Answer:
Workdone = 20 Joules
Explanation:
Given the following data;
Force = 10N
Extension, e = 4cm to meters = 4/100 = 0.04 meters
Workdone extension = 40cm to meters = 40/100 = 0.4 meters
To find the work done;
First of all, we would find the spring constant using the formula;
Force = spring constant * extension
10 = spring constant * 0.04
Spring constant = 10/0.04
Spring constant = 250 N/m
Next, we find the work done;
Workdone = ½ke²
Where;
k is the spring constant.
e is the extension.
Substituting into the formula, we have;
Workdone = ½ * 250 * 0.4²
Workdone = 125 * 0.16
Workdone = 20 Joules
Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates towards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,
a) Which point has the highest potential; A, B or C?
b) What will a negative test charge do when it is released from rest at B?
PLEASE HELP! I'LL GIVE BRAINLEST
the answer is the first one
A child with a mass of 12.32kg weight how much? Show all work including a equation
Answer:
123.2newtons
Explanation:
weight =mass × gravity
w= m×g
gravitational pull is approximately 10N/Kg
w= 12.32kg×10n/kg
=123.2newtons or 12.3N
A freight train car is moving at a constant speed with respect to the ground of Vcg. A man standing on a flatbed car throws a ball into the air and catches it as it falls. Relative to the flatbed car, the initial velocity of the ball is Vibc straight up. a. What are the magnitude and direction of the initial velocity of the ball as seen by a second man standing on the ground next to the track
Answer:
chiicken
Explanation:
People with schizophrenia are most likely to have delusions that reflect the theme of
Answer:
llogical or bizarre ideas or fantasies.
Explanation:
A rock falls from a cliff and hits the ground at a velocity of 28m/s. How long did it take to fall?
Answer:
2.8s
Explanation:
=>a = v-u/t
=> t = v - u / t
= 28-0 / 10
= 2.8 s
A ball weighing 100 g is attached to a string and swung around with a speed of 2 m/s. If the centripetal force exerted by the string is
0.5 N, what is the length of the string?
A) 0.08 m
B) 0.8 cm
C) 8 m
D) 80 cm
Assuming the ball is swung around in a circle parallel to the ground, it has a centripetal acceleration a of
a = v ² / R
where v is the tangential speed of the ball and R is the length of the string.
The tension in the string is 0.5 N, so by Newton's second law, the ball has acceleration
F = m a → a = F / m = (0.5 N) / (0.1 kg) = 5 m/s²
where m is the ball's mass.
Solve for R :
a = v ² / R → R = v ² / a = (2 m/s)² / (5 m/s²) = 0.8 m = 80 cm
The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
Steeper slopes mean higher speeds.
Steeper slopes mean lower speeds.
Steeper slopes mean higher error.
Steeper slopes mean lower error.
The slope has no relation to speed or error
Answer: Steeper slopes mean lower speeds.
Explanation:
5. A cart with one fan on It blowing to the left and carrying one block produces the x vs t graph shown If this car were carrying three blocks instead of one, with the
fan still blowing the same direction, what could the x vs t graph look like?
A Graph A
B. Graph B
OC. Graph C
O D. Graph D
Answer:
Graph C
Explanation:
With the same force and more mass, the position in time will still be parabolic
i.e. x = ½at², but the rate of acceleration will be lower so the position curve will be broader.
Darcy is going to make raspberry jam for the county fair.
• Her recipe calls for exactly 55 raspberries per jar.
Darcy has 1,700 raspberries.
Answer:
She can make have 30 jars with raspberries in them with 50 left over.
Explanation:
1,700 divided by 55
30 equally
but 50 left over
This means that she can make have 30 jars with raspberries in them with 50 left over.
