Para calcular el contenido en gramos de una bebida alcohólica basta con multiplicar los grados de la misma por la densidad del alcohol (0,8). El contenido de alcohol de una bebida depende de la concentración de alcohol y del volumen contenido.
The mass in grams and in kilograms of ethyl alcohol respectively is: a) 1185.0 g and b) 1185 kg
What is density?Density is an intensive property of matter. It represents the relationship between the mass and the volume of a body or substance. Its units are in the International System kg/m3, kg/L, g/ml, g/cm3, among others.
The density formula is:Density = m/V
The mass is obtained by clearing this equation
m=Density *Volume
datam= ?
V= 1500 cm3 * 1 * 10⁻⁶ m³ / 1 cm³ = 0.0015 m³ = 1.5 * 10⁻³ m₃
Density= 790.0 kg/m3
m = 790.0 kg/m³ * 1.5 * 10⁻³m³ = 1.185 Kgm = 1.185 kg * 1000 g/ 1 kg = 1185,0 gm= 1185,0 gSee more about this at:https://brainly.com/question/23704878Two identical (same mass and shape) balls of clay are flying through the air. Ball A is
moving to the right at 4 m/s, while ball B is moving left at 6 m/s. They collide in a
perfectly inelastic collision. What is the velocity of the resulting mass (positive is to
the right)?
Answer in units of meters/second (m/s)
The velocity of the resulting mass after the perfectly inelastic collision of identical balls of clay A and B is 1 m/s to the left.
Conservation of linear momentum
The final velocity of the two identical balls is determined by applying the principle of conservation of linear momentum as shown below;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
u₁ is the initial velocity of ball Au₂ is the initial velocity of ball Bv is the final velocity of both balls after collisionm₁ and m₂ are masses of the two ballsm₁ = m₂ = m
let right direction = positive direction
let left direction = negative direction
m(4) + m(-6) = v(m + m)
4m - 6m = 2mv
-2m = 2mv
v = -2m/2m
v = - 1 m/s
Thus, the velocity of the resulting mass after the perfectly inelastic collision of identical balls of clay A and B is 1 m/s to the left.
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Can you help me pls
What happens when a student replaces the switch in an electric circuit with an object. A light bulb in the circuit does not light up. What can the student conclude about the object
Answer:
The student can conclude that as the bulb is not lighting up so the object can be insulator
Explanation:
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Photophores help the animals which zone of the ocean? how do they help?.
While looking through a telescope, an astronomer views an object that is moving and appears to have a tail. The astronomer states that the tail is caused by evaporation. What is the astronomer most likely observing?.
Answer:
A comet
Explanation:
A comet is composed of mostly ice. As it passes close to the sun, it warms up and begins to release gases, the gases seem longer and they look like a tail. Because the ice gets warmer close to the sun and because it's icy, it changes from ice to liquid and finally vapour. hence evaporaction.
differentiate between beam and physical balance
Answer:
Physical Balance
•Physical balance are utilized for precision mass measurement.
•Physical balance can measure accurately upto a milligram.
Beam balance
•Beam consists of a horizontal beam, supported at it's centre.
•The object is kept on one pan and the standard massess in the other.
Explanation:
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Which of these is evidence of global warning?
A) Rising global temperatures
B) An overall decrease in sea levels
C) Stable precipitation patterns
D) An increase in the size of glaciers
Answer:
D
Explanation:
because the glaciers melt adding more water into the sea which make the sea levels rise.
A country creates a park to protect a forest, what type of resource?
An easy 20 points + brainiest.
Name the order of the planets in our solar system and our solar system's name.
Answer:
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, Milky Way ;-;
What is your understanding of Electricity? Describe how electricity works, circuits, how does it move, what is moving? Where does electricity come from?
How much magnification is needed to see a nanometer?.
when a block is made of _____ the cylinders may eventually wear to the point where repairs are ineffective
When a block is made of rough surfaces, the cylinders may eventually wear to the point where repairs are ineffective.
