Answer:
Diffusion in gases is quick because the particles in a gas move quickly. It happens even faster in hot gases because the particles of gas move faster.
If a particle undergoes SHM with amplitude 0.17 mm , what is the total distance it travels in one period
Answer:
Particle travels 4 * amplitude in one period = .68 mm
have a difinite shape and do not easily take the shape of their containers
What is the height of a building (in meters) if it takes a rock 8.2 seconds to drop from it's roof?
Answer:
d = 329.81m
Explanation:
V_f = V_0+a*t
V_f = Velocity final
V_0 = Velocity initial
a = acceleration
t = time
V_f = (0m/s)+(9.81m/s²)*(8.2s)
V_f = 80.442m/s
d = ((V_f-V_0)/2)*t
d = distance
d = ((80.442m/s-0m/s)/2)*(8.2s)
d = 329.81m
A wagon of dog treats (combined mass 55 kg) is rolling at 2.1 m/s. A dog with mass 21 kg dives into the wagon, colliding with just enough momentum to make both stop. If the collision between the dog and the wagon lasts 0.1 s, what is the magnitude of the average force that will be exerted on the dog by the collision with the wagon
Answer:
Explanation:
An impulse results in a change of momentum
If the wagon and dog both stop, they must have had equal and opposite momentums
FΔt = mΔv
F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)
v₁ = t₀ = 0
F = m(v₀)/t₁
F = 55(2.1)/0.1 = 1155 N
We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.
Help with a b and c.
Answer:
Explanation:
Edit to add part a
a) Heating a gas causes the atoms to increase their kinetic energy. With only atmospheric pressure to contain it, the gas will decrease in density by pushing colder gas out of the way. The lid is then sealed to the jar and allowed to cool. The cooling gas, now constrained by the volume of the jar will be forced to lower its pressure to maintain equilibrium. The lower pressure inside the jar will allow the atmospheric pressure outside the jar to "click" the lid indicating a proper seal.
b Before opening there is a much lower pressure inside the jar than outside. The outside pressure keeps the lid constantly in the "clicked" position.
c After the jar is opened, the pressure on either side of the lid is equal and an unbalanced force applied to one side of the lid or the other can cause the lid to "click" or "unclick" depending on the initial position.
A CD has a diameter of 12.0 cm. If the CD is rotating at a constant angular speed of 200 revolutions per minute, then the tangential velocity of a point on the circumference is:
Hi there!
Converting from angular velocity to tangential velocity can be done by:
v = ωr
v = tangential velocity (m/s)
ω = angular velocity (rad/sec)
r = radius (m)
Convert 12 cm to meters:
100 cm = 1 m
12 cm = 0.12 m
Now, convert rev/min to rad/sec:
[tex]{\frac{200rev}{min}} * \frac{1min}{60s} * \frac{2\pi rad}{1 rev} = 20.94 rad/sec[/tex]
v = 20.94 · 0.12 = 2.51 m/s
During take-off a 8kg model rocket is burning fuel causing its speed to increase
at a rate of 4m/s2 despite experiencing a 90N drag.
What’s is the strength of the thrust?
(Answer unit is in N)( and the answer isn’t 212)
The strength of the thrust is 122 newtons.
The motion of the rocket is described by the second Newton's law, whose model is shown below:
[tex]\Sigma F = F - D = m\cdot a[/tex] (1)
Where:
[tex]F[/tex] - Thrust, in newtons[tex]D[/tex] - Drag, in newtons[tex]m[/tex] - Mass of the rocket, in kilograms[tex]a[/tex] - Net acceleration of the rocket, in meters per square secondIf we know that [tex]D = 90\,N[/tex], [tex]m = 8\,kg[/tex] and [tex]a = 4\,\frac{m}{s^{2}}[/tex], then the strength of the thrust is:
[tex]F = D + m\cdot a[/tex]
[tex]F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 122\,N[/tex]
The strength of the thrust is 122 newtons.
