Deepa usa unidades cuadradas para hallar el área de la figura

The probability that a randomly selected customer orders an appetizer or dessert or both is 0.57 or 57%.

The probability a randomly selected customer orders an appetizer or dessert or both is determined using the formula for the probability of the union of two events:

P(A or B) = P(A) + P(B) - P(A and B)

where:

Data given:

P(A) = 0.52,

P(B) = 0.32,

P(A and B) = 0.27.

Solving for P(A or B):

P(A or B) = 0.52 + 0.32 - 0.27

P(A or B) = 0.57

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To find the equation of the tangent line to the curve y = sec(x) at the point (π/3, 2), we need to take the derivative of y with respect to x.

The derivative of sec(x) is sec(x)tan(x), so at x = π/3, we have: y' = sec(π/3)tan(π/3) = 2√3/3, Now we can use the point-slope form of a line to find the equation of the tangent line: y - y1 = m(x - x1)

where (x1, y1) is the point we're given (in this case, (π/3, 2)) and m is the slope of the tangent line (in this case, 2√3/3).

Plugging in the values, we get:

y - 2 = (2√3/3)(x - π/3)

Simplifying, we get:

y = (2√3/3)x + 2 - 2√3

So the equation of the tangent line to the curve y = sec(x) at the point (π/3, 2) is y = (2√3/3)x + 2 - 2√3.
To find the equation of the tangent line to the curve y = sec(x) at the point (π/3, 2), we need to follow these steps:

Step 1: Find the derivative of the function
The derivative of y = sec(x) is:
y' = sec(x)tan(x)

Step 2: Evaluate the derivative at the given point
At the point (π/3, 2), we can find the value of the derivative:
y'(π/3) = sec(π/3)tan(π/3) = 2*(√3/2) = √3

Step 3: Use the point-slope form of a linear equation
The point-slope form of a linear equation is:
y - y1 = m(x - x1)

Plug in the given point (π/3, 2) and the slope from Step 2 (√3):
y - 2 = √3(x - π/3)

Step 4: Simplify the equation
y - 2 = √3x - π√3/3
y = √3x - π√3/3 + 2

The equation of the tangent line to the curve y = sec(x) at the point (π/3, 2) is y = √3x - π√3/3 + 2.

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The coordinates of the reflected triangle are A' = (-3, -4), B' = (1, -4) and C' = (3, -1)

Given that, the graph of ABC has coordinates A(-3,4) B(1,4) and C(3,1) which is reflected across the x-axis,

So,

The rule of the reflection across the x-axis is = (x, y) → (x, -y)

So, the coordinates of the reflected triangle will be,

A' = (-3, -4)

B' = (1, -4)

C' = (3, -1)

The graph is attached.

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The number of ways to choose an even number of right and left jumps can be calculated using the binomial coefficient. Specifically, the number of ways to choose k objects from a set of n objects is given by:

C(n, k) = n! / (k! * (n - k)!)

where n is the total number of objects and k is the number of objects chosen.

In this case, the frog must make a total of 3 jumps to reach a side of the square, so there are 2 possible values for the number of rights jumps it makes before it reaches the top or bottom of the square: 0 or 2. If the frog makes 0 right jumps, it must make 3 left jumps. If the frog makes 2 right jumps, it must make 1 left jump. The total number of possible sequences of jumps is:

C(3, 0) + C(3, 2) = 1 + 3 = 4

Out of these 4 possible sequences of jumps, only 2 of them end on a vertical side of the square. Specifically, the frog must make 2 left jumps and 1 right jump, or 2 right jumps and 1 left jump. Therefore, the probability that the frog ends on a vertical side of the square is:

2/4 = 1/2

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Ball A weighs 30g, as stated in the problem

We have,

The problem states that there are five balls, labeled A, B, C, D, and E, and provides their respective weights:

A weighs 30g, B weighs 50g, C weighs 50g, D weighs 50g, and E weighs 80g.

There is only one ball that weighs 30g in this problem, which is ball A.

The other balls weigh different amounts - ball B, C, and D all weigh 50g, and ball E weighs 80g.

It is possible that the question is asking which ball does not weigh 30g, in which case the answer would be any of the balls except for ball A.

However, based on the wording of the original question, it specifically asks which ball weighs 30g, making ball A the correct answer.

