Carbon dioxide and water react to form methanol and oxygen, like this:

2CO2(g) + 4H2O(g) → 2CH3OH(l) + 3O2 (g)

At a certain temperature, a chemist finds that a 7.5L reaction vessel containing a mixture of carbon dioxide, water, methanol, and oxygen at equilibrium has the following composition:

Compound Amount
CO2 3.28g
H2O 3.86g
CH3OH 1.51g
O2 2.80g

Required:
Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: It is different.

Explanation:

kcal is math while calorie is different in nutrition.

Explanation:

1. It is high in sodium

2. Has low percentage of hardness minerals such as magnesium and calcium.

Answer:

1 in. =2.54 cm

3*(10^-4)*2.54=7.62*10^-4

Explanation:

Answer:

D 2,2

Explanation:

We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side

Now we have Na + Cl2 --> 2NaCl

The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side

2Na + Cl2 --> 2NaCl

Now it's balanced!

Answer: 2 copper, 2 Sulfur, 1 Magnesium, 2 Chlorine.

Explanation:

Wasn't sure if this was what you were looking for, but thought if you got the left side that was all you needed?

0.434 mol F

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 8.25 g F

[Solve] moles F

Step 2: Identify Conversions

[PT] Molar Mass of F - 19.00 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.434211 mol F ≈ 0.434 mol F

The water molecule is formed by the covalent bonding between oxygen and hydrogen atoms. Therefore, option C is correct.

Covalent bonding is a type of chemical bonding that involves the sharing of electrons between two atoms. In covalent bonding, the two atoms share a pair of electrons to fill their outermost electron shell and form a stable molecule.

This type of bonding usually occurs between non-metal atoms, which have a high electronegativity and tend to attract electrons strongly. In a covalent bond, the shared electrons are attracted to the positively charged nuclei of both atoms, creating a strong bond.

The strength of the bond depends on the number of shared electrons and the distance between the nuclei. Covalent bonds can be either polar or nonpolar, depending on the electronegativity difference between the two atoms.

In water the bond is formed between oxygen atom and two hydrogen atoms. Hence, C is correct.

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Answer:

1.   504.8 g Al(NO3)3

2.   14.3 moles O2

Explanation:

1.

g = moles x molar mass = 2.37 x 212.996 = 504.8 g Al(NO3)3

MM Al(NO3)3 = 212.996 g/mol

2.

moles = mass : molar mass = 456.89: 32 = 14.3 moles O2

Answer:

c. sublimation and melting

Hope it helps...

Have a great day : )

Answer:

Option C is your answer

C. sublimation and melting

Explanation:

hope it helps u ^_^

have a great day/night

Answer:

1. None of these have hydrogen bonding.

2. None of these have dipoles.

3. Bigger molecules will have stronger London dispersion forces. So I2 has the strongest forces,

and F2 will have the weakest. Correspondingly, I2 will have the highest boiling point and F2 will have the lowest boiling point.

Answer: F2, Cl2, Br2, I2

Explanation:

The order of the boiling points of the given molecules are required.

The required order is [tex]F_2,Cl_2,Br_2[/tex] and [tex]I_2[/tex].

The boiling points of the molecules are

[tex]Br_2=58.8^{\circ}\text{C}[/tex]

[tex]Cl_2=-34.04^{\circ}\text{C}[/tex]

[tex]F_2=-188.13^{\circ}\text{C}[/tex]

[tex]I_2=184.4^{\circ}\text{C}[/tex]

So, the increasing order of the boiling points are [tex]F_2,Cl_2,Br_2[/tex] and [tex]I_2[/tex].

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Answer:

Water

Explanation:

It is because water can be in a solid state which is ice, liquid state which is the water and gas which is the steam that comes from water

Explanation:

water as a matter could co-exist in four forms

Answer:

0.009

Explanation:

Molarity, a measure of molar concentration of a substance is calculated thus;

Molarity = number of moles ÷ volume

According to the provided information, mass of KCl = 0.47g, volume of water = 700ml

Using mole = mass/molar mass

Molar Mass of KCl = 39.10 + 35.453

= 74.553g/mol

Mole = 0.47/74.55

Mole = 0.0063mol

Volume of water = 700ml = 700/1000 = 0.7L

Molarity = 0.006/0.7

Molarity = 0.00857

The value of molarity rounded to three decimal places (3 d.p) = 0.009

Answer:

a

Explanation:

the line is going down

To determine the highest angle the pendulum will swing to after the impact, we can apply the principle of conservation of momentum. Initially, the total momentum is zero since the pendulum is at rest.