To learn more on Newton's laws, we kindly invite to check this verified question: https://brainly.com/question/13678295
13) A mass attached to the free end of a spring executes simple harmonic motion according to the equation y = (0.50 m) sin (18π t) where y is in meters and t is seconds. What is the period of vibration?
Hi there!
The period is given by:
[tex]T = \frac{2\pi}{w}[/tex]
T = Period (sec)
w = angular frequency (rad/sec)
According to the equation for SHM in terms of position:
y(t) = Asin(ωt + φ)
A = Amplitude (m)
ω = angular frequency (rad/sec)
t = time (sec)
φ = phase angle
In this instance, the angular frequency is given as 18π.
Plug this value into the equation for T:
[tex]T= \frac{2\pi}{18\pi} = \frac{1}{9} = \boxed{0.111 s}[/tex]
2 difference between calorimetry and calorimeter
Calorimetry :
the process of measuring the amount of heat released or absorbed during a chemical reaction.
Calorimeter :
device for measuring the heat developed during a mechanical, electrical, or chemical reaction, and for calculating the heat capacity of materials.
what type of stretching is beneficial for sports performance and involves momentum
Answer:
Dynamic stretching
Explanation:
Dynamic stretching is a form of stretching beneficial in sports utilizing momentum from form.
A 200-kg, 2.0-m-radius, merry-go-round in the shape of a flat, uniform, circular disk parallel to level ground is rotating at 1.2 cycles/second about an axis through its center of mass and perpendicular to the ground. A 50-kg boy jumps onto the edge of the merry-go round and lands at a fixed point. What is the angular velocity of the merry-go-round after the boy lands on it
Answer:
Explanation:
Conservation of angular momentum.
Disk I = ½MR²
Point mass I = mR² (boy)
Initial angular momentum
L₀ = Iω = ½MR²ω₀
Final angular momentum
L₁ = Iω = (½MR² + mR²)ω₁
as momentum is conserved, these are equal
(½MR² + mR²)ω₁ = ½MR²ω₀
ω₁ = ω₀(½MR²/ (½MR² + mR²))
ω₁ = ω₀(½M/ (½M + m))
ω₁ = 1.2(½(200)/ (½(200) + 50))
ω₁ = 1.2(⅔)
ω₁ = 0.8 cycles/second or 0.8(2π) = 1.6π rad/s
Which kind of chemical reaction is best
represented by the following equation?
BaCl2 + Na2S04 --> 2NaCl + BaSO4
A. Synthesis
B. Single displacement
C. Decomposition
D. Double displacement
Answer:
Synthesis
Explanation:
[tex] \color{lime}{ \sf better \: luck \: on \: your \: exam \: lol}[/tex]
A 2-kg object moving at 10 m/s has a 4-N force applied to it. Can you predict how the force will affect the object? A) yes, it will slow it down at a rate of 2 m/s2. B) yes, it will speed it up at a rate of 2 m/s2. yes, it will speed it up at a rate of 4 m/s2. D) It cannot be determined without more information.
Answer:
D) It cannot be determined without more information.
Explanation:
Velocity is a vector meaning it has both magnitude and direction.
Force and acceleration are also vectors.
Without knowing the directions of each, we cannot know if the mass has a speed (scalar value) change.
We can know that the mass will have a velocity change at the rate of 2 m/s² in the direction of the applied force.
If that force is applied in the direction of initial velocity, the velocity (and speed) will increase in magnitude in the same direction.
If that force is applied opposite of the initial velocity, the the velocity (and speed) will decrease in magnitude in the same direction. If the acceleration lasts long enough, velocity will eventually become zero and then become negative. At the same time, speed will become zero, and then increase again as speed is the absolute value of the magnitude of velocity.
If the force is applied at any other angle, both the velocity and the speed will change in both magnitude and direction.
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!pls
An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Answer:
Explanation:
acceleration= change in velocity/time taken
acceleration= 93/49
=2.02
i just want an answer please
Answer: An answer on what? I’ll never ignore you!
Explanation:
Answer:
an answer on what?
Explanation: Im here to help!!
HELPPP!! Thanks!
