Answer: A nanometer-size carrier could be designed to bring the chemotherapy drugs only to cancer cells.
Explanation:
The problem with chemotherapy as noted by the text above, is that the drugs used target both living and cancer cells and kills them regardless.
The solution therefore, would be to find a way to ensure that chemotherapy targeted only the cancer cells.
One way to do that is to design a nanometer sized carrier that would take the drugs to cancer cells alone so that they would kill only the canerous cells and leave the healthy ones.
Answer:
A. is correct edge 2023
Explanation:
Two cars approach each other from opposite directions each
with a velocity of 54 km/h. One of the cars emits a note of frequency 480 Hz. What will be the approximate frequency
heard in the other car before they cross each other?
Answer:524 Hz
Explanation:
Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.
What is frequency?Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.
For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,
[tex]f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1[/tex]
Here, [tex]V_s[/tex] is the speed of the sound.
Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.
Convert the unit of velocity of the car as,
[tex]\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s[/tex]
As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.
Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,
[tex]f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz[/tex]
The approximate frequency heard in the other car before they cross each other is 524 Hz.
Learn more about the frequency here;
https://brainly.com/question/1436295
pick the correct answer there are three correct answers
. The Soviet Yuri Gagarin was the first human to orbit Earth true or false
Answer:
true , I searched and got u the answer
4. What is the frequency of an electromagnetic wave with a wavelength
of 20 m?
Answer:
The frequency of radio waves with a wavelength of 20m is
1.5 e+7 Hertz (Hz) or 15 million Hertz.
This was obtained from the formula speed (c) is equal to the product of frequency (f) and wavelength (λ)
c = fλ
Since we are looking for the frequency, we will divide both sides of the formula above by the lamda symbol for wavelength, which gives us:
f = c / λ
The value of wavelength is already given which is 20 meters. The speed of radio waves is the same with the speed of light when travelling in a vacuum – also with the other electromagnetic waves. Hence the speed (c) is 3 e+8 m/s
f = 3 e+8 m/s / 20m
f = 1.5 e+7 H
Explanation:
this is the correct answer you want.
Why do you think the Senate requires a greater percentage of votes?
Answer:
yes
Explanation:
yes
Which phase of matter makes up stars?
Answer:
Plasma is a phase of matter that makes up stars.
An electron is traveling in the positive x direction. A uniform electric field is present and oriented in the negative z direction. If a uniform magnetic field with the appropriate magnitude and direction is simultaneously generated in the region of interest, the net force on the electron can be made to have a magnitude of zero. What must the direction of the magnetic field be?
Answer:
the fingers extended points in the negative direction of the y-axis
Explanation:
For this exercise we use the relationship of the force with the electric field
F = q E
electron charge is q = -e
F = - eE
therefore the forces are in the opposite direction to the electric field direction, which indicates that it goes towards the negative side of the Z axis.
Consequently the electric force is in the positive direction of the z axis
us the direction of the magnetic field so that it cancels out the electric forces.
For the direction of the magnetic force we use the right hand rule. The thumb points in the direction of the speed, the fingers extended in the direction of the magnetic field and the palm in the direction of the Force if the charge is positive, if the charge is negative it is in the opposite direction
In this case we want the magnetic force to be directed in the negative direction of the z axis.
The charge moves in the positive direction of the x-axis
the palm must point in the negative directional of the Z axis, ie the negative charge
therefore the fingers extended points in the negative direction of the y-axis
Compare an earthquake with a Richter scale magnitude of 5.5 to one with a magnitude of 7.5.
____________________________________________________________________
A. 2 times stronger
B. 1000 times stronger
C. 100 times stronger
D. 20 times stronger
Answer:
100 stronger
Explanation:
place the steps of protien in the correct order
Answer:
Umm, where is the pic
Explanation:
Answer:
no attachment
Explanation:
Please add attachment so I can answer
given a force of 75N and an acceleration of 3m/s2, what is the mass
force = 75N --- (given)
acceleration = 3m/s² ---- (given)
FORCE = mass × acceleration75N = mass × 3m/s²
mass = 75÷3
mass = 25kg-----------------------------FOLLOW MEmagnetism is an example of:
A. contact force
B. non-contact force
C.friction
Answer:
The answer is Non contract force
A copper telephone wire has essentially
Answer:
128.21 m
Explanation:
The following data were obtained from the question:
Initial temperature (θ₁) = 4 °C
Final temperature (θ₂) = 43 °C
Change in length (ΔL) = 8.5 cm
Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)
Original length (L₁) =.?
