DeltaMath -
Evaluate the function.

Answer:

(-1)=10

(10)= -54

(5)= -26

Step-by-step explanation:

h(-1)=4-6(-1)

h(-1)=4 (-6*-1)

h(-1)=4+6

h(-1)=10

h(10)=4-6(10)

h(10)=4 (-6*10)

h(10)=4-60

h(10)=-54

h(5)=4-6(5)

h(5)=4 (-6*5)

h(5)=4-30

h(5)=-26

Hope this helps.

From today 36 days later, all five will be tutoring again.

As we have given that,

Andrea is able to tutor every second school day

Roberto is able to tutor every third school day.

Charlene is able to tutor every fourth school day.

Maria is able to tutor every sixth school day.

Nguyen is able to tutor every ninth school day.

So, as a result, our working days are 2, 3, 4, 6, and 9 days.

Today's tutoring session will involve all five participants.

Next time, all five tutors will work together = LCM (2, 3, 4, 6, 9) = 36

Therefore, from today 36 days later, all five will be tutoring again.

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Answer:

135 minutes

Step-by-step explanation:

18 divided by 4

4.5 pages per minute

4.5 times 30 = 135

Answer: 135 minutes

Step-by-step explanation: 18 times 30, then divide by 4

Andrew has 7 dimes and 15 quarters, as obtained from the system of linear equations so formed.

A system of linear equations is a set of two or more linear equations. Linear equations refer to the equations that involve two or more variables in the form of "ax + b".

Given:

To find: Number of dimes and quarters.

Finding:

=> By unitary method, $4 = 4(100) = 400 cents

d + q = 22 (Number of coins) => d = 22 - q (eqn1)

and 10d + 25q = 400 (amount of coins)

=> 10 ( 22 - q ) + 25q = 400

=> 220 - 10q + 25q = 400

=>  15q = 400 - 220 = 180

=> q = 12, i.e., number of quarters = 22 upon the solving of this system of linear equations.

On substituting the value of q in eqn1, we get: d = 22 - 15 = 7, i.e., number of dimes = 7.

Hence, Andrew has 7 dimes and 15 quarters, as obtained from the system of linear equations so formed.

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Answer:

32/40

Step-by-step explanation:

First divide 40 by 15

to check denominator, calculate 15 * the ans and for numerator as well

The equation of the given line passes through the point (2,9) y = 4x + 1.

The slope of a line indicates its steepness. The slope is determined mathematically as "increase over run" (change in y divided by change in x).

The conventional form of a line equation is ax + by + c = 0. Here, the coefficients are a and b, the variables are x and y, and the constant term is c. It is a one-degree equation with variables x and y. The coordinates of both the point on the line that appears in the coordinate plane are represented by the values of x and y.

m = 4

equation of the line = y = mx + c

substituting the value of m = 4

y = 4x + c

the point (2,9):

putting the points in the line of the equation:

x = 2

y = 9

So,

y = mx + c

9 = 4 * 2 + c

9 = 8 + c

c = 1

The equation of the given line y = 4x + 1.

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Answer:

y=4x+1

Step-by-step explanation:

y-y1=m(x-x1)

y-9=4(x-2)

y=4x-8+9

y=4x+1

The fraction of those who were cast and got major roles is 1/5.

The number of the students who were cast out of the Ninety students auditioned  for the school play is calculated as follows;

Total number of students = 90

Number of students who were cast = ¹/₃ x 90 = 30

Number of students who go major role = 6

The fraction of those who were cast and got major roles is calculated as follows;

fraction of students who got major role = 6/30

fraction of students who got major role =  1/5

Thus, the fraction of those who were cast and got major roles is 1/5.

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Answer:

Total number of students = 90

Number of students who were cast = ¹/₃ x 90 = 30

Number of students who go major role = 6

fraction of students who got major role = 6/30

fraction of students who got major role = 1/5

1/5 = 0.2

Answer:53 shares

Step-by-step explanation:

If we assume the price remained constant, then the number of shares increased by 6%.

 (50 shares)(1 +6%) = 53 shares

The man then owned 53 shares

The number of laps that Kevin can run is 5 laps.

From the information, Kevin can run a lap around the field in 4-6 minutes and he has 30 minutes to run.

Therefore, the number of laps that he can run will be:

= Total minutes / Time taken for each lap

= 30 minutes / 6

= 5 laps.

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Answer:

15*2/3=10

10*2/3=20/3

20/3*2/3=40/9

40/9*2/3=80/27

80/27*2/3=160/81

160/81*2/3=480/243

480/243*2/3=960/729

960/729*2/3=1920/2187.

=1920/2187

The 9th term of the geometric sequence will be 1280 / 2187.

