Answer:
(B). [tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]
Step-by-step explanation:
12x - 13y = 7
17x - 22y = - 51
A = [tex]\left[\begin{array}{cc}12&-13\\17&-22\end{array}\right][/tex]
[tex]A_{x}[/tex] = [tex]\left[\begin{array}{cc}7&-13\\-51&-22\end{array}\right][/tex]
[tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]
Find f(-2)for f(x)-3 . 2^x
slope m=-2, point: (4,3)
Answer:
Step-by-step explanation:
(y - 3) = -2(x - 4)
y = -2x + 8 + 3
y = -2x + 11
pls give brainliest
Answer:
The the linear equation in point-slope form is
[tex]y-3 = -2 (x-4)[/tex]
Step-by-step explanation:
Given
slope = m = -2point (4, 3)We know that the point-slope form of the line equation is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
Here:
m is the slope(x₁, y₁) is the pointsubstituting the values m = -2 and the point (4, 3) in the point-slope form
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-3 = -2 (x-4)[/tex]
Thus, the the linear equation in point-slope form is
[tex]y-3 = -2 (x-4)[/tex]
Note: This equation could be further simplified to write it in the slope-intercept form
[tex]y=mx+b[/tex]
where m is the slope and b is the y-intercept
so writing the equation in the slope-intercept form
[tex]y-3 = -2 (x-4)[/tex]
[tex]y-3 = -2x+8[/tex]
[tex]y=-2x+8+3[/tex]
[tex]y=-2x+11[/tex]
Thus, the equation is the slope-intercept form is
[tex]y=-2x+11[/tex]