The original length can be obtained as follow:
α = ΔL / L₁(θ₂ – θ₁)
17×10¯⁶ = 8.5 / L₁(43 – 4)
17×10¯⁶ = 8.5 / L₁(39)
17×10¯⁶ = 8.5 / 39L₁
Cross multiply
17×10¯⁶ × 39L₁ = 8.5
6.63×10¯⁴ L₁ = 8.5
Divide both side by 6.63×10¯⁴
L₁ = 8.5 / 6.63×10¯⁴
L₁ = 12820.51 cm
Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
12820.51 cm = 12820.51 cm × 1 m / 100 cm
12820.51 cm = 128.21 m
Thus, the original length of the wire is 128.21 m
When you mix red and blue pigment, you produce the color:
orange
black
red
violet
Answer:
violet
Explanation:
pick the correct answer
A ball is thrown straight upward with an initial velocity of 12 m/s. How long would it take the ball to reach s spot 15 meters directly below where it was thrown?
Answer:
3.3 s
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 12 m/s
Height of tower (h₁) = 15 m
Total time (T) to reach the ground =?
Next, we shall determine the time taken to reach the maximum height from the tower. This can be obtained as follow:
Initial velocity (u) = 12 m/s
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 10 m/s²
Time (t₁) to reach the maximum height from tower =?
v = u – gt₁ (ball is going against gravity)
0 = 12 – 10t₁
Rearrange
10t₁ = 12
Divide both side by 10
t₁ = 12/ 10
t₁ = 1.2 s
Next, we shall determine the maximum height reached by the ball from the tower.
Initial velocity (u) = 12 m/s
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 10 m/s²
Maximum height from the tower (h₂) =?
v² = u² – 2gh₂
0² = 12² – 2 × 10 × h₂
0 = 144 – 20h₂
Rearrange
20h₂ = 144
Divide both side by 20
h₂ = 144 / 20
h₂ = 7.2 m
Next, we shall determine the maximum height from the ground. This can be obtained as follow:
Height of tower (h₁) = 15 m
Maximum height from the tower (h₂) = 7.2 m
Maximum height from the ground (H) =?
H = h₁ + h₂
H = 15 + 7.2
H = 22.2 m
Next, we shall determine the time taken for ball to get to the ground from the maximum height. This can be obtained as follow:
Acceleration due to gravity (g) = 10 m/s²
Maximum height from the ground (H) = 22.2 m
Time (t₂) taken for ball to get to the ground from the maximum height =?
H = ½gt₂²
22.2 = ½ × 10 × t₂²
22.2 = 5 × t₂²
Divide both side by 5
t₂² = 22.2 / 5
t₂² = 4.44
Take the square root of both side
t₂ = √4.44
t₂ = 2.1 s
Finally, we shall determine the time taken for the ball to get to the ground. This can be obtained as follow:
Time (t₁) to reach the maximum height from tower = 1.2 s
Time (t₂) taken for ball to get to the ground from the maximum height = 2.1 s
Time (T) taken for the ball to get to the ground =?
T = t₁ + t₂
T = 1.2 + 2.1
T = 3.3 s
Therefore, it will take the ball 3.3 s to get to the ground.
please help with my physics homework
Answer:
The graph data expresses the data started high up and moved into a continuous reaction before slowly decreasing and hit a point, where it remained the same.
A diver leaves the end of a 5.00 m high diving board and reaches a maximum height of 5.50 m before she strikes the water below. The landing point is 3.25 m beyond the end of the diving board in the horizontal direction. You may approximate the diver as a point particle. Hint: Carefully consider your placement of the origin before starting your calculations.
Determine:_____.
(a) After the diver leaves the diving board, how long does it take for her to strike the water?
(b) The initial velocity of the projectile 7. (hint: a vector has both direction and magnitude).
(c) The final velocity with which the diver enters the water ö, (hint: a vector has both direction and magnitude).