What is Friction?This is the force which occurs when two surfaces slide against each other. A rough surface have more friction than a smooth surface.
Friction causes wearing out of surfaces and may render repair works done ineffective in this case.
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All of the following are dimensions of progressive overload except multiple choice specificity. time. intensity. frequency.
Progressive overload is the gradual increase in stress to which we subject the body during training, where time, intensity and frequency are dimensions of it.
What is progressive overload?It is a training principle that emphasizes a progressive intensification of stress on the muscles.
It involves the systematic application of training stimuli that force the body to adapt and grow by manipulating the variables of frequency, time and intensity.
Therefore, we can conclude that progressive overload is the gradual increase in stress to which we subject the body during training, where time, intensity and frequency are dimensions of it.
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Which of the following is a consequence of the special theory of relativity?
A) A moving object's mass is constant regardless of its speed.
B) Time slows as the speed of an observer's frame of reference increases
C) A stretching of time due to a moving object can be seen under normal conditions
D) It is possible for an object with mass to travel at the speed of light.
Answer:
D.
Explanation:
Specifically, Special Relativity showed us that space and time are not independent of one another but can be mixed into each other and therefore must be considered as the same object, which we shall denote as space-time. The consequences of space/time mixing are: time dilation. and length contraction.
A bike first accelerates from 0.0m/s to 5.0m/s in 4.5s, then continues at this constant speed for another 4.5s. What is the total distance traveled by the bike
Initial speed u= 0.0 m/s
Final speed v= 5.0 m/s
Time t1= 4.5s
Time for constant speed t2=4.5s
to calculate the total distance traveled by the bike:d = d₁ + d₂
1 = ( v+u/2) × 1₁ + v × 1₂
v = final speed
u = initial speed
t₁ = time for first accelerates
t2 = time for constant speed
d = (5+0/2) × 4.5+ 5.0 x 4.5
d = 33.75m
so, the total distance traveled by the bike is 33.75 m.
# 1
[tex]\bold{a = \frac{(5-0)}{4.5} = 1.11 m/s^2 }[/tex]
[tex]\bold{ v = 0 + a \: t = 1.11 \times 4.5 = 5 }[/tex]
[tex]\bold{ d = 0 + 0 (4.5) + (\frac{1}{2})(1.11)(4.5)^2 =11.2 }[/tex]
# 2
[tex]\bold{ a = 0 }[/tex]
[tex]\bold{ v = 5 }[/tex]
[tex]\bold{ d = 11.2 + 5 (4.5) + 0}[/tex]
[tex]\bold{ = 11.2 + 22.5 = 33.7 meters}[/tex]
A solid cylindrical disk has a radius of 0.15 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 50-N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 110 rad/s2. What is the mass of the disk?
Answer:
Torque = I α = 1/2 M R^2 α where α is the angular acceleration
Torque = F R where F is applied to a distance R from center
F R = 1/2 M R^2 α
M = 2 F / (R α) = 2 * 50 / (.15 * 110) = 6.06 kg
What separates the two sections of the solar system?.
Answer:
These two groups of planets are separated by the asteroid belt, a disk of small rocky bodies orbiting the sun between Mars and Jupiter.
Explanation:
Your welcome!
1. A particle has a mass of 10 kg and a velocity of 5 m/s. What is the momentum of the
particle?
✰ Concept :-
⠀
We know that momentum is the product of mass and velocity. Thus, by the following definition, we get :-
⠀
[tex] \qquad \maltese \: \underline{ \boxed{ \purple{ \sf Momentum = Mass \times Velocity }}} \: \star[/tex]
⠀
✰ Given Information :-
⠀
A particle has mass 10 kgMoving with velocity 5 m/s⠀
✰ To Find :-
⠀
The momentum of the particle⠀
✰ Solution :-
⠀
Using the formula from the concept section, we get :-
⠀
[tex]\sf \longrightarrow Momentum =10 \: kg \times 5 \: {m}^{ - 1} ~~~ \\ \\ \\\sf \longrightarrow Momentum = {50~kg \: ms}^{ - 1} \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow \underline{ \boxed{ \frak{ \orange{Momentum = {50 ~kg\: ms}^{ - 1} }}}} \: \star \: \: \: \: \: \: \\ \\ [/tex]
Thus, the momentum of the particle is 50 kg m/s.
