Determine the volume (L) of nitrogen monoxide gas that is created at STP when 32.2 g

of solid copper reacts with excess nitric acid.

3Cu(s) + 8HNO3(aq) — 3Cu(NO3)2 (aq) + 4H2O(1) + 2NO(g)

Answers

Answer 1

Taking into account the reaction stoichiometry and STP conditions, the volume of nitrogen monoxide gas that is created at STP when 32.2 g of solid copper reacts with excess nitric acid is 7.5677 L.

Reaction stoichiometry

The balanced reaction is:

3 Cu(s) + 8 HNO₃(aq) → 3 Cu(NO₃)₂ (aq) + 4 H₂O(l) + 2 NO(g)

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

Cu: 3 molesHNO₃: 8 molesCu(NO₃)₂: 3 molesH₂O: 4 moles NO: 2 moles

The molar mass of the compounds is:

Cu: 63.54 g/moleHNO₃: 63 g/moleCu(NO₃)₂: 187.54 g/moleH₂O: 18 g/moleNO: 30 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cu: 3 moles× 63.54 g/mole= 190.62 gramsHNO₃: 8 moles× 63 g/mole= 504 gramsCu(NO₃)₂: 3 moles ×187.54 g/mole= 562.62 gramsH₂O: 4 moles ×18 g/mole= 72 gramsNO: 2 moles ×30 g/mole= 60 grams

STP conditions

The STP conditions refer to the standard temperature and pressure, which values are 0 °C and 1 atmosphere and are reference values for gases. In these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Moles of NO formed

The following rule of three can be applied: if by reaction stoichiometry 190.62 grams of Cu form 2 moles of NO, 32.2 grams of Cu form how many moles of NO?

moles of NO= (32.2 grams of Cu× 2 moles of NO)÷ 190.62 grams of Cu

moles of NO= 0.3378 moles

Then, 0.3378 moles of NO are formed.

Volume of NO created

Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of NO occupies a volume of 22.4 liters, 0.3378 moles occupies how much volume?

volume= (0.3378 moles× 22.4 L)÷ 1 mole

volume= 7.5677 L

Finally, the volume of NO created is 7.5677 L.

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The decomposition of ethanol (C2H5OH) on an alumina (Al2O3) surface C2H5OH1 g2 h C2H4 1 g2 1 H2O1 g2 was studied at 600 K. Concentration versus time data were col- lected for this reaction, and a plot of [A] versus time resulted in a straight line with a slope of 24.00 3 1025 mol/L  s. a. Determine the rate law, the integrated rate law, and the value of the rate constant for this reaction. b. If the initial concentration of C2H5OH was 1.25 3 1022 M, calculate the half-life for this reaction. c. How much time is required for all the 1.25 3 1022 M C2H5OH to decompose?

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The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

Let's consider the decomposition of ethanol on an alumina surface.

C₂H₅OH(g) ⇒ C₂H₄(g) + H₂O(g)

The plot of [A] vs time (t) resulted in a straight line, which indicates that the reaction follows zero-order kinetics.

The slope, 24.00 × 10²⁵ M/s, represents the rate constant, k.

What is zero-order kinetics?

It is a chemical reaction in which the rate of reaction is constant and independent of the concentration of the reacting substances

The rate law for zero-order kinetics is:

rate = 24.00 × 10²⁵ M/s

The integrated rate law for zero-order kinetics is:

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

What is the half-life?

Is the time for the amount of substance to decrease by half.

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, we can calculate the half-life [t(1/2)] using the following formula.

t(1/2) = [C₂H₅OH]₀ / 2 × k

t(1/2) = (1.25 × 10²² M) / 2 × (24.00 × 10²⁵ M/s) = 2.60 × 10⁻⁵ s

We can calculate the time required for all the 1.25 × 10²² M C₂H₅OH to decompose using the integrated rate law.