A current of 8 A is used to operate a Nespresso coffee machine. Choose the most suitable fuse size from the following
- 3 A
- 5 A
- 13A
-10 A
It needs fuse of size 3A to be operated
Answer: 10 A
Explanation: The 3a and 5 a will blow immediately which would not allow you to use the coffee machine
The 13 a is too high and might lead to damage to the coffee machine or a fire being started
10 A is perfect because its low enough that if their was a power surge it would be blown without damaging anything else and it is high enough to let the coffee machine work without any trouble
can someone help? NO LINKS OR IM REPORTING
Answer:
BjsjsjsiisudujdgjkkgywuuuyyyuwuA glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 Pa. Assuming that the top and bottom surfaces of the cap each have an area of 4.40 x 10-4 m2, obtain the magnitude of the force that the screw thread exerts on the cap in order to keep it on the bottle. The air pressure outside the bottle is one atmosphere
Answer:
[tex]F \approx 19.5 N[/tex]
Explanation:
From the question we are told that:
Pressure of [tex]P_{CO_2}=1.50 * 105 Pa.[/tex]
Bottle cap area [tex]A_b= 4.40 * 10-4 m^2[/tex]
Generally the equation for Resultant pressure [tex]P_r[/tex] is give as is mathematically given by
[tex]P_r=P_{CO_2}-P_a[/tex]
Where
[tex]P_a=atmospheric\ pressure = 1.013*10^5 pa[/tex]
[tex]P_r=1.50 * 105 Pa-1.013*10^5 pa[/tex]
[tex]P_r=0.487*10^5 pa[/tex]
Generally the equation for Force exerted by screw F is give as is mathematically given by
[tex]F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N[/tex]
[tex]F \approx 19.5 N[/tex]
What is responsible for the amount of current in a circuit?
Will mark as Brainliest!!!
Answer:
Voltage is required for there to be a current but resistance can effect the amount of current.
Answer:
the answer is voltage
Explanation:
we just finished this unit in class
You would like a solenoid that is 32 cm long to produce a magnetic field of 0.78 T when it carries a
current of 7.7 A. How many loops should this solenoid have?
Answer:
N = 25795 loops
Explanation:
The magnetic field of a solenoid can be calculated by using the following formula:
[tex]B = \frac{\mu NI}{L}\\N = \frac{BL}{\mu I}[/tex]
where,
N = No. of loops = ?
B = Magnetic Field = 0.78 T
L = Length of solenoid = 32 cm = 0.32 m
I = Current = 7.7 A
μ = permeability of free space = 4π x 10⁻⁷ N/A²
Therefore,
[tex]N = \frac{(0.78\ T)(0.32\ m)}{(4\pi\ x\ 10^{-7}\ N/A^2)(7.7\ A)}\\[/tex]
N = 25795 loops
How far are two protons if they exert a force of 0.5 N on one another?
Answer:
5.08 metres
Explanation:
The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron
The two protons will exert a repulsive force of 0.5 N when they are at a distance of [tex]2.146625 \times10^{-14} \,m[/tex] away from each other.
As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.
According to Coulomb's law in electrostatics, the electrostatic force between two charges can be given by;[tex]F=k\frac{q_{1}q_{2} }{r^2}[/tex]Where [tex]k \approx 9 \times 10^9 \, Nm^2 /C^2[/tex]Here, since both the particles are protons;[tex]q_1 = q_2 = 1.6 \times 10^{-19}\,C[/tex]Given that F = 0.5 NSubstituting the known values in the Coulomb's law equation, we get;[tex]0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}[/tex]
ie; [tex]r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m[/tex]
Learn more about Coulomb's Law here:
https://brainly.com/question/1698562
What are the limitations of sending information using electronic waves
Answer:
The limitations of sending information using electromagnetic waves is that when the electromagnetic waves move outward in all directions, wave transmitters need to be focused to transmit their signals to a single specified location.
A 1 kg block of wood is attached to a spring, of force constant 200 N/m, which is attached to an immovable support. The block rests on a frictional surface with a coefficient of kinetic friction of 0.2. A 20 g bullet is fired into the block horizontally compressing the spring a maximum distance of 15 cm. Find the original velocity of the bullet before the collision.
Answer:
[tex]v=15.9499m/s[/tex]
Explanation:
From the question we are told that:
Mass of wood [tex]m=1kg[/tex]
force constants [tex]k= 200N-m[/tex]
Coefficient of kinetic friction [tex]\mu= 0.2[/tex]
Bullet mass [tex]m_b= 20 \approx 0.02kg[/tex]
Spring compresion [tex]y=15cm \approx 0.15 m[/tex]
Generally the equation for kinetic energy of bullet [tex]K>E_b[/tex] is mathematically given by
Complete Question
[tex]K.E_b=spring potential energy+work done against friction[/tex]
[tex]K.E_b=\frac{1}{2} mbv^2[/tex]
[tex]\frac{1}{2} m_b v^2=\frac{1}{2} ky^2+\mu my[/tex]
[tex]\frac{1}{2} (0.02)v^2=\frac{1}{2} (0.2)(0.15)^2+0.2(1)(0.15)[/tex]
[tex]v=15.9499m/s[/tex]
[tex]v\approx16m/s[/tex]
238 U
92 ———————>
The alpha decay of ___ produces an atom with a mass number of...
