Chris recently received an array p as his birthday gift from Joseph, whose elements are either 0 or 1. He wants to use it to generate an infinite long superarray. Here is his strategy: each time, he inverts his array by bits, changing all 0 to 1 and all 1 to 0 to get another array, then concatenate the original array and the inverted array together. For example, if the original array is [0,1,1,0] then the inverted array will be [1,0,0,1] and the new array will be [0,1,1,0,1,0,0,1]. He wonders what the array will look like after he repeat this many many times.

He ask you to help him sort this out. Given the original array pp of length ????n and two indices a,b (????≪????≪????, means much less than) Design an algorithm to calculate the sum of elements between a and b of the generated infinite array p^, specifically, ∑????≤????≤????p????^. He also wants you to do it real fast, so make sure your algorithm runs less than O(b) time. Explain your algorithm and analyze its complexity.

Answer: They operate from countries that do not have strict laws against cybercrime.

They are not physically present when the crime is committed.

Explanation:

edg

Answer:

They operate from countries that do not have strict laws against cybercrime.

They are not physically present when the crime is committed.

Explanation:

Expert Answer for this question-

Explanation:

Answer- C

Explanation:

Answer:

A filter bubble

Explanation:

Answer: Animations tab

Animation styles

Lines

Motion paths

Explanation: Edg2021

Answer:

SELECT

CardNumber,

len(CardNumber) as CardNumberLength,

right(CardNumber, 4) as LastFourDigits,

'XXXX-XXXX-XXXX-' + right(CardNumber, 4) as FormattedNumber

from Orders

Explanation:

The question you posted contains the answer (See answer section). So, I will only help in providing an explanation

Given

Table name: Orders

Records to select: CardNumber, length of CardNumber, last 4 digits of CardNumber

From the question, we understand that the last four digits should display the first 12 digits as X while the last 4 digits are displayed.

So, the solution is as follows:

SELECT ----> This implies that the query is to perform a select operation

CardNumber, ---> This represents a column to read

len(CardNumber) as CardNumberLength, -----> len(CardNumber) means that the length of card number is to be calculated.

as CardNumberLength implies that an CardNumberLength is used as an alias to represent the calculated length

right(CardNumber, 4) as LastFourDigits, --> This reads the 4 rightmost digit of column CardNumber

'XXXX-XXXX-XXXX-' + right(CardNumber, 4) as FormattedNumber --> This concatenates the prefix XXXX-XXXX-XXXX to the 4 rightmost digit of column CardNumber

as FormattedNumber implies that an FormattedNumber is used as an alias to represent record

from Orders --> This represents the table where the record is being read.

Answer: Including performance tests, polls, or awards.

Listing names of satisfied users

Explanation:

For every business, it is important to build ones credibility as this is vital on keeping ones customers and clients. A credible organization is trusted and respected.

The techniques that can be used to overcome resistance and improve the credibility of a product include having performance tests, polls, or awards and also listing the names of satisfied users.

Sending unwanted merchandise and also using a celebrity name without authorization is bad for one's business as it will have a negative effect on the business credibility.

Answer:

Following are the code to the given question:

#include<iostream>// header file

using namespace std;

int main()//main function

{

   int squirrels, walnuts;//defining integer variable

   bool result = false;  //defining a bool variable that holds a false value

   cout<<"Enter the number of squirrels"<<endl;//print message

   cin>>squirrels;   // input integer value

   cout<<"Enter the number of walnuts"<<endl;//print message

   cin>>walnuts;  // input integer value

   if(squirrels < 1)//use if variable that checks squirrels value less than 1

   {    

       result = false;//use result variable that holds false value

   }

   else//defining else block

   {

       if(squirrels <= 10)//use if variable that checks squirrels value less than equal to 10

       {

           if(walnuts < 15) //use if variable that checks walnuts value less than 15

               result = false;//use result variable that holds false value

           else if(walnuts <= 30)//use elseif block that checks walnuts less than equal to 30

               result = true; //use result variable that holds true value

           else //defining else block

           result = false;//use result variable that holds false value

       }

       else if(squirrels <= 30)//use elseif that checks squirrels value less than equal to 30

