Can someone proofread this plz? I put my answers next to the number, so all I need you to do is proofread it. the picture for number 5 is pinned below.

Question 1 (1 point) A
Saved
Waves transfer energy through matter or space.

Question 1 options:
True
False
Question 2 (1 point) A
Saved
Mechanical waves can travel only though a _______________ such as a solid, liquid, or gas.

Question 2 options:

medium


vacuum


prism


anemometer

Question 3 (1 point) B
Saved
Which of the following is not a type of mechanical wave?

Question 3 options:

transverse


concave


surface


longitudinal

Question 4 (1 point) C
Saved
The particles in this wave move perpendicular to the direction of the movement of the wave. These waves are snake like.

Question 4 options:

surface


transverse


longitudinal


cyclone

Question 5 (1 point) A
Saved
The arrow points to an example of

Wave

Question 5 options:

rarefaction


sound barrier


compression


prism

Question 6 (6 points) 5,1,4,3,2,6
Saved
Match each term to its definition

Question 6 options:

answer here ___
Higher the pitch


answer here___
top of the wave


answer here___
Louder


answer here___
Distance from crest to crest


answer here___
bottom of the wave


answer here___
Height of wave

1.
Crest

2.
Trough

3.
Wave length

4.
Amplitude

5.
Higher the frequency

6.
Higher the Amplitude

Question 7 (1 point)
What is the resulting direction of a surface wave?

Question 7 options: C

opposite


circular


perpendicular


parallel

Question 8 (1 point) C

Constructive interference occurs when the crest of 2 waves meet. This can occur when 2 troughs meet as well. When this occurs, water waves look

Question 8 options:

larger


invisible


smaller


the same (no change)

Question 9 (1 point) C
Saved
Water waves are surface waves. The energy of the waves moves

Question 9 options:

both parallel and perpendicular to the wave


only parallel to the motion of the wave


only perpendicular to the motion of the wave

Question 10 (1 point) A
Which molecule makes up 3/4s of the surface of Earth?

Question 10 options:

CO2

NaCl


H2O

C6H12O6
Question 11 (1 point) A
Saved
Water does not expand when it freezes.

Question 11 options:
True
False
Question 12 (7 points) 3,4,1,2,7,6,5
Saved
Match the clue with correct answer

Question 12 options:

3
1


4
tributaries


1
estuary


2
6


7
chloroplast


6
3


5
nucleus

1.
Small rivers that flow into larger rivers

2.
Number of states that drain into Chesapeake Bay

3.
The Chesapeake Bay Watershed ranks what place in the US in terms of estuary size

4.
A body of water containing salt and fresh water.

5.
control center of cell

6.
The Cell Theory has how many statements?

7.
The site of photosynthesis

Question 13 (1 point) D
Saved
What do eukaryotes have that prokaryotes don't?

Question 13 options:

ribosomes


cytoplasm


plasma/cell membrane


nucleus

Question 14 (1 point) 1,4,3,5,2
Saved
Arrange in order from smallest to largest

Question 14 options:

1
cell

4
organ system

3
organ

5
organism

2
tissue

See the attached diagram for reference and free body diagrams. The acceleration a of each body will be the same since each connecting string is in tension.

By Newton's second law, we have

• net force on the train:

- - horizontal

[tex]\sum F = F - F_{k,T} - T_1 = m_Ta[/tex]

(where F = 12 N)

- - vertical

[tex]\sum F = N_T - m_Tg = 0[/tex]

• net force on wagon 1:

- - horizontal

[tex]\sum F = T_1 - T_2 - F_{k,1} = m_1a[/tex]

- - vertical

[tex]\sum F = N_1 - m_1g = 0[/tex]

• net force on wagon 2:

- - horizontal

[tex]\sum F = T_2 - F_{k,2} = m_2a[/tex]

- - vertical

[tex]\sum F = N_2 - m_2g = 0[/tex]

We want to determine T₂, the tension in the string connecting the two wagons.

For each body, the corresponding normal force has magnitude

N = mg

where m is the respective mass, and the kinetic friction has magnitude

Friction = 0.05 N = 0.05mg

So if µ = 0.05, then the frictional force on each body is

[tex]F_{k,T} = 0.05 (2.7\,\mathrm{ kg}) g = 1.323\,\mathrm N[/tex]

[tex]F_{k,1} = 0.05 (1.8\,\mathrm{ kg}) g = 0.882\,\mathrm N[/tex]

[tex]F_{k,2} = 0.05 (1.0\,\mathrm{ kg}) g = 0.49\,\mathrm N[/tex]

which leaves us with the system of equations,

[1] … 12 N - 1.323 N - T₁ = (2.7 kg) a

[2] … T₁ - T₂ - 0.882 N = (1.8 kg) a

[3] … T₂ - 0.49 N = (1.0 kg) a

Adding [1] and [2] eliminates T₁ :

