Can someone please help with this !!!!

Answer:

Molarity=Moles of solute/volume of solution in Litres

Simply imputing your values

you have

0.75/65

0.0115M.

Answer:

sulfate

Explanation:

because it is anions

Answer:

0.067 mole Ag°

Explanation:

Given 7.22 g Ag° = 7.22g Ag/ 107.8g/mol = 0.0670 mole Ag° (3 sig. figs.)

Answer:

C. i don't kow

Explanation:

Answer:

they are molecules with normal bonds rather than partial bonds and can occasionally be isolated.

Explanation:

In chemistry, reaction intermediates are species that are formed from reactants and are subsequently being transformed into products as the reaction progresses. In other words,  reaction intermediates are species that do not appear in a balanced reaction equation but occur somewhere along the reaction mechanism of a non-elementary reaction. They are usually short lived species that possess a high amount of energy. They may or may not be isolated.

They are often molecular species with normal bonds unlike activated complexes that are sometimes hypervalent species.

Answer:dang

Explanation:

Answer:

2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

Explanation:

Let's consider the unbalanced equation that occurs when aqueous sodium bromide reacts with chlorine gas to form aqueous sodium chloride and liquid bromine. This is a single displacement reaction.

NaBr(aq) + Cl₂(g) ⇒ NaCl(aq) + Br₂(l)

We will start balancing Cl atoms by multiplying NaCl by 2.

NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

Then, we get the balanced equation by multiplying NaBr by 2.

2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

We have

[tex]volume = \frac{24}{8} = 3 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

         B             B

W      BW          BW        

W       BW          BW

Explanation:

Hope this helps

Answer:

deez cutz

Explanation:

did i get it right

Answer:

molecules will speed up

Explanation:

Answer:A, can be caused by hurricanes

Explanation: got 100 on assignment

Answer:

a

Explanation:

Answer:

Cools Very Quickly

Explanation:

This is the right answer!

Answer:

A. Uni-cellular

Answer:

Waning Crescent

Explanation:

Hope iT Help

Brainliest please

Answer:

the answer is 4

Explanation:

your welcome lol

1) Using Gas In The Home. In our homes, we end up utilizing the material every day.

2) Use In The Industrial Sector. The industrial sector makes similar use of natural gas liquids as a fuel for process heating and raw material to produce chemicals, fertilizers, and hydrogen.

3) Transportation.

Hope this helps. Btw, I love ur pfp!

Answer:

1) Using Gas In The Home. In our homes, we end up utilizing the material every day. ...

2) Use In The Industrial Sector. The industrial sector makes similar use of natural gas liquids as a fuel for process heating and raw material to produce chemicals, fertilizers, and hydrogen.

3) Transportation.

Answer:

40 litres

Explanation:

using Boyle's law V1P1=V2P2

V1=20 l

P1= 60atm

P2= 30 atm V2=?

substituting we will have that

20×60=V2×30

V2={20×60}/30

V2=40 l

We're given the [OH⁻] as 8.34 × 10⁻¹² M. Using the formula pOH = -log[OH⁻], the pOH of this solution would be -log(8.34 × 10⁻¹²) ≈ 11.08.

The pOH is, for lack of a better term, the "opposite" of pH: A pOH of 7 is neutral; a pOH less than 7 is basic; and a pOH greater than 7 is acidic.

This follows from the relation, pH + pOH = 14. In this case, with a pOH of 11.08, our pH would be 14 - 11.08 = 2.92, which is acidic (pH < 7).

Thus, the correct answer choice is B.

These questions all involve special cases of the ideal gas law, namely Boyle's, Charles', and Gay-Lussac's Laws. The ideal gas law relates together the absolute pressure (P), volume (V), the absolute temperature (T), and number of moles (n) of a gas by the following:

PV = nRT

where R is the universal gas constant.

The special cases of the ideal gas law are obtained by holding constant all but two of the variables of a gas.

Boyle's Law relates the pressure and volume of a given mass of gas at a constant temperature: PV = k or P₁V₁ = P₂V₂.

Charles' Law relates the volume and temperature of a given mass of gas at a constant pressure: V/T = k or V₁/T₁ = V₂/T₂.

Gay-Lussac's Law relates the pressure and temperature of a given mass of gas at a constant volume: P/T = k or P₁/T₁ = P₂/T₂.

Depending on what we're given and instructed to find in each question, we can figure out which law to use.

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Question 2:

We are given the volume of a gas at some pressure, and we're to find the new volume of the gas at a different pressure. Here, we use Boyle's Law: P₁V₁ = P₂V₂ where P₁ = 60 atm, V₁ = 20.0 L, and P₂ = 30 atm. We want to find V₂, which we can determine by rearranging the equation into the form V₂ = P₁V₁/P₂. Note that pressure and volume are inversely related according to Boyle's Law; since we're decreasing the pressure, the new volume of the gas should be greater than the initial volume of 20.0 L.

