.25 moles

One mol of a gas at STP always occupies 22.4 L. We can use that relationship to find the volume of oxygen.

1 mol of O₂ = 22.4 L

volume = 17.25 moles of O₂ * 22.4 L/(1 mol of O₂)

volume = 386.4 L

Answer: 386.4 L at STP is needed to react.

The common use of density in ships and submarines is to predict whether or not a thing will float. Objects that have densities lower than those of water will sink if their densities are lower than water's.

A product's density is a measure of how heavy it is relation to its size. If added to water, an object will float if its density is less than that of the water, while it will sink if its higher density. The density of a material is a distinguishing quality that is independent of the substance's volume.

Because density is an intense property, it remains constant regardless of how much of a substance is present. Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion.

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1) Covalent bond polarity.

To determine the polarity, we use a property called electronegativity. This is a tendency to attract shared electrons in a chemical bond. If the difference in electronegativity is greater than 1.7, the bond is polar. If the difference is less than 1.7, the bond is nonpolar.

There are 3 main states of matter: gas, solid, and liquid.

The solid is characterized by its rigid structure, its high density (it means that's there's a lot of mass per unit of volume). Also, it doesn't take the container's shape as a liquid does.

Then, the description corresponds to the solid state (option B).

For this question we are going to use Gay-Lussac's Law, which is an experimental gas law that shows the relationship between temperature and pressure in a gas. The formula is:

P1/T1 = P2/T2

We have:

P1 = 97 kPa

T1 = 308 K, we need to use Kelvin

P2 = ?

T2 = 348 K

Now we add these values into the formula:

97/308 = P2/348

0.315 = P2/348

P2 = 109.6 kPa, this will be new pressure

When a metal atom combines with a nonmetal atom, the nonmetal atom will gain electrons and decrease in size

In a reaction between metals and non-metals, electrons are moved from the metal atoms to the non-metal atoms, resulting in the formation of ions. An ionic compound is the name given to the resulting substance.

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Answer:

10.6.

Explanation:

What is given?

[H⁺] = 2.79 x 10⁻¹¹ M.

Step-by-step solution:

Let's see the formula of pH:

Where [H⁺] is the proton concentration in M. So we have to replace the given data in the formula:

The pH of a [H⁺] = 2.79 x 10⁻¹¹ M solution would be 10.6.

Answer:

Explanation:

Here, we want to get an empirical formula

We start by dividing each of the masses by the corresponding atomic masses

The atomic mass of carbon is 12 amu

The atomic mass of hydrogen is 1 amu

We start the division as follows:

Now, we divide the results by the smaller of the two:

Thus, we have the empirical formula as:

Final Molarity of acetate ion is 0.0394 M. The number of moles of solute per liter of solution is referred to as molarity.

The amount of a substance in a given volume of solution is measured in molarity (M). Molarity is defined as the number of moles of a solute in one liter of solution. A solution's molarity is also known as its molar concentration.

Therefore,

We first assume that the reaction completes and that the volume of the reaction remains constant.

The balanced stoichiometric equation is as follows:

Ba(CH₃COO)₂ + (NH₄)₂SO₄ → BaSO₄ + 2NH₄(CH₃COO)

First, we must determine which reactant is in excess and which has been completely consumed by the reaction. To do so, we count the number of moles of each reactant at the beginning of the reaction.

For Ba(CH₃COO)₂

The number of moles = (Mass)/(Molar Mass)

Barium acetate mass = 2.68 g

Barium acetate molar mass = 255.43 g/mol

The number of moles = (2.68/255.43) = 0.0104 moles.

For (NH₄)₂SO₄,

Number of moles = (Concentration in mol/L) × (Volume in L)

Concentration of Ammonium surface in mol/L = 45 M

Volume in L = (300/1000) = 0.3 L

Number of moles = 45 × 0.3 = 13.5 moles

From the stoichiometric balance of the reaction,

1 mole of Ba(CH₃COO)₂ responds with 1 mole of (NH₄)₂SO₄

As a result, it is clear that Ba(CH₃COO)₂ is the limiting reagent; the chemical specie that is depleted during the reaction and determines the number of other reactants and products formed.

1 mole of Ba(CH₃COO)₂ provide 2 moles of NH₄(CH₃COO)

0.0591 moles of Ba(CH₃COO)₂ will give 2 × 0.0591 moles of NH₄(CH₃COO); 0.1182 moles of NH₄(CH₃COO).

The molarity of NH₄(CH₃COO) exist then provide as (number of moles) ÷ (Vol in L)

The number of moles = 0.1182 moles

L volume of the solution = 0.3 L

Molarity of NH₄(CH₃COO) = (0.01182/0.3)

= 0.0394 M

Note that 1 mole of NH₄(CH₃COO) contains 1 mole of acetate ion,

Hence, 0.0394 M of NH₄(CH₃COO) also contains 0.0394 M of acetate ion.

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10.7 grams

The formula for calculating the molarity of a solution is given as:

Given the following parameters

molarity of NaOH = 1.11M

volume of solution = 241.0mL = 0.241L

Find the moles of NaOH

Determine the mass of solute (NaOH)

Hence the grams of solute that would be used to prepare the solution is 10.7grams

Answer:

Explanation:

Here, we want to calculate the pressure used at the new volume

It is expected that at a higher pressure, the volume will decrease

Thus, the weight and the pressure are inversely proportional

Mathematically:

The above is according to Boyle's law which states that volume and pressure are inversely proportional

where:

V1 is the initial volume which is 4 cc

P1 is the initial weight which is 600 g

V2 is the final volume which is 2.5 cc

P2 is the final pressure which is unknown

Substituting the values:

A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 105 J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J /  kg °C.

Specific heat formula is given as :

Q = mcΔT

given that :

mass , m = 17.6 kg

Q = 8.69 × 10⁵ J

ΔT , change in temperature = 22.1 °C - 155.8 °C = 133.7  °C

c = specific heat = ?

Substituting the values in the formula we get:

Q = mcΔT

c = Q / mΔT

c = 8.69 × 10⁵ J / 17.6 kg × 133.7  °C

c = 8.69 × 10⁵ J / 2353.12 kg °C

c = 369.2 J /  kg °C

Thus, A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 10⁵ J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J /  kg °C.

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Answer:2ZnO(s)→2Zn(l)+O2(g)

Explanation:

The quantum numbers that are not possible are 16,14,15.

The quantum numbers are used to address the position of the electron in an atom. They are the set of numbers that show the most probable position of the electron in an atom. There are four sets of quantum numbers that describe the position of an electron and they are;

1) Principal quantum number

2) Orbital quantum number

3) Magnetic quantum number

4) Spin quantum number.

The set of quantum numbers 16,14,15 is not possible because ml must have values of -l to +l as we know.

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Answer: 13 O2 instead of 12 O2

Explanation: