Answer:
The program written in Java is as follows;
The program takes input for hours, days, weeks and months;
Then the inputs are converted to minutes individually and then summed up
For you to better understand the program, made use of comments to explain difficult lines,
The program is as follows
import java.util.*;
public class Assignment{
public static void main(String []args){
//This line declares all variables
int hours, days, weeks, years;
Scanner input = new Scanner(System.in);
//This line prompts user for hours input
System.out.print("Hours: ");
//This line accepts input for hours
hours = input.nextInt();
//This line prompts user for days input
System.out.print("Days: ");
//This line accepts input for days
days = input.nextInt();
//This line prompts user for weeks input
System.out.print("Weeks: ");
//This line accepts input for weeks
weeks = input.nextInt();
//This line prompts user for years input
System.out.print("Years: ");
//This line accepts input for years
years = input.nextInt();
//This line converts hours to minute
int minute = 60 * hours + 1440 * days + 10080 * weeks + 525600 * years;
//This line prints the equivalent minute of user input
System.out.println(minute +" minutes");
}
}
If the current date is Monday, February 26, 2017, what will be displayed by the alert dialog box after the following code executes? var thisDay = new Date(); alert(thisDay.toDateString());
Answer:
Mon Feb 26 2017
Explanation:
Since the current date is considered as Monday, February 26, 2017, thisDay will be set to that value.
The toDateString() method returns the first three letters of the name of the day (The first letter is capitalized), the first three letters of the name of the month (The first letter is capitalized), the day of the month as an integer, and the year as an integer (There are spaces between all)
If distances are recorded as 4-bit numbers in a 500-router network, and distance vectors are exchanged 3 times/second, how much total bandwidth (in bps) is used by the distributed routing algorithm
Answer:
A total of 6,000 bps of bandwidth is used by the distributed routing algorithm
Explanation:
This is a bandwidth requirement question.
We proceed as follows;
To calculate the total number of bits for a routing table, we use the following formula;
Routing table=Number of routers * length of cost
we are given the following parameters from the question;
Number of routers = 500
length of cost = 4 bits
Routing table = 500*4
=2000
Hence, a routing table is 2000 bits in length.
Now we proceed to calculate the bandwidth required on each line using the formula below;
Bandwidth = no.of seconds * no.of bits in routing table
Bandwidth required on each line = 3*2000
=6000
Lily is in her first year of undergraduate coursework and has not yet declared a major. She has attended a lot of career fairs and undergraduate major "open house" events to investigate her options. Marcia's theory of identity status suggests that the dimension Lily is most concerned with is the_____of 1 dimension.
Answer:
exploration
Explanation:
According to Marcia's theory of identity, the status suggests that the dimension Lily is most concerned with is the exploration dimension.
James E. Marcia who came up with the Marcia's theory of identity is a clinical and developmental psychologist. He also once taught at Simon Fraser University which is located in British Columbia, Canada and also in the State University of New York at Buffalo in Upstate, New York City.
James E. Marcia is also very much involved in clinical private practice, community consultation, clinical psychology supervision, and also in international clinical-developmental research and teaching.
Why is a DNS cache poisoning attack dangerous? Check all that apply. A. Errrr...it's not actually dangerous. B. It allows an attacker to redirect targets to malicious webservers. C. It allows an attacker to remotely controle your computer. D. It affects any clients querying the poisoned DNS server.
Answer:
(B) It allows an attacker to redirect targets to malicious webserver.
(D) It affects any clients querying the poisoned DNS server.
Explanation:
DNS cache poisoning is a serious type of attack that is designed to exploit the vulnerabilities inherent in a Domain Name Server (DNS) where a user is redirected from a real server to a fake one. It is also called DNS spoofing.
Normally, when your browser tries to visits a website through a given domain name, it goes through the DNS server. A DNS server maintains a list of domain names and their equivalent Internet Protocol addresses. This server (DNS) then responds to the request with one or more IP addresses for the browser to reach the website through the domain name.
The computer browser then get to the intended website through the IP address.
Now, if the DNS cache is poisoned, then it has a wrong entry for IP addresses. This might be via hacking or a physical access to the DNS server to modify the stored information on it. Therefore, rather than responding with the real IP address, the DNS replies with a wrong IP address which then redirects the user to an unreal website.
