define refractive index with reference to the law of reflection​

Answer:

Atoms of a certain element contain a fixed amount of energy.

Explanation:

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such defines the structure of a chemical element.

Generally, these atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

Additionally, all the physical properties of a mineral result from the mineral's internal arrangement of atoms.

The consequence of atoms being a singular closed system is that atoms of a certain element contain a fixed amount of energy because the number of protons, neutrons and electrons are in a fixed proportion.

Answer:

See Explanation

Explanation:

Given

Steps: a - f

Table

[tex]\begin{array}{ccccccc}{cm} & {9} & {10} & {13} & {18} & {50} & {83} \ \\ {Age} & {10} & {20} & {30} & {40} & {50} & {60} \ \end{array}[/tex]

Note that: The question is a practical question and the result may differ base on individuals and environment.

So, I will pick up the question from how to determine the age of the eye after the distance between the eyes and the pencil has been established

In my case, the measurement is:

[tex]Length= 10.4[/tex]

Approximate

[tex]Length= 10[/tex]

From the above table, the corresponding age to 10cm is:

[tex]Age = 20cm[/tex]

If in your measurement, the length is approximately (for example):

[tex]Length = 9cm[/tex]

The age will be:

[tex]Age = 10[/tex]

Answer:

initial velocity is v = 4.95 m / s

Explanation:

To solve this exercise we use the projectile launch ratios, when the block leaves the hill its speed is horizontal, let's find the time it takes to fall to the other point.

Initial vertical velocity is zero

          y = y₀ + v_{oy} t - ½ g t²

          y-y₀ = 0 -1/2 g t²

          t = [tex]\sqrt{ \frac{ 2(y_o -y)}{g} }[/tex]

calculate

          t = [tex]\sqrt{ \frac{2 ( 70-50)}{9.8} }[/tex]

          t = 2.02 s

with this time we can substitute in the horizontal displacement equation

          x = v₀ₓ t

          v₀ₓ = x / t

suppose that the distance between the two points is x = 10 m

          v₀ₓ = 10 / 2.02

          v₀ₓ = 4.95 m / s

initial velocity is v = 4.95 m / s

Answer:

A solar flare as it may harm satellites and aircrafts flying near poles

Explanation:

Since solar flare is electro magnetic waves going to Earth the waves will mostly get absorbed by the north and south poles resulting in the aurora borealis, but if the solar flare is strong enough it may stop communications and engines in satellites and aircrafts and in result harming them

Answer:

A solar flare as it may harm satellites and aircrafts flying near poles

Explanation:

Answer:

BaF2

Explanation:

since you got the valence numbers just do the scissors move where you:

give the F the 2 and give the Ba the 1 so it be like

BaF2 here is the chemical compound

Answer:

P=W/t

W=Pt=0.3kWx50s=15KJ

We have that the energy is used by a blender that has a power of 0.3 kW and which takes 50 seconds is

W=15KJ

From the question we are told

Generally the equation for the Power   is mathematically given as

P=W/t

Therefore

W=Pt

W=0.3*50

W=15KJ

Therefore

The energy is used by a blender that has a power of 0.3 kW and which takes 50 seconds is

W=15KJ

For more information on this visit

https://brainly.com/question/21811998

Answer: barometer.

A cyclone is a storm or system of winds that rotates around a center of low atmospheric pressure. An anticyclone is a system of winds that rotates around a center of high atmospheric pressure.

machinery part :nickel or chromium

ornamentation and decoration pieces :silver and gold

processed food :tin coated iron can

bridges and automobiles :zinc metal

distilled water:bad conductor

Answer:

iron metal :chromium

machinery part :nickel or chromium

ornamentation and decoration pieces :silver and gold

processed food :tin coated iron can

bridges and automobiles :zinc metal

distilled water:bad conductor

Explanation:

Answer:

A

Explanation:

the balancing is correct in the first one

Answer:

 v = 27.28 m /s, θ = 63.9º

Explanation:

For this exercise we can approximate the movement to a projectile launch, let's analyze the situation.

* We must find the horizontal speed, for this we will find the descent time and the horizontal distance

* We look for the vertical speed

At the highest point the speed is horizontal

Let's find the time it takes for the kite to reach the ground

             y = y₀ + v_{oy} t - ½ g t²

             0 =y₀ + 0 -1/2 gt²

             t = [tex]\sqrt{ \frac{2y_o}{g} }[/tex]

             t = √(2 40/32)

             t = 2.5 s

to find the horizontal velocity we must know the horizontal distance, let's use trigonometry

          sin θ = y / l

          θ = sin⁻¹1 y / l

          θ = sin⁻¹ 40/50

          θ = 53.1º

therefore the horizontal distance is

          x = l cos 53.1

          x = 50cos 53.1

          x = 30 m

let's use the equation

          x = v₀ₓ t

          v₀ₓ = x / t

          v₀ₓ = 30 / 2.5

          v₀ₓ = 12 m / s

we look for the vertical component of the velocity

          v_y = v_{oy} - g t

          v_y = 0 - g t

          v_y = - 9.8 2.5

          v_y = -24.5 m / s

the negative sign indicates that the speed is directed downwards, because it is the arrival point, as they indicate that there is no friction, the exit speed is the same, worse with the opposite sign

