Can any1 tell if my answer is right

With the use of the formula, the pressure on the bottom of the pool due to the water is 29400 Pascal

Given that a swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m.

Volume = Length x Width x Height

Volume = 9 x 12 x 3

Volume = 324 [tex]m^{3}[/tex]

Since 1 m^3 of water has a mass of 1000 kg,

Mass = 324 x 1000

mass = 324000 kg

To calculate the pressure on the bottom of the pool due to the water, let us use the pressure formula below

P = δgh

where

P = pressure

δ = density of the water = 1000 kg/[tex]m^{3}[/tex]

g = Acceleration due to gravity = 9.8 m/[tex]s^{2}[/tex]

h = height = 3m

Substitute all the parameters into the formula

P = 1000 x 9.8 x 3

P = 29400 Pascal

Therefore, the pressure on the bottom of the pool due to the water is 29400 Pascal

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Answer:

The answers are:

T, T, F, F, T, T, F, F, T, T, F

Good luck!

Answer:2 reactants 2 products.

this is a balanced chemical equation. That means the number of chlorine before the arrow will be the same after the arrow

Explanation: i think this answer will help you very much

Answer:

23: Acceleration 24:1m/s^2

Explanation:

[tex]a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2[/tex]

Given,

length of object, [tex]h_o = 3 cm[/tex]

We know, for flat refracting surface,  

Image distance = object distance

So,

magnification is = [tex]-1[/tex]

length of the image,

[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]

Here, negative sign means inverted image.

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The centrifugal force C = mv^2/r = kq^2/r^2 = P centripetal force. m is the electron mass, q are the proton and electron charges (opposites), and r is the Bohr radius.

Thus 1/2 mv^2/r = 1/2 kq^2/r^2 and KE = 1/2 mv^2 = 1/2 kq^2/r = 1/2 PE

Therefore KE/PE = 1/2, no matter what state the electron is in.

From Newton's law of gravity, the force of gravity is 245 Newtons

To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters

Mass m = 25 kg

Mass of the earth M = 5.97x10^24kg

Radius r = 6.38x10^6m

Force F = ?

The formula to calculate the force of gravity is

F = (GMm)/[tex]r^{2}[/tex]

Where G = 6.67 x [tex]10^{-11}[/tex]

Substitute all the parameters

F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2

F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]

F = 244.56 N

F = 245 Newtons (approximately)

Therefore, the force of gravity is 245 Newtons

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=============================================

Explanation:

To compute the speed, we divide the distance traveled over the time duration.

For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.

-----------------

For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)

speed = distance/time = (30 km)/(2 hrs) = 15 km/hr

-----------------

We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.

You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.

-----------------

For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)

So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr

The steeper slope of section C, compared to section A, means the car is going faster.

-----------------

Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km

(60 km)/(1.5 hrs) = 40 km/hr

The speed of the car during section D is 40 km per hour.

Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.

Option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.

At constant velocity, the change in displacement with time is uniform. The displacement of the given object in motion increases at equal rate.

At constant velocity, the initial velocity is equal to the final velocity.

v₁ = v₂

The acceleration of the object at constant velocity is zero, because the change in velocity with time will be zero.

[tex]a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v_2- v_1}{t} \\\\v_2 = v_1\\\\a = \frac{v_1 - v_1}{t} \\\\a = 0[/tex]

Thus, from the given options we can conclude that option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.

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Answer:

true

Explanation:

as long as you are interested, you are happy

Since lifetime activities are done for a lifetime, it is true that a well chosen lifetime activity is something that should hold a person's interest for a long time.

A lifetime activity is an activity which an individual decides to do for a lifetime.

A lifetime activity should be able to hold a person's interest for a long time, else it could lead to frustration.

Some lifetime activities include:

Therefore, it is true that a well chosen lifetime activity is something that should hold a person's interest for a long time.

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[tex]\text{Given that,}\\\\\text{Velocity, v= 311 m s}^{-1}\\\\\text{Displacement, s = 9000 m}\\\\\text{Since velocity is constant,}\\\\s=vt\\\\\implies t =\dfrac{s}v = \dfrac{9000}{311} = 28.94 ~ \text{sec}.[/tex]

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

Answer: The surface temperature of Sirius B is 25,200 Kelvins(K).

Explanation: You would think Sirius would have a surface temperature of 9,940 Fahrenheit. That is somewhat correct, but Sirius is a binary star consisting of a main-sequence star of spectral type A0 or A1, termed Sirius A, and a faint white dwarf companion of spectral type DA2, termed Sirius B. Sirius, Sirius A, and Sirius B, are all different stars. Sirius A has a temperature of 9,940 Kelvins, but Sirius B has a temperature of 25,200 Kelvins(K).

That would be 9,940 kelvins (K)

Hope it helps! :D

Answer:

2:3

Explanation:

mathqway

Answer:

The temperature will no longer rise with the heat because the energy. When the water is boiled on the steam, the temperature rises when heat is given

Explanation:

Answer:

Blue

Explanation:

Did the question already

Answer:

ybuTouch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.

Answer:

Molar mass of CrF3, Chromium(III) Fluoride is 108.9913096 g/mol

51.9961+18.9984032·3

Mass percentage of the elements in the composition

Element Symbol Atomic Mass Number of Atoms Mass Percent

Chromium Cr 51.9961 1 47.707%

Fluorum F 18.9984032 3 52.294%

Notes on using the Molar Mass Calculator

Chemical formulas are case-sensitive.

Enter subscripts as simple numbers.