Although they might not be able to control your computer remotely as long as you are not trying to visit a web page via the poisoned information, there are other dangers attached to this type of attack.
Once the DNS server has been poisoned, any client trying to query the server will also be affected since there is no direct way of knowing if the information received from the server is actually correct.
A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the attenuation in decibels?
Answer:
[tex]Attenuation = 0.458\ db[/tex]
Explanation:
Given
Power at point A = 100W
Power at point B = 90W
Required
Determine the attenuation in decibels
Attenuation is calculated using the following formula
[tex]Attenuation = 10Log_{10}\frac{P_s}{P_d}[/tex]
Where [tex]P_s = Power\ Inpu[/tex]t and [tex]P_d = Power\ outpu[/tex]t
[tex]P_s = 100W[/tex]
[tex]P_d = 90W[/tex]
Substitute these values in the given formula
[tex]Attenuation = 10Log_{10}\frac{P_s}{P_d}[/tex]
[tex]Attenuation = 10Log_{10}\frac{100}{90}[/tex]
[tex]Attenuation = 10 * 0.04575749056[/tex]
[tex]Attenuation = 0.4575749056[/tex]
[tex]Attenuation = 0.458\ db[/tex] (Approximated)
Write a C function check(x, y, n) that returns 1 if both x and y fall between 0 and n-1 inclusive. The function should return 0 otherwise. Assume that x, y and n are all of type int.
Answer:
See comments for line by line explanation (Lines that begins with // are comments)
The function written in C, is as follows:
//The function starts here
int check(x,y,n)
{
//This if condition checks if x and y are within range of 0 to n - 1
if((x>=0 && x<=n-1) && (y>=0 && y<=n-1))
{
//If the if conditional statement is true, the function returns 1
return 1;
}
else
{
//If the if conditional statement is false, the function returns 0
return 0;
}
//The if condition ends here
}
//The function ends here
Explanation:
#Write a function called after_second that accepts two #arguments: a target string to search, and string to search #for. The function should return everything in the first #string *after* the *second* occurrence of the search term. #You can assume there will always be at least two #occurrences of the search term in the first string. # #For example: # after_second("11223344554321", "3") -> 44554321 # #The search term "3" appears at indices 4 and 5. So, this #returns everything from the index 6 to the end. # # after_second("heyyoheyhi!", "hey") -> hi! # #The search term "hey" appears at indices 0 and 5. The #search term itself is three characters. So, this returns #everything from the index 8 to the end. # #Hint: This may be more complicated than it looks! You'll #have to look at the length of the search string and #either modify the target string or take advantage of the #extra arguments you can pass to find(). #Write your function here!
Answer:
Following are the code to this question:
def after_second(s,sub):#defining a method a fter_second
first = s.find(sub)#defining a variable first that hold method find value
if first != -1:#defining if block to check first variable value not equal to -1 using slicing
s = s[len(sub)+first:]#defining s variable to calculate sub parameter length of parameter and use slicing
second = s.find(sub)#defining second variable to calculate find method value
if second != -1:#defining if block to calculate second variable slicing
return s[len(sub)+second:]#return s variable value
print(after_second("heyyoheyhi","hey"))#defining print method to call after_second method
print(after_second("11223344554321","3"))#defining print method to call after_second method
Output:
hi
44554321
Explanation:
In the above python code a method "after_second" is declared, that accepts two-variable "s, and sub" as the parameter inside the method a first variable is declared that uses the inbuilt method "find" to find the value and stores it value. In the next step, two if blocks are used, in which both if blocks use the slicing to checks its value is not equal to "-1".
In the first, if block the first variable is declared that uses the s variable to calculate subparameter length by using slicing and defines the second variable that finds its value and stores its value. In the next, if block the s variable is used to return its calculated value, and at the end of the print, the method is used to call the method by passing parameter value and prints its return value.A car can move, a crystal can grow, a fire alarm is sensitive and they are classified as non-living things. Explain?
Answer:
They are all controlled by something else. A car is controlled by humans. A crystal grows due to the temperature and climate. A fire alarm only rings when it senses smoke, which is caused by something else, usually humans.
Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in the file. You function should be case-insensitive so 'Hello' and 'hello' are treated as the same word. You should ignore words of length 2 or less. Also, be sure to remove punctuation and digits.
>>>wordcount('frankenstein.txt')
artifice 1
resting 2
compact 1
service 3
Answer:
I am writing a Python program. Let me know if you want the program in some other programming language.
import string #to use string related functions
def wordcount(filename): # function that takes a text file name as parameter and returns the number of occurrences of every word in file
file = open(filename, "r") # open the file in read mode
wc = dict() # creates a dictionary
for sentence in file: # loop through each line of the file
sentence = sentence.strip() #returns the text, removing empty spaces
sentence=sentence.lower() #converts each line to lowercase to avoid case sensitivity
sentence = sentence.translate(sentence.maketrans("", "", string.punctuation)) #removes punctuation from every line of the text file
words = sentence.split(" ") # split the lines into a list of words
for word in words: #loops through each word of the file
if len(word)>2: #checks if the length of the word is greater than 2
if word in wc: # if the word is already in dictionary
wc[word] = wc[word] + 1 #if the word is already present in dict wc then add 1 to the count of that word
else: #if the word is not already present
wc[word] = 1 # word is added to the wc dict and assign 1 to the count of that word
for w in list(wc.keys()): #prints the list of words and their number of occurrences
print(w, wc[w]) #prints word: occurrences in key:value format of dict
wordcount("file.txt") #calls wordcount method and passes name of the file to that method
Explanation:
The program has a function wordcount that takes the name of a text file (filename) as parameter.
open() method is used to open the file in read mode. "r" represents the mode and it means read mode. Then a dictionary is created and named as wc. The first for loop, iterates through each line (sentence) of the text file. strip() method is used to remove extra empty spaces or new line character from each sentence of the file, then each sentence is converted to lower case using lower() method to avoid case sensitivity. Now the words "hello" and "Hello" are treated as the same word.
sentence = sentence.translate(sentence.maketrans("", "", string.punctuation)) statement uses two methods i.e. maketrans() and translate(). maketrans() specifies the punctuation characters that are to be deleted from the sentences and returns a translation table. translate() method uses the table that maketrans() returns in order to replace a character to its mapped character and returns the lines of text file after performing these translations.
Next the split() method is used to break these sentences into a list of words. Second for loop iterates through each word of the text file. As its given to ignore words of length 2 or less, so an IF statement is used to check if the length of word is greater than 2. If this statement evaluates to true then next statement: if word in wc: is executed which checks if the word is already present in dictionary. If this statement evaluates to true then 1 is added to the count of that word. If the word is not already present then the word is added to the wc dictionary and 1 s assigned to the count of that word.
Next the words along with their occurrences is printed. The program and its output are attached as screenshot. Since the frankenstein.txt' is not provided so I am using my own text file.
The dramatic growth in the number of power data centers, cell towers, base stations, recharge mobiles, and so on is damaging the environment because Radio Frequency Interference (RFI) is overcrowding specific areas of the electromagnetic spectrum.
A. True
B. False
Answer:
A. True
Explanation:
Radio frequency interference abbreviated RFI is radio interference that occurs as a result of radiation in radio frequency energy that usually causes electronic devices to malfunction. Radio frequency interference or RFI is given out or emitted by electrical devices or centres such as mobile phones, satellites or data centres which affects the environment by increasing heat and bringing about increased body temperature in humans
Consider a system consisting of m resources of the same type, being shared by n processes. Resources can be requested and released by processes only one at a time. Show that the system is deadlock free if the following two conditions hold:__________.
A. The maximum need of each process is between 1 and m resources
B. The sum of all maximum needs is less than m+n.
Answer:
Explanation:
The system will be deadlock free if the below two conditions holds :
Proof below:
Suppose N = Summation of all Need(i), A = Addition of all Allocation(i), M = Addition of all Max(i). Use contradiction to prove.
Suppose this system isn't deadlock free. If a deadlock state exists, then A = m due to the fact that there's only one kind of resource and resources can be requested and released only one at a time.
Condition B, N + A equals M < m + n. Equals N + m < m + n. And we get N < n. It means that at least one process i that Need(i) = 0.
