Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4

V = 3.9 L

Explanation:

Given:

T = 23°C + 273 = 296K

n = 0.16 mol He

P = 101 kPa = 0.997 atm

R = universal gas constant = 0.08205 L-atm/mol-K

V = ?

Using the ideal gas law,

PV = nRT

V = nRT/P

= (0.16 mil He)(0.08205 L-atm/mol-K)(296K)/(0.997 atm)

= 3.9 L

Answer:

Amount of iron fillings in mixture = 60 mg

Explanation:

Given:

Total mass of mixture = 100 mg

Amount of salt in mixture = 10 mg

Amount of sand in mixture = 30 mg

Find:

Amount of iron fillings in mixture

Computation:

Using Law of Conservation of mass;

Total mass of mixture = Amount of salt in mixture + Amount of sand in mixture + Amount of iron fillings in mixture

100 = 10 + 30 + Amount of iron fillings in mixture

100 = 40 + Amount of iron fillings in mixture

Amount of iron fillings in mixture = 100 - 40

Amount of iron fillings in mixture = 60 mg

Answer:the final mass of copper is  3.84 g. There was an increase in mass of 1.84 g from the initial mass of 2.0 g.

Explanation:

Answer:

The answer is B

Brainliest please!

Answer:

What is

the volume of the balloon when the temperature is 310K?

Answer:

a) Superficial fluid

b)  5.9*10^-2 atm

c) Gas

d) Liquid

e) Solid

Explanation:

a)  At temperatures above 405.5 K and pressures above 111.5 atm, NH3 is a superficial fluid because liquid and gases does not exit at temperature and pressure greater than  405.5 K and  111.5 atm

b) NH3 does not exist as a liquid at pressures below  5.9*10^-2 atm , That is below the triple point there is existence of liquid

c)  NH3 is a Gas at 5.90×10^-2 atm and 249.5 K.

d) NH3 is a  Liquid  at 1.00 atm and 236.0 K. because pressure and temperature ( standard ) is between the given normal melting and boiling point

e) NH3 is a solid at 24.6 atm and 185.6 K . because the pressure here is more than that of triple point while the temperature is lesser

Answer:

Explanation:...

Answer:

I’m pretty sure it’s C

Explanation:

AP Ex

Answer:

The answer is "2%"

Explanation:

Equation:

[tex]HNO_2\ (aq) \leftrightharpoons H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\ K_a = 4.0\times \ 10^{-4}[/tex]

[tex]H^{+}=?[/tex]

Formula:

[tex]Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}[/tex]

Let

[tex][H^{+}] = [NO_2^{-}] = x[/tex] at equilibrium

[tex]x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \ M\\\\[/tex]

therefore,

[tex][H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M[/tex]

Calculating the % ionization:

[tex]= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\[/tex]

The approximate percent ionization of HNO₂ in a 1.0 M HNO₂ (aq) solution is 2%.

% ionization of any compound will be calculated as follow:

% ionization = ([ion]/[acid or base]) ₓ 100

Given chemical reaction with ICE table will be represented as:

                           HNO₂(aq) → H⁺(aq) + NO₂⁻(aq)

initial                          1                0             0

change                      -x               +x           +x

equilibrium              1-x                x             x

Equilibrium constant will be represented as:
Ka = [H⁺][NO₂⁻] / [HNO₂]

Acid dissociation constant for HNO₂ = 4×10⁻⁴

Putting all values in the above equation, we get

4×10⁻⁴ = x² / 1-x

Value of changeable quantity is very less, so we neglect from the concentration of HNO₂.

4×10⁻⁴ = x²

x = 2 × 10⁻²

So, the concentration of H⁺ ion = 2 × 10⁻²M

Now we put all these values in the % ionization equation, we get

% ionization = (0.02/1) × 100 = 2%

Hence , % ionization is 2%.

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Answer:

9 moles of NaNO3 is obtained

Explanation:

The balanced chemical reaction equation for the reaction is;

Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3

Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.

1 mole of Al(NO3)3 yields 3 moles of NaNO3

4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3

Also,

3 moles of NaCl yields 3 moles of NaNO3

9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3

Hence, NaCl  is the limiting reactant and 9 moles of NaNO3 is obtained.

9 moles of NaNO₃ is obtained.

[tex]Al(NO_3)_3 + 3NaCl-----> 3NaNO_3 + AlCl_3[/tex]

From the reaction, it is seen that the limiting reactant yields the least amount of NaNO₃.

1 mole of Al(NO₃)₃ yields 3 moles of NaNO₃

4 moles of Al(NO₃)₃ yields 4 * 3/1 = 12 moles of NaNO₃

Also,

3 moles of NaCl yields 3 moles of NaNO₃

9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO₃

Hence, NaCl  is the limiting reactant and 9 moles of NaNO₃ is obtained.

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Answer:

B. The mass is greater after the reaction because the number of

atoms increases.

Answer:

Kp = 7.4727

Explanation:

Let's write the balanced equilibrium reaction:

2NH₃ <-------> N₂ + 3H₂     Kp = ??

Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:

         2NH₃ <-------> N₂ + 3H₂  

I.         4,5                 0        0

C.       -2x                +x     +3x

E.        4,5-2x            x       3x

According to this chart, the Kp expression should be:

Kp = (PH₂)³ * (PN₂) / (PNH₃)²   (1)

The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:

Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²

Kp = 39.5307 / 5.29

Hope this helps

Answer:

6

Explanation:

lol

Answer:

0.29 J/g.°C

Explanation:

Step 1: Given data

Step 2: Calculate the temperature change (ΔT)

ΔT = 99.4 °C - 92.6 °C = 6.8 °C

Step 3: Calculate the specific heat of the substance (c)

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C

Answer:

A

Explanation:

Answer:

C

Explanation:

Pretty sure!

