Calculate how many grams of sodium chloride we would need to make a solution with the same molarity of seawater, which is about 0.598 M.
Answer:
34.92 grams NaCl (in 1 L of solution)
Explanation:
The chemical formula of sodium chloride is NaCl. From the formula, we can calculate the molar mass of NaCl:
MM(NaCl)= MM(Na) + MM(Cl) = 23 g/mol + 35.4 g/mol = 58.4 g/mol
A solution of NaCl with a molarity of 0.598 M has 0.598 moles of NaCl per liter of solution. So, we multiply the moles by the molar mass of NaCl to calculate the mass we need:
mass of NaCl = 0.598 mol x 58.4 g/mol = 34.92 g NaCl
Therefore, we need 34.92 grams of NaCl to prepare 1 liter of a solution with a molarity of 0.598 M.
What volume of 15.9 M Nitric acid would be required to make 7.2 L of 6.00 M nitric acid? (hint: dilution problem) will mark brainliest if correct
a. 2.72 L
b. 686.88 L
c. .075 L
d. 272
Answer:
d
Explanation:
What is the number of moles in a sample of gas that has a volume of 3.5 L, a
pressure of 200 kPa, and a temperature of 300 K?
Explanation:
[tex]PV = nRT \\ (200000 \times 3.5 \times {10}^{ - 6} ) = n \times 8.314 \times 300 \\ n = \frac{0.07}{2494.2 } \\ n = 2.81 \times {10}^{ - 5} [/tex]
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A Chemist reacted magnesium and aluminum oxide. A reaction takes place. Explain why
Explanation:
when Magnesium is reacted with Aluminum oxide, Aluminum being a less reactive metal than magnesium, is replaced by magnesium
Al2O3 + 3Mg - 3MgO + 2Al
hence reaction takes place
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Whilst Et₃CCl is unreactive towards water even at elevated temperatures, Et₃SiCl is hydrolyzed rapidly. Explain the origin of these differences and provide a reaction scheme with mechanistic details for the hydrolysis of Et₃SiCl.
Answer:
See Explanation
Explanation:
In discussing the reason why Et₃SiCl is more easily hydrolysed than Et₃CCl, we must remember that the electronegativity difference between silicon and chlorine is much higher than the electronegativity difference between carbon and chlorine.
As a result of this, the Si-Cl bond in Et₃SiCl is more polar and hence susceptible to attack by water than the C-Cl bond in Et₃CCl.
Also, it is postulated that the presence of vacant d orbitals on silicon assists hydrolysis in Et₃SiCl. Such vacant orbitals are absent in carbon hence Et₃CCl does not undergo hydrolysis.
The reaction scheme is shown in the image attached to this answer.
If two half lives have passed since a scientist collected a 1.00- gram sample of a U-235, how much U-235 is left now?
answers for most finals chem test questions (10th)
Answer:
one quarter of the original amount, so 0.25 g
Explanation:
Answer:
C
Explanation: