please help me with Chem I ONLY HAVE 5 MINUTES if methane gas (CH4) flows at a rate of 0.25L/s, how many grams of methane gas will there be in a room after 1 hour of time has passed?
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -Assuming STP-. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
Volume Methane:
3600s * (0.25L / s) = 900L Methane
Moles methane:
PV = nRT; PV / RT = n
Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
Mass methane:
40.18 moles * (16g/mol) =
643g of methane will there be in the roomPlss hellp which law is that?
Answer:
law of motion
Explanation:
Answer:
it is a inertia of motion because the person inside a moving bus falls forward if it is stopped suddenly.
Explanation:
You dissolve 14 g of [tex]Mg(NO_{3} )_{2}[/tex] in water and dilute to 750 mL. What is the molarity of this solution?
Show your work
Please hurry!!! And help!!
*URGENT*
Best answer gets marked Brainliest!
When two nitrogen atoms combine, they form a
A) Compound
B) Liquid
C) mixture
D) Molecule
Answer:
Molecule
Explanation:
N=N
the answer is liquid
Explanation:
Coz liquid is better than anyone else about the league Now guys are u doing anything for the link to know
A nurse practitioner prepares an injection of promethazine, an antihistamine used to treat allergic rhinitis. If the stock bottle is labeled 30. mg/mL and the order is a dose of 14.0 mg , how many milliliters will the nurse draw up in the syringe?
Answer: Volume is 0.466 ml. Maybe in this case it is safer to round downward.
Explanation: V = 14.0 mg / 30 mg/mL = 0.466.. ml
2.1 milliliters will the nurse draw up in the syringe if the bottle is labeled 30. mg/mL and the order is a dose of 14.0 mg of an injection of promethazine an antihistamine.
What is antihistamine?This is a combination of medications used to treat the temporary symptoms of the common cold and for allergies related to breathing and mostly deals with breathing problems of the one.
Injection used has a fixed dose which varies according to age group for 30. mg/mL and the order is a dose of 14.0 mg can be calculated by,
14/30 ×100 = 2.1 milliliters
Therefore, the nurse draws up the syringe if the bottle is labeled 30. mg/mL and the order is a dose of 14.0 mg of an injection of promethazine an antihistamine it will be 2.1 milliliters.
Learn more about antihistamines, here:
https://brainly.com/question/13896753
#SPJ2
Calculate the pH of a 0.10 M solution of acidic acid HC2H3O2(aq) at 25 °C. Ka for HC2H3O2 = 1.8×10−5 at 25 °C g
Answer:
The answer is "3".
Explanation:
acetic acid Dissociation:
[tex]CH_3COOH \ < - - - - - - - - - - - - - \ > CH_3COO^{-}+H^{+}\\\\[/tex]
Dissociation constant of the Ka:
[tex]Ka = \frac{[CH3COO^{-}] [H^{+}]}{[CH_3COOH]}\\\\[/tex]
using the ICE table:
[tex]CH_3COOH \ < - - - - - - - - - - - - - \ > CH_3COO^{-}+H^{+}\\\\[/tex] [tex]\to 1.8 \times 10^{-5} =\frac{( x \times x) }{0.1-x} -------(2)[/tex]
x is negligible compared to Ka.
[tex]1.8\times 10^{-5} = \frac{x^2}{0.10}\\\\x^2 = 1.8 \times 10^{-6}\\\\x = 1.34 \times 10^{-3}\\\\pH = -\log [H^{+}][/tex]
From the ICE table, [tex][H^{+}] = x = 1.34 \times 10^{-3}[/tex]
[tex]\to pH = -\log(1.34 \times 10^{-3}) = 3[/tex]
is a glow stick Endothermic or exothermic ?
Answer:
exothermic
Explanation:
A gas cylinder with a volume of 5.00 L contains 6.00 moles of oxygen gas
at a temperature of 90.0 K. What is the pressure inside the cylinder? The
Ideal gas law constant( R) is 0.0821 L atm/mol K*
8.87 torr
8.87 atm
0.0821 atm
0.0821 torr
Answer:
8.87 atm
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 5 L
Number of mole (n) = 6 moles
Temperature (T) = 90 K
Gas constant (R) = 0.821 atm.L/Kmol
Pressure (P) =?
The pressure inside the container can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
P × 5 = 6 × 0.0821 × 90
P × 5 = 44.334
Divide both side by 5
P = 44.334 / 5
P = 8.87 atm
Therefore, the pressure inside the container is 8.87 atm
when naming branched chain alkanes, the names of the alkyl substituents are listed in alphabetical order
true or false?
Answer:
False that all kalwlzsjoxla
which best describes the type of titration for the graph below? O strong acid titrated with a strong base
O strong base titrated with a strong acid
O weak acid titrated with a strong base
O weak base titrated with a strong acid
Answer:
B. strong base titration with a strong acid
You must make 1 L of 0.2 M acetic acid (CH3COOH). All you have available is concentrated glacial acetic acid (assay value, 98%; specific gravity, 1.05 g/mL). It will take _________ milliliters of acetic acid to make this solution. Assume a gram molecular weight of 60.05 grams.
Answer:
The correct answer is "11.44 ml".
Explanation:
Molarity,
= 0.2 M
Density,
= 1.05 g/ml
Volume,
= 1 L
As we know,
⇒ [tex]Molarity=\frac{No. \ of \ moles }{Volume \ of \ solution}[/tex]
or,
⇒ [tex]No. \ of \ moles=Molarity\times Volume[/tex]
On putting the values, we get
⇒ [tex]=0.2\times 1[/tex]
⇒ [tex]=0.2 \ moles[/tex]
Now,
⇒ [tex]No. \ of \ moles=\frac{Mass \ taken}{Molecular \ mass}[/tex]
or,
⇒ [tex]Mass \ taken=No. \ of \ moles\times Molecular \ mass[/tex]
⇒ [tex]=0.2\times 60.05[/tex]
⇒ [tex]=12.01 \ gram[/tex]
hence,
⇒ [tex]Density= \frac{Mass }{Volume}[/tex]
or,
⇒ [tex]Volume=\frac{Mass}{Density}[/tex]
⇒ [tex]=\frac{12.01}{1.05}[/tex]
⇒ [tex]=11.44 \ ml[/tex]
Consider the energy diagram below.
A graph of reaction progression on the horizontal axis versus energy on the vertical axis. A line starts flat low on the vertical axis, the flat area is labeled A. It rises sharply to peak, labeled C, then falls a short distance before levelling off, labeled D. A dotted line follows the initial line in all respects except that it peaks higher directly above C; that peak is labeled B.
Which statement best describes the diagram?
A. The pathway A-B-D involves a catalyst and is slower than A-C-D.
B. The pathway A-B-D involves a catalyst and is faster than A-C-D.
C. The pathway A-C-D involves a catalyst and is slower than A-B-D.
D. The pathway A-C-D involves a catalyst and is faster than A-B-D.
Answer:
Explanation:
Thank you for providing the graph which was missing in the question!
D is the correct answer because a catalyst will speed up a chemical reaction. In an exothermic reaction as shown, the catalyst also enhances the reaction so that more energy is given out.
D. The pathway A-C-D involves a catalyst and is faster than A-B-D.
because a catalyst will speed up a chemical reaction.
In an exothermic reaction as shown, the catalyst also enhances the response so that more energy is given out.
What is a catalyst?A catalyst is a substance that speeds up a chemical reaction or lowers the temperature or pressure needed to start one, without itself being consumed in the course of the reaction. Catalysis is the process of adding a catalyst to facilitate a reaction.
A chemical catalyst is a substance that causes a chemical reaction to take place in a special way than it would happen without that catalyst. as an example, a catalyst should cause a reaction between reactants to happen at a faster rate or at a lower temperature than would be possible without the catalyst.