OA. 234
B. 236
C. 238
D. 240
Answer:
A. 234
Explanation:
An alpha particle is a Helium atom which has a mass number of 4 and atomic number of 2. So, an alpha particle decay cause the mass number to decrease by 4 units.
So 238 - 4 = 234
The answer is A
A cylinder of gas has a frictionless but tightly sealed piston of mass M. A small flame heats the cylinder, causing the piston to slowly move upward. For the gas inside the cylinder, what kind of process is this?
Answer:
isobaric
Explanation:
According to the attached figure, the process would be isobaric as the gas would be expanded at the time when it maintains the constant pressure
The ideal gas law derives
PV = nRT
As the flame is there at the bottom side so atoms or molecules of gas would get heat up slowly also their temperature would be increased. Thus in the case when piston would not be permitted to move so the pressure would rise having maintaining the constant volume and after this the process could be isochronic but in the given case, the piston would be permitted to move slowly upward so that there is a rise in the volume. However, the gas particles would be adjust themselves in order to maintain constant pressure so the given process represent isobaric
A child is pushing a merry-go-round. The angle through which the merry-go-round has turned varies with time according to θ(t)=γt+βt3θ(t)=γt+βt3, where γ=γ= 0.450 rad/srad/s and β=β= 1.10×10−2 rad/s3rad/s3. Part A Calculate the angular velocity of the merry-go-round as a function of time. Express your answer in terms of the variables ββ, γγ, and tt. ωz(t)ωz(t) = nothing rad/srad/s SubmitRequest Answer Part B What is the initial value of the angular velocity? ωzωz = nothing rad/srad/s SubmitRequest Answer Part C Calculate the instantaneous value of the angular velocity ωzωz at t=t= 5.25 ss . ωzωz = nothing rad/srad/s SubmitRequest Answer Part D Calculate the average angular velocity ωav−zωav−z for the time interval t=0t=0 to t=t= 5.25 ss .
Answer:
hufiui
fihgpfghlfikgergkfkjhfkhjgkffhhh
Explanation:
jjgzgcjxhgygueyuufhfugkhkckgijljhgxjgjgffhgkgjxhxjgjcjckvjgghkhkgjgjfhfhfhffrusufsflslrsyfhldufñlñudtoqdyhjjxkgsgjfktwlyfñujxjxhlxlhdktstedoyñfuyñflldytidoyeyljjcñcjluffñui5woyepurñfuñufldyrajuñdlydstdyñudñydktshñxjcñydiw5uñfitwoyeoyeñufñfuñifjñufhlsyñeifññydoysitaiwtuñdyñdlsyltslsyoyeylsuñdñjjcyldlyslatlysñudidñjdñfjñjjxlhsmzhmzjjdjdlhdñhjdñjdñjddñhflhuñfhxltkds4urayraylraluarularuñstuñtsuñtsultsuñtsuñstñitsñktssistustlulsrustlularyralultalutslutajltsñgskjlgzljg?g o uguhxputxipyfugxiñhxiñhfuñdguldthgksjmgdjmgkhdjlgdjlgd
pduoyditsyafylrayoraourauptautospustistiptsñitsñitsñitsiptsiteitdustuñtsuñtsñitwiñstñitwñitsñstuuñrsoursurosoustjlsrlutejlgsjlstjfsjlgsultsjgzjñgsññkdylfhkñdgjlfshkadmjgsuñstñkydñkydñiykdhiñstñitsuñtsisñtñtieñietñietñiteñiwtñitskñgsiñteuñwrkñsturaluglsuñtwjlfalfjalhadoyfutdllgdñitswtkgsñktjrajtsurwñwñutiñtsiwñtuwñturqlñitwualtayoryarluarlietite
If the time period of simple pendulum is doubled then it's amplitude will be
Also explain the answer
Answer:
pls check
https://www.doubtnut.com/question-answer-physics/the-amplitude-of-a-simple-harmonic-oscillation-is-doubled-how-does-this-affect-i-periodic-time-ii-ma-12009541
Consider a taut inextensible string. You shake the end of the string with some frequency, causing a wave to travel down the string. In the questions below, assume you only change one aspect of the system at a time.