⠀
[tex] \underline{ \rule{230pt}{2pt}} \\ \\ [/tex]
A 2.3-kg toy locomotive is pulling a 1.4-kg caboose. The frictional force of the track on the caboose is 0.46 N backward along the track. If the train is accelerating forward is 3.1 m/s2, what is the magnitude of the force exerted by the locomotive on the caboose
The net vertical force on the caboose (C) is
∑ F[v, C] = F[n, C] - (1.4 kg) g = 0
where F[n, C] is the magnitude of the normal force exerted by the track on the caboose; so we have
F[n, C] = (2.3 kg) g = 13.72 N
which means the coefficient of kinetic friction µ between the caboose and the track is
F[f, C] = 0.46 N = µ (13.72 N) ⇒ µ = (0.46 N) / (13.72 N) ≈ 0.034
and presumably the coefficient is the same for the locomotive.
The net vertical force on the locomotive (L) is
∑ F[v, L] = F[n, L] - (2.3 kg) g = 0
where F[n, L] is the magnitude of the normal on the locomotive, so that
F[n, L] = (2.3 kg) g = 22.54 N
and so the locomotive is opposed by a frictional force with magnitude
F[f, L] = µ (22.54 N) ≈ 0.76 N
Taking the locomotive and caboose together, the net horizontal force on the system is
∑ F[h] ≈ - F[f, C] - F[f, L] + F[engine] = (2.3 kg + 1.4 kg) (3.1 m/s²)
Solve for F[engine] :
F[engine] ≈ (3.7 kg) (3.1 m/s²) + 0.46 N + 0.76 N ≈ 13 N
Diagram of simple cell and dry cell
Answer:
Please see the file attached
CAN ANYONE HELP ME???????????
Answer:
D -- 12
Explanation:
Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!
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an airplane's speed at the time of landing is 90 m/s. ten seconds later it had a speed of 30 m/s. what was the acceleration of the airplane?
Answer:
-6 m/s^2
Explanation:
30 - 90 = -60
-60 / 10 = -6
If acceleration was constant, it will be -6 m/s^2
City leaders in a mid-sized city want to decrease carbon dioxide emissions associated with transportation in the
city.
Which two practices would most likely result in a decrease in carbon dioxide emissions?
Increase the fare for riding on buses.
Widen highways to allow for more cars.
Use electric buses instead of buses that use diesel fuel.
Increase the number of taxis allowed to operate in the city.
Provide community-owned bicycles to residents to use on errands.
The two practices are;
Use electric buses instead of buses that use diesel fuelProvide community-owned bicycles to residents to use on errands.Carbon dioxide emissionThe carbon dioxide emission results from the combustion of fossil fuels such as petrol, coal, firewood etc.
How to reduce carbon dioxide emissionCarbon dioxide emission can be reduced through the following practices;
The use of electric cars The use of solar energy to power our housesThe use of hydrogen fuel, etcThus, the two practices would most likely result in a decrease in carbon dioxide emissions are;
Use electric buses instead of buses that use diesel fuelProvide community-owned bicycles to residents to use on errands.Learn more about carbon dioxide emission here: https://brainly.com/question/11383616
A gyroscope flywheel of radius 2.12 cm is accelerated from rest at 16.2 rad/s2 until its angular speed is 1820 rev/min. (a) what is the tangential acceleration of a point on the rim of the flywheel during this spin-up process
The tangental acceleration of the flywheel of radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².
What is tangental acceleration?This is the rate of change of tangental velocity of an object in circular motion.
To calculate the tangental acceleration, we use the formula below.