We already have the two components of the velocity, let's use the Pythagorean theorem to find the modulus

          v = [tex]\sqrt{v_x^2 + v_y^2}[/tex]

          v = [tex]\sqrt{12^2 + 24.5^2}[/tex]

          v = 27.28 m /s

we use trigonometry for the angle

          tan θ = v_y / vₓ

          θ = tan⁻¹ v_y / vₓ

          θ = tan⁻¹ 24.5 / 12

          θ = 63.9º

Answer:

Dead

Explanation:

there are no blood vessels in the epidermis so the cells get their nutrients by diffusion from the connective tissue below

Answer:

Distance S = 11.77 m (Approx.)

Explanation:

Given:

Time t = 1.55 Second

Gravity acceleration = 9.8 m/s²

Find:

Distance S

Computation:

S = ut + (1/2)(g)(t)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

Distance S = 11.77 m (Approx.)

Answer:

Explanation:

From the given information:

Distance [tex]d_i = 4.8 \times 10^{10} \ m[/tex]

Speed of the comet [tex]V_i = 9.1 \times 10^{4} \ m/s[/tex]

At distance [tex]d_2 = 6 \times 10^{12} \ m[/tex]

where;

mass of the sun = [tex]1.98 \times 10^{30}[/tex]

[tex]G = 6.67 \times 10^{-11}[/tex]

To find the speed [tex]V_f[/tex]:

Using the formula:

[tex]E_f = E_i + W \\ \\ where; \ \ W = 0 \ \ \text{since work done by surrounding is zero (0)}[/tex]

[tex]E_f = E_i + 0 \\ \\ K_f + U_f = K_i + U_i \\ \\ = \dfrac{1}{2}mV_f^2 + \dfrac{-GMm}{d^2} = \dfrac{1}{2}mV_i^2+ \dfrac{-GMm}{d_i} \\ \\ V_f = \sqrt{V_i^2 + 2 GM \Big [ \dfrac{1}{d_2}- \dfrac{1}{d_i}\Big ]}[/tex]

[tex]V_f = \sqrt{(9.1 \times 10^{4})^2 + 2 (6.67\times 10^{-11}) *(1.98 * 10^{30} ) \Big [ \dfrac{1}{6*10^{12}}- \dfrac{1}{4.8*10^{10}}\Big ]}[/tex]

[tex]\mathbf{V_f =53.125 \times 10^4 \ m/s}[/tex]

Answer:

D

Explanation:

A is wrong bc best DNA will survive

B is wrong because organism adapt not only for food source but to be able to live in the environment as well

C is wrong because single celled organisms don't adapt

Answer:

false I think

Explanation:

hope that help

so it's not divided in 3 regions

Answer:

w = 2 rad / s  counterclockwise

Explanation:

This is an exercise in angular momentum, we define a system formed by the two wheels in such a way that the torques during contact have been internal and the angular moeoto0o is conserved

            L₀ = L_f

We assume that the counterclockwise rotations are positive, let's look for the initial moment before the collision

           L₀ = I w₁ + I w₂

where the angular velocity of the first wheel is w₁ = - 2.00 rad / s and the angular velocity of the second wheel is w₂ = 6.0 rad / s

As the wheels collide and remain in unity, the final angular momentum after the collision

            I_total = 2 I

            L_f = I_total w

we substitute

            I w₁ + I w₂ = I_total w

            w = [tex]\frac{I w_1 + Iw_2}{I_{total} }[/tex]

             w = [tex]\frac{I \ (w_1+w_2)}{2 \ I}[/tex]

             w = [tex]\frac{w_1 +w_2}{2}[/tex]

let's calculate

             w = [tex]\frac{-2.0 + 6.0}{2}[/tex]

             w = 2 rad / s

the positive sign indicates that the rotation is counterclockwise

The final angular velocity will be 2 rad /s counterclockwise. The pace of transition of angular displacement is described as angular velocity.

The rate of change of angular displacement is defined as angular velocity and it is stated as follows:

ω = θ t

The given data in the problem is;

[tex]\omega_1[/tex] is the angular velocity of wheel 1= 2.0 rad/s

[tex]\omega_2[/tex]  is the angular velocity of wheel 2= 6.0 rad/s

[tex]\rm \omega_f[/tex]  is the final angular velocity=?

