Compare the number of electrons with the number of protons in a charged object.

Answer:

The speed of the flashlight at that point is 3.7 m/s

Explanation:

When an object of mass M is at a height H above the ground, the potential energy of the object is:

U = M*H*g

Where g is the gravitational acceleration, g = 9.8 m/s^2

And for an object with velocity v, the kinetic energy is:

K = (M/2)*v^2

We know that when the flashlight of mass  1kg is 0.7 meters above the ground, the potential energy is equal to the kinetic energy, then:

M = 1kg

H = 0.7m

g = 9.8 m/s^2

Replacing these in the equations, we get:

U = K

(1kg)*(0.7m)*(9.8 m/s^2) = ((1kg)/2)*v^2

As the mass factor appears in both sides, we can remove it:

(0.7 m)*(9.8 m/s^2) = (v^2)/2

Now we can multiply both sides by 2:

2*(0.7 m)*(9.8 m/s^2) = v^2

Now let's apply the square root to both sides:

√(2*(0.7 m)*(9.8 m/s^2)) = v = 3.7 m/s

Answer:

Explanation:

2500 rpm = 2500 / 60 rps ( revolution per second )

= 41.67 rps .

power output = 500 kW

thermal efficiency = 20 %

power input = (100 /20) x 500 kW

= 2500 kW .

work done per second = 2500 kJ

work done per cycle = 2500 / 41.67

= 60 kJ .

We have that the  workdone per cycle is mathematically given as

Wc=12.00KJ

Question Parameters:

The power output of a car engine running at 2500 rpm is 500 kW

Generally the work done per cycle  is mathematically given as

Wc=500*1/41.666

Where

=2500rev/60sec

=41.666

Meaning one cycle takes 1/41.666

Hence

Wc=500*1/41.666

Wc=12.00KJ

For more information on work

https://brainly.com/question/756198

Answer:

Fuerza, F = 0.001 Newton

Explanation:

Dados los siguientes datos;

Intensidad del campo eléctrico = 5 * 10² N/C

Carga = 2 microculombios = 2 * 10^{-6} culombios

Para encontrar la fuerza que actúa sobre la carga;

Matemáticamente, la intensidad del campo eléctrico viene dada por la fórmula;

Intensidad del campo eléctrico = fuerza/carga

F = E * Q

F = 5 * 10² * 2 * 10^{-6}

Fuerza, F = 0.001 Newton

Answer:

0.01 C

Explanation:

Applying,

F = qvBsinФ................ Equation 1

Where F = Force on the charged particle, q = charge on the particle, v = velocity, B = magnetic field, Ф =  angle

Since the charged particle noves in a circle,

F = mv²/r................. Equation 2

Where m = mass of the particle, v = velocity of the particle, r = radius of the  circle

Substitute equation 2 into equation 1

mv²/r = qvBsinФ

make q the subject of the equation

q = mv/(rBsinФ)............. Equation 3

Given: m = 0.005 kg, v = 2 m/s, r = 0.2 m, B = 5 T, Ф = 90° (Act at right angle)

Substitute these values into equation 3

q = (0.005×2)/(0.2×5×sin90°)

q = 0.01/(1)

q = 0.01 C

Answer:

The correct answer is "1080 W".

Explanation:

Given:

Current,

I = 9.0 A

Potential difference,

V = 120 volt

As we know,

⇒ [tex]Power=IV[/tex]

On substituting the values, we get

⇒             [tex]=120\times 9.0[/tex]

⇒             [tex]=1080 \ W[/tex]

Answer:

Fuel cells (Chemical energy → Electrical energy) Battery (electricity) (Chemical energy → Electrical energy) Fire (Chemical energy → Heat and Light)

Explanation:

Answer:

Hey mate.....

Explanation:

This is ur answer.....

Newton's third law of motion states that whenever a first object exerts a force on a second object, the first object experiences a force equal in magnitude but opposite in direction to the force that it exerts.

Hope it helps!

Brainliest pls!

Follow me! :)

Answer:

An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.

Answer:

16

Explanation:

Since frequency in a stretched string f = (n/2L)√T/μ and n, L and μ are constant, f ∝ √T  where T = tension in string

Now f₂/f₁ = √T₂/√T₁

Since f₁ = f (frequency at tension T₁) and f₂ = 4f (since its frequency increases by 2 octaves to 4f at tension T₂).

So,

f₂/f₁ = √T₂/√T₁

4f/f = √T₂/√T₁

√T₂/√T₁ = 4

squaring both sides, we have

(√T₂/√T₁)² = 4²

T₂/T₁ = 16

T₂ = 16T₁

So, the tension would have to increase by a factor of 16

Answer:

s = 0.3 m

Explanation:

In order to calculate the distance traveled by the person, we will use the second equation of motion:

[tex]s = v_it + \frac{1}{2}at^2[/tex]

where,

s = distance traveled = ?

vi = initial speed = 0 m/s

t = time = 32 ms = 0.032 s

a = acceleration = 60g = (60)(9.81 m/s²) = 588.6 m/s²

Therefore,

[tex]s = (0\ m/s)(0.032\ s)+\frac{1}{2}(588.6\ m/s^2)(0.032\ s)^2[/tex]

s = 0.3 m

Answer:

I think so too

Explanation:

:*

Answer:

Ok I guess

Explanation:

Answer:

what is intera basketball?

