can somebody help me with this please​

Answer:

Explanation:

A)wkt, tanx = perpendicular(p)/base(b) .....(1)

B)We are given tanx=5/12 .....(2)

C)On comparing the quantities we get that p=5 and b=12

D)We require the value of hypotenuse(h),

for this we apply the Pythagoras theorum i.e,  

h

2

=

p

2

+

b

2

⇒

h

2

=

5

2

+

12

2

⇒

h

2

=25+144

⇒

h

2

=169

⇒

h=

√

169

⇒

h=13

Step-by-step explanation

well yeah thats the dang answer

Step-by-step explanation:

(2m + 4) / 8 = w

2m + 4 = 8w

2m = 8w - 4

m = 4w - 2

Step-by-step explanation:

option A is correct.

hope this answer helps you dear! take care

Answer:

[tex]x=6[/tex] and [tex]x=-4[/tex]

Step-by-step explanation:

[tex]x^2-2x-24=0[/tex]

[tex](x-6)(x+4)=0[/tex]

[tex]x=6[/tex] and [tex]x=-4[/tex]

Answer:

Answer: 749.84

Step-by-step explanation:

• For 4% increment

[tex] = { \rm{ \frac{(100 + 4)}{100} \times 700 }} \\ \\ = { \rm{ \frac{104}{100} \times 700}} \\ \\ = { \rm{728}}[/tex]

• For the 3% increment

[tex] = { \rm{ \frac{(100 + 3)}{100} \times 728}} \\ \\ = { \rm{ \frac{103}{100} \times 728 }} \\ \\ = { \rm{749.84}}[/tex]

Answer:

x=2

Step-by-step explanation:

-5(2)+6= -4

-4 is greater than -5

Answer:

57 Students........................

Answer:

Top left and bottom one

Step-by-step explanation:

Answer:

22 33/40

Step-by-step explanation:

Answer:

Step-by-step explanation:

25

8×1=8

8 +2=10

10+15=25

The answer is the 1st image, and the explanation is the 2nd image.

The answer in text if seeing the image is not possible; x + y = 5 and x + 2y + 8 = 15

Answer:

65--but the method is the important part that the directions indicated.

Step-by-step explanation:

26 + 39

(2 × 13) + (3 × 13)

The GCF is 13.

Factor the 13 out; it's like Distributive Property in reverse.

13 (2 + 3)

13 (5)

65

26+39= 65, so we obtain the same answer as just adding, by using GCF and Distributive Property.

Answer:

  13(2 +3)

Step-by-step explanation:

26 = 2·13

39 = 3·13

The greatest common factor is 13, so the sum can be written ...

  26 +39 = 13(2 +3)

_____

Additional comment

Of course, the value of the sum is ...

  13(2+3) = 13(5) = 65

Alternatively, the sum can be evaluated as ...

  26 +39 = 26 -1 +1 +39 = (26 -1) +(1 +39) = 25 +40 = 65

Answer:

  18

Step-by-step explanation:

Triangles FEG and DEG are congruent by SAS, so DG = FG.

  a+6 = 3a

  6 = 2a

  3 = a

  3a = 3·3 = 9 = FG = DG

DF = 9+9 = 18

Answer: Should be a line

Step-by-step explanation:

Answer:

D. Associative property of addition

Step-by-step explanation:

The associative property of addition states "Changing the group of addends does not change the sum." This means it does not matter what order you use when adding the variables together, and PEMDAS does not apply.

The commentative property of addition states the order of the numbers when adding does not change the sum. While this is true for this equation, this is not the main focus as we are still adding the same way from lines 3-4 with 6+3, instead of 3+6

Answer:

35.00?

Step-by-step explanation:

Answer:

graph them

Step-by-step explanation:

you can tell if you graph them

Answer:

Hey There!

Let's solve...

[tex] \frac{a}{a + 2} = \frac{3}{5} \\ \\ [/tex]

if a/b=c/d,then it will be a*d=b*c

Note: * means "×" or multiply

Let's continue...

