Can someone help me please on this question like quick?

Answer:Deep ocean currents (also known as Thermohaline Circulation) are caused by: ... The sinking and transport of large masses of cool water gives rise to the thermohaline circulation, which is driven by density gradients due to variations in temperature and salinity. The earth's rotation also influences deep ocean currents.

Explanation:

Answer:

18 O, 17 O, and 16 O

Explanation:

three naturally stable isotopes

The stable forms of oxygen are molecular oxygen ([tex]O_{2}[/tex]) and ozone ([tex]O_{3}[/tex]). Molecular oxygen is the most common form in the Earth's atmosphere, while ozone is found in the ozone layer of the atmosphere and has a different molecular structure than [tex]O_{2}[/tex].

The most  stable type of oxygen in the Earth's atmosphere is [tex]O_{2}[/tex], sometimes referred to as molecular oxygen or dioxygen. It is made up of two oxygen atoms joined by a link.

Another stable form of oxygen is [tex]O_{3}[/tex], also referred to as ozone. It is a molecule made up of three linked oxygen atoms. The ozone layer in the stratosphere of the Earth contains ozone, which is essential for protecting life on the planet by absorbing damaging ultraviolet (UV) radiation from the Sun.

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Answer:

The resulting mass will be higher than expected

Explanation:

We have to keep this in mind; When magnesium is being burnt in air, two reactions are taking place. The first one is;

2Mg(s) + O2(g) ------> MgO(s)   -------1

And

3Mg(s) + N2(g) -------> Mg3N2(s)  ---------2

Now, if the steps that should be taken to convert Mg3N2 to MgO are not taken, the reaction is much quicker but a higher mass of solid is obtained than what was expected.

This higher mass of solid obtained owes to the fact that Mg3N2 from reaction 2 was not converted to MgO leading to contamination of the product.

Answer:

The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.

Explanation:

Visible light is part of the electromagnetic spectrum. The electromagnetic waves are composed of electric and magnetic fields.

The visible spectrum is composed of seven different wavelengths that corresponds to different colours. When a metallic element is exposed flame, one of these colours is observed. This is commonly called the flame test.

The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.

The approximate wavelength of light (nm) emitted by strontium when it was burned is red, where red has a wavelength of round 620-750 nm.

Generally, Visible mild is phase of the electromagnetic spectrum. the electromagnetic waves are composed of electric powered and magnetic fields. When a metal factor is uncovered flame, one of they seven colors of visible spectrum is seen.

The flame shade of strontium is red, where red has a wavelength of round 620-750 nm.

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Answer:isothermic

Explanation:

Answer:

Energy abosorbed = Energy released.

Thus ISOTHERMIC

Answer:

C₈H₁₈(l) + O₂(g) ⇒ CO₂(g) + H₂O(l)

Explanation:

Let's consider the unbalanced equation for the combustion reaction of octane.

C₈H₁₈(l) + O₂(g) ⇒ CO₂(g) + H₂O(l)

We can begin balancing H atoms by multiplying H₂O by 9, and C atoms by multiplying CO₂ by 8.

C₈H₁₈(l) + O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)

Finally, we get the balanced equation by multiplying O₂ by 12.5.

C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)

Answer:

The coefficents will be 2, 25 --> 16, 18

Explanation:

Answer:

8.02 g of HCl could be left over by the chemical reaction

Explanation:

We propose the reaction:

HCl(aq) + NaOH (s) → NaCl (aq) + H₂O (l)

Ratio is 1:1. First of all, we determine the moles of reactants:

14 g . 1mol / 36.45g = 0.384 mol of acid

6.55 g. 1mol / 40g = 0.164 mol of base

If a determined mass of HCl, could be left; this means that the acid is the excess reagent.

For 0.164 moles of NaOH, we need 0.164 moles of HCl.

As we have 0.384 moles, (0.384 - 0.164) = 0.220 moles of acid are left over in the reaction. We convert the moles to mass:

0.220 mol . 36.45 g /1mol = 8.02 g

Answer:65.4 meters= 65400 millimeters

Answer:

KCl is cost effective

Explanation:

In order to know this, we need to see how much it cost 1 g of each reactant. Let's begin with HCl

HCl:

In this case, let's calculate the moles of HCl in a 0.130 M solution and then, the mass of HCl using the molecular weight of 36.5 g/mol, to get the cost the HCl at the end using the given price:

nHCl = 0.130 moles/L * 0.5 L = 0.065 moles

mHCl = 0.065 moles * 36.5 g/mol = 2.3725 g

Cost HCl = 39.95 $ / 2.3725 g = 16.84 $/g

Conclusion, 1 g of HCl costs 16.84 $

KCl:

In this case, it's pretty obvious that 1 ton of KCl cost 10$, so, there is no need to do further calculations because 1 ton (or more than 1000 kg of the salt) it's just 10$. This is less expensive than the 16.84$ for just 1 g of HCl, so, final conclusion, KCl is more cost-effective.