Answer:

Condensation and Melting

Explanation:

Gas to liquid = Condensation

Solid to liquid = Melting

Answer:

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

          Z = R + R₂

Explanation:

The impedance of a series circuit is

          Z₀² = R² + (X_L-X_C) ²

when we place another resistor in series the initial resistance impedance changes to

          Z² = (R + R₂) ² + (X_L - X_C) ²

let's analyze this expression

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

          Z = R + R₂

Answer:

Spring constant = 63.77 N/m

Explanation:

Given the following data;

Force = 44 N

Extension = 0.69 m

To find the spring constant;

Force = spring constant * extension

Substituting into the formula, we have;

44 = spring constant * 0.69

Spring constant = 44/0.69

Spring constant = 63.77 N/m

Answer:

d = 1,029 m

Explanation:

When the young man shoots the rifle the sound travels in all directions, if the young man is at the same distance from the two walls, as the speed of the wave is constant, he takes the same time to go to the wall and return for which he hears a single echo.

To calculate the distance let's use the uniform motion relationships

        v = d / t

        d = v t

As the speed is constant, the time to reach the wall is the same as it takes to go from the wall to the young man,

         t = to / 2

         t = 6/2

         t = 3 s

         d = 343 3

         d = 1,029 m

Answer:

1.8x10⁻³m

Explanation:

From the question above, the following information was used to solve the problem.

wavelength λ = 4.5x10⁻⁷m

Length L = 2.0 meters

distance d = 5 x 10₋⁴m

ΔY = λL/d

= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m

= 0.00000045 / 0.0005

= 0.0000009/0.0005

= 0.0018

= 1.8x10⁻³m

from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m

thank you!

Answer:

D

Explanation:

Think about like charges meaning the charge is the same.

Which only D has two charges and are the same, positive will repel against positive charge so select D.

Answer:

The answer is D. Here is proof . Plz mark brainliest

Explanation:

Answer:

Control of air–fuel ratio

Oxygen sensors tell the ECU whether the engine is running rich (too much fuel or too little oxygen) or running lean (too much oxygen or too little fuel) as compared to ideal conditions (known as stoichiometric).

Explanation:

Answer:

20.0 cm

Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

1/u = P'- 1/v

1/u = 55.0 D - 1/0.02 m

1/u = 55.0 m⁻¹ - 1/0.02 m

1/u = 55.0 m⁻¹ - 50.0 m⁻¹

1/u = 5.0 m⁻¹

u = 1/5.0 m⁻¹

u = 0.2 m

u = 20 cm

So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.

Answer:

[tex]\frac{K.E_t}{K.E_r} = 1[/tex]

Explanation:

The translational kinetic energy of the hoop is given as:

[tex]K.E_t = \frac{1}{2} mv^2[/tex]      ---------------------- equation (1)

where,

[tex]K.E_t[/tex] = translational kinetic energy

m = mass of hoop

v = linear speed of hoop

The rotational kinetic energy of the hoop is given as:

[tex]K.E_r = \frac{1}{2} I\omega^2[/tex]

where,

[tex]K.E_r[/tex] = rotational kinetic energy of the hoop

I = Moment of Inertia of the hoop = mr²

r = radius of the hoop

ω = angular speed of hoop = [tex]\frac{v}{r}[/tex]

Therefore,

[tex]K.E_r = \frac{1}{2} (mr^2)(\frac{v}{r} )^2\\\\K.E_r = \frac{1}{2} mv^2[/tex]------------------- equation (2)

dividing equation (1) and equation (2), we get:

[tex]\frac{K.E_t}{K.E_r} = \frac{\frac{1}{2}mv^2 }{\frac{1}{2}mv^2 }\\\\\frac{K.E_t}{K.E_r} = 1[/tex]

Answer:

D

Explanation:

D is false because asexual reproduction produces offspring much more similar to the parent than that produced in sexual reproduction.

Answer:

independent and the second one with the (-8, 1, -3)

Answer:

OK

The component of gravity that aids his sliding down.. is

Mgsin∆

Friction will oppose the motion

Therefore... The net force acting will be

MgSin∆ - Fr=Ma

Where Fr= Frictional Force

Fr = MgSin∆ - Ma

= 20x9.8Sin40 - 20x1.3

=125.99 - 26

=99.99N ~ 100N.

Answer:

Y = 3.39 x 10⁶ m

Explanation:

We will use Young's Double Slit formula here:

[tex]Y = \frac{\lambda L}{d}[/tex]

where,

Y = Fringe spacing = ?

λ = wavelength = [tex]\frac{speed\ of\ light}{frequency} = \frac{3\ x\ 10^8\ m/s}{375\ Hz}[/tex] = 8 x 10⁵ m

L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m

d = slit separation = 950 nm = 9.5 x 10⁻⁷ m

Therefore,

[tex]Y = \frac{(8\ x\ 10^5\ m)(4.03\ x\ 10^{-6}\ m)}{9.5\ x\ 10^{-7}\ m}[/tex]

Y = 3.39 x 10⁶ m

Answer:

I think its B

Explanation:

1) cuscuta - parasitic

2) pitcher plant - insectivorous

3) Green plants -Autotrophs

4) Food store in - starch

plants

5) Rhizobium -Bacteria