Consider an entity set Person, with attributes social security number (ssn), name, nickname, address, and date of birth(dob). Assume that the following business rules hold: (1) no two persons have the same ssn; (2) no two persons have he same combination of name, address and dob. Further, assume that all persons have an ssn, a name and a dob, but that some persons might not have a nickname nor an address.
A) List all candidate keys and all their corresponding superkeys for this relation.
B) Write an appropriate create table statement that defines this entity set.

Answers

Answer 1

Answer:

[tex]\pi[/tex]

Explanation:


Related Questions

During TCP/IP communications between two network hosts, information is encapsulated on the sending host and decapsulated on the receiving host using the OSI model. Match the information format with the appropriate layer of the OSI model.

a. Packets
b. Segments
c. Bits
d. Frames

1. Session Layer
2. Transport Layer
3. Network Layer
4. Data Link Layer
5. Physical Layer

Answers

Answer:

a. Packets - Network layer

b. Segments - Transport layer

c. Bits - Physical layer

d. Frames - Data link layer

Explanation:

When TCP/IP protocols are used for communication between two network hosts, there is a process of coding and decoding also called encapsulation and decapsulation.

This ensures the information is not accessible by other parties except the two hosts involved.

Operating Systems Interconnected model (OSI) is used to standardise communication in a computing system.

There are 7 layers used in the OSI model:

1. Session Layer

2. Transport Layer

3. Network Layer

4. Data Link Layer

5. Physical Layer

6. Presentation layer

7. Application layer

The information formats given are matched as

a. Packets - Network layer

b. Segments - Transport layer

c. Bits - Physical layer

d. Frames - Data link layer

What is media framing?

Answers

Answer:

media frame all news items by specific values, facts, and other considerations, and endowing them with greater apparent for making related judgments

Explanation:

Consider the following method.


public int locate(String str, String oneLetter)

{
int j = 0;
while(j < str.length() && str.substring(j, j+1).compareTo*oneLetter < 0)
{
j++;
}
return j;
}

Which of the following must be true when the while loop terminates?

a. j == str.length()
b. str.substring(j, j+1) >= 0
c. j <= str.length() || str.substring(j, j+1).compareTo(oneLetter) > 0
d. j == str.length() || str.substring(j, j+1).compareTo(oneLetter) >= 0
e. j == str.length() && str.substring(j, j+1).compareTo(oneLetter) >= 0

Answers

Answer:

All

Explanation:

From the available options given in the question, once the while loop terminates any of the provided answers could be correct. This is because the arguments passed to the while loop indicate two different argument which both have to be true in order for the loop to continue. All of the provided options have either one or both of the arguments as false which would break the while loop. Even options a. and b. are included because both would indicate a false statement.

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