Hope this helps

Answer:

4.54g of Tris base,25mL of the 0.25M stock solution of glucose and 7.5mL of the 5M stock solution of NaCl must be added and complete the volume in a volumetric flask to 250.0mL

Explanation:

To prepare the single solution we need to find the moles of each solute (Tris, glucose and NaCl) from the stock solutions anf the solid:

Moles Tris:

0.250L *(0.150mol / L) = 0.0375moles Tris * (121.1g/mol) = 4.54g of Tris base must be added

Moles glucose:

0.250L * (0.025mol/L) = 6.25x10⁻³mol glucose * (1L / 0.25mol) = 0.025L = 25mL of the 0.25M stock solution of glucose must be added

Moles NaCl:

0.250L * (0.150mol / L) = 0.0375mol NaCl * (1L / 5mol) = 0.0075L =

7.5mL of the 5M stock solution of NaCl

You must add:

4.54g of Tris base,25mL of the 0.25M stock solution of glucose and 7.5mL of the 5M stock solution of NaCl must be added and complete the volume in a volumetric flask to 250.0mL

Answer:

76.6% is percent yield of P₄

Explanation:

Percent yield is defined as 100 times the ratio of actual yield and theoretical yield. To solve this quesiton we need to find the theoretical yield of the reaction. Using:

2Ca₃(PO₄)₂(s) + 6SiO₂(s) → 6CaSiO₃(l) + P₄O₁₀(g)

P₄O₁₀(g) + 10C(s) → P₄(g) + 10CO(g)

We need to find the moles of Ca₃(PO₄)₂ and SiO₂ to find limiting reactant. With limiting reactant we can find moles of P₄O₁₀ = Moles of P₄. We must convert the moles of P₄ to mass using Molar mass (P₄ = 123.895g/mol):

Moles Ca₃(PO₄)₂ -Molar mass: 310.1767g/mol-

293.5g * (1mol / 310.1767g) = 0.9462moles

Moles SiO₂ -Molar mass: 60.08g/mol-:

378.5g * (1mol / 60.08g) = 6.30 moles

For a complete reaction of 6.30 moles of SiO₂ there are required:

6.30 moles SiO₂ * (2 moles Ca₃(PO₄)₂ / 6 moles SiO₂) =

2.10 moles Ca₃(PO₄)₂. As there are just 0.9462 moles, Ca₃(PO₄)₂ is limiting reactant

Moles P₄O₁₀ = Moles P₄:

0.9462moles Ca₃(PO₄)₂ * (1mol P₄O₁₀ / 2 mol Ca₃(PO₄)₂) = 0.4731 moles P₄O₁₀ = Moles P₄.

The mass is:

0.4731 moles P₄ * (123.895g / 1mol) = 58.6g = Theoretical yield.

Percent yield is:

44.9g / 58.6g * 100 =

Answer:

1. 0.1712M

2. 6.86mg/mL Ca, 12.14mg/mL Cl, 6860000ug/L Ca, 12140000ug/L Cl, 6860mg/L Ca, 12140mg/L Cl, 6860ug/mL Ca, 12140ug/mL Cl.

3. 6860ppm Ca and 12140ppm of Cl.

4. 1.5mL of the 1000ug/mL barium standatd must be taken.

Explanation:

1. Molarity is defined as the amount of moles of solute (Calcium chloride) present in 1L of solution.

The moles of CaCl₂ are:

1.9g CaCl₂ * (1mol / 110.98g) = 0.01712 moles

In 100mL = 0.10L:

0.01712mol / 0.10L = 0.1712M

2. The masses of Calcium and Chloride ions are:

1.9g * (40.078g Ca / 110.98g) = 0.686g Ca

And:

1.9g - 0.686g Ca = 1.214g Cl

mg/mL:

686mg Ca / 100mL = 6.86mg/mL Ca

1214mg Cl / 100mL = 12.14mg/mL Cl

ug/L:

686000ug / 0.1L = 6860000ug/L Ca

1214000ug/ 0.1L = 12140000ug/L Cl

mg/L:

686mg Ca / 0.1L = 6860mg/L Ca

1214mg Cl / 0.1L = 12140mg/L Cl

ug/mL:

686000ug Ca / 100mL = 6860ug/mL Ca

1214000ug Cl / 100mL = 12140ug/mL Cl

3. ppm are defined as mg/L, the ppm of Ca are 6860ppm Ca and 12140ppm of Cl

4. The solution must be diluted from 1000ug/mL to 30ug/mL, that is a dilution of:

1000ug/mL / 30ug/mL:

33.33 times must be diluted the solution.

As final volume of the diluted solution must be 50mL, the volume of the standard needed is:

50mL / 33.33 times = 1.5mL of the 1000ug/mL barium standatd must be taken

Answer:

d because ur heating the ice and causing friction

Answer:

86% - 14% = 72%

Explanation:

Answer:

This would be 63 gallons :)

Explanation:

The Volume of water = 2.4 × 10² L

The Volume of water in gal = ?