Answer: 2.20 g Pb

They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:       239.27   32.00        207.2

           2PbS   +   3O₂   ⟶  2Pb   +   2SO₃

m/g:      2.54        1.88

Answer:

Meaning, Advantages & Disadvantages of - Osmosis, Multiflash Distillatiob

Explanation:

Advantages - It assists equalising concentration of solute on two sides of membrane. Reverse Osmosis is used for efficient water softening, it is easy to maintain.

Disadvantages - It needs a lot of energy. A lot of pressure is required for deionisation. Water acidity level increases, as minerals get deionised.

Advantages - Its Cost efficient , distillation uses waste heat. It has High gain output ratio. Quality of feedwater is less significant, compared to reverse osmosis.

Disadvantages - It has high operating cost in case of waste heat unavailability. High temperature imply high corrosion & scale formation.

Answer:

[tex]m_P=4.75x10^{19}g\ P[/tex]

Explanation:

Hello there!

In this case, according to the given atoms of phosphorous, it is possible to calculate the mass of those atoms by bearing to mind the definition of mole in terms of the Avogadro's number; which refers to the mass and amount of particles in one mole of any element as equal to the atomic mass and the Avogadro's number respectively:

[tex]1 molP=6.022x10^{23}atoms\ P=30.97gP[/tex]

Which is used to obtain the required mass of P:

[tex]m_P=9.23x10^{41}atoms\ P*\frac{30.97g P}{6.022x10^{23}atoms\ P}\\\\m_P=4.75x10^{19}g\ P[/tex]

Regards!

To make 200 mL of a 10% by volume solution, add 20 mL corn syrup to water.

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A 500.0 g sample of aluminum, initially at 25.0 degrees, absorbs heat from its surroundings and reaches a final temperature of 90.7 degrees. 32.62245 kJ heat has been absorbed by the sample.

The term specific heat is defined as the amount of heat required to increase the temperature of 1 gram of a substance 1 degree Celsius (°C).

To calculate the amount of heat absorbed by the sample, use the formula:

Q = mcΔT

where Q is the amount of heat absorbed by the sample, m is the mass of the sample, c is the specific heat of aluminum, and ΔT is the change in temperature of the sample.

Substituting the given values into the formula, we get:

Q = 500.0 g × 0.9930 J/g·K × (90.7°C - 25.0°C)

Q = 500.0 g × 0.9930 J/g·K × 65.7 K

Q = 32,622.45 J

To convert the result to kilojoules (kJ), we divide by 1000:

Q = 32.62245 kJ

Thus, the amount of heat absorbed by the sample is 32.6 kJ.

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Answer:

[tex]T_2=400.73K[/tex]

Explanation:

From the question we are told that:

Activation energy [tex]E_a= 51.02 kJ/mol.=>51.02*10^3J/mol[/tex]

Reaction Ratio [tex]\triangle K=4.50[/tex]

Initial Temperature [tex]T_1=365K[/tex]

Generally the equation for Final Temperature [tex]T_2[/tex] is mathematically given by

 [tex]log \triangle K=\frac{E_a}{2.303R}*(\frac{T_2-T_1}{T_1T_2})[/tex]

Where

 [tex]R=Gas constant[/tex]

 [tex]R =8.3143[/tex]

Therefore

 [tex]log 4.50=\frac{51.2*10^3}{2.303*8.31432}*(\frac{T_2-365}{365*T_2})[/tex]

 [tex]log 4.50=7.328*\frac{T_2-365}{T_2}[/tex]

 [tex]0.0892=\frac{T_2-365}{T_2}[/tex]

 [tex]0.0892T_2=T_2-365[/tex]

 [tex]365=T_2-0.0892T_2[/tex]

 [tex]365=0.91T_2[/tex]

 [tex]T_2=\frac{365}{0.91}[/tex]

 [tex]T_2=400.73K[/tex]

Answer:

0.125 moles of solute

Explanation:

The formula for molarity (M) is moles of solute/liters of solution. First, convert 250 mL into liters:

250 mL/1 * 1 L/1000 mL = 0.25 L.

Then, plug in the values of m/L = M

m/0.25 = 0.5

Solve for moles (m). You would multiply 0.5 by 0.25.

m = 0.125

Lastly, if you'd like to check it and see if it's correct, do 0.125/0.25, and you should get 0.5 M.

Answer:

[tex]\boxed {\boxed {\sf 0.125 \ mol }}[/tex]

Explanation:

Molarity is a measure of concentration. It is the moles of solute per liters of solution.

[tex]molarity = \frac{ moles \ of \ solute}{ liters \ of \ solution}[/tex]

We know the solution has a molarity of 0.5 M or moles per liter. There are 250 milliliters of solution. First, we need to convert to liters. 1 liter is equal to 1000 milliliters.

Now we can substitute the values we know into the formula.

[tex]0.5 \ mol/L= \frac{ x}{0.25 \ L}[/tex]

Since we are solving for the moles of solute, we need to isolate the variable x. It is being divided by 0.25 L. The inverse of division is multiplication. Multiply both sides by 0.25 L.

[tex]0.25 \ L *0.5 \ mol/L= \frac{ x}{0.25 \ L}*0.25 \ L[/tex]

[tex]0.25 \ L * 0.5 \ mol/L =x[/tex]

[tex]0.25 * 0.5 \ mol=x[/tex]

[tex]0.125 \ mol =x[/tex]

0.125 moles of sodium phosphate are needed to make 250 mL of a 0.50 M solution.

Answer:

100 g

Explanation:

Primero hay que calcular el número requerido de moles de NaOH, usando la definición de molaridad:

Ahora hay que convertir 2.5 moles de NaOH en gramos, usando su masa molecular:

Se requieren 100 gramos de NaOH.