A series of non-zero integers where every term after the first is obtained by increasing the one before it by a constant, non-zero value known as the scale factor.

Let a₁ be the first term and r be the common ratio. Then the nth term of the geometric sequence is given as,

aₙ = a₁ · (r)ⁿ⁻¹

The sequence is given below.

15, 10, 20/3

The first term is 15. And the common ratio is given as,

r = 10 / 15

r = 2 / 3

The 9th term of the geometric sequence is given as,

a₉ = 15 · (2/3)⁹⁻¹

a₉ = 15 · (2/3)⁸

a₉ = 15 · 256/6561

a₉ = 1280 / 2187

The 9th term of the geometric sequence will be 1280 / 2187.

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The table that shows the growth rate of Plant 1 which is 4 cm/week, and the graph that gives the growth rate of Plant 2 as 2 cm/week gives the correct option as C;

C. I think that plant 1 grows more per day and I disagree with Aaliyah's reasoning

A proportional relationship between two variables is one in which one variable is a multiple of the other.

The possible table in the question is presented as follows;

Plant 1

The values on the graph are;

Plant 2

The rate, r1, of growth of Plant 1 is therefore;

r1 = 8 cm/(2 weeks) = 4 cm/week

The rate, of growth, r2, of plant 2 is found as follows;

r2 = 4 cm/(2 weeks) = 2 cm/week

Given that Plant 1 grows faster at 4 cm/week, than Plant 2, that grows at 2 cm/week, the correct statement is since Plant 1 grows 4 cm/week and Plant 2 grows 2 cm/week, Plant 1 grows more per day.

The correct option is therefore;

C. I think that plant 1 grows more per day and I disagree with Aaliyah's reasoning

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Answer: y<3x-4

Step-by-step explanation:

[tex](0,-4) \ \ \ \ \ \ (1,-1)[/tex]

                           The equation of the line

                                 [tex]\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }[/tex]

[tex]\displaystyle\\x_1=0\ \ \ \ x_2=1\ \ \ \ y_1=-4\ \ \ \ y_2=-1\\Hence,\\\frac{x-0}{1-0} =\frac{y-(-4)}{-1-(-4)} \\\\\frac{x}{1} =\frac{y+4}{-1+4} \\x=\frac{y+4}{3}[/tex]

Умножьте обе части уравнения на 3:

[tex]3x=y+4\\3x-4=y+4-4\\3x-4=y[/tex]

Thus, y<3x-4

Thus 3 bushels of pears can be acceptable term of trade for bushels of pears.

Opportunity cost of 1bushel of apple for Carlos=2pears    

Opp. Cost of 1 bushles of apple for Donna=4pears

Thus ,

Term of trade acceptable to both for one bushels of apple is 2-4 bushels of pears

a. The required equations are  6a+9p = 9.75 and 4a+5p = 5.75 .

b. The solution is given in the attached picture.

c. Apples are 1/2 and Peaches are 0.75

d. Solving the equations by putting the values

Let's take equation 1

6a+9p = 9.75

6 (1/2) + 9 (0.75) = 9.75

So equation satisfies both sides

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Answer:

The answer is 1

Step-by-step explanation:

On a graph, it would be at the plot point (3,1)

Answer

70.000 в  10 раз больше 7.000

Step-by-step explanation:

The approximation of 2798.01 to 2 significant figures is 2800

The expression is given as

2798.01

The approximation is given as

2 significant figures

The above means that we approximate the given expression such that only 2 significant figures are left

In this case, the 2 significant figures in the expression 2798.01 are 2 and 7

So, we start the approximation from 9

When 9 is approximated, the expression becomes

2798.01 = 2800

Hence, the approximation of 2798.01 to 2 significant figures is 2800

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The mean exam score of the first group is [tex]35.3[/tex]

The mean exam score for the second group is [tex]34.1[/tex]

but [tex]35.3[/tex] is greater than [tex]34.1[/tex]

Standard deviation of the first group is [tex]3.6[/tex]

Standard deviation of the second group is [tex]0.5[/tex]

but [tex]3.6[/tex] is greater than [tex]0.5[/tex].

(a) We can draw a conclusion that the score of the second group is more evenly distributed.

(b) The second group has more people get in - person interviews because  [tex]3.6\geq 0.6[/tex], so the scores of the exam for the second group are all close to 34.1. On the contrary, the score of exams for the first group is extreme polarization.

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Answer: - 10

Step-by-step explanation: -2 to the 2nd power is - 4. And 3 * - 2 is -6. So -4 + -6 = - 10.

I hope I have helped and I hope you have a wonderful day!

Answer:

awsome

Step-by-step explanation:

565

The result of the given expression f(x) + f(x) + f(x) = 3x².