The solution:  We know that one gal is equal to 3.785 litter.

So in conclusion, 2.4 × 10²L × 1 gal / 3.785 L

2.4 × 10²L × 0.264 gal. L⁻¹

0.634 × 10² gal

Hopefully this helps :3

63 gal

Answer:

The answer is below

Explanation:

The separation technique is used for separating immiscible liquids.

When separating, the stopper has to be removed when draining the lower layer so as to prevent a vacuum. If vacuum is allowed, the draining rate will reduce and stop.

The liquid should be mixed by shaking the funnel and then opening the stopcock so as the vent out gases.

When near interface between the layers, you should set your eye level so that you do not drain up to the second layer.

After completely draining the first layer, the second layer should be collected in a new flask.

After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.

After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.

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Answer: a) [tex]H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O[/tex]

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) [tex]CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-[/tex]

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) [tex]NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-[/tex]

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) [tex]H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O[/tex]

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) [tex]CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-[/tex]

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) [tex]NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-[/tex]

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

.

Answer:

5.75 L.

Explanation:

From the question given above, the following data were obtained:

Rate = 54.1 miles/gallons

Distance = 132 km

Volume (in L) consumed =?

Next, we shall convert 132 km to mile. This can be obtained as follow:

1 km = 0.621 mile

Therefore,

132 km = 132 km × 0.621 mile / 1 km

132 km = 81.972 mile

Next, we shall determine the volume (in gallons) of the gas needed. This can be obtained as follow:

Rate = 54.1 miles/gallons

Distance = 81.972 mile

Volume (in gallon) =?

Rate = Distance / volume

54.1 = 81.972 / volume

Cross multiply

54.1 × volume = 81.972

Divide both side by 54.1

Volume = 81.972 / 54.1

Volume = 1.52 gallon.

Finally, we shall convert 1.52 gallon to litre (L). This can be obtained as follow:

1 gallon = 3.785 L

Therefore,

1.52 gallon = 1.52 gallon × 3.785 L / 1 gallon

1.52 gallon = 5.75 L

Therefore, 5.75 L of the gas will be consumed.

Answer:

20 kJ

Explanation:

The products are C + D which is on the right side of the diagram. And it says it has 20 kJ of energy.

Answer:

uh i think 12?

Explanation:

Answer:

Conformation

Explanation:

Conformation refers to "any of the spatial arrangements which the atoms in a molecule may adopt and freely convert between, especially by rotation about individual single bonds"(Oxford dictionary).

Carbon-Carbon single bonds are known to undergo rotations about its axis. These rotations leads to various conformations. The energy difference between conformations may be low or high depending on the structure of the molecule. The difference in energy between conformations determines a molecules's preferred conformation.

Answer:

89%

Explanation:

The computation of the sample percentage is sugar is shown below:

As we know that

The mass of the total sample mixture is

= Mass of salt + mass of sugar

= 0.8920

And, the mass of salt is 0.0982 g

So, the mass of sugar is

= 0.8920 - 0.0982

= 0.7938 g

Now the percentage of the sample is sugar is

= 0.7938 ÷ 0.8920

= 89%

Answer:

From the Online Catalog to the Shelf

Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.

Explanation:

Answer:

From the Online Catalog to the Shelf

Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.

Answer:

Simple cubic

Explanation:

The density of metal A (ρa) = 6.17 g/cm³, The density of metal B (ρb) = 8 g/cm³, The atomic weight of metal A (Aa) = 171.3 g/mol, The atomic weight of metal B (Ab) = 162 g/mol, the unit cell edge length (a) = 0.332 nm, concentration of metal A (Ca) = 25%, concentration of metal B (Cb) = 75%

The average density is given by:

[tex]\rho_{ave}=\frac{100}{\frac{C_a}{\rho_a} +\frac{C_b}{\rho_b} } \\\\\rho_{ave}=\frac{100}{\frac{25}{6.17} +\frac{75}{8} } =7.45\ g/cm^3\\\\The\ average\ atomic\ weight\ is:\\\\A_{ave}=\frac{100}{\frac{C_a}{A_a} +\frac{C_b}{A_b} } \\\\A_{ave}=\frac{100}{\frac{25}{171.3} +\frac{75}{162} } =164.23\ g/mol\\\\The\ number\ of\ atoms\ per\ unit(n)\ is:\\\\n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} \\\\N_A=Avogadro\ constant=6.02*10^{22} \ mol^{-1},a=0.332\ nm=3.32*10^{-8}cm\\\\Substituting:\\\\[/tex]

[tex]n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} =\frac{7.45*(3.32*10^{-8})^3*6.02*10^{23}}{164.23} \\\\n=0.999\\[/tex]

n≅1

Since n≅1, the crystal structure for this alloy is simple cubic