Complete the statement below to explain how this model shows that 1/2 ÷ 2/3 = 3/4.
Answers
Given a model in which some boxes are given.
Here, 1/2 is represented by 3 boxes and 2/3 is represented by 4 boxes. Thus, the model represents that 3/4 of 2/3 bar is equal to 1/2.
So, the mathematical representation of the model is:
[tex]\frac{1}{2}=\frac{3}{4}\times\frac{2}{3}[/tex]If we divide both the sides by 2/3, we get:
[tex]\begin{gathered} \frac{1}{2}\div\frac{2}{3}=\frac{3}{4}\times\frac{2}{3}\div\frac{2}{3} \\ \frac{1}{2}\div\frac{2}{3}=\frac{3}{4} \end{gathered}[/tex]Related Questions
find the perimeter of a square with a side lengh of 12 feet
Answers
Given:
Side length, a = 12 feet
Let's find the perimeter of the square.
To find the perimeter of the square, apply the formula:
[tex]\text{Perimeter = 4a}[/tex]Given:
a = 12 feet
Thus, we have:
[tex]\text{ Perimeter = 4(12) = 48 feet}[/tex]Therefore, the perimeter of the square is 48 feet.
ANSWER:
[tex]\text{ 48 ft}[/tex]Highly use distance from point a is approximately 7.1 units. Is the correct answer A, B, C, or D?
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ANSWER
Point D
EXPLANATION
The distance between two points (x₁, y₁) and (x₂, y₂) is given by the Pythagorean Theorem,
[tex]d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]Let's find the distance between points A and B,
[tex]d_{AB}=\sqrt[]{(1-4)^2+(1-4)^2}=\sqrt[]{(-3)^2+(-3)^2}=\sqrt[]{9+9}=\sqrt[]{18}\approx4.2[/tex]The distance between points A and C is,
[tex]d_{AC}=\sqrt[]{(1-(-3))^2+(1-4)^2}=\sqrt[]{(4)^2+(-3)^2}=\sqrt[]{16+9}=\sqrt[]{25}=5[/tex]And the distance between points A and D is,
[tex]d_{AD}=\sqrt[]{(1-(-4)^2+(1-(-4)^2}=\sqrt[]{(1+4)^2+(1+4)^2}=\sqrt[]{(5)^2+(5)^2}=\sqrt[]{25+25}=\sqrt[]{50}\approx7.1[/tex]Hence, point D is at approximately 7.1 units from point A.
Order these numbers from least to greatest. -6.44, 12/50, 0.2, -40.
Answers
To answer this question, we need to take into account that negative numbers are always lesser than a positive number, and, between two negative numbers, the one that has the greatest distance from 0 is lesser than the other negative number.
We have the numbers:
[tex]-6.44,\frac{12}{50},\bar{0.2},-\sqrt[]{40}[/tex]With the help of a calculator, we can find the value of all these numbers in decimal expression:
[tex]\frac{12}{50}=\frac{6}{25}=0.24[/tex]The number above is a terminating decimal. Only have two decimals.
[tex]\bar{0.2}=0.222222222222\ldots[/tex]The latter is a periodic decimal number.
[tex]-\sqrt[]{40}=-6.32455532034[/tex]Now, we can observe the negative numbers:
[tex]-6.44,-\sqrt[]{40}=-6.32455532034[/tex]The number with the greatest absolute value, that is, with the greatest distance from 0 is -6.44, since:
[tex]|-6.44|=6.44,|-6.32455532034|=6.32455532034[/tex]Therefore, we have the least number is -6.44, then -√40.
Now, which one is the greatest?:
[tex]\frac{12}{50}=0.24,\bar{0.2}=0.222222222\ldots[/tex]We can apply the same here. The one with the greatest absolute value is 0.24.
Therefore, to order these numbers from least to greatest is:
[tex]-6.44<-\sqrt[]{40}<\bar{0.2}<0.24[/tex]For each expression, write an equivalent expression in standard form. Show your reasoning. [tex](x - 2)( x + 2)[/tex]
Answers
(x - 2) (x+2)
we will expand by opening the parenthesis
x(x+2) - 2(x+2)
x² + 2x - 2x - 4
x² - 4
help please I need 5 points total. i need 2 to left of vertex. i need vertex. i need 2 to right of vertex. Please, quickly, I am timedgraph only goes up to 14. thank you
Answers
The graph is displayed below:
• The points are: (2, 11), (3, 6), (7, 6), and (8, 11)
• The vertex is (5, 2). ,This is because the graph opens up and the lowest point is always the vertex for this type of graphs.