Condition A, Pi can let out at least 1 resource. So there will be n-1 processes sharing m resources now, Condition a and b still hold. In respect to the argument, No process will wait forever or permanently, so there's no deadlock.
Velma is graduating from Ashford at the end of next year. After she completes her final class, she will reward herself for her hard work with a week-long vacation in Hawaii. But she wants to begin saving money for her trip now. Which of the following is the most effective way for Velma to save money each month?
This question is incomplete because the options are missing; here are the options for this question:
Which of the following is the most effective way for Velma to save money each month?
A. Automatically reroute a portion of her paycheck to her savings account.
B. Manually deposit 10% of her paycheck in her savings account.
C. Pay all of her bills and then place the remaining money in her savings account.
D. Pay all of her bills and then place the remaining money in her piggy bank.
The correct answer to this question is A. Automatically reroute a portion of her paycheck to her savings account.
Explanation:
In this case, Velma needs to consistently save money for her vacation as this guarantees she will have the money for the trip. This means it is ideal every month she contributes consistently to her savings for the vacation.
This can be better be achieved by automatically rerouting a part of her paycheck for this purpose (Option A) because in this way, every month the money for the vacations will increase and the amount of money will be consistent, which means Velma will know beforehand the money she will have for the vacation. Moreover, options such as using a piggy bank or paying the bills and using the rest for her savings, do not guarantee she will contribute to the savings every month, or she will have the money she needs at the end.
Assuming a Stop-and-Wait system, if the bandwidth-delay product of a channel is 500 Mbps and 1 bit takes 25 milliseconds to make the roundtrip, what is the bandwidth-delay product? If the data packets are 2500 bits in length, what is the utilization?
Answer:
Bandwidth delay product = 2500 Kbits
Utilization = 0.02%
Explanation:
We proceed as follows;
From the question, we are given that
band width = 500 Mbps
The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3
= 2500 Kbits
The system can send 12500 Kbits during the time it takes for the data to go from the sender to the receiver and then back again.
However, the system sends only 2500 bits.
The the link utilization =
2500/(12500 x 10^3) = 0.02%
A systems administrator wants to replace the process of using a CRL to verify certificate validity. Frequent downloads are becoming problematic. Which of the following would BEST suit the administrators needs?
A. OCSP
B. CSR
C. Key escrow
D. CA
Answer:
A. OCSP
Explanation:
Online Certificate Status Protocol (OCSP) is an Internet Protocol that is used as an alternative for CRL and is used to obtain the revocation status of a digital certificate.
A certificate revocation list (CRL) is a set of digital certificates that have been rendered invalid/revoked by the Certificate Authority (CA) because they can no longer be trusted.
Because an OCSP response uses less data than a CRL, it would be best suited to the administrator's needs.
Which are true of the Transmission Control Protocol (TCP)? Multiple answers: You can select more than one option A it supports full duplex communication B it has graceful connection shutdown C its connections are logical D its data is sent as a discrete messages E it is an end-to-end protocol
Answer:
A, B, C, D and E
Explanation:
Transmission Control protocol (TCP) is a protocol that describes how connections are made and maintained between devices in a network which will help applications in these devices communicate and transmit data.
The following are some of the features of TCP:
i. It supports full duplex communication: In other words, TCP allows for concurrent transmission of data in both directions.
ii. it has a graceful connection shutdown: TCP allows for graceful termination and closing of connection. This means that when there is no more data to be sent by any of the communicating devices, rather than just close connection from its end, it first informs the other device about its completion and asks if it's safe to close the connection. From there, if the other device then says it doesn't have any data to send either, they then reach a consensus to close the connection at their respective ends.
iii. Its connections are logical: TCP makes use of the reliability and flow control mechanisms which require that it initialize and maintain some status information for each stream of data. This status information containing sockets, sequence numbers and window sizes is called a logical connection.
iv. Data is sent as discrete messages: Like other discrete messages, the IP treats the data in TCP as discrete messages by placing them into the IP datagram and transmitting to the target host.
v. It is an end-to-end protocol: TCP governs the way data is transmitted between two devices at their respective ends to ensure reliable delivery. In other words, it is responsible for the transmission of data from a source to one or more destinations. It sits on the operating system of the source and also on the operating system(s) of the destination(s).