As the wheel collides the initial momentum is equal to the final momentum;

Momentum before collision

[tex]\rm L_0 = I \omega_1 + I \omega_2[/tex]

Momentum after the collision when the two-wheel becomes one wheel;

[tex]\rm \I_ {total }= 2 I \\\\ L_f= I_{total}\omega \\\\[/tex]

From the conservation of momentum principle;

[tex]\rm L_i = L_f \\\\ I \omega_1 + I \omega_2 = I_{total}\omega \\\\ \rm \omega= \frac{ I \omega_1 + I \omega_2 }{2I} \\\\ \omega = \frac{\omega_1 + \omega_2}{2} \\\\[/tex]

[tex]\omega=\frac{-2.0+ 6.0}{2} \\\\ \omega=2\ rad/sec[/tex]

Hence the final angular velocity will be 2 rad /s counterclockwise.

To learn more about the angular velocity refer to the link;

https://brainly.com/question/1980605

Answer:

I hypothesis that the motion involving the balls in the experiment were moving to create data.

Explanation:

I hope this helps!

Answer:

Option 2

Explanation:

As per the relation between the distance of the galaxy and shifting of the light of the galaxy towards any specific wavelength of the electromagnetic spectrum, a galaxy at great distance shifts more towards the red spectra that has the highest wavelength.

Thus, this observation give details about the distance of the galaxy from earth.

Answer:

b

Explanation:

Answer:

F' = 9F

Explanation:

The complete question is "Objects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the charge of Object 2 is tripled, then the new electrostatic force will be _____ units".

The electric force is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

If F = 36 units,

[tex]36=\dfrac{kq_1q_2}{r^2}\ ...(1)[/tex]

If charges are tripled, q₁' = q₂' = 3q₁ and 3q₂

So,

[tex]F'=\dfrac{kq_1'q_2'}{r^2}\\\\F'=\dfrac{k\times 3q_1'\times 3q_2'}{r^2}\\\\F'=9\times \dfrac{kq_1'q_2'}{r^2}\\\\F'=9F[/tex]

So, the new force becomes 9 times of the initial force.

Answer:

a). 53.78 m/s

b) 52.38 m/s

c) -75.58 m

Explanation:

See attachment for calculation

In the c part, The negative distance is telling us that the project went below the lunch point.

A biome, in simple terms, is a set of ecosystems sharing similar characteristics with their abiotic factors adapted to their environments.

Answer:

Explanation:

radius of circle r = 0.9 m.

(a ) In a motion on circular path , work done is zero because force ( centripetal force ) acts perpendicular to displacement .

( b )

Tension in string T = m ω²r

Putting the values

60 = .072 x ω² x 0.9

ω² = 926

ω = 30.4 rad /s

angle made in 20 revolutions θ = 20 x 2π = 126.6 rad

time taken = θ / ω

= 126.6 / 30.4

= 4.16 s .

The angle of deviation is defined as the angle which is obtained from the difference between the angle of incidence and the angle of refraction created by the ray of light travelling from one medium to another that has a different refractive index.  I hope this helps you

Answer:

the resistance of the wire has no effect on the brightness of the bulb.

Explanation:

Let's apply ohm's law for your light bulb circuit plus wires plus switch

             V = I R_{bulb} + I R_ {wire}

the current in a series circuit is constant

             V = I (R_{bulb} + R_{wire})

To know the effect of the wires on the brightness of the bulb, we must look for the value of the typical resistance of these elements.

Incandescent bulb

Power 60 W

let's use the power ratio

            P = V I = V2 / R

            R = V2 / P

the voltage value for this power is V = 120 V

            R = 120 2/60

            R_bulb = 240 Ω

Resistance of a 14 gauge copper wire (most used), we look for it on the internet

            R = 8.45 Ω/ km

in a laboratory circuit approximately 2 m is used, so the resistance of our cable is

            R = 8.45 10⁻³ 2

            R_wire = 0.0169 Ω

let's buy the two resistors

            R_{bulb} = 240

            R_{wire} = 0.0169

            [tex]\frac{R_{bulb} }{R_{wire} } = \frac{240 }{ 0.0169}[/tex]

              [tex]\frac{ R_{bulb} }{ R_{wire} } = 1.4 \ 10^4[/tex]

therefore resistance of the bulb is much greater than that of the wire, therefore almost all the power is dissipated in the bulb.

In summary, the resistance of the wire has no effect on the brightness of the bulb.

Answer:

Explanation:

Maximum emf produced = nωAB. where n is no of turns , A is area , B is magnetic field and ω is angular velocity .

n = 100 , A = .035 m²

B = .05 T

ω = 2π f , f is no of revolution per second by coil

= 2 x 3.14 x 6 x 3

= 113.04 rad /s

Maximum emf produced = 100 x 113.04 x .035 x .05

= 19.78  volt .

Answer:

B as distance increase force decrease, but it is not a linear relationship.