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

0 M = 1.25 × 10²² M - 24.00 × 10²⁵ M/s × t

t = 5.21 × 10⁻⁵ s

The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

Learn more about zero-order kinetics here: https://brainly.com/question/13314785

Which one of the following statements about balanced is true? A reaction is balanced by

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Just helping the community

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Answer:

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Explanation:

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REALLY NEED HELP RN
HELP ME ?
PLEASE!??

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Answer:

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this is physics not chem but you just multiply 13 by 642 to get 8,346. also I'm sorry but it's easy

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Answer:

base sa research po

Explanation:

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Answer:

Hydrogen atoms are fused into deuterium, then helium-3, then helium-4, each step giving off large amounts of energy.

Explanation:

Because that's how it works :D

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Answer:

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Explanation:

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Answer:

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Answers

Answer:

Answer E.

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We can go through each answer choice:

A. Since the ball rebounds at half the initial speed, there is a loss in kinetic energy. This is NOT an elastic collision.

B. A collision involving sticking is an example of a perfectly INELASTIC collision. This is NOT an elastic collision.

C. A reduced speed indicates that there is a loss of kinetic energy. This is NOT elastic.

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Let:

m = mass of each ball

v = velocity

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E

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hope this helps

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Answers

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Thus, since carbon is in group 4A we infer it needs 4 more electrons to complete the octet, and that is achieved due to the 4 bonds it is having with the two hydrogen atoms and double bond with the oxygen atom.

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Learn more:

https://brainly.com/question/10535983https://brainly.com/question/21089350

Answer:

Ok I seen the answers on here talk about over complicated lol

Explanation:

CH2O

1 carbon atom

2 hydrogen atoms

1 oxygen atom

then is born CH2O aka formaldehyde : )

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Answers

Answer:

The correct answer choice is A. A chemical change has occurred because new compounds have been produced.

Explanation:

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Answers

Answer:

So we're trying to find the number of carbon moles in the compound. We know that we have 200g of the compound and that 40% of it is Carbon. and 40% of 200 is 80g (change 40% into a decimal and multiply it by 200 and you get 80g)

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Answer:

6.67 moles of carbon in compound

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Answer:

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Answers

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Answer:

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Answers

The Story Behind The Snowy Sour
As the air gets cooler and winter creeps in, I’m looking forward to the first snowfall of the season. This cocktail is all you will need to help you through. I took a classic sour cocktail and elevated it with a winter-citrus-infused simple syrup, made by combining clementine, orange, and honey with sugar and water. All the flavors came together really well, and the gin and fresh lemon juice amalgamate beautifully.

Ingredients In The Snowy Sour:

1.5 ounces gin
1 ounce lemon juice
¾ ounce winter citrus syrup
1 egg white
Snowy Sour Directions:

Combine all ingredients in a cocktail shaker with ice.
Shake hard to chill and combine.
Strain out ice.
Shake hard again to create a silky consistency.
Finely strain into your cocktail glass.
Garnish and enjoy!
Winter Citrus Simple Syrup Ingredients:
2 ounces clementine juice
2 ounces orange juice
2 ounces honey
2 ounces sugar
1 cup water
Winter Citrus Simple Syrup Directions:
Combine all ingredients into a small saucepan.
Bring to a boil.
Remove from heat element and stir while cooling.
Allow to sit for 30 minutes to an hour.

CH6COOH

Vinegar pickles

Differentiate between acids and bases on the basis of their pH values Give an example of each type. Please help worth 100 points!!!!!!!

Answers

Answer: Well 0-7 is acid, and 0-3 is a strong acid. 4-7 is a weak acid. 8-11 is strong base. 12-14 is weak base!

Explanation:

NEED ASAP WILL GIVE BRAINLIST

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we can get rid of scurvy as well as rickets ......

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Answers

lipid pigment any of various pigments having lipid characteristics, some of which also contain protein or iron, the most important one being lipofuscin. respiratory p's substances, e.g., hemoglobin, myoglobin, or cytochromes, which take part in the oxidative processes of the animal body.

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Answers

Answer:

The mass of 1 molecule of water is 18.02

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I hope this is correct, and helps you out :)

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