Carlos Measured the link of a book to be 21 cm the actual length of a book is 23cm which of these is closest to the percent error for Diego's measurements

Answer:

I dont know what sin is

Step-by-step explanation:

Complete Question:

g(x), represents transformations on the parent function of [tex]y = (\frac{1}{2})^x[/tex].

Write the equation for g (x ) with the following transformations:

Reflect over y-axis, and shift right 7

Answer:

[tex]g(x) = (\frac{1}{2})^{-x-7}[/tex]

Step-by-step explanation:

Given

[tex]y = (\frac{1}{2})^x[/tex]

Represent the function as:

[tex]f(x) = (\frac{1}{2})^x[/tex]

Taking the transformations, one after the other:

Reflect over the y-axis.

This is represented by the rule: (x,y) ==> (-x,y)

So, we have:

[tex]f'(x) = (\frac{1}{2})^{-x}[/tex]

Shift right 7 units

This is represented by (x,y) = (x - b, y)

Where b represents the number of units

So, we have:

[tex]f'(x-7) = (\frac{1}{2})^{-x-7}[/tex]

Hence:

[tex]g(x) = (\frac{1}{2})^{-x-7}[/tex]

Answer:

When x=2

Step-by-step explanation:

Well in the first one it tells you that 2x is 90.

In the second it's y=40x+10

So you plug 2 in as the x.

y=40(2)+10

y=80+10

y=90

Hope this helps

Answer:

Step-by-step explanation:

Answer: $117,000

Step-by-step explanation:

The maximum that Arianna may borrow is 2.5 times her annual income.

First step therefore, would be to calculate her annual income:

= 900 * 52 weeks

= $46,800

She may borrow 2.5 times this:

= 46,800 * 2.5

= $117,000

Answer:

y=0.5x-3

Step-by-step explanation:

m=(-12+14)/(-18+22)=0.5

y+14=0.5(x+22)

y=0.5x-3

Answer:

B is the answer.

Step-by-step explanation:

took test. 100% sure.

Answer:

Step-by-step explanation:

bbbbbbbbbbbbb

Answer:

18t-72

Step-by-step explanation:

Answer:

Triangular prism

Step-by-step explanation:

A triangular prism has 9 edges, 6 vertices and 5 faces. I don't think there is any other shape which fits 9 edges and 6 faces.

Answer:

B) ΔGRS ≈ ΔART by SAS Similarity

Step-by-step explanation:

Answer:

64*x^-6

Step-by-step explanation:

Simplify Using Laws of Exponent (4x^-2)^3

Given data

(4x^-2)^3

Let us open the bracket

=4^3*x^-2*3

=64*x^-6

=64x^-6

Hence the equivalent is

64*x^-6

Answer:

y=-2x+5

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

Answer:

1152

Step-by-step explanation:

Answer:

22,000

Step-by-step explanation:

c=2πr

2(3.14)3500

Answer:

Here, it's ratio

Step-by-step explanation:

4/9: 2 and 2/9

simplify

1:5

6/7:x

6/7 x 5 is....

30/7

Mixed number is 4 2/7

BLAM!!!

Answer:

[tex]\frac{2x+y}{w}[/tex]

Answer:

7.0

Step-by-step explanation:

Right angled triangle. To find the hypotenuse, use Pythagorean theorem.

Hypotenuse² =  base² + altitude²

                      = 6.5² + 2.7²

                      = 42.25 + 7.29

                     = 49.54

hypotenuse = √49.54 = 7.04 = 7

Step-by-step explanation:

by using Pythagoras law

h²=p²+b²

missing angle =h let

h²=(2.7)²+(6.5)²

h=√(49.50)=7.03=7

Answer:

6-12.

Step-by-step explanation:

Between 6 to 12 two numbers must the third side of the card fall.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We are given that Sarah is creating a triangular birthday card for her teacher.

Thus in order to glue lace around the outside of the card, Sarah needs to know the length of each side.

It should be known that two of the sides measure 4 inches and 9 inches.

Therefore, in between 6 to 12 the third number must be lie.

More about the Algebra link is given below.

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Answer:

[tex]\frac{10\sqrt{6} }{3}[/tex] and [tex]\frac{11\sqrt{3} }{3}[/tex]

Step-by-step explanation:

(a)

A = [tex]\frac{1}{2}[/tex] × 4[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]

   = 2[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]

   = [tex]\frac{10\sqrt{2} }{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator

= [tex]\frac{10\sqrt{6} }{3}[/tex] units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4[tex]\sqrt{2}[/tex] )² + ([tex]\frac{5}{\sqrt{3} }[/tex] )²

    = 32 + [tex]\frac{25}{3}[/tex]

    = [tex]\frac{96}{3}[/tex] + [tex]\frac{25}{3}[/tex]

    = [tex]\frac{121}{3}[/tex] ( take the square root of both sides )

h = [tex]\sqrt{\frac{121}{3} }[/tex] = [tex]\frac{11}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator

h = [tex]\frac{11\sqrt{3} }{3}[/tex]

Answer:

You may have gotten the opposite and adjacent mixed up.