2. Stacey is factoring the expression, 12x^2-4x. After factoring completely, Stacey got 4x(3x-1). How can she check to see if she factored correctly? Explain and show work to support your explanation
Answers
She can check that by expanding the factored equation, if she gets the original expression, then the factoring is correct
[tex]4x(3x-1)=12x^2-4x[/tex]Answer:
She is correct!
Step-by-step explanation:
She would check if it is correct by doing this.
You would factor out 4.
[tex]4 (3x^{2} - x )[/tex]
Then you would consider [tex]3x^{2} -x[/tex]. Factor out [tex]x[/tex].
[tex]x (3x-1)[/tex]
Then rewrite the complete factored expression.
[tex]4x(3x-1)[/tex]
Therefore, Stacey is correct.
Hope this helps! :))
what does the 9 mean in 98
Answers
Solution
For this case we can do this:
[tex]\frac{98}{9}[/tex]Which represent how many times are 9 in 98 after do the operation we got: 10.88 so then we
ms. zanotti receives text messages throughout her work day from her daughter day care provider. the possible number of text messages that she receives in a given day and the probabilities are given in the table.
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a)
[tex]\begin{gathered} \text{ From the table, we can s}ee\text{ that } \\ \text{ The probability that she receives exactly }4\text{ text messages per day =}\frac{3}{16} \end{gathered}[/tex]b)
[tex]\text{ The probability that she receives fewer than 4 text messages = 1-}\frac{3}{16}=\frac{13}{16}[/tex]c)
[tex]\text{ The probability that she receives least two messages = }\frac{3}{8}+\frac{1}{16}+\frac{3}{16}=\frac{6+1+3}{16}=\frac{10}{16}=\frac{5}{8}[/tex]Example 1 Pav needs to at the bus stop for 8.20am. She gets up at 7.10am. She spends 45 minutes getting ready. She spends 5 minutes looking for her umbrella. She puts out the washing which takes 15 minutes. She then sets out, taking 6 minutes to walk to the bus stop. Will she catch the bus on time?
Answers
ANSWER
No, she won't catch the bus on time.
EXPLANATION
Pav gets up at 7.10 am and spends 45 minutes getting ready. 45 minutes from 7.10 am is,
[tex]7h10\min +45\min =7h(10+45)\min =7h55\min [/tex]Then she spends 5 minutes looking for her umbrella. 5 minutes from 7.55 am is,
[tex]7h55\min +5\min =7h(55+5)\min =7h60\min =8h[/tex]Then, she puts out the washing for another 15 minutes. 15 minutes from 8 am is,
[tex]8h0\min +15\min =8h(0+15)\min =8h15\min [/tex]And then, she has a 6-minute walk to the bus stop. 6 minutes from 8.15 am is,
[tex]8h15\min +6\min =8h(15+6)\min =8h21\min [/tex]Pav will get to the bus stop at 8.21 am and, therefore, she will not catch the bus on time.
what is the volume of the largest sphere that you could carve out of a wooden block whose edges measure 8 m by 8 m by 8 m? Use the Pi and round to the nearest tenth
Answers
Given data:
The given cube .
The expression for the volume of the sphere is,
[tex]\begin{gathered} V=\frac{4}{3}\pi(\frac{8}{2}m)^{3^{}} \\ =268.0826m^3 \\ \approx261m^3 \end{gathered}[/tex]Thus, the volume of the sphere is 261 cubic-m.