Therefore,

The ball that weighs 30g is Ball A.

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The probability that the second card is a spade given the first one is a spade is 12/51.

To find the probability that the second card drawn is a spade given that the first one is a spade, we need to use conditional probability.

Let's first find the probability of drawing a spade on the first draw. Since there are 13 spades in a standard deck of 52 cards, the probability of drawing a spade on the first draw is 13/52 or 1/4.

Now, since we are drawing without replacement, there are only 51 cards left in the deck for the second draw and only 12 spades left. So, the probability of drawing a spade on the second draw given that the first one was a spade is 12/51.

Therefore, the probability that the second card is a spade given that the first one is a spade is 12/51 or approximately 0.235.

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To determine the required sample size for a political poll with a 4% margin of error and a 97.5% confidence level, a formula can be used. For this scenario, the sample size required would be approximately 862 respondents.

To calculate the sample size needed for a political poll with a 4% margin of error and a 97.5% confidence level, the following formula can be used:

n = (Z^2 * p * (1-p)) / E^2

Where:

n is the sample size

Z is the Z-score associated with the desired confidence level (in this case, it is 2.24)

p is the expected proportion of support for the candidate (this value is typically unknown, so a conservative estimate of 0.5 is often used to get the maximum sample size)

E is the margin of error

Plugging in the values for this scenario, we get:

n = (2.24^2 * 0.5 * (1-0.5)) / 0.04^2

n ≈ 862

Therefore, the required sample size for this political poll is approximately 862 respondents. This sample size would provide a margin of error of 4% at a 97.5% confidence level, meaning that there is a 97.5% chance that the true proportion of support for the candidate lies within the range of the survey results plus or minus the margin of error.

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Answer:

3 cm²

Step-by-step explanation:

to find radius, divide the area by pi π and round to nearest tenths.

Answer:

2.99977cm

Step-by-step explanation:

π≈2.99977cm

The coefficient of x^14 in this product to find the number of ways to select the 14 balls under the given constraints.

To solve this problem using generating functions, we can first consider the number of ways to select any number of blue balls between 3 and 10. Let B(x) be the generating function for the number of ways to select blue balls. Then:

B(x) = (x^3 + x^4 + ... + x^10) / (1 - x)^100

The denominator (1-x)^100 represents the total number of ways to select any 14 balls from the jar, without any restrictions on the number of blue balls. The numerator (x^3 + x^4 + ... + x^10) represents the number of ways to select between 3 and 10 blue balls.

To find the total number of ways to select 14 balls with the given restriction, we need to subtract from the total number of ways the number of ways to select fewer than 3 blue balls and the number of ways to select more than 10 blue balls. Let R(x) be the generating function for the number of ways to select red and green balls:

R(x) = (1 + x + x^2)^200

Then the generating function for the total number of ways is:

G(x) = (B(x) * R(x)) / (1 - x)^100

To find the coefficient of x^14 in G(x), we can expand the numerator as a product of power series and multiply by the denominator, then extract the coefficient of x^14. This is a bit tedious, but we can use a computer algebra system or a spreadsheet to do the calculations.

The final answer is the coefficient of x^14 in G(x), which represents the number of ways to select 14 balls from the jar with the given restriction.

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Other answers are possible.

===================================================

Explanation for Problem 1, part (a)

We need to determine the equation of the line currently graphed.

That line goes through (0,4) and (4,1)

Use the slope formula on those two points.

[tex](x_1,y_1) = (0,4) \text{ and } (x_2,y_2) = (4,1)\\\\m = \text{slope} = \frac{\text{rise}}{\text{run}} = \frac{\text{change in y}}{\text{change in x}}\\\\m = \frac{\text{y}_{2} - \text{y}_{1}}{\text{x}_{2} - \text{x}_{1}}\\\\m = \frac{1 - 4}{4 - 0}\\\\m = -\frac{3}{4}\\\\[/tex]

The slope is -3/4, which in decimal form is -0.75

I'll stick to the fraction form.

The graphed line has these two key important properties

So we go from [tex]y = m\text{x} + b[/tex] to  [tex]y = -\frac{3}{4}\text{x} + 4[/tex]

If we introduce a second equation that is exactly [tex]y = -\frac{3}{4}\text{x} + 4[/tex], then this system

[tex]\begin{cases}y = -\frac{3}{4}\text{x} + 4\\y = -\frac{3}{4}\text{x} + 4\\\end{cases}[/tex]

will have infinitely many solutions. They are the same line, so they overlap perfectly to share the same set of solution points.

