Drive a car at a rate of 40 miles per hour or drive a car at a rate of 50 feet per second? I need the calculations too and I don’t understand.

Answer:

276

Step-by-step explanation:

Circumference = 2πr

= 276

Answer:

area = 12.6 m²

Step-by-step explanation:

r = 4/2 = 2

area = πr² = (3.14)(2²) = 12.56 m²

Answer:

Height of building = 86.9 ft

Step-by-step explanation:

I've drawn a triangle image to depict this question and I have attached it.

From the attached image, we can see that ABC is the height of the building.

We can see the distance from your eye to the ground indicated and also the distance from the horizontal distance from the building to you indicated.

We can use pythagoras theorem to find AB.

AB/57 = tan 55°

AB = 57 × 1.4281

AB = 81.4 ft

Now, total height of the building is AB + BC.

BC = 5.5 ft since B is parallel to your eye and height from there to the ground is 5.5 ft.

Thus;. Height of building = 81.4 + 5.5 = 86.9 ft

ig hanganaahajssislaalalla

Answer: 35

Step-by-step explanation:

3•10=30, 30+5=35

Answer:

hi

Step-by-step explanation:

3(x+4)=-18

3 × X + 3× 4=-18

3x+12=-18

3x=-18-12

3x= -30

x= -30/3

x= -10

hope it helps

have a nice day

Answer:

y = 4x + ( - 3 )

Step-by-step explanation:

y = 4x + 1

( 1 , 1 ) and m = 4

y - 1 = 4( x - 1 )

y = 4x - 3

Answer:

Total interest to be paid: $210

Total amount to be repaid: $3,710

Step-by-step explanation:

You can ignore the monthly payment for this problem.

For simple interest, the formula is I = PRT where I = interest earned, P = principal amount borrowed/deposited, R = rate as a decimal, and T = time in years.

I = (3,500)(0.06)(1)

I = 210

Then add that to the amount borrowed ($3,500) and you're done.

3,500 + 210 = $3,710

Please let me know if you have questions.

Answer:

652

Step-by-step explanation:

Answer: 60

Step-by-step explanation:

6n2

n=5

6(5)2

6×10 = 60

Answer:

that somehow the supposed 'twin' sister has now been integrated into one. The parents looked at the girl, and the girl blinked back. Could it be that their soul has somehow been conjoined? "Oh Lord have Mercy" prayed the mother, while the father looked at the little girl with disgust. He had already wanted a son, but to have a two-hearted freak with them? Your daughter could be one of them. And what will you do, then. You knew this would happen. The father shook off the thought. He WILL NOT let Okani know.

Step-by-step explanation:

Kevin knit 9 scarves, and each scarf was 49.2 inches long.

Converting this length to feet, we find that each scarf is 4.1 feet long.

Let's use the variable "L" to represent the length of each scarf in inches. Since Kevin knit 9 scarves, we can write the equation for the total length of all scarves as:

[tex]\(L_{\text{total}} = L \times 9\)[/tex]

We are given that the total length of all scarves is 442.8 inches. So, we can write:

[tex]\(442.8 \text{ inches} = L \times 9\)[/tex]

To find the length of each scarf, we need to isolate "L" on one side of the equation. To do that, we can perform the following steps:

Divide both sides of the equation by 9 to get:

[tex]\(\frac{{442.8 \text{ inches}}}{{9}} = \frac{{L \times 9}}{{9}}\)[/tex]

Simplifying, we get:

[tex]\(49.2 \text{ inches} = L\)[/tex]

Now, we have found the length of each scarf in inches (49.2 inches). To convert this length to feet, we know that 1 foot is equal to 12 inches. So, to find the length in feet, we divide the length in inches by 12:

[tex]\(L_{\text{feet}} = \frac{{L_{\text{inches}}}}{{12}}\)[/tex]

Substituting the value of [tex]\(L_{\text{inches}}\)[/tex] with 49.2 inches:

[tex]\(L_{\text{feet}} = \frac{{49.2 \text{ inches}}}{{12}}\)[/tex]

Now, let's perform the division:

[tex]\(L_{\text{feet}} = 4.1 \text{ feet}\)[/tex]

So, each scarf is 4.1 feet long.

Kevin knit 9 scarves, and each scarf was 49.2 inches long.

Converting this length to feet, we find that each scarf is 4.1 feet long.

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Answer:

D.

Step-by-step explanation:

The situation that can be modeled by the expression -3/4 x 2/5  is:

Abdi owes Kim 3/4 of a dollar. He pays her 2/5 of how much he owes.

The expression -3/4 x 2/5 gives us the fraction of a dollar that Kim receives from Abdi, which is -3/10 of a dollar.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.com

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

The expression -3/4 x 2/5 means that we multiply -3/4 by 2/5.

Multiplying two fractions involves multiplying their numerators together and their denominators together. So,

-3/4 x 2/5 = (-3 x 2) / (4 x 5) = -6/20 = -3/10

Therefore,

The situation that can be modeled by the expression -3/4 x 2/5  is:

Abdi owes Kim 3/4 of a dollar. He pays her 2/5 of how much he owes.

The expression -3/4 x 2/5 gives us the fraction of a dollar that Kim receives from Abdi, which is -3/10 of a dollar.

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Answer: (6,-4) music

Step-by-step explanation:

Answer:

he can buy 6 gift cards, 7 theatre cards with a remainder of $10.

