DONT SKIP PLEASE ILL GIVE BRAINLIEST
3. Which expression is equivalent to the one below?
-3(10+)
A
-5
-5-
В.
c. -5 + 1/2
D. -5+1

Answer: 55/126

Step-by-step explanation:

For this equation, the easiest way to solve is to change the denominators, or bottom halves, of both fractions to be the same thing. The easiest way to do this is to multiply themselves with a “funny form” of one. A funny form of one is just a way of representing “1” with numbers that aren’t 1. “2/2” is a funny form of one. log(x)/log(x) is a funny form of one, etc..

(3/7)x(9/9)=27/63

(4/9)x(7/7)=28/63

These fractions are very close. If you are willing to settle for an unsimplified fraction, the answer here would be 27.5/63. If you aren’t willing to settle for the unsimplified form, we can multiply both fractions by a funny form of one again, most easily 2/2, and find the median of the two fractions.

(27/63)x(2/2)=54/126

(28/63)x(2/2)=56/126

The median of these two fractions is 55/126.

55/126 is exactly halfway between 3/7 and 4/9.

Answer:

-6,-8

Step-by-step explanation:

Answer:

(p)60/100     :)

Step-by-step explanation:

Answer:

[tex]1-\frac{2+13+25}{100} = 0,6[/tex]

Answer:

22+ r = 30

I think this is the answer

Answer:

y = 48°

Step-by-step explanation:

The value of an inscribed angle is half the value of the arc it subtends.

The angle marked x subtends the arc marked 66°, so has a value of ...

x = 66°/2

x = 33°

The value of y is similarly found.

y = 96°/2

y = 48°

The angle marked with a dot is an external angle of the triangle, so is the sum of the remote internal angles, x and y:

dot angle = x + y = 33° +48° = 81°

Of course, angle z is the supplement of this:

z = 180° -81°  

z = 99°

Answer:

For Q. 17 I believe it's "the function has a minimum at -1" take this answer with a grain of salt but the other three seem to be true and I don't know how to solve this one so I'm assuming it's the false one.

Answer:

1/6

Step-by-step explanation:

in the model it shows 6 spots, 1 of those 6 are colored in.

Answer:

Problem 1:

I = 0.4 volts

Problem  2:

V = 250 volts

Step-by-step explanation:

Given:

Potential difference V = 10 V,

Resistance R = 25 ω,

V = IR

I = V/R

I = 10/25

I = 0.4 volts

Current I = 5 A,

Resistance R = 50 ω,

Potential difference

V = IR

V = 5× 50

V = 250 volts

-TheUnknownScientist

Answer:

4.5

Step-by-step explanation:

54/12=4.5

Answer:

Table C

Step-by-step explanation:

Answer:

D. 20 inches

Step-by-step explanation:

Answer:

13.5

Step-by-step explanation:

72/(16/3)

Answer

Calculate Volume ... the length and mass measurements all had 3 significant figures.

Step-by-step explanation:

G O O G L E

Answer:

A

Step-by-step explanation:

100 - 30 - 40 = 30%

30% of 50 = 15 pizzas

Answer:

1/4

Step-by-step explanation:

Answer::112

Step-by-step explanation:

Answer:

I'm sorry dont leave me I need you here with me now

I'm sorry that are love is gone the love is gone☹☹

Answer:

F.   4h ≥ 18

Step-by-step explanation:

In 1 hour, she walks 4 miles.

In h hours, she walks 4h miles.

She wants to walk at least 18 miles. That means she wants the distance she walks to be 18 miles or greater.

4h ≥ 18

Answer: F.   4h ≥ 18

Answer:

B

Step-by-step explanation:

A square root can‘t be negative so

x -1 ≥ 0

x ≥ 1

We can say that the domain is

[1 ; +oo)

The function p(x)=[tex]\sqrt{x+1}+2[/tex]. The domain of the function is [1,∞) or {x|x≥1}.

Given that,

The function p(x)=[tex]\sqrt{x+1}+2[/tex]

We have to find the function domain.

The sets of all the x-coordinates and all the y-coordinates of ordered pairs, respectively, make up the domain and range of a relation.

The components of a function are its domain and range. Range, Domain, and Function. If a function f: A→ B exists that maps every element in A to an element in B, then A is the domain and B is the co-domain. The representation of an element 'a' under a relation R is given by 'b', where (a,b) R. The range of the function is the set of photos. In general, a function's domain and range are denoted as follows: Domain(f) = {x ∈ R} and range(f)={f(x) : x ∈ domain(f)}.

The domain of the function is [1,∞) or {x|x≥1}.

Therefore, The domain of the function is [1,∞) or {x|x≥1}.

To learn more about domain visit: https://brainly.com/question/28135761

#SPJ2

Answer: Should be about a 20.4% chance

Step-by-step explanation:

17 times 6 divided by 5

Answer:

16.97

Step-by-step explanation:

Answer:

obtuse

Step-by-step explanation:

Answer:

b :)

Step-by-step explanation:

None of the other answers make sense. And acute is smaller than a 90 and obtuse is bigger than a 90 if I remember correctly.

Hope this helps!