Approximate the area under the graph of f(x) over the specified interval by dividing the interval into the indicated number of subintervals and using the left endpoint of each subinterval. f(x) -; interval [1, 5); 4 subintervals x2 O 1.4636 O 1.4236 O 0.4636 0 2.0833
Answers
The approximate area under the curve using the left-end points is 1.4236
Here; f(x) = 1/x^2 , [a,b] = [1,5] and n = 4
We start by calculating the width of each of the triangles on the interval
Mathematically, that would be;
[tex]\frac{b-a}{n}\text{ = }\frac{5-1}{4}\text{ = 1}[/tex]Since there are 4 sub-intervals, there are 4 rectangles
So using the left end-points, we have;
[tex]1\text{ }\times\text{ f(1) + (1 }\times\text{ f(2)) + (1 }\times\text{ f(3)) + (1 }\times\text{ f(4))}[/tex]where;
[tex]\begin{gathered} f(1)\text{ = }\frac{1}{1^2}\text{ = 1} \\ \\ f(2)\text{ = }\frac{1}{2^2}\text{ = 0.25} \\ \\ f(3)\text{ = }\frac{1}{3^2}=\text{ }\frac{1}{9}\text{ = 0.11111} \\ \\ f(4)\text{ = }\frac{1}{4^2}\text{ = }\frac{1}{16}\text{ = 0.0625} \end{gathered}[/tex]So the approximate area under the curve will be;
[tex]1\text{ + 0.25 + 0.1111 + 0.0625 = 1.4236}[/tex]Sam and Carlos has decided to build a cylindrical water tank made out of polyethylene accompanied by a rectangular prism base made out of concrete. Given: Density of concrete = 2.4g/cm3Density of polyethylene = 0.900g/cm3The water tank has a height of 8ft and a width of 5ft. The concrete base has a length of 9ft, a width of 7ft, and a height of 1 foot. Calculate the amount of material needed to build each object.Calculate the cost with an explanation or spreadsheet to show the breakdown of costs. *Note that the costs you come up with should be a reasonable price and should altogether add up to $20,000 or less.
Answers
From the statement, we have the following objects.
1) A water tank made of polyethylene with:
• height h = 8 ft,
,• width or diameter d = 5 ft,
,• thickness t.
2) A concrete base with:
• base b = 9 ft,
,• width w = 7 ft,
,• height h = 1 ft.
We also know that:
• the density of polyethylene is ρₚ = 0.900 g/cm³,
,• the density of concrete is ρc = 2.4 g/cm³.
We convert the densities to g/ft³:
[tex]\begin{gathered} \rho_p=0.900*\frac{g}{\text{ cm}^3}=0.900*\frac{g}{\text{ cm}^3}*(\frac{30.48\text{ cm}}{1\text{ ft}})^3\cong25485.16\frac{g}{\text{ ft}^3}\cong25.49\frac{kg}{ft^3}, \\ \rho_c=2.4*\frac{g}{\text{ cm}^3}=2.4*\frac{g}{\text{ cm}^3}*(\frac{30.48\text{ cm}}{1\text{ ft}})^3\cong67960.43\frac{g}{\text{ ft}^3}\cong67.96\frac{kg}{ft^3}. \end{gathered}[/tex]1) Volume of the water tank
Using the data from the water tank, we make the following diagram:
The volume of the water thank is given by:
[tex]V_T=t\cdot A_b+t\cdot A_s=t\cdot(A_b+A_c).[/tex]Where:
• Ab = area of the base,
• Ac = area of the curved side,
,• t = thickness of the tank.
The area of the base is:
[tex]A_b=\frac{\pi d^2}{4}\cong\frac{3.14\cdot(5ft)^2}{4}\cong19.63\text{ ft}^2.[/tex]The area of the curved side is:
[tex]A_c=l\cdot h=(\pi\cdot d)\cdot h\cong3.14\cdot5\text{ ft}\cdot8\text{ ft}=125.6\text{ ft}^2.[/tex]Replacing th values of Ab and Ac in the formula above, we get thevolume of the tank
[tex]V_T=t\cdot(19.63\text{ ft}^2+125.6\text{ ft}^2)=t\cdot145.23\text{ ft}^2.[/tex]The mass of the tank is given by:
[tex]m_T=V_T\cdot\rho_p\cong t\cdot142.23ft^2\cdot25.49\frac{kg}{\text{ ft}^3}=3625.44\text{ kg}\cdot\frac{t}{\text{ ft}}.[/tex]By replacing the value of the thickness, we get the mass of the tank.
2) Voume of the base
The concrete base is a rectangular prism. Its volume is given by:
[tex]V_b=b\cdot w\cdot h.[/tex]Replacing the values of b, w and h, we get:
[tex]V_b=9ft\cdot7ft\cdot1ft=63\text{ ft}^3.[/tex]The mass of the base is:
[tex]m_b=V_b\cdot\rho_b=63\text{ ft}^3\cdot67.96\frac{kg}{\text{ ft}^3}=4281.48\text{ }kg[/tex]Answer• The ,mass of the water tank, is:
[tex]m_T=V_T\cdot\rho_p\cong t\cdot142.23ft^2\cdot25.49\frac{kg}{\text{ ft}^3}=3625.44\text{ kg}\cdot\frac{t}{\text{ ft}}[/tex]Replacing the value of the thickness t (in ft), we get the mass.