V₂ = (60 atm)(20.0 L)/(30.0 atm) = 40.0 L.

So, at 30 atm, the balloon will have a volume of 40.0 L.

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Question 3:

This is another Boyle's Law question. The standard pressure (our initial pressure) is 1 atm. Here, we are decreasing the volume of the gas, and we want to find the new pressure; the pressure of the gas should thus increase proportionally (the pressure will be greater than 1 atm). Rearranging Boyle's Law to solve for P₂, we get P₂ = P₁V₁/V₂.

P₂ = (1 atm)(8.00 L)/(3 L) = 2.67 atm.

So, the new pressure of the gas is 2.67 atm (or 3 atm if we're considering V₂ to comprise one significant figure).

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Question 4:

Here, we are increasing the temperature of a gas at a known pressure, and we want to determine what the new pressure will be. This is a Gay-Lussac's Law question; from the law, we see that pressure and temperature are directly proportional. Since we're increasing the temperature of the gas, we should expect the pressure of the gas to be greater than the initial 200 atm. Gay-Lussac's Law rearranged to solve for P₂ gives us P₂ = P₁T₂/T₁. When working with gas laws, temperatures must be in Kelvin (°C + 273.15 = K). So, T₁ = 300.15 K, T₂ = 350.15 K, and P₁ = 200 atm.

P₂ = (200 atm)(350.15 K)/(300.15 K) = 233 atm.

So, if the temperature is increased from 27 to 77 °C, the pressure of the gas in the tennis ball will be 233 atm. Here, it's ambiguous how many sig figs to use; if we use one sig fig per P₁, then our P₂ would equal P₁, which I think would be an absurd for a question to ask for. I would stick with either 233 atm or 230 atm (following the two sig figs of the temperatures), or you may go with however you've been instructed.

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Question 5:

This is a Charles' Law question; we're looking for the new volume of a gas when the temperature of the gas is increased. As was the case in Gay-Lussac's Law, the two parameters in Charles' Law—volume and temperature—are directly proportional. Since the temperature of the gas is increased, we should expect the new volume of the gas to also increase (V₂ will be greater than 5.00 L). Temperatures should be in Kelvin.

V₂ = V₁T₂/T₁ = (5.00 L)(300.15 K)/(250.15 K) = 5.99 L.

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Question 6:

Another Charles' Law question. As with question 5, we want to find the new volume of the gas after a change in temperature. This time, the final temperature is lower than the initial temperature, so we should expect that V₂ will be less than the initial 0.5 L. Again, temperatures in Kelvin.

V₂ = V₁T₂/T₁ = (0.5 L)(313.15 K)/(493.15 K) = 0.317 L.

So, the volume of the balloon when it is fully cooled by your refrigerator will be 0.317 L.

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Question 7:

This is yet another Charles' Law question, and, again, we are solving for V₂ after a change in temperature. Since the final temperature is greater than the initial temperature, V₂ should be greater than 2.2 L. Again, the temperatures should be in Kelvin.

V₂ = V₁T₂/T₁ = (2.2 L)(653.15 K)/(453.15 K) = 3.17 L.

The new volume of the gas is 3.17 L ≈ 3.2 L (two sig figs).

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Question 8:

We return to Gay-Lussac's Law here; pressure and temperature are directly proportional, and the temperature of the gas is increased. Thus, P₂ should be greater than 3 atm. Again, remember that temperatures must be in Kelvin.

P₂ = P₁T₂/T₁ = (3 atm)(298.15 K)/(288.15 K) = 3.1 atm.

So, the pressure inside the can after the temperature rise is 3.1 atm. Not a big increase, but an increase nonetheless.

Answer:

b. 101.02°C

Explanation:

The elevation of boiling point in a solvent due the addition of a solute is a colligative property called Boiling point Elevation. The formula is:

ΔT = Kb*m*i

Where ΔT is change in boiling point

Kb is boilinig point elevation constant = 0.512°C/m for water

m is molality of the solution = 0.50m

And i is Van't Hoff Factor (4 for the Al(NO₃)₃ because its disolution produce 4 ions)

Replacing:

ΔT = 0.512°C/m*0.50m*4

ΔT = 1.02°C

As the boiling point of pure water is 100°C and the increasing is of 1.02°C, boiling point of the solution is:

101.02°C

Right option is:

Answer:

There are 1.8021⋅1024 molecules of CH4 in 48 grams of CH4 .

Explanation:

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Answer:

C) limiting reagent

Explanation:

The limiting reagent is the reactant that you don't have a lot of, it will be completely used up in the reaction