[tex]a \times 5 = (a + 2) \times 3 \\ now \: expand \: \\ a \times 5 = 3a + 6 \\ \\ a \times 5 - 3a = 3a + 6 - 3a \\ [/tex]

[tex]now \: it \: will \: be \: a \times 2 = 6 \\ so \: 2a = 6 \\ \\ therefore \: a = \frac{6}{2} \\ simplify \\ \\ \frac{ \cancel{6}^{3} }{ \cancel{2} ^{1} } \\ so \: a = 3 [/tex]

So final answer is a=3

The value of a in the equation is 3

The equation is given as:

[tex]\frac{a}{a+2} =\frac 35[/tex]

Start by cross multiplying the above equation

[tex]5 \times a = 3 *(a + 2)[/tex]

Simplify each product

[tex]5a =3a + 6[/tex]

Collect like terms

[tex]5a -3a = 6[/tex]

Evaluate the difference

[tex]2a = 6[/tex]

Divide both sides by 2

[tex]a = 3[/tex]

Hence, the result of the equation is 3

Read more about equations at:

https://brainly.com/question/2972832

Answer:

I think it is 1/2 because it goes up 1 over 2

Answer:

b. Kilograms

Step-by-step explanation:

200 US Dollar is 30837.86 Jamaican Dollar.

Answer : The watermelon weighs more

Step - by - step explanation :

First do . . . what is 7.5 kilograms into pounds ? 16.5347 ( rounded is 17 pounds )

Second compare . . . 17 > 12

Hope this helped ! :D

Answer:

  126 cm^2

Step-by-step explanation:

The surface area of one cube face is (3 cm)^2 = 9 cm^2.

Each cube has 6 faces, but joining them together hides 4 of the faces. The surface area of the resultant solid is ...

  (6·3 -4)·(9 cm^2) = 126 cm^2

We will simplify the left hand side of the equation to look like the right

[tex]\displaystyle \frac{1-sin(t)}{cos^{2}(t)} + \frac{1}{1 - sin(t)}[/tex]

taking the LCM

[tex]\displaystyle \frac{[1-sin(t)]^{2} + cos^{2}(t)}{[cos^{2}(t)][1 - sin(t)]}[/tex]

expanding the binomial in the numerator

[tex]\displaystyle \frac{[1 + sin^{2}(t) - 2sin(t) + cos^{2}(t)]}{[cos^{2}(t)][1 - sin(t)]}[/tex]

Since sin²x + cos²x = 1

[tex]\displaystyle \frac{[2 - 2sin(t)]}{[cos^{2}(t)][1 - sin(t)]}[/tex]

factoring out the 2 from the numerator

[tex]\displaystyle \frac{2[1 - sin(t)]}{[cos^{2}(t)][1 - sin(t)]}[/tex]

1-sin(t) will cancel out

[tex]\displaystyle \frac{2}{cos^{2}(t)}[/tex]

since cos²(t) = 1/(sec²(t))

[tex]2 sec^{2}(t)[/tex]

which is equal to the right hand side of our given equation.

So we verified the identity!

Answer:

[tex]\rm 2 \sec {}^{2} T[/tex](Verified identity)

Step-by-step explanation:

Please refer to the attachment for calculations.

I hope this helps!

Answer:

(x-1)(x-2)

x=1, x=2

Step-by-step explanation:

Answer:

$1.35 per pound

Step-by-step explanation:

25.65/19=1.35

Answer:

11. attends

12. attend

Answer:

Daughter is 6 , mother is 30.

Step-by-step explanation:

Answer:

Step-by-step explanation:

we should divide it by 3 to get a perfect square .and the square root of the perfect square is 49

[tex]\begin{gathered}\:\:\:\:\:\:\:\:\:\:\:\begin{gathered} \begin{array}{c|c} \underline{\sf{3}}& {\sf{ \underline{ \pink{7203} \: } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\ \underline{\sf{7}}&{\sf{ \underline{2401 \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{7}}&{\sf{ \underline{343 \: \: \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{7}}&{\sf{ \underline{49\: \: \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{7}}&{\sf{ \underline{7 \: \: \: \: \: }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \\\underline{\sf{}}&{\sf{ 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \end{array}\end{gathered}\end{gathered}[/tex]

[tex]\qquad[/tex][tex]\purple{ \bf\longrightarrow 7203 = 3 \times 7 \times 7 \times 7 \times 7} [/tex]

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