After the impact, the total momentum remains zero because the block and embedded projectile move together as a single system.First, let's convert the weight units to a common system. The 5-pound rod is approximately 2.27 kg, and the 10-pound wooden block is around 4.54 kg. The projectile's weight is 0.3 oz, which is about 0.0085 kg.The momentum before the impact is zero, so the momentum after the impact must also be zero. This can be expressed as:(2.27 kg + 4.54 kg + 0.0085 kg) * V_final = 0Solving for V_final gives us V_final ≈ 0 ft/s. Since the velocity is zero after the impact, the pendulum will momentarily stop at its highest point.Therefore, the highest angle the pendulum will swing to after the impact is 0 degrees, or it will come to rest at the vertical position.

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Answer:

i think the answer is A....

Explanation:

Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface.

Answer:

Option F 6 will be the answer.

Answer: 12.1 ml of ethanol is needed

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} CO_2=\frac{18.2g}{44g/mol}=0.414moles[/tex]  

[tex]C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)[/tex]  

According to stoichiometry :

2 moles of [tex]CO_2[/tex] is produced by = 1 mole of [tex]C_2H_5OH[/tex]

Thus 0.414 moles of [tex]CO_2[/tex] is produced by=[tex]\frac{1}{2}\times 0.414=0.207moles[/tex]  of [tex]C_2H_5OH[/tex]

 Mass of [tex]C_2H_5OH=moles\times {\text {Molar mass}}=0.207moles\times 46.07g/mol=9.54g[/tex]

Volume of ethanol = [tex]\frac{\text {Mass of ethanol}}{\text {density of ethanol}}=\frac{9.54g}{0.789g/ml}=12.1ml[/tex]

12.1 ml of ethanol is needed to produce 18.2 g of [tex]CO_2[/tex]

Answer:

NaO2

Explanation:

Solutions are mixtures that are homogenous and comprise solutes and solvents. Methyl alcohol will react with solid sodium chloride to form a solution. Thus, option D is correct.

The solutions are the mixtures of the solute and the solvent. The solute and the solvent are capable of forming a solution only if they both are either polar or nonpolar.

Here, chlorine is a gas, and sodium superoxide is a solid that cannot react with solid sodium chloride to make a solution and hence is eliminated. As sodium chloride is polar it cannot react with nonpolar carbon tetrachloride.

Methyl alcohol is polar and so is sodium chloride. They will react together as,

CH₃OH + NaCl → CH₃Cl + NaOH

Therefore, option D. CH₃OH will react to form a solution.

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Answer: In 1860s, Norwegian scientists C. M. Guldberg and P. Waage noted a peculiar relationship between the amounts of reactants and products in an equilibrium. Today, we call this observation the law of mass action. It relates the amounts of reactants and products at equilibrium for a chemical reaction. For a general chemical reaction occurring in solution, aA + bB ⇄ cC + dD the equilibrium constant, also known as Keq, is defined by the following expression: Keq = [C]c/[D]d where [A] is the molar concentration of species A at equilibrium, and so forth. The coefficients a, b, c, and d in the chemical equation become exponents in the expression for Keq. The Keq is a characteristic numerical value for a given reaction at a given temperature. That is, each chemical reaction has its own characteristic Keq. The concentration of each reactant and product in a chemical reaction at equilibrium is related; the concentrations cannot be random values, but they depend on each other. The numerator of the expression for Keq has the concentrations of every product (however many products there are), while the denominator of the expression for Keq has the concentrations of every reactant, leading to the common products over reactants definition for the Keq. Let us consider a simple example. Suppose we have this equilibrium: A ⇄ B .There is one reactant, one product, and the coefficients on each are just 1. The Keq expression for this equilibrium is Keq = [B]/[A]. Exponents of 1 on each concentration are understood. Suppose the numerical value of Keq for this chemical reaction is 2.0. If [B] = 4.0 M, then [A] must equal 2.0 M so that the value of the fraction equals 2.0: Keq = [B]/[A] = 4.0/2.0 =2.0 .By convention, the units are understood to be M and are omitted from the Keq expression. Suppose [B] were 6.0 M. For the Keq value to remain constant (it is, after all, called the equilibrium constant), then [A] would have to be 3.0 M at equilibrium: Keq = [B]/[A] = 60/3.0= 2.0 .If [A] were not equal to 3.0 M, the reaction would not be at equilibrium, and a net reaction would occur until that ratio was indeed 2.0. At that point, the reaction is at equilibrium, and any net change would cease. However, that the forward and reverse reactions do not stop because chemical equilibrium is dynamic.