Each solution is of the form (x,y) = (x, -0.75x+4) where x is any real number.

Let's rewrite that second equation so we appear to be a bit more creative.

I'll multiply both sides by 4 and then move the x term to the left side. This will get the equation into standard form Ax+By = C.

[tex]y = -\frac{3}{4}\text{x} + 4\\\\4y = 4(-\frac{3}{4}\text{x} + 4)\\\\4y = -3\text{x} + 16\\\\3\text{x}+4y = 16\\[/tex]

Therefore this system

[tex]\begin{cases}y = -\frac{3}{4}\text{x} + 4\\3\text{x}+4y = 16\\\end{cases}[/tex]

will have infinitely many solutions of the form  (x,y) = (x, -0.75x+4)

Each solution is on the line shown in the graph that is given.

---------------------

Explanation for Problem 1, part (b)

The given graph has the equation [tex]y = -\frac{3}{4}\text{x} + 4\\[/tex] as found in the previous part. The slope is -3/4 = -0.75

We want a parallel line to this, because parallel lines never cross which leads to "no solutions". So the answer will also have a slope of -3/4.

Parallel lines have equal slopes, but different y intercepts.

In this case, the y intercept is b = 1 due to the point (0,1)

We arrive at the answer [tex]y = -\frac{3}{4}\text{x} + 1\\[/tex]

This system shown below has no solutions

[tex]\begin{cases}y = -\frac{3}{4}\text{x} + 4\\y = -\frac{3}{4}\text{x} +1\\\end{cases}[/tex]

---------------------

Explanation for Problem 1, part (c)

The new line must go through (0,2) and (4,1)

Compute the slope.

[tex](x_1,y_1) = (0,2) \text{ and } (x_2,y_2) = (4,1)\\\\m = \text{slope} = \frac{\text{rise}}{\text{run}} = \frac{\text{change in y}}{\text{change in x}}\\\\m = \frac{\text{y}_{2} - \text{y}_{1}}{\text{x}_{2} - \text{x}_{1}}\\\\m = \frac{1 - 2}{4 - 0}\\\\m = -\frac{1}{4}\\\\[/tex]

The slope is m = -1/4 and the y intercept is b = 2

We go from y = mx+b to [tex]y = -\frac{1}{4}\text{x} + 2\\[/tex] which is the answer.

This system

[tex]\begin{cases}y = -\frac{3}{4}\text{x} + 4\\y = -\frac{1}{4}\text{x} +2\\\end{cases}[/tex]

has one solution at (4,1) which is where the two lines cross.

---------------------

Explanation for Problem 2

The given equation of this system is [tex]y = \frac{3}{4}\text{x} - 4\\[/tex]

It has a slope of 3/4.

Anything parallel to this will also have the same slope. Refer to problem 1, part (b).

All we have to do is change the y intercept to something other than -4

Let's say we go for 5.

This system

[tex]\begin{cases}y = \frac{3}{4}\text{x} - 4\\y = \frac{3}{4}\text{x} +5\\\end{cases}[/tex]

has no solutions.

You could use graphing software like GeoGebra or Desmos to confirm any of the answers mentioned earlier.

The answer is 11101 in binary, which is equivalent to the decimal number 29 using binary multiplication.

To perform binary multiplication, we use the same method as we do for decimal multiplication, but only with 0s and 1s.

So, to multiply 1011 and 101, we first write them down like this:

   1011
 x  101
 ------
 
Now we start with the rightmost digit of the second number (1), and multiply it with every digit of the first number, one by one, starting from the right:

   1 0 1 1
 x 1 0 1
 ------
   1 0 1 1
 0 0 0 0
 1 0 1 1
-------------

The first row represents the multiplication of the last digit of the second number (1) with every digit of the first number. The second row represents the multiplication of the second last digit of the second number (0) with every digit of the first number, and so on.

Now we add up all the rows, taking care to align them properly:

   1 0 1 1
 x 1 0 1
 ------
   1 0 1 1
 0 0 0 0
 1 0 1 1
-------------
 1 1 1 0 1

So the answer is 11101 in binary, which is equivalent to the decimal number 29.