       {

           if(walnuts >= 2*squirrels) //use if block to check walnuts value greater than equal to 2 times of squirrels

               result = true; //use result variable that holds true value

           else//defining else block

               result = false;//use result variable that holds false value

       }

       else if(walnuts == 60 + squirrels - 30)//using elseif that checks walnuts value equal to squirrels

           result = true;//use result variable that holds true value

       else //defining else block

           result = false;//use result variable that holds false value

       }

       if(result)//use if to check result  

           cout<<"True";//print True as a message

       else  //defining else block

           cout<<"False";//print False as a message

       return 0;

}

Output:

Enter the number of squirrels

10

Enter the number of walnuts

30

True

Explanation:

In this code, two integer variable "squirrels and walnuts" and one bool variable "result" is declared, in which the integer variable use that input the value from the user-end, and inside this the multiple conditional statements is used that checks integer variable value and use the bool variable to assign value as per given condition and at the last, it uses if block to check the bool variable value and print its value.

Answer:

Add Labels.

As far as i remember.

Explanation:

Hope i helped, brainliest would be appreciated.

Have a great day!

   ~Aadi x

Add Labels is step two of the Five-Step Worksheet Creation Process. It helps in inserting the data and values in the worksheet.

A label in a spreadsheet application like Microsoft Excel is text that offers information in the rows or columns around it. 3. Any writing placed above a part of a chart that provides extra details about the value of the chart is referred to as a label.

Thus, it is Add Labels

For more details about label worksheet in Excel, click here:

https://brainly.com/question/14719484

#SPJ2

Answer:

See explanation

Explanation:

Replace the ____ with the expressions in bold and italics

1)          return km

return km returns the result of the computation

2)  = convert_distance(my_trip_miles)

convert_distance(my_trip_miles) calls the function and passes my_trip_miles to the function

3)  + str(my_trip_km)

The above statement prints the returned value

4)  +str(my_trip_km * 2)

The above statement prints the returned value multiplied by 2

Answer:

0

5

10

15

20

Explanation:

P=O should be P=0, but even with this error this is the output.

When P reaches 20 it will execute the loop once more, so 20 gets printed, before getting increased to 25, which will not be printed because then the loop ends.

Solution :

[tex]$\#$[/tex]include [tex]$<stdio.h>$[/tex]  

[tex]$\#$[/tex]include [tex]$<string.h>$[/tex]    

void parse[tex]$\_$[/tex]name([tex]$char \ full[]$[/tex], char first[tex]$[],$[/tex] char last[tex]$[])$[/tex]

{

// to_get_this_function_working_immediately, _irst

// stub_it_out_as_below._When_you_have_everything_else

// working,_come_back_and_really_parse_full_name

// this always sets first name to "Noah"

int i, j = 0;

for(i = 0; full[i] != ' '; i++)

  first[j++] = full[i];

first[j] = '\0';  

// this always sets last name to "Zark"

j = 0;

strcpy(last, full+i+1);

// replace the above calls with the actual logic to separate

// full into two distinct pieces

}

int main()

{

char full[40], first[20], last[20];

double hours[5];

// ask the user to enter full name

printf("What is your name? ");

gets(full);

// parse the full name into first and last

parse_name(full, first, last);

// load the hours

for(int i = 0; i < 5; i++)

{

   printf("Enter hours for day %d: ", i+1);

   scanf("%lf", &hours[i]);

}

// create the time card

FILE* fp = fopen("timecard.txt", "w");

fprintf(fp, "First Name: %s\n", first);

fprintf(fp, "Last Name: %s\n", last);

double sum = 0.0;

for(int i = 0; i < 5; i++)

{

   fprintf(fp, "Day %i: %.1lf\n", i+1, hours[i]);

   sum += hours[i];

}

fprintf(fp, "Total: %.1f\n", sum);    

printf("Timecard is ready. See timecard.txt\n");

return 0;

}