If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most correct situation?
a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas
b. Keep the gas in a fixed container at constant pressure and increase the temperature
c. Keep the gas in a fixed container at constant pressure and decrease the temperature
d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas
Answer:c i think
Explanation: not sure
How much potential energy does an 8 kg flower pot hanging 5 m above the ground have
Answer:
Explanation:
Relative to ground level it has
PE = mgh = 8(10)(5) = 400 J
When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large
amounts of energy, how does it transfer this energy to its surrounding environment?
Answer:
It releases some of the energy into the atmosphere as hot steam.
Explanation:
12) A horizontal force of 200 N is applied to move a 55-kg cart (initially at rest) across a 10 m level surface. What is the final speed of the cart? [hint: use work – energy principle] [3 marks]
Hi there!
We can use the following:
W = ΔKE = F · d
Find the work done on the cart:
W = 200 · 10 = 2000 J
Now, this is equal to the change in kinetic energy of the object. Its initial kinetic energy is 0 J since it starts from rest, so:
2000J = KEf - KEi
KE is given as:
[tex]KE = \frac{1}{2}mv^2[/tex]
2000J = 1/2(55)v²
4000 = 55v²
√(4000/55) = 8.53 m/s
explain the process of convergence and divergence ! HELPPP
Answer:
Divergence generally means two things are moving apart while convergence implies that two forces are moving together. ... Divergence indicates that two trends move further away from each other while convergence indicates how they move closer together.
Explanation:
A 21 newton force keeps a 3 kg object in uniform circular motion. The speed of the object is 9 m/s. The magnitude of the centripetal acceleration is
3 m/s^2
7 m/s^2
27 m/s^2
30 m/s^2
Answer:
Explanation:
F = ma
a = F/m = 21/3 = 7 m/s²
two factors affecting the magnitude of force of gravity betwwn 2 objects are A. mass and matter B. mass and distance C. weight and mass D. distance and weight
Answer:
B. MASS & MATTER
Explanation:
Newton's law also states that the strength of gravity between any two objects depends on two factors: the masses of the objects and the distance between them. Objects with greater mass have a stronger force of gravity between them.
If a 35 kg box collides with a stationary 120 kg box with a force of 90 N, what must be true of the magnitude of the reaction force?
Newton's third law allows to find the result for the value of the reaction force during the collision is:
The reaction force is F = 90 N and is applied to the lighter body.Newton's third law stable that the forces appear in pairs or ea that when two bodies interact, the interaction forces appear in the two bodies simultaneously, in general they are called action and reaction forces.
These furas are of the same magnitude, but in the opposite direction, each one applied to one of the bodies.
They indicate that the most lighter body collides with the one with the greatest mass with a force of F = 90 N. If we call this the action, the larger body must react with a force of equal magnitude on the lighter body.
Consequently, the reaction force is F = 90 N directed towards the lighter body.
Learn more about Newton's third law here: https://brainly.com/question/9857272
A mars surface exploration vehicle drops a rock off a 1.00 I'm high vertical Cliff. The sound of the rock landing at the base of the cliff is recorded by instruments on the vehicle 27.1 seconds later. Calculate the acceleration due to gravity on Mars given that the speed of sound on Mars is 320 m/s
The acceleration due to gravity on Mars is 11.81 m/s².
The given parameters:
Height of the cliff, h = 1 mTime of motion of the sound wave, t = 27.1 sSpeed of sound in mass, v = 320 sThe equation of motion to determine the acceleration due to gravity on the moon is calculated as follows;
[tex]s = vt + \frac{1}{2} gt^2[/tex]
where;
s is the distance traveledt is the time of motionSince the time measured is two way time, the new equation for the total distance traveled is calculated as;
[tex]v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{320 \times 27.1}{2} \\\\d = 4,336 \ m[/tex]
The acceleration due to gravity is calculated as follows;
[tex]s = vt + \frac{1}{2} gt^2\\\\4,336 = 0 \ + \ \frac{1}{2} \times g \times (27.1)^2\\\\4,336 = 367.21g\\\\g = \frac{4,336}{367.21} \\\\g = 11.8 1 \ m/s^2[/tex]
Thus, the acceleration due to gravity on Mars is 11.81 m/s².