Similar to Wi-Fi, ____ is designed to provide internet access to fixed locations (sometimes called hot zones), but the coverage is significantly larger
Answer:
WiMAX.
Explanation:
WiMAX is an acronym for Worldwide Interoperability for Microwave Access, it is a wireless communications which is primarily based on the IEEE 802.16 standards for creating Metropolitan Area Network (MAN) for the internet users.
Similar to Wi-Fi, WiMAX is designed to provide internet access to fixed locations (sometimes called hot zones), but the coverage is significantly larger.
WiMAX is capable of covering large metropolitan distance of several kilometers while Wi-Fi covers just a local (short) area measured in meters.
Generally, WiMAX was invented by the WiMAX forum and is a telecommunications standard protocol that provides fixed and fully mobile internet access services over a wide range.
vSphere Client is used to install and operate the guest OS. true or false
Answer:
True
Explanation:
A guest Operating System (OS) is a secondary OS to the main installed OS which is the host Operating System (OS). Guest OS can either be a part of a partition or a Virtual Machine (VM). This guest OS is used as a substitute to the host OS.
vSphere Web Client can be installed by using a CD-ROM, DVD or ISO image which has the installation image to make a Virtual Machine (VM) functional.
Rosseta Technologies, an information technology service provider to a company based out of Germany, allows its employees to work from home twice a month. Its major concern is the leakage of confidential data from the laptops or an employee making copies of sensitive files on his personal laptop. Which of the following would help the firm enforce access controls and storage guidelines on its laptops?
a. Anenterprise search software
b. A binary search tool
c. A perceptive software pack
d. A Domain search engine
Answer:
a. An enterprise search software.
Explanation:
In this scenario, Rosseta Technologies, an information technology service provider to a company based out of Germany, allows its employees to work from home twice a month. In order to prevent the leakage of confidential data from the laptops or an employee making copies of sensitive files on his personal laptop, Rosetta technologies should use an enterprise search software.
Enterprise search software is a computer application which is typically used to make relevant data from sources, such as a database, file system and intranet searchable to a specific or defined group of people.
An enterprise search software would help the firm enforce access controls and storage guidelines on its laptops.
On enterprise search software, there are basically two (2) ways to enforce access controls as a security policy on users;
1. Early binding: at the index stage, permissions are analyzed and ascribed to each document in the enterprise search software.
2. Late binding: it involves the process of analyzing permissions and ascribing them to each document at the query stage in the enterprise search software.
A printer is connected locally on Computer1 and is shared on the network. Computer2 installs the shared printer and connects to it. Computer1 considers the printer to be a(n) ________________ printer, and Computer2 considers the printer to be a(n) ________________ printer.
Answer:
A printer is connected locally on Computer1 and is shared on the network. Computer2 installs the shared printer and connects to it. Computer1 considers the printer to be a(n) _____local___________ printer, and Computer2 considers the printer to be a(n) _____network___________ printer.
Explanation:
Any printer installed directly to Computer 1 is a local printer. If this printer is then shared with computers 2 and 3 in a particular networked environment, it becomes a shared printer. For these other computers 2 and 3, the shared printer is a network printer, because it is not locally installed in each of them. There may be some features which network computers cannot use on a shared printer, especially if the printer can scan documents.
When Windows deletes the driver package and driver files, in what situation might it not delete driver files used by the device that is being uninstalled?
Answer:
when there is no junk
Explanation:
If you choose the checkbox next to “Delete the driver software from this device,” your computer will no longer contain the driver or any associated registry keys. Either method will prevent you from using the device until you reinstall the device driver.
What is situation deletes driver files used by the device?To connect and communicate with particular devices, a computer needs device drivers.
It may be taken out without any trouble. However, it also comes with the installers for your PC's drivers. You will need to go to the manufacturer's website to download them again if you accidentally delete them.
Therefore, No, unless your new driver is broken and corrupts data. Install the driver if it comes from a reliable source. It is not intended to. Having a backup system that keeps your data safe in case of issues is a good idea.