Formula:
a = αr............. Equation 1Where:
a = Tangental accelerationr = radius of the flywheelα = Angular acceleration of the flywheel.From the question,
Given:
r = 2.12 cm = 0.0212 mα = 16.2 rad/s²Subsitute these values into equation 1
a = (0.0212×16.2)a = 0.34 m/s²Hence, The tangental acceleration of the flywheel of radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².
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write different Betweens
Three point starter and four point starter~
Ty ~
The most significant difference between the three point and the four-point starter is that in three-point starter the no voltage coil (NVC) is connected in series with the field winding whereas in four-point starter the NVC is directly connected to the supply voltage.
☆...hope this helps...☆
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Which terms describe the different movements of earth? check all that apply. rotation revolution tilted orbit lunar cycle elliptical orbit
Revolution and rotation are the terms that describe the different movements of the earth.
What is the earth?Our home planet is Earth. Earth and its moon, according to scientists, originated about the same period as the rest of the solar system.
That would have been around 4.5 billion years ago, according to scientists. Earth is the solar system's fifth-largest planet.
The rotation and revolution of the earth are two different movements. The movement of the earth on its axis is known as rotation.
Revolution is the movement of the earth around the sun in a fixed route or orbit. The earth's axis, which is an imaginary line, forms a 6612° angle with its orbital plane.
Hence revolution and rotation are the terms that describe the different movements of the earth.
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positively charged center of an atom
Answer:
the nucleus
Explanation
How do you think the switch controls the flow of current to the light?
Answer:
A switch interrupts the flow of current in a circuit.
Explanation:
True or False : Waves lose most of their energy when traveling across the ocean.
Answer:
true
Explanation:
that's the answear
Answer:
it is false i got
Explanation:
it right
A toy car pushed across the floor is observed to slow down and stop based on Newton’s first law of motion what is the best conclusion
A : an object in motion eventually stops
B. The car must have been going slightly uphill
C. The car did not have enough mass to keep going
D. There must have been an unbalanced force acting on the toy car
An object in motion eventually stops because of friction.
What is Newton’s first law of motion?Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or continue its moving in a straight line at constant speed unless force is applied on it.
So we can conclude that An object in motion eventually stops is the correct answer.
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b. The silica cylinder of a radiant wall heater is 0.6 m long
and has a radius 6 mm. If it is rated at 1.5 kw estimate
its temperature when operating. [The Stefan constant,
6=6 x 10-8 wm-2-4)
Ans: 1025 K
So, If the silica cyliner of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
To estimate the operating temperature of the radiant wall heater, we need to use the equation for power radiated by the radiant wall heater.
Power radiated by the radiant wall heaterThe power radiated by the radiant wall heater is given by P = εσAT⁴ where
ε = emissivity = 1 (since we are not given), σ = Stefan-Boltzmann constant = 6 × 10⁻⁸ W/m²-K⁴, A = surface area of cylindrical wall heater = 2πrh where r = radius of wall heater = 6 mm = 6 × 10⁻³ m and h = length of heater = 0.6 m, and T = temperature of heaterSince P = εσAT⁴
P = εσ(2πrh)T⁴
Making T subject of the formula, we have
Temperature of heaterT = ⁴√[P/εσ(2πrh)]
Since P = 1.5 kW = 1.5 × 10³ W
Substituting the values of the variables into the equation, we have
T = ⁴√[P/εσ(2πrh)]
T = ⁴√[1.5 × 10³ W/(1 × 6 × 10⁻⁸ W/m²-K⁴ × 2π × 6 × 10⁻³ m × 0.6 m)]
T = ⁴√[1.5 × 10³ W/(43.2π × 10⁻¹¹ W/K⁴)]
T = ⁴√[1.5 × 10³ W/135.72 × 10⁻¹¹ W/K⁴)]
T = ⁴√[0.01105 × 10¹⁴ K⁴)]
T = ⁴√[1.105 × 10¹² K⁴)]
T = 1.0253 × 10³ K
T = 1025.3 K
So, If the silica cylinder of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
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