• The ,mass of the concrete base, is:
[tex]m_b=V_b\cdot\rho_b=63\text{ ft}^3\cdot67.96\frac{kg}{\text{ ft}^3}=4281.48\text{ }kg[/tex]Find the product of these complex numbers.(8 + 5i)(6 + 3i) =A.33 + 54iB.63 + 54iC.48 + 15iD.48 - 15i
Answers
The expression is given to be:
[tex]\left(8+5i\right)\left(6+3i\right)[/tex]To expand the expression, we can apply the complex arithmetic rule given to be:
[tex]\left(a+bi\right)\left(c+di\right)=\left(ac-bd\right)+\left(ab+bc\right)i[/tex]Taking values of a, b, c, and d to be:
[tex]\begin{gathered} a=8 \\ b=5 \\ c=6 \\ d=3 \end{gathered}[/tex]We can solve it to give:
[tex]\begin{gathered} \left(8+5i\right)\left(6+3i\right)=\left(8\cdot\:6-5\cdot\:3\right)+\left(8\cdot\:3+5\cdot\:6\right)i \\ \left(8+5i\right)\left(6+3i\right)=33+54i \end{gathered}[/tex]ANSWER
[tex](8+5\imaginaryI)(6+3\imaginaryI)=33+54\imaginaryI[/tex]OPTION A is the correct option.
Find the a area and b perimeter of the figure. Dimensions are in feet.
Answers
a. Area
The area of the figure is the sum of the area of the rectangle and the area of the triangle. Therefore:
Area of triangle is given by
[tex]A=\frac{1}{2}bh[/tex]First, we find the height of the triangle using the Pythagorean theorem:
[tex]\begin{gathered} h^2+b^2=c^2 \\ h^2+12^2=(10+5)^2 \\ h^2+144=225 \\ h^2+144-144=225-144 \\ h^2=81 \\ h=\sqrt[]{81} \\ h=9 \end{gathered}[/tex]So, the area is:
[tex]\text{Area}=\frac{1}{2}(12)(9)=\frac{108}{2}=54[/tex]Area of rectangle is given by
[tex]\text{Area}=length\times width=5\times4=20[/tex]The area of the figure is:
[tex]\text{Area of figure=54+20=}74[/tex]Answer: area = 74 ft^2
b. Perimeter
Perimeter is the sum of all sides, therefore:
[tex]\text{Perimeter}=10+4+5+4+12+9=44[/tex]Answer: perimeter = 44 ft
Find the common difference of the arithmetic sequence. 4, 3 2/3, 3 1/3, 3, .... The common difference is ?
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The numbers of the seria are:
[tex]4,3\cdot\frac{2}{3},3\cdot\frac{1}{3},3[/tex]so to find the diference we made the rest of two numbers so:
[tex]3\cdot\frac{2}{3}-4=-\frac{1}{3}[/tex]So the difference is -1/3
The Height in feet above the ground of an arrow after it is shot can be molded  by Y= -16 X squared +63+4. Can the arrow pass over a tree that is 68 feet tall?
Answers
SOLUTION
From
[tex]\begin{gathered} y=-16x^2+63x+4 \\ At\text{ maxi}mum\text{ height }\frac{d\text{ y}}{d\text{ x}}\text{ is = 0} \\ So\text{ we will differentiate }y=-16x^2+63x+4 \\ y=-16x^2+63x+4 \\ \frac{d\text{ y}}{d\text{ x}}\text{ = -32x + 63 = 0} \\ -32x\text{ + 63 = 0} \\ 32x\text{ = 63} \\ \text{x = }\frac{63}{32}\text{ = 1.97} \end{gathered}[/tex]Now, we will substitute 1.97 for x into y
[tex]\begin{gathered} \text{From } \\ y=-16x^2+63x+4 \\ y=-16(1.97)^2+63(1.97)+4 \\ y\text{ = -62.09 + 124.11 + 4} \\ y\text{ = 66.02 } \end{gathered}[/tex]Since y which is the height of the arrow is 66.02 feet, and the tree is 68 feet tall, the arrow can not pass over the tree. Because for the arrow to pass over the tree, its height must be above 68 feet tall.
what is g(r)=25−3r?