Learn more about driver files here:
https://brainly.com/question/10608750
#SPJ5
A security administrator is investigating a report that a user is receiving suspicious emails. The user's machine has an old functioning modem installed. Which of the following security concerns need to be identified and mitigated? (Select TWO).
a) Vishing
b) Whaling
c) Spear phishing
d) Pharming
e) War dialing
f) Hoaxing
Answer:
Spear Phishing and War Dialing
Explanation:
So let's tackle these one at a time.
Vishing is simply any type of message (i.e., email, text, phone call, etc.) that appears to be from a trusted source but is not.
Whaling is simply a spear phishing attack of a high-value target such as a CEO or someone with high-level access at a company.
Spear phishing is simply a targeted phishing attack, usually towards a specific person or group of people. (Phishing attack is simply a social attack to try and gain unauthorized access to a resource).
Pharming is an attack that attempts to redirect website traffic to a fake site.
War dialing is a technique to automatically scan a list of numbers in an area in attempt to search for exposed modems, computers, board systems, or fax machines, in order to breach the network.
Hoaxing is simply a social attack that describes a serious threat in attempts to retrieve unauthorized access or money from a victim. (Think microsoft tech support scams)
Now that we have defined these things, let's identify the possible threats that need to be reported.
(a) Vishing? The sec admin report doesn't mention the source of the message so we cannot associate this one
(b) Whaling? The sec admin report says a user, implying someone not high up in the company, but doesn't say it's not someone high up. This is possible.
(c) Spear phishing? The sec admin report says a user, implying that only this user is being targeted so this is definitely valid.
(d) Pharming? The sec admin report says nothing about site redirection.
(e) War dialing? The sec admin report doesn't say anything about unauthorized scanning; however, it mentions the user has an old functioning modem, so this is possible.
(f) Hoaxing? The sec admin report doesn't mention a pop up in the email or the content of the email so we are uncertain.
Thus with these considerations, the two threats that are identified and need mitigation are Spear phishing and War Dialing/Whaling. Note that we aren't positive of the war dialing or whaling, but a case could be made for either; however, given the modem information, the question seems to indicate war dialing.
Some network applications defer configuration until a service is needed. For example, a computer can wait until a user attempts to print a document before the software searches for available printers.
What is the chief advantage of deferred configuration?
Answer:
The drivers wont be loaded and the deamons will not be running in the background unnecessarily, that makes the processes to run more faster
Explanation:
The chief advantage of deferred configuration or the advantage when some network applications defer configuration until a service is needed is that the drivers won't be loaded and the deamons will not be running in the background unnecessarily or when idle, that makes the processes to run more faster.
Network configuration is the activity which involves setting up a network's controls, flow and operation to assist the network communication of an organization or network owner.
A company wants a recruiting app that models candidates and interviews; displays the total number of interviews on each candidate record; and defines security on interview records that is independent from the security on candidate records. What would a developer do to accomplish this task? Choose 2 answers
a. Create a roll -up summary field on the Candidate object that counts Interview records.
b. Create a master -detail relationship between the Candidate and Interview objects.
c. Create a lookup relationship between the Candidate and Interview objects.
d. Create a trigger on the Interview object that updates a field on the Candidate object.
Answer:
c. Create a lookup relationship between the Candidate and Interview objects.
d. Create a trigger on the Interview object that updates a field on the Candidate object.
Explanation:
Objects relationships is considered a form of field type that joins two or more objects together such that, after understanding objects and fields, it creates some form of bonding known as object relationships. This helps define security on interview records that is independent from the security on candidate records.
For an example, in a standard object like Account, where a sales representative opens an account, and has had interviews or chats with a few people at that account’s company, and as well made contacts with the likes of executives or IT managers and still stored those contacts’ information in salesforce.
