Could someone help me with this one? I'm a tad stuck. I'll give brainliest to the correct answer!

Approximate solutions are the estimate values of an equation

The approximate solution of the equation is x = 0.45

The equation is given as:

[tex]x^3 + 2x- 1= 0[/tex]

The iteration is given as:

[tex]x_{n+1} = \frac{1}{x_n^2 + 2}[/tex]

To start with, we have:

[tex]x_1 = 1[/tex]

So, we have:

[tex]x_2 = \frac{1}{1^2 + 2} = \frac 13 =0.33333333[/tex]

The next iteration is:

[tex]x_3 = \frac{1}{0.33333333^2 + 2} = 0.47368421102[/tex]

The next iteration is:

[tex]x_4 = \frac{1}{0.47368421102^2 + 2} = 0.4495641344[/tex]

The next iteration is:

[tex]x_5 = \frac{1}{0.4495641344^2 + 2} = 0.45411035264[/tex]

The next iteration is:

[tex]x_6 = \frac{1}{0.45411035264^2 + 2} = 0.45326473189[/tex]

Notice that:

x5 and x6 have the same value to 2 decimal places.

i.e. [tex]x_5 \approx x_6 = 0.45[/tex]

Hence, the approximate solution of the equation is x = 0.45

Read more about approximate solutions at:

https://brainly.com/question/10171109

Answer:

sin A= 3/5

sin C= 4/5

cos A= 4/5

cos C= 3/5

Step-by-step explanation:

Please see the attached picture for the full solution.

Answer:

178 miles

Step-by-step explanation:

Let Eric has driven d miles.

As the rate of charge of driving the truck = 76 cents /mile

So, the charge of driving the truck for d miles = 76d cents= $0.76d

The base fee of the truck was $16.95.

Total money paid at the time of returning the truck = $152.23

So, 16.95+0.76d=152.23

0.76d= 152.23-16.95=135.28

d=135.28/0.76

d=178

Hence, he drives 178 miles.

Answer:

Length = 22 ; width = 10

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

Perimeter = 64 feets

Length = 2 + (2*width)

Let :

Length = l ; width = w

Perimeter = 2((2 + (2w)) + w)

64 = 2(2 + 3w)

64 = 4 + 6w

64 - 4 = 6w

60 = 6w

w = 60/6

w = 10

Width = 10

Length = 2 + (2*width) = 2 + (2*10) = 2 + 20 = 22

Answer:

The correct answer is 10n ≥ 470.

Step-by-step explanation:

Since, the school club wants to collect at least 500 canned goods, then we know that they don't want to collect any less: they must collet 500 or more canned goods.

They already collected 30 canned goods, therefore we can subtract this quantity from out goal.

500 - 30 = 470

Since there are 10 club members, the number of members multiplied by "n" the minimum amount of canned goods that they can collect, will equal the total amount of canned goods that they need.

Hope this helps! :D

Answer:

m = 3

Step-by-step explanation:

Pick two points from the table.

(-1, 1) and (1, 7)

Apply the slope formula.

[tex]m=\frac{7-1}{1+1}=\frac{6}{2}=\boxed{3}[/tex]

Hope this helps.

Answer:

50

Step-by-step explanation:

Answer: the answer is 50

Step-by-step explanation:

30% off means they are paying 70% of the original price.

Sale price = 2.40 x 0.70 = $1.68 for 10 plates

50 plates /  10  = 5

They buy 5 packages of plates.

1.68 x 5 = $8.40

Total price = $8.40

Answer:

Step-by-step explanation:

2.40 X 5 =$12

12 X 0.3=$3.6 off

12-3.6=$8.40

Therefore it'll cost $8.40

Discount amount = price x discount percentage as a decimal:

Discount amount = 62.00 x 0.15 = 9.30

Discount = $9.30

Answer:

$52.70

Step-by-step explanation:

Answer:

x = - 2

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

f(x) + g(x)

= x² - 2x + 6x + 4

= x² + 4x + 4

Equating to zero

x² + 4x + 4 = 0 ← left side is a perfect square

(x + 2)² = 0, thus

x + 2 = 0 ( subtract 2 from both sides )

x = - 2

Answer:

True, True, False.

Step-by-step explanation:

A) Rise/Run is 8/1

B) 8 dollars are earned every hour

C) Correct equation is y=8x

Answer:

The 2nd one should be the correct answer

answer: the 2nd option. (aka: 2(3x+5)

if : 3x+3x+5+5= 6x+10

THEN: 2(3x+5)

HOW: 2 times 3x.

           2 times 5

           6x+10.

hope i helped! we just passed this subject in my class. Good luck!!