Answer:

5.43×10¯³² J

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.66×10⁴ hm

Energy (E) =?

Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:

1 hm = 100 m

Therefore,

3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm

3.66×10⁴ hm = 3.66×10⁶ m

Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:

Wavelength (λ) = 3.66×10⁶ m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 3.66×10⁶ × f

Divide both side by 3.66×10⁶

f = 3×10⁸ / 3.66×10⁶

f = 81.97 Hz

Finally, we shall determine the energy of the photon. This can be obtained as follow:

Frequency (f) = 81.97 Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 81.97

E = 5.43×10¯³² J

Therefore, the energy of the photon is 5.43×10¯³² J

(I leave off the x10^23 because they both will divide out)    Use your per

Answer:

Increases, decreases

Explanation:

Answer:

A) actual yield

Explanation:

Theoretical yield is the amount of product expected based on the stoichiomety.

Percent yield is the actual yield over the theoretical yield.

Answer:

Hydrogen bonds can be intermolecular (occurring between separate molecules) or intramolecular (occurring among parts of the same molecule).

Explanation:

Hydrogen bonds can be intermolecular (occurring between separate molecules) or intramolecular (occurring among parts of the same molecule). Hope this helps.

3.44 × 10⁻¹⁰ g Pb

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 1.00 × 10¹² atoms Pb

[Solve] grams Pb

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Pb - 207.2 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.44072 × 10⁻¹⁰ g Pb ≈ 3.44 × 10⁻¹⁰ g Pb

Answer:

[tex]\boxed {\boxed {\sf 3.44 *10^{-10} \ g \ Pb}}[/tex]

Explanation:

1. Atoms to Moles

Use Avogadro's Number to convert atoms to moles. This number: 6.022*10²³, tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of lead.

[tex]\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]

Multiply by the given number of atoms.

[tex]1.00 *10^{12} \ atoms \ Pb *\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]

Flip the fraction so the atoms of lead cancel.

[tex]1.00 *10^{12} \ atoms \ Pb *\frac {1 \ mol \ Pb}{6.022*10^{23} \ atoms \ Pb}[/tex]

[tex]1.00 *10^{12}*\frac {1 \ mol \ Pb}{6.022*10^{23}}[/tex]

[tex]\frac {1.00 *10^{12}\ mol \ Pb}{6.022*10^{23}} = 1.66057788*10^{-12} \ mol \ Pb[/tex]

2. Moles to Grams

Use the molar mass to convert moles to grams. This can be found on the Periodic Table. For lead it is 207.2 grams per mole.

[tex]\frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]

Multiply by the number of moles we calculated.

[tex]1.66057788*10^{-12} \ mol \ Pb* \frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]

[tex]1.66057788*10^{-12}* \frac {207.2 \ g\ Pb}{ 1 }[/tex]

[tex]1.66057788*10^{-12}* {207.2 \ g\ Pb}= 3.44071737*10^{-10} \ g \ Pb[/tex]

3. Round

The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we calculated, it is the hundredth place. The 0 in the thousandth place tells us to leave the 4.

[tex]3.44 *10^{-10} \ g \ Pb[/tex]

Answer:

(B. Plants and meat)

Explanation: