do the planets orbit the sun in a perfect circle

Answers

Answer 1

Answer:

All the planets in the Solar System orbit the Sun. When planets orbit the Sun, they don’t move around in a perfect circle. They all follow an 'elliptical path', meaning it looks more like an oval.

Explanation:

Answer 2

Answer:no planets orbit the sun in a perfect circle because they travel in a slightly elliptical orbit

Explanation:


Related Questions

This was merely an accident and I did not mean to post a question.

Answers

Answer:

ok  a good rest of your day

Explanation:

2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?

Answers

Answer:

The building are not getting farther and farther away, road signs, exits, other cars

Explanation:

When electrons are shared unequally a/an
bond is formed

Answers

Covalent bonds form when electrons are shared between atoms and are attracted by the nuclei of both atoms. In pure covalent bonds, the electrons are shared equally. In polar covalent bonds, the electrons are shared unequally, as one atom exerts a stronger force of attraction on the electrons than the other.

A 1,000 kg car traveling 15.0 m/s brakes and comes to a stop after traveling 20.0 m.


a. What is the car’s initial kinetic energy?
b. What is the car’s final kinetic energy?
c. How much work does it take to stop the car?
d. How much constant force is applied in bringing the car to a stop?

Answers

a. initial kinetic
Ek=1/2mv ²
Ek=1/2(1000)(15²)
Ek=112,500J

b. final kinetic energy=0J
as it comes to a stop so v=0

c. Work = ∆Energy
Or
Work=Fs

∆E/W= initial energy - final energy
∆E/W=112,500-0
∆E/W=112,500 J

d.W=Fs

112,500=F(20)
112,500/20 =F
F=5625 N

A. The car’s initial kinetic energy is 112500 J

B. The car’s final kinetic energy is 0 J

C. The amount of work done to stop the car is –112500 J

D. The force applied in bringing the car to a stop is –5625 N

A. How to determine the initial kinetic energy Mass (m) = 1000 KgInitial velocity (u) = 15 m/sInitial kinetic energy (KEᵢ) =?

KEᵢ = ½mu²

KEᵢ = ½ × 1000 × 15²

KEᵢ = 112500 J

B. How to determine the final kinetic energy Mass (m) = 1000 KgFinal velocity (v) = 0 m/sFinal kinetic energy (KEբ) =?

KEբ = ½mv²

KEբ = ½ × 1000 × 0²

KEբ = 0 J

C. How to determine the workdone Initial kinetic energy (KEᵢ) = 112500 J Final kinetic energy (KEբ) = 0 JWorkdone (Wd) =?

Wd = KEբ – KEᵢ

Wd = 0 – 112500

Wd = –112500 J

D. How to determine the force

We'll begin by calculating the acceleration. This can be obtained as follow:

Initial velocity (u) = 15 m/sFinal velocity (v) = 0 m/sDistance (s) = 20 mAcceleration (a) =?

v² = u² + 2as

0² = 15² + (2 × a × 20)

0 = 225 + 40a

Collect like terms

0 – 225 = 40a

–225 = 40a

Divide both side by 40

a = –225 / 40

a = –5.625 m/s²

Finally, we shall determine the force. This is illustrated below:

Mass (m) = 1000 KgAcceleration (a) = –5.625 m/s²Force (F) =?

F = ma

F = 1000 × –5.625

F = –5625 N

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what is the range of plane if the angle of the projective is 30° with a speed of √2g?​

Answers

Answer:

The range is 17.32 m

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Initial velocity (u) = √2g

Acceleration due to gravity (g) = 10 m/s²

Range (R) =?

The range can be obtained as follow:

R = u²Sine2θ /g

R = (√2g)²Sine 2θ / g

R = 2g² × Sine (2×30) / g

R = 2g × Sine 60

R = 2 × 10 × 0.8660

R = 17.32 m

Therefore, the range is 17.32 m

Series circuit when you had one bulb and battery voltage was at 9 volts, what was current into battery?
1) .90amps
2) .40amps
3) .30 amps

Answers

Answer:

incomplete question, resistor must be there

Explanation:

____________ is the rate at which the electric charges move through a given area.
Magnetism
Current
Induction
Flux

Answers

Answer:

current is the rate at which the electric charges move through a given area

8.How long is a day? A year?

Answers

Answer:

24 hours. 365 days

Explanation:

An object of mass 1.5 kg is moving forwards along the floor against an applied force of
40.0 N [backwards]. If the coefficient of kinetic friction is 0.25, determine the
acceleration of the object.

Answers

Answer:

The acceleration of the object is -29.12 m/s².

Explanation:

The acceleration of the object can be calculated by Newton's second law:

[tex] \Sigma F = ma [/tex]

[tex] - F - F_{\mu} = ma [/tex]                        

[tex] - F - \mu mg = ma [/tex]                        

Where:

F: is the applied force = 40.0 N

μ: is the coefficient of kinetic friction = 0.25

m: is the mass of the object = 1.5 kg

g: is the acceleration due to gravity = 9.81 m/s²

a: is the acceleration =?

[tex] a = \frac{- F - \mu mg}{m} = \frac{-40.0 N - 0.25*1.5 kg*9.81 m/s^{2}}{1.5 kg} = -29.12 m/s^{2} [/tex]

The minus sign is because means that the object is decelerating due to the applied force and the friction.  

Therefore, the acceleration of the object is -29.12 m/s².

I hope it helps you!  

Easy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 770 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 350 N. What is the speed of the rider at the top of the loop?

Answers

Answer:

v = 17.30 m / s

Explanation:

For this exercise we will use Newton's second law

at the bottom of the loop and stopped

           ∑ F = 0

           N-W = 0

           N = W

            W = 770 N

the mass of the body is

            W = mg

             m = W / g

            m = 770 / 9.8

            m = 78.6 kg

on top of the loop and moving

           ∑ F = m a

           N + W = m a

note that the three vectors go in the same vertical direction down

           

the centripetal acceleration is

           a = v² / r

we substitute

           N + W = m v² / r

           v = [tex]\sqrt{(N+W) \frac{r}{m} }[/tex]

let's calculate

          v = [tex]\sqrt{ (350+770) \frac{21}{78.6} }[/tex]

          v = 17.30 m / s

A sound wave is propagating through the air from left to right as shown in the diagram below.

Answers

Answer:

Explanation: Pules

Answer: longitudinal (compression)

Explanation:

Can you describe how and why the molecules move from one side to the other?

Answers

The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.

The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.

The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.

The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.

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A satellite orbits earth at constant speed in circular orbit.Which statement is correct? A The resultant force on the satellite is zero. B The resultant force on the satellite is towards the Earth. C The resultant force on the satellite is away from the Earth. D The resultant force on the satellite is in the direction of motion.

Answers

Answer:

B The resultant force on the satellite is towards the Earth.

Explanation:

In the case when the satellite orbits earth would be at constant speed in the circular orbit so hee the resultant force that on the satellite would be with regard to the earth

So as per the given situation, the option B is correct

And, the rest of the options would be wrong

And, the same would be relevant

A race car has a mass of 710kg. It starts from rest and speeds up to 12m/s in 12.0s. The car is uniformly accelerated during the entire time. What net force is applied to it?

Answers

First calcualte the acceleration =V/t=12/12=1m/s2
Second calcualte the net force according to the Newton second law
F=ma=710x1=710N

A 8.57-m ladder with a mass of 21.4 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 258 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.63 rad/s2 about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder

Answers

Answer:

[tex]1311.5\ \text{Nm}[/tex]

Explanation:

l = Length of ladder = 8.57 m

m = Mass of ladder = 21.4 kg

F = Force on ladder = 258 N

[tex]\alpha[/tex] = Angular acceleration = [tex]1.63\ \text{rad/s}^2[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Net torque is given by

[tex]\tau=lf-\dfrac{l}{2}mg\\\Rightarrow \tau=8.57\times 258-\dfrac{8.57}{2}\times 21.4\times 9.81\\\Rightarrow \tau=1311.5\ \text{Nm}[/tex]

The net torque acting on the ladder is [tex]1311.5\ \text{Nm}[/tex].

Kepler's second law states that a line from the sun to a planet sweeps out equal areas in equal times. 2 d coordinate system with an elliptical orbit of planet around the sun. The elliptical orbit is centered at the origin. The Sun is located on the x axis between the origin and the far left edge of the orbit. The Planet is on the orbital path in the first quadrant and has a velocity vector that is pointing counter-clockwise on the orbital path. There is a line connecting the sun and the planet. The Perihelion is marked as the point where the orbit crosses the x axis closest to the Sun. The Aphelion is marked as the point where the orbit crosses the x axis farthest away from the Sun. The aphelion is the point in the orbit where the planet is the furthest distance from the sun, The perihelion is the point at which the planet is closest to the sun. At which point must the speed of the planet be greater

Answers

Answer:

the speed is higher in the PERIHELIUM

Explanation:

As stated in your statement, Kepler's second law says that a vector from the sun to the planet also sweeps equal in equal times. This is a consequence that the sun-planet system is isolated, therefore the angular momentum is conserved.

            L = r x p = m r x v

where m is the planet mass   and the Sun is considered fixed

Let's analyze this expression, if the anglar momentum  is a constant when r is less (perihelion) the speed must increase, so that the product remains fixed

So the speed is higher in the PERIHELIUM

580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum (m=3)?
(Remember, nano means 10^-9.)
(Unit=deg)

Answers

Answer:

0.66 degrees

Explanation:

The computation of the angle of the third dark interference is shown below:

The condition of the minima is

Path difference = (2n +1) × [tex]\lambda[/tex]÷ 2

For third minima, n = 2

Now

xd ÷ D = (2 × 2 + 1) × [tex]\lambda[/tex]÷ 2

d tan Q_3 = 5[tex]\lambda[/tex] ÷ 2

tan Q_3 = 5[tex]\lambda[/tex] ÷ 2d

Q_3 = tan^-1 × (5[tex]\lambda[/tex] ÷2d)

= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)

= 0.66 degrees

A wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x10⁻⁷ Ωm. Calculate the length of the wire.