solve for g(4)
Answers
Given:
[tex]g(r)=25-3r[/tex]Evaluate the function at r=4,
[tex]\begin{gathered} g(r)=25-3r \\ g(4)=25-3(4) \\ g(4)=25-12 \\ g(4)=13 \end{gathered}[/tex]Answer: g(4)=13
Find the quadratic equation with the roots indicated.{5 +/- i square root of 2}
Answers
Solution:
Given:
[tex]5\pm i\sqrt{2}[/tex]The roots of the quadratic equation are;
[tex]\begin{gathered} x=5\pm i\sqrt{2} \\ x=5+i\sqrt{2}\text{ OR }x=5-i\sqrt{2} \\ \\ The\text{ factors from the root are:} \\ (x-5-i\sqrt{2})=0\text{ OR }(x-5+i\sqrt{2})=0 \\ \\ As\text{ a quadratic equation:} \\ (x-5-i\sqrt{2})(x-5+i\sqrt{2})=0 \end{gathered}[/tex]Expanding the factors further;
[tex]\begin{gathered} (x-5-i\sqrt{2})(x-5+i\sqrt{2})=0 \\ x^2-5x+ix\sqrt{2}-5x+25-5i\sqrt{2}-ix\sqrt{2}+5i\sqrt{2}+2=0 \\ Collecting\text{ the like terms and simplifying further:} \\ x^2-5x-5x+ix\sqrt{2}-ix\sqrt{2}-5i\sqrt{2}+5i\sqrt{2}+25+2=0 \\ x^2-10x+27=0 \end{gathered}[/tex]Therefore, the quadratic equation is;
[tex]x^2-10x+27=0[/tex]
Einstein's equation for mass-energy equivalence, E = mc2, qives the equivalent energy of an object, E, where m is the mass of the object and c is the speed of light.Solve for m in terms of E and c.m=
Answers
1) In this literal equation problem, let's perform some algebraic manipulations:
[tex]\begin{gathered} E=mc^2 \\ \frac{E}{m}=\frac{mc^2}{m} \\ c^2=\frac{E}{m} \\ mc^2=E \\ \frac{mc^2}{c^2}=\frac{E}{c^2} \\ m=\frac{E}{c^{2}} \end{gathered}[/tex]Note that the point here is to isolate m on the left side, so we needed to divide both sides and then cross multiply them.
A point starts at the location (1.5,0) and moves counter-clockwise along a circular path with a radius of 1.5 units that is centered at the origin of an x-y plane. An angle with its vertex at the circle's center has a measure of θ radians and subtends the path the point travels. Let x represent the point's x-coordinate. (Draw a diagram of this to make sure you understand the context!)Complete the following statements.As θ varies from 0 to π/2, xvaries from ____to ____units.As θ varies from π/2 to π, x varies from ____to _____units.As θ varies from π to 3π/2, x varies from ____ to ____ units.As θ varies from 3π/2 to 2π, x varies from ____ to ____ units.
Answers
We start with an image of the diagram as follows;
Now, we want to complete the statements
1. The first part talks about the first quadrant. As we can see, the value of x on the first quadrant ranges from the starting point x = 1.5 to the origin x = 0
2. The second part talks about the second quadrant. As we can see here, the value of x starts from the origin at x = 0 to x = -1.5
3. This talks about the third quadrant. The value of x here moves from x = -1.5 to x = 0
4. This talks about the fourth quadrant. The value of x here moves from x = 0 to x = 1.5
hi, I need help with this. I don’t need an explanation just the answer.. it’s due in 5 minutes and my last tutor didn’t help..
Answers
Given that KN represents a proportional relationship and coordinate of N is (18,12)
Therefore, coordinate of K must be (2,3) as no other coordinates are in proportional relationship with N
Hence, correct option is (B)
what is the slope of the blue line?what is the slope of a parallel line?
Answers
To find the slope (m) of a line given two points (x1, y1) and (x2, y2), we can use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Points (-3,2) and (0,-2) lies on the blue line, then its slope is:
[tex]m_1=\frac{-2-2}{0-(-3)}=-\frac{4}{3}[/tex]Two lines are parallel if they have the same slope. Then,
Original slope: -4/3
Parallel slope: -4/3
here is a pattern of dots. how many dots will there be in step 10
Answers
Given data:
The given pattern is shown.
The expression for the dot pattern is,
[tex]a_n=n^2+1_{}[/tex]For step 10 subtitute 10 for n in the above expression.
[tex]\begin{gathered} a_{10}=10^2+1 \\ =101 \end{gathered}[/tex]Thus, the numbers of dots in step 10 are 101.
In each pair of graphs shown here, the values of function g are the values of function f multiplied by a scale factor. Express g in terms of f using function notation.