Step-by-step explanation:

Answer:

x=5/3 or x=-4

Step-by-step explanation:

Answer:

khing chong

Step-by-step explanation:

Answer:

a. The distance the train travelled in the first hour is approximately 28.3 miles

b. The location of the train at 5:00 p.m. is 53 miles east, and 46 miles west

c. The location of the train at any given time by the function, f(t) = (-8 + 24·t, -10 + 15·t)

d. The train does not collide with the cyclist when the bike goes over the train tracks

Step-by-step explanation:

a. The given information on the train's motion are;

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Therefore, the difference between the two times the train was spotted, t = 3:00 p.m. - 2:00 p.m. = 1 hour

Making use of the coordinate plane for the two locations the train was spotted, we have;

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour is given by the formula for finding the distance, 'd', between two points, (x₁, y₁) and (x₂, y₂) as follows;

[tex]d = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]

Therefore;

[tex]d = \sqrt{\left (5-(-10) \right )^{2}+\left (16-(-8) \right )^{2}} = 3 \cdot\sqrt{89}[/tex]

The distance the train travelled in the first hour, d = 3·√89 ≈ 28.3 miles

b. The speed of the train, v = (Distance travelled by the train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arctangent of the slope, 'm', of the path of the train;

[tex]\therefore The \ slope \ of \ the \ path \ of \ the \ train, \, m =tan(\theta) = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

∴ m = tan(θ) = (5 - (-10))/(16 - (-8)) = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizonal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

Where;

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity, [tex]v_y[/tex] = 3*√89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have;

y = -10 + 15·t

The x-component of the velocity, vₓ = 3*√89 mph × cos(arctan(0.625)) = 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't', f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to react the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8) = (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

At the time the cyclist is at the track along the east-west axis, at the point (8, 0), the train is at the point (11.2, 2) therefore, the train does not collide with the cyclist when the bike goes over the train tracks.

If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

The location south the train is spotted = 10 miles south and 8 miles west

The time the observer spotted the train = 2:00 pm

The location of the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east

Thus, the difference between the two times the train was spotted,

t = 3:00 p.m. - 2:00 p.m. = 1 hour

The distance is the product of velocity and time.

Distance = Velocity × Time

The initial location of the train = (-10, -8)

The final location of the train = (5, 16)

Therefore the distance the train travelled in the first hour

[tex]d = \sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} } \\d = \sqrt{(5 -(-10) )^{2} +(16-(-8) )^{2} }[/tex]

d = 3√89

The distance the train travelled in the first hour, d = 28.3 miles

b. The speed of the train, v = (Distance travelled by train)/Time

∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour

The speed of the train in the first hour, v ≈ 28.3 mph

The direction of the train, θ, is given by the arc tangent of the slope, 'm', of the path of the train;

∴ m = tan(θ) = (5 - (-10))/(16 - (-8))

m = 0.625

c. Distance = Velocity × Time

At 5:00 p.m., we have;

The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours

The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles

Using trigonometry, we have the horizontal distance travelled, 'Δx', in the 2 hours is given as follows;

Δx = d₁ × cos(θ)

∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48

The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles

The vertical distance increase in the two hours, Δy is given as follows;

Δy = 56.6 × sin(arctan(0.625)) ≈ 30

The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles

Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)

The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west

c. The function, 'f', that would give the train's position at time-t is given as follows;

The P = f(28.3·t, θ)

28.3·t = √(x² + y²)

θ = arctan(y/x)

Parametric equations

y - 5 = 0.625·(x - 16)

∴ y = 0.625·x - 10 + 5

The equation of the train's track is, therefore, presented as follows;

y = 0.625·x - 5

d = 28.3·t

The y-component of the velocity,

= 3 × √89 mph × sin(arctan(0.625)) = 15 mph

Therefore, we have

y = -10 + 15·t

The x-component of the velocity,

vₓ = 3 × √89 mph × cos(arctan(0.625))

= 24 mph

Therefore, we have;

x = -8 + 24·t

The location of the train at any given time, 't',

f(t) = (-8 + 24·t, -10 + 15·t)

d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph

The distance of the cyclist from the track = The x-intercept

                                                                   = 5/0.625 = 8

The distance of the cyclist from the track = 8 miles

The time it would take the cyclist to reach the track, t = 8 miles/10 mph = 0.8 hours

The location of the train in 0.8 hours, is f(0.8)

= (-8 + 24×0.8, -10 + 15×0.8)

∴ f(0.8) = (11.2, 2)

therefore, If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.

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Answer:

(a) K = 2T

K + 6 = 4T

(b) 2T + 6 = 4T

6 = 4T - 2T

6 = 2T

6/2 = 2T/2

T = 3

When T = 3, K = 6

Answer:

40 m

Step-by-step explanation:

(=^w^=) woof

Answer:

40 [tex]m^2[/tex]

Step-by-step explanation:

the formula for a rectangular prism is:

A=2(wl+hl+hw)

so when you fill in the numbers, you get 40 because l = 2 and w and h are 2

2·(2·4+2·4+2·2)=40

Answer:

Savings in March: $60

Savings in April: $60 + 150% of $60=$60 +$90=$150

Step-by-step explanation:

Liam adds another 150% of the original amount to his savings. So, his total amount does not change but the amount increases by $90 (150% of $60).

Answer:

54 unit sq

Step-by-step explanation:

Answer:

54 i think

Step-by-step explanation:

Answer:

30 ft

Step-by-step explanation:

[tex]C=\frac{n^2}{5} +175\\\\355=\frac{n^2}{5} +175\\\\180=\frac{n^2}{5}\\\\n^2=900\\\sqrt{n^2} =\sqrt{900} \\n=30[/tex]

Answer:

I think it's 25

Step-by-step explanation:

I used a protractor

Answer:

The answer is , More students watch 3 hours of television than watch more than 3 hours of television.

Step-by-step explanation:

Answer:  The most common number of hours that a student watches per week is 3.

Step-by-step explanation:

With 3 having 16 dots and others having lower than these dots that are 16 we can notice that 3 is the most common number and that's the simplest way I can put it.

Hope this helped!!

Answer:

yeah same for me but with ice cream