Learn more about catalysts here
https://brainly.com/question/12507566
#SPJ2
Carbon dioxide had how many nonbonding electron pairs in its electron arrangement?
A. 2
B. 4
C. 8
D. 6
E. 3
Answer: A.) 2 is the answer.
Explanation:
When a balloon containing 635 mL of air is taken from sea level (at standard pressure) to a higher altitude, the balloon expands to 829 mL. What is the air pressure at this new altitude (in atm)?
Answer:
0.766atm
Explanation:
Boyles law
P1V1=P2V2
1×635=P2×829
P2=635/829
P2=0.766atm
Which law is that pls hellp
Answer:
It is newton's first law of motion which states "Everybody continues to be in its state of rest or uniform motion in a straight line unless it is compelled by some external effort to change that state".
Explanation:
You have at your lab bench the following chemicals: NaH2PO4(s), Na2HPO4(s), Na3PO4(s) and deionized water. You also have standard glassware available. Describe how you would make 1.00 L of buffer with a pH of 7.00 using only solid materials and deionized water so that the concentration of the weak acid in the buffer is 0.150 M.
Answer:
Weigh 17.997g Na2HPO4 and 13.486g of NaH2PO4 dissolving those salts in 1.00L of deionized water
Explanation:
A buffer is made with the mixture of a weak acid and its conjugate base. We have as first to find the correct mixture based on the pKa's of the acids:
pKa H3PO4- NaH2PO4 = 2.148
pKa NaH2PO4 - Na2HPO4 = 7.198
pKa Na2HPO4 - Na3PO4 = 12.375
A buffer works in a range of pH's of pKa±1. Thus, we choice NaH2PO4 - Na2HPO4.
The first equation that we can write is:
NaH2PO4 = 0.150 moles -Because the concentration of the weak acid is 0.150M, in 1L = 0.150moles
Using H-H equation for this mixture:
pH = pKa + log [Na2HPO4] / [NaH2PO4]
pH is desire pH = 7.00
pKa is 7.198
[Na2HPO4] and [NaH2PO4] could be taken as the moles of each salt.
Replacing:
7.00 = 7.198 + log [Na2HPO4] / [0.150moles]
-0.198 = log [Na2HPO4] / [0.150moles]
0.6339 = [Na2HPO4] / [0.150moles]
0.095 moles = [Na2HPO4]
The mass of each salt that we must weigh is:
NaH2PO4 -Molar mass: 119.98g/mol-
0.150mol * (119.98g/mol) = 17.997g Na2HPO4
Na2HPO4 -Molar mass: 141.96g/mol-
0.095 moles * (141.96g / mol) = 13.486g of NaH2PO4
Thus, to prepare the buffer we have to:
Weigh 17.997g Na2HPO4 and 13.486g of NaH2PO4 dissolving those salts in 1.00L of deionized water
If it takes 720. mL of 0.00125 M Mg(OH)2 to neutralize 425 mL of an HCI
solution, what is the concentration of the HCI? Mg(OH)2 + HCl →MgCl2
+ H20
Answer:
0.004235 M
Explanation:
The neutralization reaction of this question is given as follows:
Mg(OH)2 + 2HCl → MgCl2 + 2H2O
Using the formula below:
CaVa/CbVb = na/nb
Where;
Ca = concentration of acid (M)
Cb = concentration of base (M)
Va = volume of acid (mL)
Vb = volume of base (mL)
na = number of moles of acid = 2
nb = number of moles of base = 1
From the information provided in this question;
Ca = ?