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To identify missing values, you can check if there are any responses with blank or incomplete answers in the survey data.

These responses may indicate that the corresponding data is missing. Alternatively, you can use software tools such as Excel or statistical packages like R or Python to automatically identify missing values.

To identify erroneous values, you can check if there are any responses that are outside the expected range of values or seem to be unlikely or illogical. For example, if the survey asks respondents to rate the taste of the candy on a scale of 1-10, a response of 100 would be considered erroneous. Similarly, if a respondent rates the texture of the candy as "very bad" but also rates the creaminess of filling as "very good", this may indicate an error.

Once you have identified missing or erroneous values, you can decide how to handle them. For missing values, you can either exclude the corresponding responses from the analysis or use imputation techniques to estimate the missing values based on other available data. For erroneous values, you may need to contact the respondents to clarify their responses or exclude the corresponding responses from the analysis.

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The indicated probabilities using the z-scores and the standard normal distribution table are as follows:

The probabilities are found by determining the z-scores and the  standard normal distribution table;

a) mean, μ = of 5.2

standard deviation,σ = 1.4

Using a calculator, the z-score for x = 6 is z = -1.43, and the z-score for x = 9 is z = 1.43.

Using the standard normal distribution table, the area between these z-scores is approximately 0.4236.

b) mean, μ = 30.4

standard deviation, σ = 4.6

Using a calculator, the z-score for x = 25 is z = -1.83, and the z-score for x = 32 is z = 0.87.

Using the standard normal distribution table, the area between these z-scores is approximately 0.6915.

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Therefore, 698 of the 2510 students have not taken a course in any of these three programming languages using principle of inclusion-exclusion.

We can solve this problem using the principle of inclusion-exclusion. First, we add up the number of students who have taken at least one course:

n(J or L or C) = n(J) + n(L) + n(C) - n(J and L) - n(L and C) - n(J and C) + n(J and L and C)

n(J or L or C) = 1876 + 999 + 345 - 876 - 231 - 290 + 189

n(J or L or C) = 1812

So there are 1812 students who have taken at least one course. Therefore, the number of students who have not taken any of these courses is:

n(not J and not L and not C) = 2510 - n(J or L or C)

n(not J and not L and not C) = 2510 - 1812

n(not J and not L and not C) = 698

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2, -8

The solution set for an equation is all of the values that make the equation true.

Factoring

One way to solve many quadratic equations, especially those with a leading coefficient of 1, is factoring. Remember that quadratic functions are written in the form of ax² + bx + c. This means that the b-value is 6 and the c-value is -16.

In order to factor the equation above, we need to find 2 factors that add to b and multiply to c. In this case, these 2 factors are -2 and 8. Now, plug these values into the form (x+A) * (x+B) = 0.

Now it is easy to see that if x = 2, then the equation will be true.

Additionally, if x = -8, then the equation will be true. The factored form of the quadratic lets us easily see that the solution set is 2 and -8.

Solution Sets

The solution set to an equation is the values that make the equation true. Since this equation is a quadratic set equal to zero, the solution set is also the zeros of the function. Zeros are points where the function crosses the x-axis (aka where y = 0). For quadratics, there can be 0, 1, or 2 real solutions. In this case, the function crosses the x-axis in 2 separate locations, so the solution set has 2 answers.

The number of seconds that the gymnast is in the air will be 3.625 seconds.

Given that:

Equation, y = − 16x² + 58x

Where y represents the height of the gymnast (in feet) after x seconds for one of the jumps.

The number of seconds that the gymnast is in the air will be given as,

y = 0

− 16x² + 58x = 0

16x² − 58x = 0

2x(8x − 29) = 0

x = 0

8x - 29 = 0

x = 29/8 = 3.625 seconds

The number of seconds that the gymnast is in the air will be 3.625 seconds.

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The nearest tenth of a foot, the thickness T of the cantilever at x = 6 feet is 7.6 feet.