(12 N - 1.323 N - T₁) + (T₁ - T₂ - 0.882 N) = (2.7 kg) a + (1.8 kg) a

[4] … 9.795 N - T₂ = (4.5 kg) a

Divide through both sides of [3] by 1.0 kg to solve for a :

a = (T₂ - 0.49 N) / (1.0 kg)

Substitute this into [4] and solve for T₂ :

9.795 N - T₂ = (4.5 kg) (T₂ - 0.49 N) / (1.0 kg)

(9.795 N - T₂) (1.0 kg) = (4.5 kg) (T₂ - 0.49 N)

9.795 N - T₂ = 4.5 T₂ - 2.205 N

12 N = 5.5 T₂

T₂ = (12 N) / 5.5 ≈ 2.1818 N ≈ 2.2 N

Answer:

6 m/s

Explanation:

p=mv

p=3 kg.m/s

m=0.5 kg

rearrange and substitute to find v:

(3)=(0.5)v

v=3/0.5

v=6 m/s

Answer:

3 miles

Explanation:

5 + 2 - 2 - 2 = 3 miles

Answer:

lifting a bag of groceries.

work is force by distance, if there is no movement there is no work done

Answer:

C. They are too close to the sun.

Explanation:

Answer:

Transparent = lets light pass through without significant interference

Translucent = lets light pass through with significant interference

Opaque = Doesn't let light pass, instead absorbs it

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

Answer:

Explanation:

Answer:

The student does a work of 500 Newton meter on the box.

Explanation:

I think ....... the answer will be ......

like a theory

Answer:

They would land at the same time

Explanation:

They would land at the same exact time.

As weird, impossible and unbelievable as it appears. When in a vacuum, every weight, body and material when released from the same height would land on the ground at the same time. This also means that like in the question, a feather and a ball would land at the same time. And just for illustrations as well, a feather and a car would land at the same time as well.

Answer:

A) a = 73.304 rad/s²

B) Δθ = 3665.2 rad

Explanation:

A) From Newton's first equation of motion, we can say that;

a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.

Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s

Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s

We are given; t = 10 s

Thus;

a = 733.04/10

a = 73.304 rad/s²

B) From Newton's third equation of motion, we can say that;

ω² = ω_o² + 2aΔθ

Where Δθ is angular displacement

Making Δθ the subject;

Δθ = (ω² - ω_o²)/2a

At this point, ω = 0 rad/s while ω_o = 733.04 rad/s

Thus;

Δθ = (0² - 733.04²)/(2 × 73.304)

Δθ = -537347.6416/146.608

Δθ = - 3665.2 rad

We will take the absolute value.

Thus, Δθ = 3665.2 rad

Answer:

The speed of the car is 14.7m/second or 15 m/second approximately.

Explanation:

A microwave beam at [tex]2.10\times10^1^0Hz[/tex] is generated by a stationary speed gun. It bounces off a car and returns at a higher frequency of 1030 Hz. The car's observed frequency would be the product of adding the two frequencies. That is to say,

       F =[tex]2.1\times10^1^0+1030[/tex] =[tex]2.100000103\times10^1^0Hz[/tex]

Using doppler effect formula

[tex]F=\frac{C}{C-V}\times f[/tex]

Where

F = observed frequency

f = source frequency

C = speed of light = [tex]3\times10^8[/tex]

V = speed of the car

 Putting the values in the formula -

        [tex]2.100000103\times10^1^0=\frac{3\times10^8}{3\times10^8-V}\times2.1\times 10^1^0[/tex]

                 [tex]\frac{2.100000103\times10^1^0}{2.1\times10^1^0}[/tex] [tex]=\frac{3\times10^8}{3\times10^8-V}[/tex]

          [tex]1.000000049=\frac{3\times10^8}{3\times10^8-V}[/tex]

by cross multiplication ,

   300000014.7 - 1.000000049V = [tex]3\times10^8[/tex]

    Collect the like terms  

1.000000049V = 14.71429

      Make V the subject of formula

V = [tex]\frac{14.71429}{1.000000049}[/tex]

V = 14.7 m/s

Therefore , the speed of the car is 15m/second approximately.

Answer:

S = 415.1 meters

Explanation:

Dados los siguientes datos;

Velocidad inicial = 25 m/s

Tiempo, t = 7 segundos

Para encontrar la altura (desplazamiento) de la pelota, usaríamos la segunda ecuación de movimiento;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Dónde;

S representa el desplazamiento o altura medida en metros.

u representa la velocidad inicial medida en metros por segundo.

t representa el tiempo medido en segundos.

a representa la aceleración medida en metros por segundo cuadrado.

Sustituyendo en la ecuación, tenemos;

[tex] S = 25*7 + \frac {1}{2}*(9.8)*7^{2}[/tex]

[tex] S = 175 + 4.9*49 [/tex]

[tex] S = 175 + 240.1 [/tex]

S = 415.1 meters

Answer:

5.2 kg

Explanation:

Answer:

During photosynthesis solar energy is converted into chemical energy

Explanation:

During photosynthesis solar energy is converted into chemical energy in the form of energy rich bond of ATP molecule.