Answers

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m

Calculati rezistenta filamentului unui bec al lanternei de buzunar daca la tensiunea de 3,5 v el este parcurs de un curent cu intensitatea de 0,28 A

Answers

Answer:

Resistencia = 12.5 Ohmios

Explanation:

Dados los siguientes parámetros;

Voltaje = 3.5 Volts

Corriente = 0.28 Amps

Para encontrar el resistencia;

La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.

Matemáticamente, La ley de Ohm viene dada por la fórmula;

Voltaje = corriente * resistencia

Resistencia = voltaje/corriente

Resistencia = 3.5/0.28

Resistencia = 12.5 Ohmios

Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.

Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²​

Answers

Answer:

40 Kpa

Explanation:

150 cm2 = 0.015 m2

[tex]p \: = \frac{mg}{ a} = 40000[/tex]


1. Which term is the name given to the underwater mountains in the
middle of oceans? *
mid-ocean crust
mid-ocean mountas
mid-ocean ridges
mid-ocean basins

Answers

Answer:

The name given to the underwater mountains in the middle of oceans is;

Mid-ocean ridges

Explanation:

Mid-ocean ridges, also known as mid-oceanic ridge is a mountain range made by plate tectonics under the water.

The magma created at a divergent boundary where two tectonic plates meet due to the rise of convection currents in the Earth's mantle which is beneath the oceanic crust results in the uplifting of the ocean floor.

If the mass of the cement is 15000kg. calculate the density of this cement sample in kgm-3​

Answers

The density of this cement sample is equal to [tex]2727.27\;kg/m^3[/tex]

Given the following data:

Mass of cement = 15000 kgLength = 1.1 mWidth = 2 mHeight = 2.5 m

To calculate the density of this cement sample​:

First of all, we would determine the volume of the rectangular block.

[tex]Volume = length \times width \times height\\\\Volume = 1.1 \times 2 \times 2.5\\\\Volume = 5.5 \;m^3[/tex]

Now, can calculate the density of this cement sample:

Mathematically, the density of a substance is given by the formula;

[tex]Desnity =\frac{Mass}{Volume}[/tex]

Substituting the values into the formula, we have;

[tex]Density=\frac{15000}{5.5} \\\\Density =2727.27\;kg/m^3[/tex]

Read more: https://brainly.com/question/18320053

Note: 1.1 m, 2 m, 2.5 m are the figures provided from a rectangular block of cement.

When particles in a gas slow down, cool down and gather as a liquid, matter is:
A)freezing
B)sublimating
C)melting
D)condensing


Answers

A gas to liquid phase change is condensation, so the correct answer choice would be D.

fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket​

Answers

Answer:

Thrust = 200 N

Explanation:

The engine thrust can be found by using the following formula:

[tex]Thrust = mv[/tex]

where,

m = mass flow rate of the fuel = 0.05 kg/s

v = velocity of ejected gases = 4000 m/s

Therefore, using the given values in the equation, we get:

[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]

Thrust = 200 N

A fruit basket of mass 44.5 kg weighs approximately how much in newton? (Answer should have a number and a proper unit) *

Answers

Answer:

445N

Explanation:

F=mg

m=44.5kg

g=10m/s2

F=44.5 * 10

=445N

A light wave has a frequency of 5 x 108. What is the wavelength of the light wave? (Assume the speed of light to be 3 x 108.)

Answers

Answer:

Wavelength of light wave = 0.6 m

Explanation:

Given:

Frequency of wave = 5 x 10⁸

Speed of light = 3 x 10⁸ m/s

Find:

Wavelength of light wave

Computation:

The size of a wave form is its spatial duration, or the duration in which the wave's form repeats.

Wavelength of light wave = Speed of light / Frequency of wave

Wavelength of light wave = [3 x 10⁸] / [5 x 10⁸]

Wavelength of light wave = 0.6 m

Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?
A. Elements with intermediate numbers of valence electrons are the last chemically stable.
B. Elements with the highest number of valence electrons are the most chemically stable.
C. Elements with intermediate number of valence electrons are the most chemically stable.
D. Elements wit the lowest number of valence electrons are the most chemically stable.

Answers

Answer:

C. Elements with intermediate number of valence electrons are the most chemically stable.

why brittles of a paint brush spread when in water and cling when taken out of water​

Answers

Answer:

surface tension

Explanation:

because of surface tension in water

.
[tex]25 {?}^{?} \times \frac{?}{?} [/tex]

Answers

Answer:

what is your exact question.

what are u asking exactly ?

The body needs small amounts of ________ to help enzymes break down proteins.

Answers

Answer:

I would say vitamin B-6

Explanation:

it is also known as pyridoxine. it helps ebzymes break down protein and carry the dismantled amino acids to the blood stream

Hope this helps ✌✌

Answer:

The body needs small amount of vitamin B-6 to help enzymes break down protein and carry the dismantled amino acids to the blood stream.

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