Answer:

Jenelle invested $ 13,000 in Fund A and $ 4,000 in Fund B.

Step-by-step explanation:

Given that Jenelle invested $ 17000 in two mutual funds, and Fund A earned 4% profit during the first year, while Fund B suffered a 1.5% loss, if she received a total of $ 460 profit, to determine how much had she invested in each mutual fund, the following calculation must be performed:

17000 x 0.04 - 0 x 0.015 = 680

15000 x 0.04 - 2000 x 0.015 = 570

10,000 x 0.04 - 7000 x 0.015 = 295

12500 x 0.04 - 4500 x 0.015 = 432.5

13000 x 0.04 - 4000 x 0.015 = 460

Therefore, Jenelle invested $ 13,000 in Fund A and $ 4,000 in Fund B.

Answer:

-3

Step-by-step explanation:

Hey there!

Equation:

m - n

Solving:

m - n

= 4 - 7

Start at 4 and go up 7 spaces to your left/right

= -3

Therefore, your answer should be: -3

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

(a) Sample Space

[tex]S = \{0,1,2,3\}[/tex]

(b) PMF

[tex]\begin{array}{ccccc}x & {0} & {1} & {2} & {3} \ \\ {P(x)} & {1/3} & {1/6} & {1/6} & {1/3} \ \end{array}[/tex]

(c) CDF

[tex]\begin{array}{ccccc}x & {0} & {1} & {2} & {3} \ \\ {F(x)} & {1/3} & {1/2} & {2/3} & {1} \ \end{array}[/tex]

Step-by-step explanation:

Solving (a): The sample space

From the question, we understand that at most 3 cars will be repaired.

This implies that, the number of cars will be 0, 1, 2 or 3

So, the sample space is:

[tex]S = \{0,1,2,3\}[/tex]

Solving (b): The PMF

From the question, we have:

[tex]P(2) = P(1)[/tex]

[tex]P(0) = P(3)[/tex]

[tex]P(1\ or\ 2) = 0.5 * P(0\ or\ 3)[/tex]

[tex]P(1\ or\ 2) = 0.5 * P(0\ or\ 3)[/tex] can be represented as:

[tex]P(1) + P(2) = 0.5[P(0) + P(3)][/tex]

Substitute [tex]P(2) = P(1)[/tex] and [tex]P(0) = P(3)[/tex]

[tex]P(1) + P(1) = 0.5[P(0) + P(0)][/tex]

[tex]2P(1) = 0.5[2P(0)][/tex]

[tex]2P(1) = P(0)[/tex]

[tex]P(0)= 2P(1)[/tex]

Also note that:

[tex]P(0) + P(1) + P(2) + P(3) = 1[/tex]

Substitute [tex]P(2) = P(1)[/tex] and [tex]P(0) = P(3)[/tex]

[tex]P(0) + P(1) + P(1) + P(0) = 1[/tex]

[tex]2P(1) + 2P(0) = 1[/tex]

Substitute [tex]P(0)= 2P(1)[/tex]

[tex]2P(1) + 2*2P(1) = 1[/tex]

[tex]2P(1) + 4P(1) = 1[/tex]

[tex]6P(1) = 1[/tex]

Solve for P(1)

[tex]P(1) = \frac{1}{6}[/tex]

To calculate others, we have:

[tex]P(2) = P(1)[/tex]

[tex]P(2) = P(1) = \frac{1}{6}[/tex]

[tex]P(0)= 2P(1)[/tex]

[tex]P(0) =2 * \frac{1}{6}[/tex][tex]P(0) =\frac{1}{3}[/tex]

[tex]P(3) = P(0) =\frac{1}{3}[/tex]

Hence, the PMF is:

[tex]\begin{array}{ccccc}x & {0} & {1} & {2} & {3} \ \\ {P(x)} & {1/3} & {1/6} & {1/6} & {1/3} \ \end{array}[/tex]

See attachment (1) for histogram

Solving (c): The CDF ; F(x)

This is calculated as:

[tex]F(x) = P(X \le x) =\sum\limit^{3}_{x_i \le x} P(x_i)[/tex]

For x = 0;

We have:

[tex]P(X \le 0) = P(0)[/tex]

[tex]P(X \le 0) = 1/3[/tex]

For x = 1

[tex]P(X \le 1) = P(0) + P(1)[/tex]

[tex]P(X \le 1) = 1/3 + 1/6[/tex]

[tex]P(X \le 1) = 1/2[/tex]

For x = 2

[tex]P(X \le 2) = P(0) + P(1) + P(2)[/tex]

[tex]P(X \le 2) = 1/3 + 1/6 + 1/6[/tex]

[tex]P(X \le 2) = 2/3[/tex]

For x = 3

[tex]P(X \le 3) = P(0) + P(1) + P(2) + P(3)[/tex]

[tex]P(X \le 3) = 1/3 + 1/6 + 1/6 + 1/3[/tex]

[tex]P(X \le 3) = 1[/tex]

Hence, the CDF is:

[tex]\begin{array}{ccccc}x & {0} & {1} & {2} & {3} \ \\ {F(x)} & {1/3} & {1/2} & {2/3} & {1} \ \end{array}[/tex]

See attachment (2) for histogram