ATP (Adenosine triphosphate) and ADP (Adenosine diphosphate) molecules are termed currency of energy. ADP molecule is converted into ATP molecules, whenever energy is available in certain exothermic reactions of metabolism.

ATP molecules are store- house of energy. ATP molecule is broken down into ADP molecule in presence of enzyme ATPase, releasing energy whenever energy is required.

The synthesis of ATP molecules, utilizing solar energy during photosynthesis, is termed photo-phosphorylation.

These ATP molecules produced during light reaction of photosynthesis are utilized in dark reaction of photosynthesis (Calvin cycle).

ATP molecules synthesized during photo-phosphorylation may also be used in other metabolic reactions.

Photo-phosphorylation is of 2 types, i.e. Cyclic and Non-cyclic photo-phosphorylation.

Chlorophyll molecules entrap solar energy . There are 2 types of photo-systems in chlorophyll. These are photo-system -I and photo-system-II .

The electrons of chlorophyll molecule of photo-system I get excited which pass through series of electron carriers in electron transport system arranged in the order of decreasing energy level.

During the passage of electrons from carriers of higher energy level to the carriers of lower energy level, the energy is lost which is utilized for converting ADP molecule into ATP molecule.

Photo-system I is concerned with light reaction of photosynthesis only, constituting cyclic photo-phosphorylation.

The electron transport during Photo-system II results in the synthesis of NADPH2 in presence of enzyme NADP reductase. NADPH2 is used in reduction reaction of Calvin cycle.

Both Photo-systems participate in non-cyclic photo-phosphorylation that results in the synthesis of NADPH2 in addition to the synthesis of ATP molecules.

Answer:

D

Explanation:

I hope this helps :)

Let me know if you want a full explanation

The energy an object has while it is moving is called kinetic energy, or the energy of motion. Thus, the correct option for this question is D.

Kinetic energy may be defined as a type of energy that an object possesses due to its motion. It is defined as the work that is required in order to accelerate a body of a given mass from rest to its stated velocity. It is also known as the energy that is possessed by an object by the virtue of its motion.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles. Any object in motion is using kinetic energy: a person walking, a thrown baseball, a crumb falling from a table, and a charged particle in an electric field are all examples of kinetic energy at work.

Therefore, the energy an object has while it is moving is called kinetic energy, or the energy of motion. Thus, the correct option for this question is D.

To learn more about Kinetic energy, refer to the link:

https://brainly.com/question/25959744

#SPJ2

Explanation:

The Shadow zone is the area of the earth

from angular distances of 104 to 140 degrees from a given earthquake that does not receive any direct P waves

Answer: 324.135 kJ

Explanation:

Given

Mass of dropping is [tex]m=2250\ kg[/tex]

The initial height of dropping is [tex]h_1=16\ m[/tex]

The final height of dropping [tex]h_2=1.3\ m[/tex]

Gravitational potential energy is the function of height i.e.

[tex]\Rightarrow \text{G.E.}=mgh[/tex]

Change in Gravitational Energy is

[tex]\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ[/tex]

Answer:

bottle opener and door knob

Explanation:

Answer:

bottle opener

door handle

Answer: 40.311 m

Explanation:

Given

Ant walks 15 m east

then 40 m North and finally 20 m west

from the figure, ant is 40 m North and 5 m west

Using Pythagoras, we can write

[tex]\Rightarrow d=\sqrt{40^2+5^2}\\\Rightarrow d=\sqrt{1625}=40.311\ m[/tex]

Answer:

The human arm is a class 3 lever

Explanation:

Answer:

A bent arm is a Class 3 lever. The pivot is at the elbow and the forearm acts as the lever arm. The biceps muscle provides the effort (force) and bends the forearm against the weight of the forearm and any weight that the hand might be holding.

Explanation:

Answer:

increased greenhouse gases

Explanation:

I think this is the right answer...

Answer:

it Quadruples

Explanation:

Answer:

Hey mate....

Explanation:

This is ur answer.....

A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared. For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa.

Hope it helps you,

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pascal is the SI unit of pressure symbolized by Pa

1 Pa=1N/m^2

1Pa=1kg/ms^2

Answer:

Abyssal fans, also known as deep-sea fans, underwater deltas, and submarine fans, are underwater geological structures associated with large-scale sediment deposition and formed by turbidity currents

Explanation:

They are underwater deltas and submarine fans, they are associated with large scale sediment, and formed by turbidity currents.

Answer:

200 N/m²

Explanation:

Pressure = Force / Area

Force =100N

Area = 100cm x 50 cm= 5000cm² =0.5m²

Hence Pressure = 100N / 0.5m²

Pressure = 200N/m²