Cb = 0.00125 M
Va = 425 mL
Vb = 720 mL
na (HCl) = 2
nb = (Mg(OH)2) = 1
Using the formula; CaVa/CbVb = na/nb
Ca × 425/0.00125 × 720 = 2/1
425Ca/0.9 = 2
472.2Ca = 2
Ca = 2/472.2
Ca = 0.004235 M
The bond angles marked a, b, and c in the molecule below are about __________, __________, and __________, respectively. Select correct answer. Select correct answer. 120°, 109.5°, 120° 90°, 90°, 90° 109.5°, 120, 109.5° 109.5°, 109.5°, 109.5° 109.5°, 109.5°, 90°
Answer:
109.5°, 120°, 109.5°
Explanation:
The bond angles that are marked as a, b and c in the given molecules is in the order of :
Angle a : 109.5°
Nitrogen is [tex]$sp^3$[/tex] hybridized and the geometry is tetrahedral. So the bond angle is 109.5°
Angle b : 120°
Carbon is [tex]$sp^2$[/tex] hybridized, so the shape is trigonal planer and the bond angle is 120°
Angle c : 109.5°
Carbon is [tex]$sp^3$[/tex] hybridized and the geometry is tetrahedral. The bond angle is 109.5°
Please answer these quickly. :)
Q.1
a) 1 mol of N2 requires 3 moles of H2
so 4 moles of hydrogen will require = 4/3 = 1.33 moles
Answer of A) 1.33 moles
b) 2.5 moles of nitrogen gas were require to produce 5.00 moles of NH3
c) 7.5 moles of hydrogen gas were require to produce
5.00 moles of NH3
Q.2
a) 6 moles of H2 gas were require to make 6.00 mol H2S
b)24 moles of H2 gas were required to react with 3 moles of S8
c)56 moles of H2S are produced from 7 mol of S8
How many molecules of sodium fluoride (NaF) are found in 7.2 moles of sodium fluoride?
Answer:
well please answer me it's question too after you get it
Explanation:
i am also stucked in that question
No. of molecules of any substance is one mole
= Avogadro's Number = (6.022 x 10^23)
So, no. of molecules in 7.2 moles of sodium fluoride
= 7.2 × (6.022 x 10^23)
= 4.33584^24
How to do 3 and 4 questions
Answer:
3) Q = -836.8 J.
4) Q = 950J.
Explanation:
Hello there!
In this case, for those calorimetry problems, we use the general equation:
[tex]Q=mC\Delta T[/tex]
Thus, we proceed as follows:
3) Here, the temperature difference is from 80 °C to 40 °C, the mass is 5.0 g and the specific heat 4.184 in SI units; thus, the heat is calculated as follows:
[tex]Q=(5g)(4.184\frac{J}{g\°C} )(40\°C-80\°C)\\\\Q=-836.8J[/tex]
4) Here, the temperature difference is from 100 °C to 200 °C, the mass is 5.0 g and the specific heat about 1.90 in SI units; thus, the heat is calculated as follows:
[tex]Q=(5g)(1.90\frac{J}{g\°C} )(200\°C-100\°C)\\\\Q=950J[/tex]
Regards!
Name the following alkene:
CH3CH = CHCH2CH3
A. 3-pentane
B. 2-pentene
C. 2-pentane
D. 3-pentene
Answer:
2-pentene
Explanation:
The name of the alkene is 2 pentene. The correct option is B, 2-pentene.
What is 2-pentene?Alkenes with the chemical formula [tex]C_5H_10[/tex] are known as pentene. Within its molecular structure, each has one double bond.
The given alkene [tex]CH_3CH = CHCH_2CH_3[/tex] is 2-pentene because the double bond is present in the second carbon and it's pentene because there are five carbons present.
Thus, the correct option is B. 2-pentene.
Learn more about 2-pentene
https://brainly.com/question/19593832
#SPJ2
If 15L of neon is at 25C is allowed to expand to 45L. What is the new temperature to maintain constant pressure?
Answer:
[tex]T_2=894.45K=621.30\°C[/tex]
Explanation:
Hell there!
In this case, according to the given information, it turns out possible for us to calculate the new temperature by applying the Charles' law as a directly proportional relationship between temperature and volume:
[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]
Thus, we solve for the final temperature, T2, as shown below (make sure T1 is in Kelvins):
[tex]T_2=\frac{V_2T_1}{V_1} \\\\T_2=\frac{(25+273.15)K*45L}{15L}\\\\T_2=894.45K=621.30\°C[/tex]
Regards!