Answers
From the given graph, we can note that
[tex]\begin{gathered} f(0)=-8 \\ \text{and} \\ g(0)=-13.6 \end{gathered}[/tex]the factor between these values is
[tex]\frac{-13.6}{-8}=1.7[/tex]this implies that
[tex]g(0)=1.7f(0)[/tex]and this relationship applies for every point in the graph. Therefore, the answer is
[tex]g(x)=1.7f(x)[/tex]Express the following percent into lowest term : 12.5%: options- a)1/8 b)1/4 c)1/12
Answers
Answer:
[tex]A\colon\text{ }\frac{1}{8}[/tex]Explanation:
Here, we want to express the given percentage as a fraction
What we have to do here is just to divide the percentage by 100
Mathematically, we have this as follows:
[tex]12.5\text{ \% = }\frac{12.5}{100}\text{ = }\frac{1}{8}[/tex]if the temperature rises 4 degrees in 10 hours, what is the constant of proportionality
Answers
4 degrees in 10 hours, means 4/10 = 0.4 degrees per hour
So the constant of proporcionality is 0.4
Answer: 0.4 degrees per hour
Esmeralda is buying some new shirts and sweaters. She is able to buy 5 shirts and 4 sweaters for $267 or she is able to buy 3 shirts and 5 sweaters for $259. How much does a shirt cost? How much does a sweater cost?
Answers
Let the cost of a shirt be x, and let the cost of a sweater be y.
The cost of 5 shirts will be 5x and the cost of 4 sweaters will be 4y.
Since it is given that 5 shirts and 4 sweaters cost $267, it follows that:
[tex]5x+4y=267[/tex]This gives the first equation.
The cost of 3 shirts will be 3x and the cost of 5 sweaters will be 5y.
Since it is given that 3 shirts and 5 sweaters cost $259, it also follows that:
[tex]3x+5y=259[/tex]This forms the second equation.
Next, solve equations simultaneously:
[tex]\begin{gathered} 5x+4y=267 \\ 3x+5y=259 \\ \text{Multiply the first equation by 5 and the second equation by 4:} \\ 25x+20y=1335 \\ 12x+20y=1036 \\ \text{Subtract the second equation from the first to get:} \\ 25x-12x+20y-20y=1335-1036 \\ \Rightarrow13x+0=299 \\ \Rightarrow13x=299\Rightarrow\frac{13x}{13}=\frac{299}{13} \\ \Rightarrow x=23 \end{gathered}[/tex]Substitute the x value, x=23 into the first equation to get the value of y.
[tex]\begin{gathered} 5x+4y=267 \\ \Rightarrow5(23)+4y=267\Rightarrow115+4y=267 \\ \Rightarrow4y=267-115\Rightarrow4y=152 \\ \Rightarrow\frac{4y}{4}=\frac{152}{4}\Rightarrow y=38 \end{gathered}[/tex]Hence, the cost of a shirt is $23 and the cost of a sweater is $38.
i need help to determine whether the slope in this graph is Positive, negative, zero or undefined.
Answers
Consider that the line shown in the graph is perfectly vertical.
So the angle formed by the line with positive direction of x-axis is 90 degrees,
[tex]\theta=90^{\circ}[/tex]The solpe (m) of a line making an angle Θ with the positive x-axis is given by,
[tex]m=\tan \theta[/tex]Substitute the value and obtain the slope as follows,
[tex]m=\tan (90^{\circ})[/tex]It is known that the tangent function is undefined at 90 degrees.
Find the slope and tell what kind of slope each line illustrates.
Answers
step 1
Find out the slope
we need two points
looking at the graph
we take the points (-4,4) and (-3,-2)
m=(-2-4)/(-3+4)
m=-6/1
m=-6
the slope is -6
Is a negative slope ( that means, is a decreasing function)
Determine if the expression 3 is a polynomial or not. If it is a polynomial, state thatype and degree of the polynomial.The given expression represents va polynomial. The polynomial is anone of the above and has a degree of oamonomialbinomialtrinomialnone of the aboveattempt 201
Answers
yes, 3 is a polynomial, a monomial, and its degree is 0 (zero)
1) Since a polynomial is defined as:
[tex]P(x)=a_nx^n+a_{n-1}x^{n-1}+....a_1x+a_0[/tex]2) Examining the number 3, we can tell the following:
[tex]3=3x^0[/tex]So, yes, 3 is a polynomial, and better classified as a monomial (for there's one single term), and the degree of this polynomial is 0