Answer:
a) 1.38 s
b) v₀ = 3.92 m/s θ₀ = 53.1º
c) vf = 10.7 m/s θf = -77.2º
Explanation:
a)
Once the diver leaves the board, she has an initial velocity vector, that we can split in two directions perpendicular each other, the vertical direction (coincident with the y-axis, positive upward) and the horizontal direction (coincident with the x-axis, positive away from the diving board).These velocities, are independent each other, due to they are perpendicular.In the horizontal direction, since no acceleration takes place, she keeps the horizontal component v₀ₓ, constant.In the vertical direction, she is always accelerated downward by gravity, which constant value is g = 9.8m/s2.With this all information, we can find the total time since she left the diving board till she strikes the water below, taking advantage of the fact that she reached to a maximum height of 5.5 m,i.e. , 0.5m above the diving board. When at this point, the vertical component of the velocity is zero, so we can write the following kinematic equation:[tex]v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (1)[/tex]
Solving for v₀y in (1):[tex]v_{oy} = \sqrt{2*g*\Delta_{ymax} } = \sqrt{2*9.8m/s2*0.5m} = 3.13 m/s (2)[/tex]
When she is at the highest point, her final vertical speed is zero, so we can find the time when she reached to this point, applying the definition of acceleration, as follows:[tex]v_{fyhmax} = v_{oy} - g*t_{hmax} = 0 (3)[/tex]
Solving for t in (3), we get:[tex]t_{hmax} =- \frac{v_{oy}}{g} =\frac{3.13m/s}{9.8m/s2} = 0.32 s (4)[/tex]
Since at this point, the vertical speed is zero, we can apply the equation for the displacement (vertical in this case) for a total displacement of 5.5 m (taking as the origin the point just below the end of the diving board, on the surface of the water), with initial speed equal to zero, as follows:[tex]\Delta y = \frac{1}{2}* g * t^{2} = 5.5 m (5)[/tex]
Solving for t (which we will call t₂) in (5), we get:[tex]t_{2} = \sqrt{\frac{2*\Delta y}{g}} = \sqrt{\frac{2*5.5m}{9.8m/s2} } = 1.06 s (6)[/tex]
The total time will be just the sum of (4) (since leaving the diving board till reaching the maximum height) and (6) (from there until she strikes the water), as follows:Δt = thmax + t₂ = 0.32 s + 1.06 s = 1.38 s (7)b)
In order to know the value of v₀, we need first to get the values of vox and voy.We know that the horizontal speed remains constant, so, if we know the total time traveled (same as in a)) and the horizontal distance (given), we can find v₀ₓ applying the definition of average velocity, as follows:[tex]v_{ox} =\frac{\Delta x}{\Delta t} =\frac{3.25m}{1.38s} = 2.36 m/s (8)[/tex]
We know the value of v₀y from (2):[tex]v_{oy} = 3.13 m/s (9)[/tex]
Applying the Pythagorean theorem, we can get the magnitude of v₀ as follows:[tex]v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{(2.36m/s)^{2} + (3.13m/s)^{2}} = 3.92m/s (10)[/tex]
We can find the angle that it makes with the horizontal, applying the definition of tangent of an angle, as follows:[tex]tg_{(\theta o)} = \frac{v_{oy}}{v_{ox} } = \frac{3.13}{2.36} = 1.33 (11)[/tex]
⇒ θ₀ = tg⁻¹ (1.33) = 53.1º
c)
In order to find the vertical component of the final velocity, we can use the following kinematic equation, for the total vertical displacement of 5.5 m since it started to fall after reaching to the maximum speed:[tex]v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (12)[/tex]
When it started to fall, in the vertical direction, the diver was at rest, so in (12) we have v₀y = 0.Solving for vfy in (12) we get:[tex]v_{fy} = \sqrt{2*g*\Delta_{y} } = \sqrt{2*9.8m/s2*5.5m} = -10.4 m/s (13)[/tex]
We already know that the horizontal component is the same as the initial v₀ₓ, so we can find the magnitude of the final velocity applying the Pythagorean Theorem as follows:[tex]v_{f} = \sqrt{v_{fx}^{2} + v_{fy}^{2}} = \sqrt{(2.36m/s)^{2} + (-10.4m/s)^{2}} = 10.7 m/s (14)[/tex]
Finally, as we did in (11) to find the angle that it makes with the horizontal, we can find θf as follows:[tex]tg_{(\theta f)} = \frac{v_{fy}}{v_{fx} } = \frac{-10.4}{2.36} = -4.41 (15)[/tex]
⇒ θf = tg⁻¹ (-4.41) = -77.2º
Lithium an element in group 1. What element is below Lithium in the same group
Answer:
Group 1A (or IA) of the periodic table are the alkali metals: hydrogen (H), lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).
Explanation:
Hope it helps! Correct me if I am wrong :>
A mustang, has an average velocity of 33 m/s while covering a course that is 21 miles long. (1 mile = 1609 m). How long did it take the driver to complete the course?