Qualitatively explain the effect of changing concentration of Cu2+ on voltage using your experimental observations and the Keq values below. (No calculations are required).
(a) Cu^2+(aq) + 4NH3(aq) ⇄ [Cu(NH^3)4]^2+(aq) Keq = 1.2 x 10^12
(b) CuS(s) ⇄ Cu^2+(aq) + S^2-(aq) , Keq = 8.5 x 10^-45
Cu/Zn = 0.525 V
after 1 drop NH3: 0.505 V
after 2 drops NH3: 0.435 V
Cu/Zn = 0.510 V
after 1 drop Na2S: 0.452 V
after 2 drops Na2S: 0.393 V
How many moles (of molecules or formula units) are in each sample?
0.2346 g C8H18
Express your answer to four significant figures.
nC8H18 =
R-134a is contained in a frictionless piston-cylinder device. The initial temperaure of the mixture is 39.37 oC. Over an hour 400 kJ of thermal energy is transferred to the roon which is maintained at a constant temperature of 22 oC. The condensation process is internally reversible. Determine the total entropy generation during this thermal energy process
Solution :
Given :
Initial temperature of the refrigerant is :
[tex]$T_i=39.37 ^ \circ C$[/tex]
= ( 39.37 + 273 ) K
= 312.3 K
Room which is maintained at constant temperature is :
[tex]$T_o=22 ^ \circ C$[/tex]
= (22+273) K
= 295 K
The thermal energy transferred to the room is :
Q = 400 kJ
= [tex]$400 \times 10^3 \ J$[/tex]
Therefore, the total entropy generation during the thermal energy process is :
[tex]$\Delta S =\left[\frac{-Q}{T_i}+ \frac{+Q}{T_i}\right]$[/tex]
Here, -Q = heat is leaving the system maintained at a temperature of [tex]$T_i$[/tex] K.
+Q = heat is entering the system maintained at a temperature of [tex]$T_o$[/tex] K.
Therefore, substituting the values :
[tex]$\Delta S =\left[\frac{-400\times 10^3}{312.3}+ \frac{400\times 10^3}{295}\right]$[/tex]
= [-1280.8197 + 1355.9322]
= 75.1125 J/K
= 0.0751125 kJ/K
= 0.075 kJ/K
Pls help which law is that???
Answer:
it is newtons third law
Explanation:
Answer:
Newton's Third Law: Action & Reaction
Calculate ΔG∘rxn at 298 K for the following reaction:
I2(g)+Br2(g)⇌2IBr(g)Kp=436
The change in free energy can help us to discover whether a reaction can be sponteanous or not. The change in free energy fro this reaction is -1.51 kJ/mol.
What is change in free energy?The change in free energy is referred to as that which determines the spontenity of a chemical reaction. For a spontenous reaction the change in free energy must be negative.
Now;
ΔG = -RTlnK
R = gas constant
T = temperature
K = equilibrium constant
So;
ΔG = -(8.314 * 298 * ln 436)
ΔG = -1.51 kJ/mol
Learn more about free energy: https://brainly.com/question/15319033
How many grams of BaPO3 are present in a 3.8 mole sample?
Explanation:
M(Bapo3) = 216m/mol
n = 3.8 mole
m = M × n = 216 × 3.8 = 820.8g
Which of the following is true about the reaction below. Bromide acts as a nucleophile in the first step of the reaction. Bromide acts as an electrophile in the first step of the reaction. Bromide acts a a nucleophile in the second step of the reaction. Bromide acts as an electrophile in the second step of the reaction.
Answer:
Option C
Explanation:
The complete question is attached herewith
Solution
The electropositive effect of carbocation depends on the degree of conjugate structure.
It is highest for a third degree structure as compared to a second degree structure and it is the least for the first degree structure.
In this reaction Br act as a negative ion and the structure has positive charge.
Thus, Br will act as a nucleophile in the second step of the reaction as in the first step H-Br will rearrange
Option C is correct