Medicine High School

Can defect in the bone marrow cause an increase in the production of red blood cells. If yes what are the reasons if no please do explain.
PLEASE HELP ME​

Answers

Answer 1

Answer:no

Explanation: Bone Marrow has stem cells that synthesize Red blood cells, white blood cells, and platelets, a defective bone marrow won't produce enough stem cells to make enough RBCs.

Related Questions

Why must a baby be delivered within 24 to 48 hours after the mother’s water has broken??

Answers

Answer:

beecause then the baby will explode

Explanation:

trust me bro

how is dna profiles are built

Answers

Explanation:

there is the answer hope this is right

Separate white and red blood cells with a centrifuge.
Extract DNA nuclei from the white blood cells. ...
Cut DNA strand into fragments using a restriction enzyme.
Place fragments into one end of a bed of agarose gel with electrodes in it. ...
Use an electric current to sort the DNA segments by length.

I’ve also added a picture as well.

Tetracycline has been shown to form a calcium complex in bone-forming tissue in infants given oral tetracycline in doses of 0.011 g/lb of body weight q6h. How many milligrams of tetracycline will be administered for 5 days if a child weighs 8 kg?​

Answers

Since tetracycline has been shown to form a calcium complex in bone-forming tissue in infants given oral tetracycline in doses of 0.011 g/lb of body weight q6h. The amount of milligrams of tetracycline that will be administered for 5 days if a child weighs 8 kg is: 3.88g

What is the computation for the above?

Given:

0.011g/lb = 6 hours

That means

0.011g/0.453592kg (because lb is converted to kg)

or

0.02425g/kg

or

0.194/8kg/ 6 hours (because we multiplied to get the dosage for an 8kg baby)

Hence in 5 days, the total amount of tetracycline that would have been administered is:

0.194 x 4 (because there are 24 hours in a day)

= 0.776; Then we say

0.776 x 5 (because we are looking for the dosage over a 5-day period.

= 3.88g over a five-day period.

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area of tissue necrosis from ischemia its a 7 letter word for crossword

Answers

Hopefully this is the answer your looking for.

(Aseptic Necrosis)

If a pharmacist fortified 10g 0f a 0.1% tacrolimus ointment by adding 12g of an ointment containing 0.05% of the same drug. What would be the

a. total amount of the ointment after after fortification?



​

Answers

The percentage strength of the mixture (tacrolimus ointment) is 0.73%.

What is tacrolimus ointment?

Tacrolimus ointment is utilized to manage the symptoms of eczema (atopic dermatitis; a skin infection that causes the skin to be dry and itchy, with red, scaly rashes on occasion) in patients who are unable to use other prescribed medication for their condition or whose eczema has not reacted to another medication.

To get the percentage strength (concentration) of the mixture, we must use the following formula for the concentration of a mixture.

Concentration is defined as:

M₁V₁ + M₂V₂ = (M₁+ M₂)V₃

Where:

M₁ is the Mass of the first ointment = 10g

M₂ is the Mass of the second ointment = 12g

V₁ is the Volume of the first  ointment = 0.1%

V₂ is the Volume of the second ointment = 0.05%

V₃ is the Volume of the third ointment (That is the mixture)


M₁+ M₂ = 10 + 12 = 22g

Inserting all the values, we have

V₃ = [(10 x 0.1) + (12 x 0.05)]/22

V₃ = 0.07272727272; Hence

V₃ [tex]\approx[/tex] 0.073%

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Full Question:

If a pharmacist fortified 10 g of a 0.1 % W/W tacrolimus (PROTOPIC) ointment by adding 12g of an ointment containing 0.05% W/W of the same drug, what would be the percentage strength of the mixture?

2. If 25g of 2% hydrocortisone ointment were diluted with 10g of ointment base, what would be the concentration of hydrocortisone in the mixture?​

Answers

If 25g of 2% hydrocortisone ointment were diluted with 10g of ointment base, the concentration of hydrocortisone in the mixture is 1.43%

What would be the concentration of hydrocortisone in the mixture?​

The dilution of solids in pharmacy aims at lowering the concentration of an active substance in a solution.

In the question above, hydrocortisone ointment needed to be diluted with a base ointment.

25g + 10g= 35g, the weight of the mixture

The concentration of hydrocortisone in the mixture is

25g X 2% = 35g X unknown concentration, Y (% )

Y (%) = 50g ÷ 35g

Y (%) = 1.43%

Therefore, the concentration of hydrocortisone in the mixture is 1.43%

In summary, the concentration of hydrocortisone in a mixture of 25g of 2% hydrocortisone ointment when diluted with 10g of ointment base, is 1.43%.

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Developing the flu after being exposed to someone sick with the flu is an example of



A-artificially acquired active immunity
B-naturally acquired active immunity
C-artificially acquired passive immunity
D-naturally acquired passive immunity

Answers

Answer: B-naturally acquired active immunity.

Explanation:

Answer:

Explanation:

ur mom

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