Hence, what would a developer do to accomplish this task is to:
1. Create a lookup relationship between the Candidate and Interview objects.
2. Create a trigger on the Interview object that updates a field on the Candidate object.
How I to turn this ''loop while'' in ''loop for''?
var i = 0;
while (i < 20) {
var lineY = 20 + (i * 20);
line(0, lineY, 400, lineY);
i++;
}
Answer:
for (var i = 0; i <20; i++)
{
var lineY = 20 + (i * 20);
line(0, lineY, 400, lineY);
}
Explanation:
To turn the loop while to for loop, you start by considering the iterating variable i and its iterating operations which are;
var i = 0; while (i < 20) and i++;
Where var i = 0; is the initializing statement
(i < 20) is the conditional statement
i++ is the increment
The next is to combine these operations to a for loop; using the following syntax: for(initializing; condition; increment){}
This gives: for(var i = 0; i<20; i++)
Hence, the full code snippet is:
for (var i = 0; i <20; i++)
{
var lineY = 20 + (i * 20);
line(0, lineY, 400, lineY);
}
A large population of ALOHA users manages to generate 50 requests/sec, including both originals and retransmissions. Time is slotted in units of 40 msec.
Required:
a. What is the chance of success on the first attempt?
b. What is the probability of exactly k collisions and then a success?
c. What is the expected number of transmission attempts needed?
Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt = [tex]e^{-G}G^k[/tex] but k = 0, therefore Probability that there is success on the first attempt = [tex]e^{-G}=e^{-2}=0.135[/tex]
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = [tex][1-e^{-G}]^k=[1-0.135]^k=0.865^k[/tex]
P(success in k+1 attempt) = [tex]e^{-G}=e^{-2}=0.135[/tex]
Probability of exactly k collisions and then a success = [tex]0.865^k0.135[/tex]
c) Expected number of transmission attempts needed = probability of success in k transmission = [tex]e^{G}=e^{2}=7.389[/tex]
Boolean expressions control _________________ Select one: a. recursion b. conditional execution c. alternative execution d. all of the above
Answer:
Option D, all of the above, is the right answer.
Explanation:
A Boolean expression is an expression in Computer Science. It is employed in programming languages that create a Boolean value when it is evaluated. There may be a true or false Boolean value. These expressions correspond to propositional formularies in logic. In Boolean expression, the expression 3 > 5 is evaluated as false while 5 > 3 is evaluated as true
Boolean expressions control all of the above method execution and as such option d is correct.
What is Boolean expressions?A Boolean expression is known to be a kind of logical statement that is said to be one of the two options that is it can be TRUE or FALSE .
Conclusively, Note that Boolean expressions are used to compare two or more data of any type only if both parts of the expression have equal basic data type. Boolean expressions control recursion, conditional execution and alternative execution.
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What is cutting-edge technology
Answer:
Cutting-edge technology refers to technological devices, techniques or achievements that employ the most current and high-level IT developments; in other words, technology at the frontiers of knowledge. Leading and innovative IT industry organizations are often referred to as "cutting edge."
Explanation:
Explain why it is not necessary to create an inbound rule on the internal 192.168.12.10 Windows server so that it can receive the response (ICMP echo reply) from the internal 192.168.12.11 Windows server.
Answer:
The file and printer sharing (Echo Request - ICMPv4-In) rule option should be listed for all profile.
Explanation:
The main reason why it is not compulsory or obligatory to design an inbound rule on the internal 192.168.12.10 Windows server in other to be able to accept the response (ICMP echo reply) generated from the internal 192.168.12.11 Windows server is that the file and printer sharing (Echo Request - ICMPv4-In) rule option or alternative needed to be listed for all profile.
Inbound rules filter or sieve traffic advancing from the network to the local computer based on the filtering conditions set out in the rule.
function of network security
Answer:ffffffffffffgggggg
Explanation:vvvc
"The ______ code of a rootkit gets the rootkit installation started and can be activated by clicking on a link to a malicious Web site in an email or opening an infected PDF file."
Answer:
Dropper.
Explanation:
A rootkit can be defined as a collection of hidden malicious computer software applications that gives a hacker, attacker or threat actor unauthorized access to parts of a computer and installed software. Some examples of rootkits are trojan, virus, worm etc.
The dropper code of a rootkit gets the rootkit installation started and can be activated by clicking on a link to a malicious website in an email or opening an infected PDF file such as phishing.
Hence, the dropper code of a rootkit launches and installs the loader program and eventually deletes itself, so it becomes hidden and not be noticed by the owner of the computer.
A rootkit can affect the performance of a computer negatively causing it to run slowly.