The given equation for the bottom edge of the cantilever is y = 2Vx, where V is the height of the cantilever. Therefore, the height of the cantilever is:

V = y / (2x)

At x = 6 feet, the value of y is:

y = 2Vx = 2(3.2) = 6.4 feet

To find the thickness T at x = 6 feet, we can use the Pythagorean Theorem:

T² = b² - y²

where b is the height of the cantilever. We have already calculated V to be 3.2 feet, so:

b = 3.2 + y = 3.2 + 6.4 = 9.6 feet

Substituting these values into the equation for T², we get:

T² = (9.6)² - (6.4)² = 57.76

Taking the square root of both sides, we get:

T ≈ 7.6 feet

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The solution is : the probability, to the nearest 10th of a percent, that both marbles drawn will be green will be 0.053.

Here, we have,

n(r) = 7

n(b) = 8

n ( g) = 5

Total number of marbles = 20

The probability that both marbles drawn will be green will be

The probability of the first being green = 5/20 and the probability that the second marble is green = 4/19.

We will multiply the two together , we have

5/20 x 4/19

= 20/380

= 0.05263157895

Therefore : the probability, to the nearest 10th of a percent, that both marbles drawn will be green will be 0.053

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William owes a total of $10,142.84.  To calculate this, we first need to determine the total interest paid over the 3-year period.

Using the formula A = P(1 + r/n)^(nt), where:
A = the final amount owed
P = the principal amount borrowed (in this case, $9000)
r = the interest rate (4.5%)
n = the number of times the interest is compounded per year (annually in this case)
t = the number of years (3 in this case)

We can plug in the values:
A = 9000(1 + 0.045/1)^(1*3)
A = 9000(1 + 0.045)^3
A = 9000(1.1412)
A = 10,270.88

This gives us the total amount owed after 3 years. But we only want to know the principal plus interest, so we subtract the original amount borrowed:

10,270.88 - 9000 = 1270.88

Therefore, William owes a total of $10,142.84 (rounded to the nearest cent).

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Shift from the starting demand curve to inward.

If there was a demand factor shift that increased the world food demand in 2007-2008, then the world food demand curve would shift outward, to the right of the original demand curve. This means that at any given price, the quantity of food demanded would be higher than before the shift.

This is because an increase in demand factors, such as population growth or changes in consumer preferences, would cause consumers to demand more food at each price level. As a result, the entire demand curve would shift to the right, indicating a higher quantity demanded at every price level.

On the other hand, if there was a demand factor shift that decreased the world food demand, then the demand curve would shift inward, to the left of the original demand curve. This would indicate a lower quantity demanded at every price level.

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The measure of the unknown angles are:

m ∠a = 155°

m ∠b = 25°

m ∠c = 155°

From the question, we are to determine the measure of the unknown angles.

From the given information,

The unknown angles are ∠a, ∠b, and ∠c.

From the given diagram, we can write that

m ∠b + 155° = 180° (Sum of angles on a straight line)

Calculate the m ∠b

m ∠b + 155° = 180°

Subtract 155° from both sides of the equation

m ∠b + 155° - 155° = 180° - 155°

m ∠b = 25°

m ∠c = 155° (Corresponding interior angles)

m ∠a = 155° (Vertically opposite angles)

Hence, the values of the angles are:

m ∠a = 155°

m ∠b = 25°

m ∠c = 155°

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The distance between the points (2, 3) and (-1, -4) is equal to √58 units.

In Mathematics and Geometry, the distance between two (2) end points that are on a coordinate plane can be calculated by using the following mathematical equation:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Where:

x and y represent the data points (coordinates) on a cartesian coordinate.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(-1 - 2)² + (-4 - 3)²]

Distance = √[(-3)² + (-7)²]

Distance = √[9 + 49]

Distance = √58 units.

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The solution to the inequality (g/20) ≤ 5 is given as follows:

B. g ≤ 100.

The inequality in the context of this problem is defined as follows:

(g/20) ≤ 5.

We solve the inequality similarly to an equality, isolating the desired variable. The difference is that we obtain a range with infinity values, instead of a single value as is the case for an equality.

The multiplication is the inverse operation of the division, hence the solution is given as follows:

g ≤ 20 x 5.

g ≤ 100.

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Using order of magnitude the capacity a cup would hold would be 250 milliliters of liquid.

Order of magnitude is the relative size of a quantity

To determine if a cup would hold 250 liters of liquid or 250 milliliters of liquid, we need to determine the order of magnitude of the capacity of a cup.

We know that the order of magntude of the capacity of a cup is in the order milliliters since it is small and not in the order of magnitude of liters.