The converter uses a simple dot instead of using a midpoint typographic dot (·) in formulas for adduct molecules, such as water of hydration.

Example: type CuSO4.5H2O instead of CuSO₄·5H₂O.

Explanation:

please mark my answer in brainlist plz

This question involves the concepts of the law of conservation of momentum.

The magnitude of the final momentum of the eight ball is "0.22 N.s".

According to the law of conservation of momentum:

[tex]P_{i1}+P_{i2}=P_{f1}+P_{f2}[/tex]

where,

[tex]P_{i1}[/tex] = initial momentum of the cue ball = 0.23 N.s

[tex]P_{i2}[/tex] = initial momentum of the eight ball = 0 N.s (since ball is initially at rest)

[tex]P_{f1}[/tex] = final momentum of the cue ball = 0.01 N.s

[tex]P_{f2}[/tex] = final momentum of the eight ball = ?

Therefore,

[tex]0.23\ N.s + 0\N.s = 0.01\ N.s+P_{f2}\\\\P_{f2} = 0.22\ N.s[/tex]

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These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).

In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.

When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.

Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.

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Primary clarifiers removing biological nutrients is not true. Primary clarifiers

involves the use of processes such as sedimentation in order to remove

particles floating or other inorganic solids from the waste water.

Biological nutrients such as nitrogen and  phosphorus are found in waste

water and removal of these important nutrients for other uses is a part of

waste water management.

The secondary clarifiers are the ones responsible for the removal of

biological nutrients in the waste water through biofiltration etc.

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Answer

C

hope this helps!!

*please mark brainliest if correct!! Trying to level up!!

The distance between Jupiter and the sun is 5.2 AU.

According to Kepler's third law, the square of the period of revolution of planets is proportional to the cube of their mean distances from the sun. From this; T^2 = r^3.

Now, we are told that the orbital period (T) is 11. 9 Earth years. We have to make the distance the subject of the formula.

r =T^2/3

r = (11.9)^2/3

r = 5.2 AU

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Answer:

The answer is A. 5.2 AU

Explanation:

in jus dat ni ni fr

Answer:

The capacitance C of a capacitor is defined as the ratio of the maximum charge Q that can be stored in a capacitor to the applied voltage V across its plates. In other words, capacitance is the largest amount of charge per volt that can be stored on the device: C = Q V . 1 F = 1 C 1 V .

Explanation:

A capacitor's capacity to hold an electric charge when a potential difference (voltage) is applied across its plates is measured by the capacitance of the device.

It can be calculated using the formula C = Q/V,

where Q is the electric charge stored on the capacitor in coulombs (C), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V). The capacitor's physical properties, such as the area of the plates, the space between them (dielectric separation), and the substance between the plates (dielectric constant), all affect capacitance. A better charge storage capability is indicated by a higher capacitance value.

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Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass in kg

v is the velocity in m/s

From the question

m = 60 kg

v = 10 m/s

We have

[tex]k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000[/tex]

We have the final answer as

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf 3000 \ J}}[/tex]

Explanation:

Kinetic energy is the energy an object has due to motion. It is calculated using the following formula:

[tex]KE=\frac{1}{2} mv^2[/tex]

The mass of the go-cart is 60 kilograms and the velocity is 10 meters per second.

Substitute the values into the formula.

[tex]KE= \frac{1}{2} (60 \ kg)(10 \ m/s)^2[/tex]

Solve the exponent.

[tex]KE = \frac{ 1}{2} (60 \ kg)(100 \ m^2/s^2)[/tex]

Multiply the numbers together.

[tex]KE= 30 \ kg * 100 \ m^2/s^2[/tex]

[tex]KE= 3000 \ kg*m^2/s^2[/tex]

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 3000 kg*m²/s² equals 3000 Joules.

[tex]KE= 3000 \ J[/tex]

The go-cart has 3000 Joules of kinetic energy.

Answer:

Explanation:

An open train car rolls along a track while it is being filled with sand. There is negligible friction. The speed of the train car will be slowed down.

Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor.

Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.

Speed indicates the rate of movement of something or someone. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.

Therefore, an open railway car is packed with sand and is rolling along a track. Very little friction exists. The railway car's speed will be slowed down.

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Their combined momentum after they meet is 0.

According to the law of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.

Let the mass of each billiard balls = m.

If the initial velocity of first ball is u; according to the question, the initial velocity of the second ball be -u.

Hence, initial momentum of the first ball is: P₁ = mu

initial momentum of the second ball is: P₂ = -mu

Hence, total initial momentum of the two balls = P₁ + P₂ = mu + ( -mu) = 0.

So, according to law of conservation of momentum:

Their combined momentum after they meet is = 0.

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The combined momentum of the two billiard balls after they meet is zero.

When two pool balls of the same size and speed roll directly at each other and collide, their momentum will increase.

Let us denote the speed of the first ball as [tex]\rm p_1[/tex] and the speed of the second ball as [tex]\rm p_2[/tex]. The momentum of the balls are equal in magnitude but opposite in direction because they have the same mass and velocity.

[tex]\rm p_1= -p_2[/tex]

When the balls collide, their momentum increases:

Total momentum after the collision= [tex]\rm p_1+ p_2[/tex]

Substituting the relationship

[tex]\rm p_1= -p_2[/tex]

Total momentum after the collision

[tex]\rm p_1- p_1= 0[/tex]

Therefore, the combined momentum of the two billiard balls after they meet is zero.

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Answer:

there very old

Explanation:

Answer: rolling friction

Explanation: I think it is the answer