1. If you shake the end of the string twice as rapidly (double the frequency), what will happen to the speed of the wave?
2. If you double the tension in the string, what will happen to the speed of the wave?
3. If you shake the end of the string twice as rapidly (double the frequency), what will happen to the wavelength of the propagating wave?
4. If you double the tension in the string, without changing the rate at which you're shaking it, what will happen to the wavelength of the wave?
For each question, choose from the following choices:
a. It will double.
b. It will remain unchanged.
c. It will increase by a factor of √ 2.
d. It will increase by a factor of 4.
e. It will be half as fast/long.
Answer:
Part 1:
Option B is correct (It will remain unchanged).
Part 2:
Option C is correct (It will increase by a factor of √ 2)
Part 3:
Option E is correct (It will be half as fast/long.)
Part 4:
Option C is correct (It will increase by a factor of √ 2.)
Explanation:
Formula we are going to use:
V=f*λ
Where:
V is the speed of Sound
f is the frequency of wave
λ is the wavelength.
The speed of wave , tension and linear density have following relation:
[tex]V=\sqrt{F/\rho}[/tex]
Where:
V is the speed of Sound (Initial)
F is the tension in string (Initial)
[tex]\rho[/tex] is the linear density of string (Constant)
Terms:
V' is the new speed
f' is the new frequency
λ' is the wavelength
Solution:
Part 1:
From [tex]V=\sqrt{F/\rho}[/tex]:
Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.
Option B is correct (It will remain unchanged)
Part 2:
If F'=2F then
[tex]V=\sqrt{F/\rho}[/tex]
[tex]V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'= \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V[/tex]
Option C is correct (It will increase by a factor of √ 2)
Part 3:
Formula we are going to use:
V=f*λ
Given f'=2f,
Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.
V'=f'*λ'
f*λ=f'*λ'
f*λ=2f*λ'
Solving above Equation:
λ'=λ/2
Option E is correct (It will be half as fast/long.)
Part 4:
T'=2T means [tex]V'=\sqrt{2}V[/tex] (From Part 1)
f'=f
Now:
V'=f'*λ'
[tex]\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda[/tex]
Option C is correct (It will increase by a factor of √ 2.)
35. What would a ship's position be if that ship started at
point B and traveled at an average velocity of 35 km/h
west to point D in a time period of 1.2 h?
Answer:
The final position of the ship after the given time period is 42 km West of B.
Explanation:
Given;
average velocity of the ship, v = 35 km/h
time taken for the ship to reach point D, t = 1.2 hours
The position of the ship after the given time period is calculated as follows;
x = v x t
x = (35 km/h) x 1.2 h = 42 km
x = 42 km West of B.
Therefore, the final position of the ship after the given time period is 42 km West of B.
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?
A) Θ decrease
B) Θ increase
C) Θ remains the same
D) distant between spheres increases
Answer:
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)
Explanation:
please click the heart and rate excellent and brainleist to ❤☺️☻♨️♨️☻☺️❤
In an electrical circuit, electrons move from the __________.
A. Negative pole to negative pole B. Negative pole to positive pole
C. Positive pole to positive pole
Answer:
the answer is B from negative pole to positive pole
what is the process that creates wind.
Answer:
Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.
plz mark me as brainliest.
When turning from your path onto a perpendicular path your speed
SHOULD BE at a STEADY
DRIVERS ED PLEASE HELP
Answer: 5-15MPH
Explanation: Trust me
Two children are sitting on a see-saw, as shown. Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw.
We have that for the Question "Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw"
It can be said that
The distance = [tex]1.8m[/tex]From the question we are told
weights are = 300 N and 500 N
length l = 6 m
take x distance from the 300 N
total torque is zero
[tex]300*3 = 500x\\\\x = 1.8 m[/tex]
For more information on this visit
https://brainly.com/question/23379286
Use the simulation to determine the relationship between the distance from the magnet and the strength of the magnetic field at that point. Use a ruler to measure distance on the screen. Use a power fit to determine the B vs. r relationship for each location. To simplify your data collection, chose a data-collection axis where either Bx or By = 0. Measure the distance from the nearest edge of the magnet. You will need to obtain a ruler for collecting data.
Explanation:
give me more detail and i well help you out