Consider the reaction.

A(aq)↽−−⇀2B(aq)=4.87×10−6 at 500 K

If a 2.00 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?

Consider The Reaction.A(aq)2B(aq)=4.87106 At 500 KIf A 2.00 M Sample Of A Is Heated To 500 K, What Is

Answers

Answer 1

Note the signs of equilibrium:-

Reaction don't procede forward or backwardConcentration of products and reactants remains same .

So

if

Concentration of A is 2M then concentration of B should be same .

So equilibrium constant K is 1

[tex]\\ \rm\rightarrowtail K=\dfrac{[Products]^a}{[Reactants]^b}[/tex]

So

[B]=[A]^2[B]=2^2[B]=4M
Answer 2

The equilibrium constant K is the ratio of product of molar concentrations of products to the product of molar concentrations of reactants. The concentration of B in the given reaction is 0.0031 M.

What is rate of a reaction?

Rate of a reaction is the rate of decrease in the concentration of the reactants or rate of increase in the concentration of products.

Consider the simple reaction A ⇄2B, the rate of the reaction can be written as follows:

rate = K [A]

Where, k is the equilibrium constant or rate constant and [A] is the concentration of reactant A. If A have any coefficients, then the coefficient number is written as power of the concentration term.

The equilibrium constant K = [B]²/ [A] it is given 4.87 ×10⁻⁶ . Thus concentration of B can be calculated as follows:

[B]² = K [A]

       = (4.87 ×10⁻⁶)×2.00 M

       =9×10⁻⁶

  [B] = 0.0031 M

Hence, the concentration of the product B is 0.0031 M.

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Related Questions

A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves. What is the solute in this scenario?

Answers

Answer:

The answer is the Sodium Chloride.

Explanation:

A solute is the minor component in a solution, dissolved in the solvent, and the sodium is being dissolved in water ( or the solvent).

A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves, in this scenario sodium chloride is solute.

What are solute?

Those substance which are present in the solution relatively in less amount is known as solute.

In the question given that 36 grams of sodium chloride is added in the 200 grams of water. From this it is clear that sodium chloride is a solute and water is a solvent, which additionally makes a solution.

Hence, sodium chloride is a solute.

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what would happen if you put vegetable oil and ice cubes into a beaker together? what would happen if you left it on the counter overnight?

Answers

Oil is hydrophobic, which means that it repels water. The ice cube will immediately begin to melt as soon as it is placed in the oil. Because oil is hydrophobic, it will not mix with the water.

If you leave the beaker overnight, you'll notice that the water sinks to the bottom and the oil floats to the top. This is because water has a higher density than oil, causing it to sink.

Hope this helps!

Balance the equation ​

Answers

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Before tackling this problem, be sure you know how to find the antilog of a number using a scientific calculator.
A solution has a pH of 5.4. Write the formula you will use to calculate the [H+] and then show all your work leading to the determination of [H+].

Answers

Question:-

A solution has a pH of 5.4, the determination of [H+].

Given :- pH:- 5.4 pH = - log[H+]

To find :- concentration of H+

Answer:- Antilog(-5.4) or 4× 10-⁶

Explanation:- Formula:- pH = -log H+

Take negative to other side

-pH = log H+

multiple Antilog on both side

(Antilog and log cancel each other )

Antilog (-pH) = [ H+ ]

New Formula :- Antilog (-pH) = [+H]

Now put the values of pH in new formula

Antilog (-5.4) = [+H]

we can write -5.4 as (-6+0.6) just to solve Antilog

Antilog ( -6+0.6 ) = [+H]

Antilog (-6) × Antilog (0.6) = [+H]

[tex]Antilog (-6) = {10}^{ - 6} , \\ Antilog (0.6) = 4 [/tex]

put the value in equation

[tex] {10}^{ - 6} \times 4 = [H+] \\ 4 \times {10}^{ - 6} = [H+][/tex]

Which statements describe the motion of the object represented by the graph? Select three options.

The object is moving away from the origin.
The object is moving towards the origin.
The object started at the origin.
The object started at 2 meters.
The object is traveling at a constant velocity.

Answers

Answer:

The object is moving away from the origin.

Explanation:

Answer:

The object is moving away from the origin

The object started at 2 meters.

The object is traveling at a constant velocity.

Explanation:

The line on the graph is moving in the upward direction which means the farther right on the graph you go the farther up the line is. The line also has a constant slope which indicates that the object is moving at a constant rate. and if you look at x=0 the y=2 so therefor the object started at 2 meters.

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Answers

Answer:

O place them in a flame dissolve them in water o add more particles to the solution.

How many grams of aluminum oxide will you need to start with in order to make 6500 g of aluminum hydroxide?

Answers

Answer:

Explanation:

2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.

Answer:

56.7 grams of aluminum oxide (AI²O³) are produced.Need a fast expert's response.

What is the measurement of 2 polar bears

Answers

Answer:

An adult male is between 2.4-3m (8-10 feet) in size and weighs between 350-680kg (775-1500lbs). Females are slightly smaller at around 1.8-2.4m (6-8 feet) and weigh between 150-250kg (330-550lbs).

Volume of distillate = 300 ml
Volume of Ethanol in the mixture = 450 ml
% Recovery =

Answers

Based on the distillation data provided, the percent recovery of ethanol is 66.7%

What is distillation?

Distillation is a separation technique which is used to separate two miscible liquids based on differences in their boiling points.

At the boiling point of the first liquid, it distills over and is obtained by condensation.

The liquid obtained is known as distillate.

In the distillation of ethanol, the percent recovery is calculated as follows:

Percent recovery = (volume of distillate/volume of ethanol in mixture) × 100%

From the data given:

Volume of distillate = 300 mlVolume of Ethanol in the mixture = 450 ml

Percent Recovery = (300/450) × 100%

Percent recovery = 66.7%

Therefore, the percent recovery of ethanol is 66.7%.

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