So, therefore, the capacity a cup would hold would be 250 milliliters of liquid.

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The value of the indicated angle is 128⁰.

The value of the indicated angle is calculated applying intersecting chord theorem as shown below.

The tangent angle formed outside the circumference is equal to the angle formed by the intersection of the chords at the center.

Angle adjacent the indicated angle = 52⁰ (intersecting chord theorem)

The value of the indicated angle is calculated as follows;

52⁰ + ? = 180 ( sum of angles on a straight line )

? = 180 - 52⁰

? = 128⁰

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23 tortillas can be made from the remaining dough.

If 16 small tortillas have been cut from a square sheet of dough with a side length of 14 inches, then the area of the initial sheet of dough is:

Area of initial sheet of dough = (side length)² = 14² = 196 square inches

The circumference of each small tortilla is given as 7.85 inches. We can use the formula for the circumference of a circle to find its radius "r":

Circumference = 2πr

7.85 = 2πr

r = 7.85 / (2π) ≈ 1.25 inches

The area of each small tortilla is given by:

Area of each small tortilla = πr^2 ≈ 4.91 square inches

The total area of 16 small tortillas is:

The total area of 16 small tortillas = 16 × Area of each small tortilla ≈ 78.57 square inches

Therefore, the area of the leftover dough is:

Area of leftover dough = Area of an initial sheet of dough - Total area of 16 small tortillas

= 196 - 78.57

≈ 117.43 square inches

Number of small tortillas that can be made from the leftover dough ≈ Area of leftover dough / Area of each small tortilla

≈ 117.43 / 4.91

≈ 23.93

Since we can only make whole tortillas, we can make a maximum of 23 small tortillas from the leftover dough.

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Complete question:

16 small tortillas have been cut from the square sheet of dough. The circumference of each small tortilla is 7.85 in. How many small tortillas can be made from the leftover dough?  while the side of the dough is 14. Show your thinking

volume (v) = 105

volume (v) = 105

volume (v) = 105 formula to find volume

volume (v) = 105 formula to find volumevolume= v

volume (v) = 105 formula to find volumevolume= vlength = l

volume (v) = 105 formula to find volumevolume= vlength = lwidth = w

volume (v) = 105 formula to find volumevolume= vlength = lwidth = w v = l x w x h

volume (v) = 105 formula to find volumevolume= vlength = lwidth = w v = l x w x hv = 5 x 3 x 7

volume (v) = 105 formula to find volumevolume= vlength = lwidth = w v = l x w x hv = 5 x 3 x 7v = 15 x 7

v = 105

However, in some cases, the default location of the click point may be set by default to the top-left corner of the screen or window, which would correspond to the coordinate (0, 0) in a Cartesian coordinate system.

If no coordinates have been assigned to the cursor, the default location of the click point will depend on the program or application being used. In most cases, the default location will be the center or starting position of the screen or window in which the program is running, which could be any location on the screen. Therefore, none of the options provided is necessarily correct.

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The probability that this new camera phone will be successful if its success has been predicted is approximately 0.857 or 85.7%.

To find the probability that the new camera phone will be successful given its success has been predicted, we can use the Bayes' theorem formula:

P(A|B) = (P(B|A) * P(A)) / P(B)

Here, let A be the event that the product is successful, and B be the event that the product is predicted to be successful. We are given the following probabilities:

P(A) = Probability of a product being successful = 0.60
P(B|A) = Probability of predicting success given the product is successful = 0.40

We also need to find P(B), the probability of predicting success. This can be calculated as:

P(B) = P(B|A) * P(A) + P(B|A') * P(A')

where A' is the event that the product is not successful (failure).

We are given:

P(A') = Probability of a product being not successful = 1 - P(A) = 0.40
P(B|A') = Probability of predicting success given the product is not successful = 0.10

Now, we can find P(B):

P(B) = (0.40 * 0.60) + (0.10 * 0.40) = 0.24 + 0.04 = 0.28

Now we can apply the Bayes' theorem formula:

P(A|B) = (P(B|A) * P(A)) / P(B)
P(A|B) = (0.40 * 0.60) / 0.28
P(A|B) = 0.24 / 0.28
P(A|B) = 0.8571 (rounded to four decimal places)

So, the probability that this new camera phone will be successful if its success has been predicted is approximately 0.857 or 85.7%.

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