Answer

the first one is the answer and none of the above

Step-by-step explanation:

Answer:

its the first one

Step-by-step explanation:

Answer:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

Step-by-step explanation:

Given

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

Reflection: [tex]y = x[/tex]

Required

Determine the coordinates of G'H'I'

The following applies when a line A is reflected over [tex]y = x[/tex]

[tex]A = (x,y)[/tex]

[tex]A' = (y,x)[/tex]

i.e, we simply swap the positions of x and y

So, for:

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

The reflections are:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

See attachment

Answer:

d 4x^2 + 24x - 8

Step-by-step explanation:

Perimeter of the rectangle = 2x² - 5 + 12x + 1 + 2x² - 5 + 12x + 1

                                            = (2x²+ 2x²) + (12x+ 12x) + (- 5 + 1 - 5 + 1)

                                            = 4x² + 24x - 8

Answer:  [tex]\frac{8x^3}{27y^6}[/tex]

This is the fraction 8x^3 all over 27y^6

On a keyboard, we can write it as (8x^3)/(27y^6)

===========================================================

Explanation:

The exponent tells you how many copies of the base to multiply with itself.

We'll have three copies of [tex]\left(\frac{2x}{3y^2}\right)[/tex] multiplied with itself due to the cube exponent on the outside.

So,

[tex]\left(\frac{2x}{3y^2}\right)^3 = \left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2x*2x*2x}{(3y^2)*(3y^2)*(3y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{(2*2*2)*(x*x*x)}{(3*3*3)*(y^2*y^2*y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{9y^6}\\\\[/tex]

-------------------

Or another approach you could take is to cube each component of the fraction. The rule I'm referring to is [tex]\left(\frac{a}{b}\right)^c = \frac{a^c}{b^c}[/tex]

Applying that rule will lead to:

[tex]\left(\frac{2x}{3y^2}\right)^3 = \frac{(2x)^3}{(3y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2^3*x^3}{3^3*(y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^{2*3}}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^6}\\\\[/tex]

Either way you should get 8x^3 all over 27y^6 as one fraction.

Answer:

D

Step-by-step explanation:

This is equivalent to t < 4.

clearly this is not part of the set.

Answer:

4x−7+6y+2x+x+16−3x

=4x+−7+6y+2x+x+16+−3x

Combine Like Terms:

=4x+−7+6y+2x+x+16+−3x

=(4x+2x+x+−3x)+(6y)+(−7+16)

=4x+6y+9

Answer:

=4x+6y+9

Answer:

12%

Step-by-step explanation:

We can get SI of 3 years = 12005 - 9800 = 2205

SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting SI]

Principal = 12005 - 3675 = 6125

So Rate = (100*3675)/(6125*5) = 12%

Answer:

He would need to walk the dog 6 more times because 8 times 11 is 88 and if he has already walked the dog 5 times you would subtract that from 11 to get 6. So the answer would be 6

Step-by-step explanation:

8·11= 88

11-5= 6

Answer:

D 5x + 13 = 12

Step-by-step explanation:

3 + 5(x + 2) = 12

3 + 5x + 10 = 12

5x = -1

x = -1/5

D) 5x + 13 = 12

5x = 12 - 13 = -1

x = -1/5

Answer:

0

Step-by-step explanation:

The minimum number of cavities a patient had was 0 cavities.

Answer:

0

Step-by-step explanation:

The smallest number that indicates cavity is '0' therefore it is the minimum number of cavities

Given:

Hyperbola with directrices at y = ±2 and foci at (0, 6) and (0, −6).

To find:

The equation of hyperbola.

Solution:

We have, directrices at y = ±2 so this hyparabola is along the y-axis.

The standard form of hyperbola is

[tex]\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1[/tex]      ...(i)

where, (h,k) is center, foci are [tex](h,k\pm c)[/tex] and directrix are [tex]y=k\pm \dfrac{a^2}{c}[/tex].

On comparing foci, we get

[tex](h,k\pm c)=(0,\pm 6)[/tex]

[tex]h=0,k=0,c=6[/tex]

On comparing directrix we get

[tex]k\pm \dfrac{a^2}{c}=\pm 2[/tex]

[tex]\dfrac{a^2}{c}=2[/tex]

[tex]\dfrac{a^2}{6}=2[/tex]

[tex]a^2=12[/tex]

Now,

[tex]a^2+b^2=c^2[/tex]

[tex]12+b^2=(6)^2[/tex]

[tex]b^2=36-12[/tex]

[tex]b^2=24[/tex]

Putting [tex]h=0,k=0,a^2=12,b^2=24[/tex], we get

[tex]\dfrac{(y-0)^2}{12}-\dfrac{(x-0)^2}{24}=1[/tex]

[tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex]

Therefore, the equation of hyperbola is [tex]\dfrac{y^2}{12}-\dfrac{x^2}{24}=1[/tex].

Answer:

the person above has the right answer. I took the test.

Step-by-step explanation:

The person above is correct.

[tex]\Large\boxed{\tt Answer: 5\frac{2}{3} }[/tex]

[tex]\tt Step-by-step~explanation:[/tex]

We can solve this by dividing both numbers by four.

[tex]\tt 8\div4=2\\12\div4=3\\\frac{2}{3}[/tex]

We then add that to 5 to get our answer.