A quadratic function is one of the following: f(x) = ax² + bx + c, where a, b, and c are positive integers and an is not equal to zero.

As per the given question;

f(x) = x²

Now, we have to estimate the value of the function;

= f(x) + f(x) + f(x)

Substitute the value of f(x).

= x² + x² + x²

= 3x²

Thus, the value of the given function is found as 3x².

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[tex]3(x - 2) = 6 \\ x - 2 = \frac{6}{3} \\ x - 2 = 2 \\ x = 2 + 2 \\ x = 4[/tex]

Answer:

Step-by-step explanation:

x =4

We must deposit (B) $6,301.70 today to withdraw $10,000 in 6 years.

To find the amount:

Given -

Estimate the initial deposit required to obtain $10,000 in 6 years:

Therefore, we must deposit (B) $6,301.70 today to withdraw $10,000 in 6 years.

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The correct question is given below;
You can earn 8 percent interest, compounded annually. How much must you deposit today to withdraw $10,000 in 6 years?

A. $5,402.69

B. $6,301.70

C. $6,756.76

D. $8,432.10

E. $9,259.26

The value of the given expression (5 x − 2 y) = 12.

The substitution technique is an algebraic approach for solving simultaneous linear equations. In this procedure, the value of one variable through one equation is substituted in the second equation, as the name implies.

Three phases are involved in the substitution method: Solve one equation for one of the variables. Substitute (plug-in) this expression in the other equation as well as solve. Replace the value in the original equation to obtain the equivalent variable.

5 x − 2 y

x = 2;

y = -1;

substituting the value in the given equation:

5 x − 2 y

5(2) - 2(-1)

5(2) - (-2)

5(2) +2

10+2

12

The value of the given expression (5 x − 2 y) = 12

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The answer for the following algebraic expression [tex]10y-3(y+5)[/tex] is Option C [tex]7y-15[/tex].

According to the given question statement, We are supposed to simplify the given algebraic expression [tex]10y - 3(y + 5)[/tex]

Solution is as follows:

[tex]10y - 3(y + 5)\\= 10y-3(y)-3(5)\\\[/tex]

[tex]=10y-3y-15[/tex]

[tex]=7y-15[/tex]

Hence [tex]7y-15[/tex] is our final answer.

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Two possible lengths for CD if C, D, and E are collinear, CE 17.9 cm, and DE = 8.2 cm is 12.3cm and 19.3cm.

In space, a point is a precise position or location. It is possible to depict it in relation to a coordinate system and its origin. It has no length and is a zero-dimensional entity.

A line is made up of an unlimited number of points that form a straight line. One-dimensional objects like lines lack both thickness and width. It stretches forever in both directions. An endpoint and a beginning point define a line segment, which is a component of a line. A linear equation can be used to depict a line.

D is between C and E

_   _   _

C  D   E

CD =CE-DE

CD=15.8-3.5cm

CD=12.3 cm

E is between D and C

_  _  _

D  E C

CD=CE+DE

CD=15.8+3.5cm

=19.3cm

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By applying the criterion of the law of cosine, the triangle presented in the picture is possible.

Herein we find an hypothetical triangles with all side lengths known.  A criterion is using the law of cosine, a possible triangle has cosine values between - 1 and 1. Then, we proceed to check for each side:

cos A = - (a² - b² - c²) / (2 · b · c)

cos A = - (25² - 2² - 24²) / (2 · 2 · 24)

cos A = - 0.469

cos B = - (b² - a² - c²) / (2 · a · c)

cos B = - (2² - 25² - 24²) / (2 · 25 · 24)

cos B = 0.998

cos C = - (c² - a² - b²) / (2 · a · b)

cos C = - (24² - 25² - 2²) / (2 · 25 · 2)

cos C = 0.53

Since the law of cosine gives realistic results, then the triangle presented in the picture is possible.

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The output value of (y) will be 1 .

We have given an exponential function [tex]y=10.5^x[/tex]     ......(1)

It is given that input value is 0 which means that replace the x with the input value in the given function.

Putting x = 0 in the equation (1) , we get

  [tex]y=10.5^0[/tex]

Value of any number raised to power zero is always one .

   [tex]y=1[/tex]

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The inequalities that represent constraints for the situation will be:

x+y ≤ 12

x >= 3

y >= 6

Let x represent the loaves of bread

Let y represent the number of eggs.

From the information, Each egg costs $0.20 and each loaf of needs at least 6 eggs and 3 loaves of bread.

Therefore,

x >= 3

>= 3y >= 6

Also, Dwayne can spend no more than $12 at the grocery store buying loaves of bread and eggs. This will be x+y ≤ 12.

The correct options are C, D, and F.

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