[tex]\frac{24}{7}[/tex]

Step-by-step explanation:

An easy way to remember these trigonometric ratios is by using SOHCAHTOA, where:

SOH stands for-

[tex]Sine=\frac{Opposite}{Hypotenuse}[/tex]

CAH stands for-

[tex]Cosine=\frac{Adjacent}{Hypotenuse}[/tex]

TOA stands for-

[tex]Tangent=\frac{Opposite}{Adjacent}[/tex]

We are asked to find tan 74° given the right triangle. To find this, we must find the lengths of the opposite side and the adjacent side of the 74° angle. From looking at the triangle, we can see that the side opposite from the 74° angle is 24, and the adjacent is 7. So plugging it into the trigonometric ratio that we found using SOHCAHTOA, we find that:

[tex]tan74=\frac{24}{7}[/tex]

So the answer would be [tex]\frac{24}{7}[/tex]

Seeing as how you picked [tex]\frac{7}{24}[/tex] as your answer, it seems that you may have gotten the opposite and the adjacent mixed up or used [tex]tangent=\frac{adjacent}{opposite}[/tex] as your trigonometric ratio.

I hope you find my answer and explanation to be helpful. Happy studying.

Answer:

Answering so you can give other person branliest

Answer:

24-18=6+6+12

hope this helps you!!

Step-by-step explanation:

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. [tex]\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}[/tex] Therefore, because sin is y/r, r = [tex]\sqrt{5}[/tex] and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = [tex]\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}[/tex]

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = [tex]4\sqrt{2}[/tex]. Now, to find csc, we have to do r/y.

csc = [tex]\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}[/tex]

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = [tex]\sqrt{7/16}[/tex] = [tex]\frac{\sqrt{7}}{4}[/tex]

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -[tex]\sqrt{7/9} = \frac{-\sqrt{7}}{3}[/tex]

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = [tex](\frac{-\sqrt{6}}{2})^{2}[/tex]

1 + cot^2 = 6/4

cot^2 = 2/4

cot = [tex]\frac{\sqrt{2}}{2}[/tex]

tan = [tex]\sqrt{2}[/tex]

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

[tex](\frac{2}{\sqrt{2}})^2[/tex] + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -[tex]\sqrt{3}[/tex]

cos = [tex]\frac{-\sqrt{3}}{3}[/tex]

Hope this helps!! :)

Answer:

sin(θ)=√7/4

tan(θ)= - √7/3

Step-by-step explanation:

c^2= √(4^2-(-3^2))

c^2= √(16-9)

c^2= √7

sin(θ)= opp/hyp=√7/4

tan(θ)= (opp )/adj= - √7/3

Answer:

x = 22

Step-by-step explanation:

19+23=2X-2

42 = 2x - 2

-2x = -2 - 42

-2x = -44

x = 22

hope this helps

Answer:

B.  [tex]x = -4\,\lor \,x = -1[/tex]

Step-by-step explanation:

Let [tex]\sqrt{-4-5\cdot x} = x[/tex], we solve for [tex]x[/tex] by algebraic means.

1) [tex]\sqrt{-4-5\cdot x} = x[/tex] Given

2) [tex]-4-5\cdot x = x^{2}[/tex] Definition of power/Symmetry of equality

3) [tex]x^{2}+5\cdot x + 4 = 0[/tex] Compatibility with addition/Commutative and associative properties/Existence of additive inverse/Modulative property

4) [tex](x+4)\cdot (x+1) = 0[/tex]         [tex]x^{2}+(a+b)\cdot x +a\cdot b = (x + a)\cdot (x+b)[/tex]

5) [tex]x = -4\,\lor \,x = -1[/tex] Result

Hence, the correct answer is B.

Answer:

0 = -16t² + 3200 → 16t²= 3200 → t² = 200 → t = 10√2 s ≈ 14 s

The time taken by the skydiver to reach the ground is 14.1 second.

The solutions to the quadratic equation are the values of the unknown variable x, which satisfy the equation. These solutions are called roots or zeros of quadratic equations. The roots of any polynomial are the solutions for the given equation.

Given that, the height of a skydiver jumping out of an airplane is given by n = -16t² + 3200.

Here, n=0

-16t² + 3200=0

-16t²=-3200

t²=200

t=√200

t=14.14

t=14.1 second

Therefore, the time taken by the skydiver to reach the ground is 14.1 second.

To learn more about the solution of quadratic equation visit:

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Answer:

arc XY = 46°

Step-by-step explanation:

the arc of an inscribed angle is equal to 2 x the inscribed angle

mXY

Answer:

so simple pls follow up..

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