Answer:
t = 1023.9 seconds
Explanation:
Given that,
The average velocity of a Mustang, v = 33m/s
Distance, d = 21 miles = 33789 m
Let the driver takes t seconds. So,
Speed = distance/time
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{33789}{33}\\\\t=1023.9\ s[/tex]
So, it will take 1023.9 seconds to complete the course.
an object with a mass of 3.2 kg has a force of 7.3 newtons applied to it. what is the resulting acceleration of the object?
Answer:
2.28m/s^2
Explanation:
F=ma
a=F/m
a=7.3/3.2
a=2.28m/s^2
I threw a plastic ball in the pool for my dog to fetch. The mass of the ball was 125g. What must the volume be to have a density of 0.500g/mL
Answer:
250 mL
Explanation:
Density equation:
[tex]Density = \frac{mass}{volume}[/tex]
Variables:
D = density
m = mass
V = volume
Solve:
M = 125 g
D = 0.500 g/mL
V = ?
[tex]0.500 g/mL = \frac{125 g}{V}[/tex]
V = 250 mL
if an object isn't moving the forces are acting on the object are: A. not present B. unbalanced C. balanced D. accelerated
When conducting an experiment, a scientist should exhibit all of these traits EXCEPT
a-bias
b-curiosity
c-honesty
d-skepticism
When conducting an experiment, a scientist should exhibit all of these traits except bias. Thus, the correct option for this question is A.
What are the properties of scientists?The properties of scientists are as follows:
They must be curious about their work.They must have a lot of patience as they are required to repeat experiments multiple times. Their courageous behavior motivates them to perform consistently.They are open-minded and free from any type of cultural and religious bias. They are creative, persistent, communicative, and detail-orientated individuals.If scientists have properties of bias and discrimination, they never work consistently and are focused because their biased behavior ruins their interest, talent, and future perspectives.
Therefore, when conducting an experiment, a scientist should exhibit all of these traits except bias. Thus, the correct option for this question is A.
To learn more about Scientists, refer to the link:
https://brainly.com/question/26386481
#SPJ2
Can someone please explain why the answer to this net torque question is +115 Nm
Answer:
Net torque in positive direction:
Fz = -450 * cos 30 deg * 1.5 = -585 N-M
Fz = 200 * 3.5 = 700 N-M
Net F = 115 N-M
Torque is generally defined as L = R X F
X cross Y = Z normal coordinate system
Note that Z will be out of the page giving the positive value for the torque.
If a roller coaster cart, with a mass of 100 kg, traveled this coaster, how much kinetic energy would it have at point 'E'?
Answer:
Explanation:
Assuming no friction between the roller coaster car and the hill, and neglecting air resistance, the kinetic energy the roller coaster car would have at the bottom of the hill would be equal to its gravitational potential energy at the top of the hill, by conservation of energy.
Which of the following DOES NOT affect the electric force?
Answer:did you get an answer ?
Explanation:
Method
1. Place a trolley on a smooth runway and tilt the runway very slightly so that the
slope compensate for the friction between the wheels and the runway. If
pushed gently, the trolley should move at a constant velocity.
2. Measure the mass of the trolleys.
3. Attach the ticker timer to the trolley and thread the tape through the ticker
timer.
4. Attach a smooth pulley vertically to the bottom of the runway.
Answer:
3
Explanation:
it's too because on you measuring mass of something
when do we experience conservation of energy
Always, whether we notice it or not. It's a law of nature.
By riding an elevator up 200 m, a person’s GPE increases by 164,000 J. What is the person’s mass?
Answer:
Person’s mass M = 83.67 kg (Approx.)
Explanation:
Given:
Gravitational potential energy = 164,000 J
Height = 200 m
Find:
Person’s mass M
Computation:
Gravitational acceleration g = 9.8 m/s²
Gravitational potential energy = mgh
164,000 = (m)(9.8)(200)
Person’s mass M = 83.67 kg (Approx.)
15. If a dog pulls a 5 kg sled with a force of 70 N, what is its acceleration?
Answer:
14 m/s^2
Explanation:
We have to use the equation F=ma because the question is a Newton's second law question.
First, list known values
F (force) = 70 N
m (mass) = 5 kg
a (acceleration) = ? (we have to solve for this)
Second, plug in known values into equation.
F=ma
70=5a
Third, solve. To solve this all you have to do is divide both sides by 5
70/5=5/5a
Fourth, your answer will be 14 meters per second squared (m/s^2)
I hope this answer helps and have a great day!