Learn more about acceleration due to gravity here: https://brainly.com/question/88039
Define the term dimension
Answer:
Q1. A measurable extent of a particular kind, such as length, breadth, depth, or height.
Q2. A dimensional constant is a physical quantity that has dimensions and has a fixed value. Some of the examples of the dimensional constant are Planck's constant, gravitational constant, and so on.
Q3. Physical quantities which posses dimensions and have variable are called dimensional variables. Examples are length, velocity, and acceleration etc.
Q4. Dimensionless variables are the quantities which doesn't have any dimensions the the value is a variable. Eg: angle = arc/ radius. Dimensions = L/L. = 1. So angle does not have any dimensions and the value can vary.
Q5. Principle of Homogeneity states that dimensions of each of the terms of a dimensional equation on both sides should be the same. This principle is helpful because it helps us convert the units from one form to another.
Q6. Dimensional analysis has been around a long time, Newton called it the "Great principle of Similitude", but the modern form can be traced back to James Clerk Maxwell. It was Maxwell who distinguished mass [A/], length [£], and time [7"] as the independent dimensions from which others could be derived.
Q7. Mass, length, time, temperature, electric current, amount of light, and amount of matter.
Q8. Dimensional analysis is used to convert the value of a physical quantity from one system of units to another system of units. Dimensional analysis is used to represent the nature of physical quantity. The expressions of dimensions can be manipulated as algebraic quantities.
Hope that helps. x
yayy here you are f, r, e, e, p, o, i, n, t, s
Answer:
Albert Einstein Albert Einstein was a German-born theoretical physicist, widely acknowledged to be one of the greatest physicists of all time. Einstein is best known for developing the theory of relativity, but he also made important contributions to the development of the theory of quantum mechanics.Explanation:
Thank you so much buddy !!The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve of the particle at the origin in cosinusoidal form is shown in the figure.
Try to find (1) the vibration function of the particle at the origin, (2) the wave function of the planar simple harmonic wave according to the origin.
The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve of the particle at the origin in cosinusoidal form is shown in the figure.
Try to find (1) the vibration function of the particle at the origin, (2) the wave function of the planar simple harmonic wave according to the origin.
Answer:
Figure 16.8 The pulse at time
t
=
0
is centered on
x
=
0
with amplitude A. The pulse moves as a pattern with a constant shape, with a constant maximum value A. The velocity is constant and the pulse moves a distance
Δ
x
=
v
Δ
t
in a time
Δ
t
.
The distance traveled is measured with any convenient point on the pulse. In this figure, the crest is used.
Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!
Answer:
Explanation:
Photosynthesis is needed to store energy for the growth of the plant. It is like a factory that uses sunlight energy to convert 6CO₂ and 6H₂O into C₆H₁₂O₆ and 6O₂
Cell respiration is the process of breaking down the glucose and converting it into the other needed components of life. It's the engine that's fueled by the sugar of photosynthesis.
n a distant solar system, a planet of mass 5.0 x 1024 kg orbits a sun of mass 3.0 x 1030 kg at a constant distance of 2.0 x1011 m. How many earth days does it take for the planet ot execute one complete orbit about the sun
Answer:
F = M2 ω^2 R centripetal force of sun on planet
ω = (F / (M2 R))^1/2 = 2 pi f = 2 pi / P where P is the period
P = 2 pi (M2 * R / F)^1/2
F = G M1 M2 / R^2 gravitational force on planet
P = 2 pi {R^3 / (G M1)]^1/2
P = 6.28 [(2.0E11)^3 / (6.67E-11 * 3.0E30)]^1/2
P = 6.28 (8 / 20)^1/2 E7 = 3.9E7 sec
1 yr = 3600 * 24 * 365 = 3.15E7 sec
P = 3.9 / 3.2 = 1.2 years